Answer:
[tex]we \: have \: \\ w = mg \\ 73.8 = m \times 9.8 \\ or \: m = \frac{73.8}{9.8} \\ or \: m = 7.5306[/tex]
Equation of Motion Problems
Displacement. Distance. Speed and Velocity
1. Donovan Bailey ran the 100 m dash at the Atlanta Olympics in 9.84 s. Michael Johnson ran the 200 m in 19.32
s and the 400 m in 43.49 s. Find their average speed in each case.
Wom
kilometrom
Answer:
Below in bold.
Explanation:
1. Speed = distance / time
= 100 / 9.84
= 10.16 m/s.
Speed = 200/19.32 = 10.35 m/s.
Speed = 400/43.49 = 9.20 m/s.
A skyrocket travels 113m at an angle of 82.4 with respect to the ground and toward the south. What’s the rocket’a horizontal displacement?
Answer:
∆x = 14.9 m, south
Explanation:
∆x = d(cos q) = (113 m)(cos 82.4°)
If a skyrocket travels 113 meters at an angle of 82.4 with respect to the ground and toward the south, then the horizontal displacement of the rocket would be 14.945 meters southwards.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem if a skyrocket travels 113 meters at an angle of 82.4 with respect to the ground and toward the south.
The horizontal displacement = 113 Cos82.4
= 14.945 meters
Thus, the horizontal displacement of the rocket would be 14.945 meters southwards.
To learn more about displacement here, refer to the link;
https://brainly.com/question/10919017
#SPJ2
What equal amounts of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitational attraction? Do you need to know the Moon’s distance to solve this problem? Why or why not? (b) How many metric tons of hydrogen would be needed to provide the positive charge calculated in part (a)? The molar mass of hydrogen is 1.008 g/mol.
Answer:
Fg = G M m / R^2 gravitational attraction
Fe = k Q^2 / R^2 electric repulsion
G M m = k Q^2
Q = (G M m / k)^1/2
Since m = .0123 M
Q = (.0123 G / k)^1/2 * M
Q = (.0123 * 6.67 * 10E-11 / 9 * 10E9)^1/2 * 5.98 * 10E24
Q = 5.71 * 10E13 C charge required on each body
n = 5.71 * 10E13 / 1.6 * 10E-19 = 3.57 * 10E32 atoms
N = 3.57 * 10E32 / 6.02 * 10E23 = 5.93 * 10E8 g-mol = 5.93 * 10E*5 kg-mol
Since 1 metric ton = 1000 kg
One would need 593 metric tons of hydrogen
According to O*NET, what are common work contexts for Foresters?
Answer: Foresters. Manage public and private forested lands for economic, recreational, and conservation purposes. May inventory the type, amount, and location of standing timber, appraise the timber's worth, negotiate the purchase, and draw up contracts for procurement.
Explanation:
An object of irregular shape has a characteristic length of L = 0.5 m and is maintained at a uniform surface temperature of Ts = 400 K. When placed in atmospheric air at a temperature of T[infinity] = 300 K and moving with a velocity of V = 25 m/s, the average heat flux from the surface to the air is 10,000 W/m2 . If a second object of the same shape, but with a characteristic length of L = 2.5 m, is maintained at a surface temperature of Ts = 400 K and is placed in atmospheric air at T[infinity] = 300 K, what will the value of the average convection coefficient be if the air velocity is V = 5 m/s?.
Answer:
The value of the average convection coefficient is 20 W/Km².
Explanation:
Given that,
For first object,
Characteristic length = 0.5 m
Surface temperature = 400 K
Atmospheric temperature = 300 K
Velocity = 25 m/s
Air velocity = 5 m/s
Characteristic length of second object = 2.5 m
We have same shape and density of both objects so the reynold number will be same,
We need to calculate the value of the average convection coefficient
Using formula of reynold number for both objects
[tex]R_{1}=R_{2}[/tex]
[tex]\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}[/tex]
[tex]\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}[/tex]
Here, [tex]k_{1}=k_{2}[/tex]
[tex]h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}[/tex]
[tex]h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}[/tex]
Put the value into the formula
[tex]h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}[/tex]
[tex]h_{2}=20\ W/Km^2[/tex]
Hence, The value of the average convection coefficient is 20 W/Km².
Which is the average velocity of a 35 kg kid sliding for 3.66 m on ice?
Answer:
Calculate the displacement of the car during the above acceleration. { ⃑ = –130 m} c. ... A 2.0 kg brick has a sliding coefficient of friction of 0.38.
Explanation:
its a fill in the blank can someone plz help me
Answer:
That is Melon Collision and the second blank is Lone Collision.
Explanation:
A graduated cylinder has 20mL of water. A rock is placed in the graduated cylinder and the volume rises to 30mL. How can you calculate the volume of the rock?
Answer:
B. Subtract the new volume from the original volume
Explanation: