What is the purpose of cell respiration?

to breath in food
to expel unwanted oxygen
to produce energy from food

When molybdenum is not accessible, vanadium nitrogenase, a crucial enzyme for nitrogen fixation found in nitrogen-fixing bacteria, is employed instead.

Vanadium is a rare element that life uses mostly through vanadium nitrogenases. Vanadium nitrogenase, a crucial enzyme in the nitrogen cycle, turns nitrogen gas into ammonia, making previously inaccessible nitrogen available to plants. Vanadium nitrogenase, in contrast to molybdenum nitrogenase, can also convert carbon monoxide into ethylene, ethane, and propane. However, both enzymes can convert acetylene to ethylene and protons to hydrogen gas . Members of the bacterial genus Azotobacter, as well as the species Rhodopseudomonas palustris and Anabaena variabilis, all include vanadium nitrogenases.Vanadium nitrogenase performs most of the same tasks as the more popular molybdenum.

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Alkanes like ethane and propane are produced as a result of the nitrogenase process. This reaction can result in H2 as it transforms N2 NH3 (dihydrogen).

Diazotrophs are a class of enzymes that can convert atmospheric nitrogen into ammonia. Both MoFe protein and VFe protein, which contain vanadium, are present. Alkanes are saturated acyclic hydrocarbons. They consist of higher members like propane, methane, ethane, etc. The nitrogenase enzyme is essential for the fixation of nitrogen. The nitrogenase enzyme is used in the typical nitrogenase process to change nitrogen (N2) into ammonia (NH3). The two proteins molybdenum-iron and iron protein make up the majority of this enzyme. Alkanes like ethane and propane are produced as a result of the nitrogenase process. This reaction can result in H2 as it transforms N2 NH3 (dihydrogen). This H2 is used to create alkanes like ethane (C2H6) and propane as well as to decrease carbon monoxide (C3H8).

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The alkyl halide product is insoluble in water is reagent (or compound) causes the observed visual change in positive Lucas test.

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The balanced reactions in term of numbers of atoms and electrons is given below:

3 IO₃- + 1 Re → 3 IO- + 1 ReO₄-

The half-reactions for oxidation and reduction:

Oxidation: IO₃ → IO-

Reduction: Re → ReO₄-

Make sure that the number of electrons gained or lost in each half-reaction is the same. In this case, both reactions involve the loss or gain of one electron, so we can proceed.

Balance the number of atoms of each element on both sides of each half-reaction:

Oxidation: 3 IO₃- → 3 IO-

Reduction: 1 Re → 1 ReO₄-

Multiply one or both half-reactions by a factor so that the number of electrons gained and lost are equal. In this case, we do not need to multiply any of them.

Add the half-reactions together, making sure that any species that appear on both sides of the equation cancel out:

3 IO₃- + 1 Re → 3 IO- + 1 ReO₄-

The reaction is now balanced in terms of atoms and electrons.

Check whether the overall reaction is in basic solution, If the reaction is in basic solution, the final step is to balance the oxygen and hydrogen atoms.

The final balanced equation will be:

3 IO₃- + 1 Re + 3 H₂O → 3 IO- + 1 ReO₄- + 6OH-

The balanced reaction is in basic solution as the overall equation is balanced in terms of oxygen and hydrogen atoms.

Therefore, the correct answer is as given above

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From the law of conservation of mass, the mass of products will be 25 g when 25 g baking soda decomposes.

Matter can be changed through physical changes or chemical changes from one form to another form, but through all these changes, the matter will be conserved.

The quantity of matter that exists before and after the change will be the same so none of the matter is created or destroyed.

The balanced equation for the decomposition of baking soda:

NaHCO₃ → Na₂CO₃ + H₂O + CO₂

Given, the mass of the baking soda = 25 g

From the law of the conservation of the mass:

The mass of the products after decomposition = 25 g

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I,II and III would be expected have sp2 hybridization on atom A . So the correct option is -I, II and III

sp2 hybridization is a type of chemical bonding in which an atom's three orbitals (one s-orbital and two p-orbitals) mix together to form three hybrid orbitals. These hybrid orbitals are oriented in a trigonal planar arrangement, and each one is directed at an angle of 120 degrees from the other two. In sp2 hybridization, one of the p-orbital remains un-hybridized, meaning that it does not participate in bonding. The unhybridized p-orbital can hold a lone pair of electrons, which gives the molecule its characteristic shape and reactivity.

