A water balloon is hovering directly above the line join points ANB which are 4.6 km apart if the angles of elevation to the balloon from point a to B or 28.8° and 52.2 respectively find the altitude of the balloon
Answer:
Drawing the triangle:
H / x = tan 52.2 = 1.29
H / (4.6 - x) = tan 28.8 = .550
H = 1.29 x
H = .55 * 4.6 - .55 x
1.84 x = 2.53 combining equations
x = 1.38
4.6 - 1.38 = 3.22
Total base of triangle = 1.38 + 3.22 = 4.6
H / x = tan 52,2 = 1.29
H = 1.29 * 1.38 = 1.78 height of triangle
Check:
1.78 / 3.22 = tan 28.9
This agrees with the given value of 28.8
What chemical reactions support all life on earth?
Answer:
I’d say both anabolic and catabolic chemical reactions make life on Earth possible. Anabolic is the building up of molecules from atoms or small molecules and catabolic is the chemical reactions of breaking them down.
Explanation:
During which time does Jamal have the greatest momentum?
Answer:
Momentum Packet Answer KEY - Science Online
YOU WILL SEE THE PDF
Which statement best describes the energy changes that occur while a child is riding on a sled down a steep, snow-covered hill?
a
Kinetic energy decreases and potential energy increases.
b
Both potential energy and kinetic energy decrease.
c
Both potential energy and kinetic energy increase.
d
Kinetic energy increases and potential energy decreases.
Answer: When a child is riding on a sled down a steep, snow-covered hill, his elevation decreases and hence Kinetic energy increases and potential energy decreases.
i think this will help you
A water balloon is launched with a speed of 40 m/s at an angle of 60 degrees to the horizontal. What is the vertical component of the velocity?
a 40 m/s
b 34.6 m/s
c 0 m/s
d 20 m/s
Vertical component = 40 m/s x sin(60) = 34.6 m/s
Answer: b. 34.6 m/s
a bullet is fired out of a gun up at an angle with the horizontal. if its initial horizontal velocity is 10m/s what is the most likely horizontal velocity after two seconds
Hi there!
[tex]\large\boxed{10 m/s}}[/tex]
When a projectile is launched, the HORIZONTAL component remains constant.
The force of gravity only changes the vertical component of the velocity.
As the two components are completely independent of one another, the horizontal component is UNCHANGED.
8 million electrons per second through an ohmic gas
the compare software
hope it's help
Answer:
you ask or answer?
Explanation:
thanks for point
Two forces that act on very small distances (smaller than you can see ) are
How do you find the final velocity of two objects colliding when you only have the mass and initial velocity of both objects
Answer:
We are required to analyze the conservation of kinetic energy in a perfectly inelastic collision.
kinetic energy:K=1/2mv²
momentum:p=mv
Explanation:
Using the equations for final velocity in terms of masses and initial velocity for a perfectly inelastic collision, work out the final kinetic energy. Calculate the initial kinetic energy and show that kinetic energy is not conserved. Use variables, no numbers
You need to follow law of conservation of energy
Energy is neither created nor destroyedWe know
Kinetic Energy=mass(Velocity)^2You may use momentum formula mass×velocity
In both you need to form equations then solve for final velocity
A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
So acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.
The Earth currently has an orbital period of 1 year and a semi-major
axis length of 1 AU. If the Earth's orbit changed and the semi-major
axis length increased to 1.1 AU, how would the Earth's orbital period change?
A: It would increase by 0.15 years
B: It would increase by 0.032 years
C: It would decrease by 0.15 years
D: It would decrease by 0.032 years
The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
T = orbital period at R = 1 yearR = initial axis length = 1 AUT' = orbital period at R'R' = final axis length = 1.1 AU.So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period increases by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
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1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.
Answer:
C
Explanation:
because the concave mirror is always inverted
d ) when object is between focus and mirror , image formed is always virtual and erect
What is a Concave mirror ?
A concave mirror has a reflective surface that is curved inward and away from the light source .
a) Incorrect because image can be equal to , smaller then , and bigger then the object
b) and c) Incorrect when object is between focus and mirror , image formed is virtual and erect
d ) Correct option when object is between focus and mirror , image formed is always virtual and erect
e) Incorrect except one case in all other cases nature is real and inverted
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how to find velocity of center of mass before and after the collision
Hey there! I'll try to provide you with my best answer.
Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
45. 3. (III) A 7.26 kg bowling ball hangs from the end of a 2.5 m rope. The ball is pulled back until the rope makes an angle of 45 with the vertical. a. What is the increase in the ball’s potential energy when it is lifted? b. If the ball is released from rest and swings downward like a pendulum, how much kinetic energy will the ball have at the bottom of its swing? c. How fast will the ball be moving at the bottom of its swing?
Explanation:
For the first question look at the picture. It should be pretty clear. Remember that cos45° = sqrt2 / 2.
2) We calculate it thanks to the conservation of mechanical energy:
Em1 = Em2
U1 + K1 = U2 + K2
K1 = 0J
U2 = 0j
U1 = K2
3) mgh = 1/2mv^2
v = sqrt(2gh)
How many kilojoules are in 1,967,256J? Round your answer to the nearest whole number.
Answer:
1,967 kilojoules.
Explanation:
1 kilo = a thousand.
There are 1.967 kilojoules in 1,967,256 joules.
