What is the limit of [(x+2) /(x+1)] ^x as x approaches to infinity?
Answers
first thing we need to do is factorise because we can't calculate infinity/infinity
and we are left with 1^infinity this is an euler function
an euler function looks like this
![What Is The Limit Of [(x+2) /(x+1)] ^x As X Approaches To Infinity?](https://brainimage.s3.us-east-005.backblazeb2.com/answers/attachments/Rs6KjKsx4vQ15OnLZHsY3P9H34AoKffb.png)
Related Questions
Evaluate
f(x)=5x-3
f(5) =
Answers
f(x)=5x-3
use the substitution method
f(5)=(5)(5)-3
multiply the parentheses first
using: PEDMAS
P=Parentheses
E= Exponents
D=Division
M=Multiplication
A= Addition
S=Subtraction
(5)(5)=25
25-3
=22
answer:
f(5)=22
brainlist asap, please help i need to boost my grade in math ♡´･ᴗ･`♡
♡︎♡︎♡︎♡︎♡︎♡︎♡︎♡︎♡︎♡︎♡︎♡︎
question: mona borrowed $6000 for college expenses. After 2 1/2 years she will have paid $750 in interest. What is the interest rate? ______
Answers
Answer:
5250
i hope this is right.
Answer:
5250
Step-by-step explanation:
person on my top got it ^
Which expressions represent the distance between-1 and 4? Choose ALL that apply. 14 - 11 | 4 – (-1) HH34 4342 0 3 5 |-1 - 4 |-1 - (-4)
Answers
|-12| - |-5| = 12 - 5 = 7 ==> The absolute value of -12 and -5 are 12 and 5 respectively. Therefore, 12 minus 5 equals 7. The distance from -5 to -12 on the number line is 7.
help me answer these questions please 15, 19 and 20 please
Answers
Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Please help me thank you so much I appreciate it
Answers
Answer:
12
Step-by-step explanation:
To find perimeter, add the lengths of each side. 5 + 4 + 3 = 12
Answer:
12
Step-by-step explanation:
5+4+3
Harper is a salesperson who sells computers at an electronics store. She makes a base pay amount of $100 per day regardless of sales and she earns a commission of 1% of the dollar amount of sales that she makes. Write an equation for P, in terms of x, representing Harper’s total pay on a day which she sells x dollars worth of computers
Answers
Answer:
100x-p*1%
Step-by-step explanation:
Suppose that in one week in November in St. Louis, the temperature dropped by an average of 4 degrees every day. The temperature at the beginning of the week was 65 degrees. Write an equation that relates the temperature (t) to the number of days that have passed (d). helpppp
Answers
Answer:
t = 65 - 4d
Step-by-step explanation:
Linear Modeling
The temperature in St. Louis dropped by 4 degrees every day in one week.
When d days have passed, the temperature will have dropped by 4d degrees.
We know the temperature t at the beginning of the week was 65 degrees.
Thus, when d days pass, the linear model for the temperature t is:
t = 65 - 4d
Simplify using the laws of exponets.
Answers
Answer:
2*5
Step-by-step explanation:
when youre dividing with powers you have to subtract them so 2*5-2*4=2*1. When the power is in brackets you multiply the whole power. So 2*1 x 5 = 2*5.
I will give you brainliest if you answer this right.
Answers
1/10
1/6
2/3
3/5
Answer this ASAP please. If you can’t see then zoom in. Giving out 25 points and Brainliest to the one who answers correctly. There is a PT2 to this, so you’ll have another chance to answer if you want.
Thank you in advance.
Answers
Answer:
Put 2 feet down for both of them and add 3 extra feet for nate
Step-by-step explanation:
Answer:
add 3 extra feet for Nate and put 2 feet from the both of them
Step-by-step explanation:
A equation of a line in slope intercept form with the given slope and Y-intercept slope: -4, Y-intercept : -9
Answers
Answer:
y = -4x - 9
Step-by-step explanation:
Use slope intercept form, y = mx + b, where m is the slope and b is the y intercept.