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the complete question is :

Which of the following would be expected to have sp2 hybridization on atom A? O I and IV O II O I and III O I, II, and III

Answer:

Explanation:

It pumps about 79*71 = 5629 ml per minute.

To convert ml to m3, we can use the conversion factor 1 m3 = 1,000,000 ml.

So, 5629 ml = 5629/1,000,000 m3

Then to find the mass of the blood that is being pumped through the heart per minute, we can use the density of the blood which is 1060 kg/m3 and multiply it with the volume of blood (5629/1,000,000 m3) that is being pumped through the heart per minute.

mass of blood = (5629/1,000,000 m3) * 1060 kg/m3 = 5.977 kg/min

The heart pumps about 5.977 kg of blood per minute for a person at rest.

Answer: 7.52*10^23 molecules.

Explanation: This is a classic Stoichiometry problem.

In one mole of any substance, there are 6.02*10^23 molecules. This number is called Avogadro's number. We are given 55 grams of Co2 so to convert that to moles, we divided by the molar mass of Co2. We find the molar mass by adding the molar masses of the elements that make up the compound.

There is one molecule of Carbon and two molecules of Oxygen in one molecule of Co2. From the periodic table, the molar mass of Carbon is 12.01 and 16.00 for Oxygen. 1(12.01)+2(16.00) gives us the molar mass. We then divided 55 grams by that mass to find the number of moles. We then multiply the number of moles by Avogadro's number (6.02*10^23) to find the total number of molecules.

You can use this method for solving any problem that asks you to find the number of atoms or molecules of some number of grams of a substance.

Answer:

Solid piece of ice.

Explanation:

Solid piece of ice can easily melt due to heat radiation

The Ka of the 2-hydroxyethylammonium ion is 3.125 x 10^-10 and the pH of 0.42 M methylammonium bromide is 4.3 x 10^-3.

(a) Given pKb of HOCH2CH2CH2NH2 = 4.49

We know that pKa + pKb = 14 and Ka x Kb = 10^-14

Here pKb = -log(Kb) then Kb = 10^-4.49 = 0.32 x 10^-4

Ka = 10^-14/0.32 x 10^-4 = 3.125 x 10^-10

(b) Given the Kb of  CH3NH2 = 4.4 x 10^-4

pKb = 3.35 then pKa = 14 -3.35 = 10.65

The concentration of methylammonium bromide, CH3NH3Br = 0.42M

CH3NH3Br  -> CH3NH2 + HBr

Kb = [HBr] [CH3NH2]/[CH3NH3Br]

4.4 x 10^-4 =  [HBr] [CH3NH2]/0.42

[HBr] [CH3NH2] = 4.4 x 10^-4 x 0.42 = 1.84 x 10^-4

We know that pH = -log([HBr])

[HBr] = 10^-1.84 x 10^-4 = 0.99M

pH = -log(0.99) = 4.3 x 10^-3

Hence the pH of methylammonium bromide is 4.3 x 10^-3.

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In order to round this up to 84 grammes correctly after solving for this, we will receive 83.9 grammes. We're finished with this final response.

PubChem's entry for gold trichloride is AuCl3.

used to create various gold compounds as the initial solution. a step before making ultra pure gold metal. Using electroplating as an anode in an electric cell as well as electroless plating. Brightfield and darkfield microscopy both require cell body stains.

Ingestion swallowed is toxic. Skin Absorption through the skin could be dangerous. makes the skin burn.

The quantity and kinds of nutrients that enter and leave the cells are controlled.

Just round this up to 84 grammes correctly once we have solved for this and arrived at 83.9 grammes. We're finished; this is the last response we have.

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mCPBA is widely used for chemical transformations such as the oxidation of carbonyl compounds.

mCPBA reacts with alkenes to produce epoxides. The stereochemistry is always preserved in this reaction, which is one of its essential characteristics. In other words, a trans alkene will produce a trans epoxide while a cis alkene will produce a cis-epoxide.

Meta-chloroperoxybenzoic acid, or m-CPBA, is a very helpful reagent that is typically used in the synthesis of epoxides. mCPBA, MCPBA, or m-CPBA may all be used interchangeably. It's all essentially the same.

Take note of the additional O in the molecule, which otherwise resembles a carboxylic acid. It should be similar to the distinction between hydrogen per-oxide (HOOH) and hydrogen oxide to understand what is meant by a "per-acid" (H2O). You should take note of how weak the oxygen-oxygen bond is (approximately 33 kcal/mol or 138 kJ/mol).

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One mole of sulphur contains 6.02 × 10²³ S atoms . Hence, 1 atom is equivalent to 1.6 × 10⁻²⁴ moles of S .

One mole of a substance is its amount containing 6.02 × 10²³  atoms or molecules. This number is called Avogadro number. One mole of every elements contains Avogadro number of atoms.

Similarly one mole of every compound contains 6.02 × 10²³  molecules. The mass of one mole of compound is called its molar mass.

S is 16th element in periodic table. S is nonmetal.  One mole of S contains 6.02 × 10²³ S atoms . Hence number of moles of one atom :

1/ 6.02 × 10²³  =  1.6 × 10⁻²⁴ moles

Hence, there will be  1.6 × 10⁻²⁴ moles  S in one atom of sulphur.

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The difference between the two compounds a saturated hydrocarbon is a compound in which all the carbon-carbon bonds are single bonds and an unsaturated hydrocarbon compound that contains at least the double or triple bond between carbon atoms.

A saturated hydrocarbon is a hydrocarbon compound in which all the carbon-carbon bonds are single bonds. An example of a saturated hydrocarbon is methane (CH4). The Lewis structure of methane would be:

H

|

H-C-H

|

H

An unsaturated hydrocarbon is a hydrocarbon compound that contains at least one double or triple bond between carbon atoms. An example of an unsaturated hydrocarbon is ethene (C2H4). The Lewis structure of ethene would be:

H H

| |

C = C

| |

H H

The main difference between saturated and unsaturated hydrocarbons is the presence of double or triple bonds. Saturated hydrocarbons only contain single bonds between carbon atoms, while unsaturated hydrocarbons contain at least one double or triple bond. This difference in bonding leads to a difference in chemical properties such as reactivity. Unsaturated hydrocarbons tend to be more reactive than saturated hydrocarbons because the double or triple bond provides a site for chemical reactions to occur. Saturated hydrocarbons are usually more stable and less reactive than unsaturated hydrocarbons. It's worth to mention that unsaturated hydrocarbons have higher boiling point than saturated hydrocarbons of similar molecular mass because the double bond creates stronger intermolecular forces of attraction between the molecules.

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The given statement stating that air quality is a measure of how clean or polluted the air  in an ecosystem is, hence the statement is  true.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .

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The reaction of cyclohexanone with dimethylamine, in the presence of catalytic amount of an acid forms a compound as shown in the reaction sequence.

If water is continually removed throughout the reaction, the chemical that results is typically referred to as an enamine. Salts like dimethylamine hydrochloride, an odourless white solid with a melting temperature of 171.5 °C, are created when dimethylamine reacts with acids.

Methanol and ammonia undergo a catalytic reaction at high pressure and temperatures to generate dimethylamine: (CH3)2NH + 2 H2O = 2 CH3OH + NH3. Dimethylamine is a base for a number of important industrial chemicals.  Dimethyl dithiocarbamate, a precursor to zinc bis(dimethyldithiocarbamate) and other compounds used in the sulphur vulcanization of rubber, is produced when it combines with carbon disulfide.

Dimethylamine is the source of the solvents dimethylformamide and dimethylacetamide. It is used as a raw ingredient to make a variety of medications and agrichemicals, including dimefox and diphenhydramine, respectively. 