What is law of energy conservation?Energy can neither be created nor destroyed.It is only get transfered from one form to another form.What is the SI unit of energy?Joule is a SI unit of energy.There are 1000 joules in 1 kilojoules .learn more about unit of energy here - https://brainly.com/question/3012083
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how to solve for time given distance and velocity
Answer:
Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:
S = Vt + S0
With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).
From this you can calculate t, if that's what you want.
which is the following is a modern method used to pressure food
1. sprey drying
2.salting
3. smoking
4. Honey
Answer:
1. Spray Drying
Explanation:
it is the most modern
if a 1000kg car goes from a speed of 6.5 m/s to a stop in 3 seconds what is the force acting on the car
Answer:
-6500N
Explanation:
F = ma
Note: 1N = 1 kg⋅m⋅s−2
a = (0-6.5m/s)/3s
a = -6.5m/s^2
F = 1000kg(-6.5m/s^2)
F = -6500kgm/s^2
F = -6500 N
What is the wavelength of an AM radio wave in a vacuum if its frequency is 810 kHz?
what is the electric field strength at a distance of .50 m from a 1.00x10^-6 c charge?
Answer:
e = k q / r² then,
e = 9×10^9 * 1×10^-6 / 50² = 3.6 N/C
hope this helps ❤.
how much power is needed to lift a box with a force of 780 newtons over a distance of 2 meters in 45 seconds
Answer:
34.67 WExplanation:
Power is the rate at which work is done and can be found by using the formula
[tex]p = \frac{w}{t} \\ [/tex]
p is the power in Watts (W)
w is the workdone in joules
t is time in s
but workdone = force × distance
From the question
force = 780 N
distance = 2 m
workdone = 780 × 2 = 1560 N
Since we now have the value of workdone we can find the power
We have
[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]
We have the final answer as
34.67 WHope this helps you
A car is being towed. What is the car’s
mass if the net force on the car is 4,000 N and it has an
acceleration of 2.5 m/s^2?
Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.
What is force ?A physical cause that can change the state of motion or rest of a body is called force. It is the product of mass and acceleration off the body.
Here,
Net force acting on the car, F = 4000 N
Acceleration of the car, a = 2..5 m/s²
We know that,
F = ma
So, m = F/a
m = 4000/2.5
m = 1600 kg
Hence,
Mass of the car having acceleration 2.5 m/s² and net force 4000 N is 1600 kg.
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A certain satellite is in circular orbit about the earth at an altitude of 550km. If the satellite makes a revolution in 110minutes, calculate its orbital speed
Answer:
Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].
The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:
[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].
Convert the units of both distance and time to standard units:
Orbital radius:
[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].
Orbital period:
[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].
Calculate the circumference of this orbit:
[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].
Calculate the orbital speed (tangential) of this satellite:
[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].
Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
Answer:
300 Newtons
Explanation:
Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.
The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have
Force = 12 × 25 = 300 Newtons or 300 N for short.
what is the theory relativity by Einstein?
:MAIN ANSWER:
determined that the laws of physics are the same for all non-accelerating observers
Explanation:
Albert Einstein, in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels, according to Wired.
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HAPPY HOLIDAYS DEC 2021
a convex lens has a focal length of 0.5 it is combined with a second lens so combination has power 2.5 diopter which of the following could be second lens
A) concave lens focal length 2m
B) convex lens focal length 0.5m
C) concave lens 0.5m
D) convex lens 2m
Answer:
concave lens focal length 2m
Which best describes how plant and animal cells carry out the basic functions of life?
A.
Plant and animal cells do not need food molecules for growth.
B.
Plant and animal cells do not make molecules for their own growth and repair.
C.
Plant and animal cells break down food for growth and repair.
D.
Plant and animal cells perform life functions such as making food molecules for growth.
SOMEONE, PLEASE HELP ME AS FAST AS YOU CAN, I WOULD GIVE MORE POINTS BUT THIS IS THE REST OF MY POINT, PLEASE SOMEONE WHO IS SUPER KIND HELP ME.
Answer:
1. The formula for speed is speed = distance ÷ time. To work out what the units are for speed, you need to know the units for distance and time
2. 36÷4= 9
(formula) Speed = distance ÷ time
3. Meter (M) centimeter (cm) kilometers (km)
4. Seconds , Hour, Minute
5. 65÷13=5 (object A)
125÷ 25= 5 (object B)
their both Equal of the amount of speed, so they are travelling at the same speed
Hope I helped
The rays travelled from AIR to an unknown substance. Calculate the n value and
determine the unknown by following these steps: {6 marks}
Medium
n
air
water
ethanol
quartz glass
crown glass
flint glass
ruby
zircon
diamond
1
1.33
1.37
1.47
1.52
1.58
1.54
1.92
2.42
a. On your PAPER calculate n for the unknown value using Ray #1. Type in your
final answer to the electronic box. On paper, ensure #6 is written beside the
calculations.
b. Using the table provided, determine what material was used in the dish to
ar bu
ano below
Answer:
So what you do is you add all of them then you put an n with the answer.
Explanation:
A 5kg ball is on top of the school building at a height of 40m above the ground.
A. calculate the potential energy of the ball at that height.
B. How much power would it take to get the ball from the ground to that height in 1 minute.
C. If it is dropped what type of energy will the ball have as it approaches the ground.
D. What speed will the ball hit the ground
Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.