Since we are already given the slope and y intercept, we just have to plug them into the equation to find the equation:
y = mx + b
y = -4x - 9
So, y = -4x - 9 is the equation of the line in slope intercept form
Rob did 15 push-ups on Monday, but on Tuesday he did 3 more than on Monday. What was the percent change?
Answers
Answer:
20%
Step-by-step explanation:
Rewrite the equation 8r+62 - 7 = 2 in standard form and Identify a, b, and c
Answers
Answer:
a = 0
b = 8
c = 53
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Algebra I
Standard Form: ax² + bx + c = 0Step-by-step explanation:
Step 1: Define
8r + 62 - 7 = 2
Step 2: Rewrite
Add: 8r + 55 = 2Subtract 2 on both sides: 8r + 53 = 0Step 3: Identify Variables
a = 0
b = 8
c = 53
Find the unknown of the following
Answers
Step-by-step explanation:
For 4.
4b + 2b + 3b = 180°< Sum of angles of triangle >
9b = 180°
b = 180° / 9
b = 20°
4b = 4* 20° = 80°
2b = 2* 20° = 40°
3b = 3 * 20° = 60°
For 5.
x = 64° + 45° <Exterior angle of a triangle is equal to the sum of two opposite interior angles>
x = 109°
Hope it helps :)
n/ 39 = 8/13
Please select the best answer from the choices provided.
A: n = 32
B: n = 2 2/3
C: n = 24
D: n = 63 3/8
Answers
Answer:
24 is the correct answer
13n=39x8
n=312/13
n=24
Kate Sanders, a researcher in the department of biology at PFW University, studied the effect of agricultural contaminants on the stream fish population in northeastern Indiana (April 2012). Specially designed traps collected samples of fish at each of four stream locations. A research question was: did the differences in agricultural contaminants found at the four locations alter the proportion of the fish population by gender
Answers
Full question attached
Answer and explanation:
Null hypothesis : all population proportions are equal, p1=p2=p3=p4
Alternative hypothesis : Not all population proportions are equal
To find our p-value using chi Square method, we first find expected frequencies from observed frequencies above
Expected Frequencies:
Gender A. B. C. D
Male. 46.81 46.81 44.21 43.17
Female 43.19. 43.19 40.79 39.83
Total = 348
chi Square for table = (observed frequency - expected frequency)²/expected frequency
Gender. A. B. C. D
Male. 0.10 0.17 0.52 0.40
Female 0.11 0.18 0.56 0.44
x²= 2.49
Degrees of freedom(df)= k – 1 = (4 – 1) = 3
Using the chi Square table with degree of freedom = 3, 2 and x²= 2.49 shows, the p –value = 0.4771 therefore we do not reject null hypothesis since p value is greater than significance level 0.08
We do not reject the null hypothesis
b. There is no evidence of differences in proportion
Aaliyah is 3 times as old as AJ. 4 years ago, Aaliyah was 7 times as old as AJ. How old is Aaliyah now?
Answers
Answer:
Aaliyah is 18years old now
Step-by-step explanation:
let AJ's age=x
Aaliyah's age=3x
Four years ago,
AJ's age=x-4
Aaliyah's age=3x-4
3x-4=7(x-4)
3x-4=7x-28
3x-7x=-28+4
-4x=-24
x=6
Aaliyah's present age=3x=3×6=18
Integrate the following problem:
[tex]\int {e^{-x} \cdot cos(2x)} \, dx[/tex]
P.S:
Have fun Lauren (and possibly Kelvy)!
Answers
Answer:
[tex]\displaystyle \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex]
Step-by-step explanation:
The integration by parts formula is: [tex]\displaystyle \int udv = uv - \int vdu[/tex]
Let's find u, du, dv, and v for [tex]\displaystyle \int e^-^x \cdot cos2x \ dx[/tex] .
[tex]u=e^-^x[/tex][tex]du=-e^-^x dx[/tex] [tex]dv=cos2x \ dx[/tex] [tex]v= \frac{sin2x}{2}[/tex]Plug these values into the IBP formula:
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = e^-^x \cdot \frac{sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex] [tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex]Now let's evaluate the integral [tex]\displaystyle \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex].
Let's find u, du, dv, and v for this integral:
[tex]u=-e^-^x[/tex] [tex]du=e^-^x dx[/tex] [tex]dv=\frac{sin2x}{2} dx[/tex] [tex]v=\frac{-cos2x}{4}[/tex]Plug these values into the IBP formula:
[tex]\displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} - \int \frac{-cos2x}{4}\cdot e^-^x dx[/tex]Factor 1/4 out of the integral and we are left with the exact same integral from the question.
[tex]\displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx[/tex]Let's substitute this back into the first IBP equation.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ][/tex]Simplify inside the brackets.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ \frac{e^-^x \cdot cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ][/tex]Distribute the negative sign into the parentheses.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4} - \frac{1}{4} \int cos2x \cdot e^-^x dx[/tex]Add the like term to the left side.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx + \frac{1}{4} \int cos2x \cdot e^-^x dx= \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4}[/tex] [tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4}[/tex]Make the fractions have common denominators.
[tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x}{4} - \frac{e^-^x \cdot cos2x}{4}[/tex]Simplify this equation.
[tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4}[/tex]Multiply the right side by the reciprocal of 5/4.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4} \cdot \frac{4}{5}[/tex]The 4's cancel out and we are left with:
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{5}[/tex]Factor [tex]e^-^x[/tex] out of the numerator.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x(2 \cdot sin2x-cos2x)}{5}[/tex]Simplify this by using exponential properties.
[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x}[/tex]The final answer is [tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex].
Answer:
[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]
Step-by-step explanation:
We would like to integrate the following integral:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx[/tex]
Since this is a product of two functions, we can consider using Integration by Parts given by:
[tex]\displaystyle \int u\, dv =uv-\int v\, du[/tex]
So, let’s choose our u and dv. We can choose u base on the following guidelines: LIATE; or, logarithmic, inverse trig., algebraic, trigonometric, and exponential.
Since trigonometric comes before exponential, we will let:
[tex]u=\cos(2x)\text{ and } dv=e^{-x}\, dx[/tex]
By finding the differential of the left and integrating the right, we acquire:
[tex]du=-2\sin(2x)\text{ and } v=-e^{-x}[/tex]
So, our integral becomes:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=(\cos(2x))(-e^{-x})-\int (-e^{-x})(-2\sin(2x))\, dx[/tex]
Simplify:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\int e^{-x}\sin(2x)\, dx[/tex]
Since we ended up with another integral of a product of two functions, we can apply integration by parts again. Using the above guidelines, we get that:
[tex]u=\sin(2x)\text{ and } dv=e^{-x}\, dx[/tex]
By finding the differential of the left and integrating the right, we acquire:
[tex]du=2\cos(2x)\, dx\text{ and } v=-e^{-x}[/tex]
This yields:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[(\sin(2x))(-e^{-x})-\int (-e^{-x})(2\sin(2x))\, dx\Big][/tex]
Simplify:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[-e^{-x}\sin(2x)+2\int e^{-x}\cos(2x)\, dx\Big][/tex]
We can distribute:
[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)-4\int e^{-x}\cos(2x)\, dx[/tex]
The integral on the right is the same as our original integral. So, we can isolate it:
[tex]\displaystyle \Big(\int e^{-x}\cos(2x)\, dx\Big)+4\Big(\int e^{-x}\cos(2x)\, dx)\Big)=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]
Combine like integrals:
[tex]\displaystyle 5 \int e^{-x}\cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]
We can factor out an e⁻ˣ from the right:
[tex]\displaystyle 5\int e^{-x}\cos(2x)\, dx=e^{-x}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]
Dividing both sides by 5 yields:
[tex]\displaystyle \int e^{-x}\cos(2x)\, dx=\frac{e^{-x}}{5}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]
Rewrite. We of course also need the constant of integration. Therefore, our final answer is:
[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]
Landon bought a tray of plants for $8.15. There were 16 plants in the tray. If Landon only bought 1 plant, about how much would it have cost?
Answers
A sailboat is 175 feet from the base of a lighthouse. If the angle of elevation to the top of the lighthouse is 23°, find the height of the lighthouse, to the nearest hundredth of a foot.
Answers
9514 1404 393
Answer:
74.28 ft
Step-by-step explanation:
The tangent of the angle is the ratio of opposite side (lighthouse height) to adjacent side (distance from lighthouse).
tan(23°) = height/(175 ft)
height = (175 ft)·tan(23°) ≈ 74.28 ft
Which of the following MUST be true for two negative number?
Answers
Then solve each problen
Situation 1: A pair of shoes is on sale for 80% of the original price.
The sale price is $60. What was the original price?
food drive
Answers
Answer:
75
a(0.80)=60
a=60/0.80
a=75
The sprit club is making school jackets to sell. The cost c (in dollars) for silkscreening supplies and jackets is c=20x+270, where x is the number of jackets. The club sells each jacket for $35. Write an equation for revenue R in terms of the number of jackets. How many jackets must the club sell to break even?
Answers
Answer:
The club must sell 18 jackets to break even
Step-by-step explanation:
Given:
C = 20x + 270
Where,
x = number of jackets
Equation for revenue R in terms of the number of jackets
Revenue = price × quantity
Price of the jacket = $35
Quantity of the jacket = x
Revenue = price × quantity
= 35 * x
R = 35x
Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.
Cost = revenue
20x + 270 = 35x
270 = 35x - 20x
270 = 15x
x = 270 / 15
= 18
x = 18 jackets
The club must sell 18 jackets to break even
Answer:
torture
Step-by-step explanation:
I was just working on a prblem like this and I hate it
A shop sells apple juice in cartons of two sizes. A 500 ml carton costs $1.30.
a) Work out the cost of 250 ml of this apple juice. A 750 ml carton costs $1.86.
b) Work out the cost of 250 ml of this apple juice.
c) Which carton is better value for money?
Answers
I need help need it done in 20 minutes will give 20 points each
Answers
Answer:
Lets start by isolating for one variable In this case I chose y -7x-2y=14 -2y=14+7x y=-7 -3.5x (1)Next plug the y into the second equation to solve for x
6x+6(-7 -3.5x) =186x+(-42)+ (-21x) =18 6x-21x= 60 -15x=60x=-4Now we know x and we can plug into the original equation (1)
x= -4 y= -7 - 3.5× -4 y= 7Rate brainlist and drop a follow for future help
Answer:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
6*x-6*y-(18)=0
STEP
1
:
Pulling out like terms
1.1 Pull out like factors :
6x - 6y - 18 = 6 • (x - y - 3)
Equation at the end of step
1
:
STEP
2
:
Equations which are never true:
2.1 Solve : 6 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Equation of a Straight Line
2.2 Solve x-y-3 = 0
Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).
Step-by-step explanation:
x= 1 y= 1
hope am right if i am, pls brainliest
Which of the following is an appropriate line of fit for the data?
1
T
2
3
4
5
6
y
8
15
23
28
37
44
Oy= 5x + 1
y = 7x + 2
2
Oy= -62 +5
Oy= 6.52
Answers
Answer:
123idbd8dbokeofyccbdid12332
What postulate/theorem can be used to prove the following triangles congruent?
Answers
Answer: SAS
Step-by-step explanation:
It is given that the two sides are congruent.
The angle between the two congruent sides is also congruent because of the vertical angle theorem.
Since a side, angle, and side are congruent, the theorem is SAS.
find the scale factor of the dilation
Answers
Answer:
k=1/2
It is a reduction
Step-by-step explanation:
To the scale factor, you simply divide the length of the post image by the image.
10/20=k
1/2=k
What is 82.403 rounded to the nearest whole number
Answers
Answer: 82
Step-by-step explanation:
Just Some e-dgenuity i need to get done
Answers
Answer:
Check mark number
2
4
5