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The percent abundances of the other two isotopes of masses 288 and 290 are 57.5% and 7.5% respectively.

Isotopes of an element refer to the atoms of an element that have different atomic masses.

The relative atomic mass of an element or the weighted average atomic mass of an element is the sum of the isotopic mass and the relative abundances of each of the isotopes of an element.

The percent abundances of the other two isotopes of an element that has three isotopes with mass numbers of 288, 290, and 291, and whose weighted average atomic mass of this element is 289.2, and the percent abundance of the heaviest isotope-291 is 35% is determined as follows:

Let the percent abundance of the isotope of mass 228 be x;

the percent abundance of the isotope of mass 290 will be 65% - x

289.2 = 288x + 290(0.65 - x) + 291 * 0.35

289.2 = 288x + 188.5 - 290x + 101.85

2x = 1.15

x = 0.575 or 57.5%

Hence, the percent abundances are 57.5% and 7.5% respectively.

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H3BNH3(s) - NH3(g) + BH3 is the correct option

The standard enthalpy of production is the enthalpy change that occurs when 1 mole of a substance is made up of its constituent elements in their standard states. In its natural condition, a pure element has a standard enthalpy of production of zero.

The physical states of the reactants and products (gas, liquid, solid, or solution), the pressure of any gases present, and the reaction temperature all affect how much hydrogen (H) is created during a reaction.

The change in a system's enthalpy that happens when one mole of a substance burns completely in oxygen or air at a certain temperature is known as the enthalpy of combustion.

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Sulfur hexafluoride is a light yellowish-green gas with HBr. Whether Cl2 is polar or not may be a point of contention for many pupils. SF6< HBr<Cl2<CO in order of increasing root-mean-square velocity at 50.

It is a gas that is tasteless, odourless, inflammable, and non-toxic. Six fluorine atoms are joined to a central sulphur atom in Sulfur hexafluoride, which has an octahedral structure. Due to the fact that bromine is a member of the halogen family, hydrogen bromide, abbreviated as HBr, is a hydrogen halide chemical. Although quite caustic and hazardous, this chemical has a variety of uses. In both organic and inorganic bromine compounds, it is employed to produce them. Chlorine is a substance that has the chemical formula Cl2. It is regarded as being the second-lightest halogen. It is a light yellowish-green gas that exists at room temperature.

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According to the given statement Total amount of heat absorbed = 5,922 J+15,792 J is 21,714 J.

The amount of energy absorbed or released during a chemical reaction can be expressed in terms of Calorie and joule.

The SI unit of energy is the joule (J) and is used to express energy as both heat and work.

Mass of sample m = 47.00 g

specific heat capacity of water c = 4.2Jg −1 K −1

specific latent heat of fusion of ice L = 336Jg −1

Amount of heat energy absorbed when 47.00 g of sample at 0° C changes into 30°C =

47 x 4.2 × 30 = 5,922 J.

Amount of heat energy absorbed when 47.00g of sample at 0° C changes into ice at  0° C = 47 × 336J = 15,792 J.

Total amount of heat absorbed = 5,922 J+15,792 J.

                              21,714 J.

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The concentration of 2NH₃ is zero and initial change in equilibrium for 2NH₃ is 2x.

By introducing or removing one or more reactants or products, a chemical system that is in equilibrium can be momentarily shifted out of equilibrium. To bring the system back to equilibrium, more adjustments are made to the reactant and product concentrations.

Initial:

The reactants' initial concentrations are 2.0 mol H₂ and 1.0 mol N₂. The concentration of the product 2NH₃ is initially 0.

Change:

Let's use the variable "x" to represent the change in concentration.

The reactant's concentration decreases over time by a factor of x. Put any coefficients you have in front of the variable x as -3x for 3H₂ and -x for N₂ if you have any (such as 3H₂). Since 2 moles of NH₃ are produced on the product side, its concentration will change by +2x.

Equilibrium:

Equilibrium = Initial + change

For 3H₂ = 2.0 [initial] + (-3x) [change] = 2.0 - 3x

For N₂ = 1.0 + (-x) = 1.0 - x

For 2NH₃ = 0 + 2x = 2x

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Answer: Air

Explanation: As a metal, aluminum, gold, and copper are all bad insulators and good conductors for heat and electricity. Air in general is a good insulator.

Answer: You could say carbon monoxide from incomplete combustion

Explanation:

The value of Fx is -5.00N.  The torque or moment of force is the rotational force.

Determine Fx?

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Given that there is a concentration of 0.9 gram of NaCl per 100mL of water.

Therefore for 1000mL ,i.e., 1 litre of water, NaCl requirement is 0.900 × 10 = 9 grams.

Dialysis is the process of removing colloids from dissolved ions, crystalloid molecules, or molecules with tiny dimensions.

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The balanced equation for the reaction is BaCl2 + 2NaOH → Ba(OH)2 + 2NaCl

Based on the given information, we can calculate the amount of Ba(OH)2 obtained.

30 g BaCl2 × (1 mol BaCl2/208.23 g BaCl2) × (1 mol Ba(OH)2/1 mol BaCl2) × (137.3 g Ba(OH)2/1 mol Ba(OH)2) = 8.42 g Ba(OH)2

20 g NaOH × (1 mol NaOH/39.997 g NaOH) × (2 mol Ba(OH)2/2 mol NaOH) × (137.3 g Ba(OH)2/1 mol Ba(OH)2) = 17.48 g Ba(OH)2

Therefore, a total of 25.9 g of Ba(OH)2 is obtained during the reaction of 30 g of BaCl2 and 20 g of NaOH.

There is a surplus of NaOH, with a total of 2.5 g of NaOH remaining (20 g NaOH - 17.48 g Ba(OH)2 = 2.52 g NaOH).

What is balanced equation?

A balanced equation is an equation in which the number of atoms of each element on either side of the equation are equal. For example, the following equation is balanced: 2H2 + O2 → 2H2O

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170.21 cm³  volume would the butane gas sample occupy at a pressure of 2.35 atm.

When the temperature and quantity of the gas are held constant, the volume of a gas is inversely proportional to its pressure. This implies that when a gas's pressure rises, so will its volume, and the opposite is also true. Boyle's law is this. To make predictions in response to a change in either pressure or volume, use the following formula:

P₁V₁ = P₂V₂

Initial pressure, P1, is equal to 760 torr at 1 atm.

400 cm3 is the initial volume (V1).

P2 = 3 atm final pressure

Final volume equals (V2 = L)

V₂ = P₁V₁/P₂

V₂ = (1 atm × 400 cm³)/2.35 atm = 170.21 cm³

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The volume of butane gas is equal to 63.83 mL if the butane gas sample is held at a pressure of 2.35 atm. N-butane or normal butane are other names for butane.

With respect to a set quantity of gas and a constant temperature, the ideal gas equation states that PV = nRT = constant.

Therefore, for two distinct states of an ideal gas, P1V1 = P2V2 = constant.

V2 = P1V1/P2 after rearranging the equation above.

Take P1 equal to 1 atm and V1 equal to 150 mL.

P2 = 2.350 atm as well

When these numbers are substituted in the equation above, V2 = (1 atm 150 mL)/2.350 atm = 63.83 mL is the result.

So, 63.83 mL is the amount of butane gas.

The manufacturing of gasoline, lighter fuel, and cigarette lighters are all common uses for butane gas. Butane has the chemical formula C4H10.

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RNA stays in the nucleus whereas DNA can leave is a false.

Why DNA is stored in the nucleus but RNA can leave it?

A single-stranded mRNA created during DNA transcription exits the nucleus through nuclear pores. Nuclear pores control how molecules are transported into and out of the nucleus.

Where does RNA leave?

Messenger RNAs (mRNAs), which drive protein synthesis, must be exported to the cytoplasm because of this physical barrier, whereas proteins that take part in nuclear functions are imported into the nucleus. Additionally, certain RNA types that have been exported to the cytoplasm come back into the nucleus [1].

Hence above given is a correct answer.

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Answer:i think its C

Explanation: