What is the standard form equation of an ellipse that has vertices (−2,14) and (−2,−12) and co-vertices (9,1) and (−13,1)?

Hello,

[tex]y = ax + b[/tex]

We know the slope is 2 so :

[tex]y = 2x + b[/tex]

The equation of the line that passes through the point (5,4) so :

[tex]4 = 2 \times 5 + b[/tex]

[tex]4 = 10 + b[/tex]

[tex]b = 4 - 10[/tex]

[tex]b = - 6[/tex]

The equation of the line that passes through the point (5,4) and has a slope of 2 is :

[tex]y = 2x - 6[/tex]

y = 2x - 6

Most lines are written in slope-intercept form, but we can use slope-point form in situations like this.

Slope-Point Form

The formula for slope-point form is [tex]y-y_{1}=m\left(x-x_{1}\right)[/tex]. So, we can plug in the information we have, the point and slope.

This is an equation for the line given to us. However, this form can be simplified further.

Slope-Intercept Form

Slope-intercept form is written as y = mx + b, where m is the slope and b is the y-intercept. To find the most simplified form of the equation we need to use the properties of equality.

First, distribute the 2

Next, add 4 to both sides

Now, we have the equation for the line in slope-intercept form. Both of the equations technically meet the requirements for the question, but slope-intercept is more common to use.

Considering that the graphs have two intersection points, the two lines are equal.

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In a graph, the solution of two linear equations is the intersection of the two lines. Hence, if there are two solutions, as is the case in this problem, the two lines are equal.

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The function with the greatest average rate of change is the function k(x)

The average rate of change is calculated as

[tex]m = \frac{y_2 - y_1}{x_2 -x_1}[/tex]

The interval is [0,2].

So, we have

[tex]m = \frac{y_2 - y_1}{2 -0}[/tex]

[tex]m = \frac{y_2 - y_1}{2}[/tex]

For function j(x), we have

j(2) = 3 * 1.6^2 = 7.68

j(2) = 3 * 1.6^0 = 3

So, we have

[tex]m_j = \frac{7.68 - 3}{2}[/tex]

[tex]m_j = 2.34[/tex]

For function g(x), we have

g(2) = 25/2

g(0) = 8

So, we have

[tex]m_g = \frac{25/2 - 8}{2}[/tex]

[tex]m_g = 2.25[/tex]

For function k(x), we have

k(2) = 9

k(0) = 4

So, we have

[tex]m_k = \frac{9 - 4}{2}[/tex]

[tex]m_k = 2.5[/tex]

For function f(x), we have

f(2) = 1.5 * 2^2 = 6

f(0) = 1.5

So, we have

[tex]m_f = \frac{6 - 1.5}{2}[/tex]

[tex]m_f = 2.25[/tex]

The function with the greatest average rate of change is the function k(x) with a rate of 2.5

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Answer:

$21.15

Step-by-step explanation:

(235)(.045)(2)

Answer:

When t = 4

Step-by-step explanation:

The phone will hit the ground when h = 0.

[tex]16t^2 + 32t + 384 =0 \\ \\ t^2 + 2t + 24=0 \\ \\ (t+6)(t-4)=0 \\ \\ t=-6, 4[/tex]

However, as time cannot be negative, we know the answer is when t = 4.

Answer:

  A.  $56

Step-by-step explanation:

The markup is added to the cost price to find the selling price.

The markup is 75% of the cost price:

  markup = 75% × $32 = $24

The selling price is the cost price plus the markup:

  selling price = cost + markup

  selling price = $32 +24 = $56

The selling price of shoes in the athletic store is $56 per pair.

The selling price for shoes in the athletic store with 75% mark up is [tex]\$56[/tex]

Selling price of the item is sum of Markup and cost price.

The cost of shoes is [tex]\$32[/tex]. The company decides Markup by [tex]75\%[/tex] of cost price.

Markup = [tex]\frac{75}{100}\times 32[/tex]

Markup = [tex]\$24[/tex]

Selling price = Markup + Cost price

Selling price = [tex]24+32[/tex]

Selling price = [tex]\$56[/tex]

The selling price for the shoes in the athletic store is [tex]\$56[/tex].

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Answer: (2, -25)

Step-by-step explanation:

The x coordinate of the vertex is [tex]x=-\frac{-4}{2(1)}=2[/tex].

When x=2, [tex]h(2)=2^2 - 4(2)-21=-25[/tex].

So, the vertex is (2, -25).

Answer: The center of the circle will be (1,2) and the radius will be 2.5

Step-by-step explanation: Basically since its (x-1) it would become x=1 so that's ur first value same thign with y but that would be ur second value. And since in your equation it is 6.25 that would be 2.5 because 6.25 is r^2 and you are looking for r.

The value of y  / 3 in the equation is x / 4.

Therefore,

x + 4 / 4 = y + 3 / 3

then y / 3 can be found as follows,

x + 4 / 4  = x / 4 + 4 / 4 = x  / 4 + 1

y + 3 / 3  = y / 3 + 3 / 3  = y / 3 + 1

x  / 4 + 1 = y / 3 + 1

subtract 1 from both sides of the equation

x  / 4 + 1 - 1 = y / 3 + 1 - 1

x / 4 = y / 3

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The value of x to the nearest hundredth is 4.14

The given diagram is a right triangle with the following parameters

Opposite side to 16 degrees = x

Hypotenuse = 15

Using the expression below

sin theta = x/15

sin16 = x/15

x = 15sin16

x = 4.135

Hence the value of x to the nearest hundredth is 4.14

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Answer:

  (f∘g)(x) = 27x² -90x +77

Step-by-step explanation:

The composition of functions (f∘g)(x) is interpreted to mean f(g(x)). The value is found the way any function value is found. The argument is substituted for the variable in the function definition.

After substituting g(x) for the argument of f(x), the resulting expression can be simplified.

  [tex](f\circ g)(x) =f(g(x))=f(3x-5)\\\\=3(3x-5)^2+2=3(9x^2-30x+25)+2\\\\\boxed{(f\circ g)(x)=27x^2-90x+77}[/tex]

Answer: 23.1

Step-by-step explanation:

[tex]\frac{x}{14}=\frac{33}{20}\\\\x=\frac{(33)(14)}{20}\\\\x=23.1[/tex]

The lowest carrier frequency at which each modulated wave S(t) component may be uniquely defined by m(t) is

Fc,Fc+w,Fc-w =>1.5k,2.5k,0.5kHz

-Fc,-Fc+w,-Fc-w =>-1.5k,-0.5k,-2.5kHz

"-w,w -1kHz,1kHz" are the frequency components of the detector output in this case.

Fc,Fc+w,fc-w =>0.75k,1.75k,-0.25kHz

-Fc,-Fc+w,-Fc-w =>-0.75k,0.25k,-1.75kHz

This is further explained below.

For a modulated wave with frequency components, the equation looks like this:

Fc,Fc+w,Fc-w =>1.5k,2.5k,0.5kHz

-Fc,-Fc+w,-Fc-w =>-1.5k,-0.5k,-2.5kHz

"-w,w -1kHz,1kHz" are the frequency components of the detector output in this case.

b)

In conclusion, we may state that the modulated wave has frequency components as well.

Fc,Fc+w,fc-w =>0.75k,1.75k,-0.25kHz

-Fc,-Fc+w,-Fc-w =>-0.75k,0.25k,-1.75kHz

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Answer: The transverse axis of the hyperbola lies on the line y=–3 and has length 6; the conjugate axis lies on the line x=2 and has length 8.

Step-by-step explanation:

Answer:

f(x + 3) = 2(x + 7)

Step-by-step explanation:

Now lets find out what does f(x + 3) means.

f(x + 3) means shifting the entire function 3 units to the left. Which also means, all x values will be shifted to the left by that number of units. (Excluding the constant that is multiplied or divided by x, eg. 5x + 6 shifted by 7 units to the left is 5(x + 7) + 6 and not 5x + 7 + 6.)

From the above,

f(x + 3) = 4(x + 3) + 2 = 4x + 12 + 2 = 4x + 14 = 2(x + 7)

Answer:

$73915.40

Step-by-step explanation:

→ Find the multiplier

( 3 + 100 ) ÷ 100 = 1.03

→ Multiply by principal amount and raise it to the power of years

55000 × 1.03¹⁰ = 73915.40

Answer: $630,513.36

Step-by-step explanation:

Let's make a table of values to see how much he earns every year after graduation.

1 year -> $55,000

2 years -> 55,000 * 103% = $56,650

3 years -> 56,650 * 103% = 55000 * 103% * 103% = $58,349.50

4 years ->  58349.50 * 103% = 55,000 * 103% * 103% * 103% = 55000(1.03)³

Here, we see that every year, he gets 103% of what he got the previous year, which is also 1.03 times his previous salary.

We also see that we multiply 55000 by 1.03 three times in the fourth year, and two times in the third year. This means that we multiply 55000 by 1.03 n-1 times.

Using this, let's generalize this for n.

n years -> [tex]55000(1.03)^{n-1}[/tex]

We are trying to find his total income after ten years, or the sum of his salary from year 1 to year 10. We can represent this in sigma notation like this

[tex]% Adjusted limits of summation$\displaystyle\sum_{n=1} ^{10} 55000(1.03)^{n-1}$[/tex]

This essentially translates to the sum of the first ten terms in the sequence [tex]55000(1.03)^{n-1}[/tex], starting at n=1.

Since this is a geometric sequence, or a sequence where we need to multiply by the same number to get to the next term, we can find the sum using the sum of geometric series formula. This formula is as follows:

[tex]S_n=a_1\frac{1-r^n}{1-r}[/tex]

where [tex]S_n[/tex] is the sum of the first n terms, [tex]a_1[/tex] is the first term, r is the common ratio, and n is the number of terms. In this question, [tex]S_n[/tex] is the total income after n years, [tex]a_1[/tex] is his salary after the first year, r is how much his salary increases by each year, and n is the number of years we are calculating the sum for.

[tex]a_1[/tex] -> 55000

r -> 1.03

n -> 10

Now that we have the values for each variable, let's plug them in and solve

[tex]S_{10}=55000(\frac{1-1.03^{10}}{1-1.03})\\S_{10}=630513.36[/tex]

The total income he will have received after ten years is $630,513.36.

Answer:

BA + BC = AC

Step-by-step explanation:

B is the midpoint of AC

Then

BA = AC/2 and BC = AC/2

Then

BA + BC = AC/2 + AC/2 = AC

Answer:a

Step-by-step explanation:

The two characteristics that makes the median a better choice are: A. The data are skewed and there are outliers.

In a data distribution, the median is a better choice to use to describe the data over the mean when an outlier exist and the data is skewed.

IN the dot plot given below, the data has an outlier of 10 while the data distribution is also screwed, this makes the median a better choice.

Therefore, the answer is: A. The data are skewed and there are outliers.

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Answer:

min = a_1

for i:= 2 to n:

      if [tex]a_i[/tex] < min then min = [tex]a_i[/tex]

return min

Step-by-step explanation:

We call the algorithm "minimum" and a list of natural numbers [tex]a_1, a_2, \cdot\cdot\cdot, a_n.[/tex]

So lets first set the minimum to [tex]a_1[/tex]

min = a_1

now we want to check all the other numbers.

We can use a simple for loop, to find the minimum

min = a_1

for i:= 2 to n:

      if [tex]a_i[/tex] < min then min = [tex]a_i[/tex]

return min

Answer:

The sequence of natural numbers is a_1, a_2, a_3, ..., a_n.

Use min as the variable that will contain the minimum value.

Set min = a_1

In a loop, compare min to each number from a_2 to an.

If min > a_i, then let min = a_i

min = a_1

for i = 2 to n

  if min > a_i, then min = a_i

The equation of a line parallel to the given line and passing through the point (0, 8) is 5y - 3x = 40

The equation of a line in point-slope form is expressed as;

y - y0 = m(x -x0)

where

m is the slope

(x0, y0) is the point on the line

Given the following parameters

Point (0,8)

Slope from the equation = 3/5

Substitute

y - 8 = 3/5(x - 0)
5(y -8) =3x

5y - 40 = 3x

5y - 3x = 40

Hence the equation of a line parallel to the given line and passing through the point (0, 8) is 5y - 3x = 40

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Answer:

[tex]6 + ( \frac{4}{3} + ( \frac{5}{6} - \frac{1}{3} ))[/tex]

[tex] = 6 + ( \frac{4}{3} + ( \frac{5 - 2}{6})) [/tex]

[tex] = 6 + ( \frac{4}{3} + \frac{3}{6})[/tex]

[tex] = 6 + ( \frac{8 + 3}{6})[/tex]

[tex] = 6 + \frac{11}{6} [/tex]

[tex] = \frac{6}{1 } + \frac{11}{6} [/tex]

[tex] = \frac{36 + 11}{6} [/tex]

[tex] = \frac{47}{6} [/tex]

[tex] = 7 \frac{5}{6} [/tex]

After conversion 98.2 °F=119.2°C

96.6 °F=116.3°C

100.1 °F==122.6°C

How can we convert temperature from Fahrenheit to Celsius?

We will convert using this formula

C= (F-32) *5/9

We will convert temperature from Fahrenheit to Celsius as shown below:

C= (F-32) *5/9

For Oral

Temperature=98.2°F

C= (98.2-32) *5/9

=119.16°C

Rounding to nearest tenth

=119.2°C

For Axillary

Temperature=96.6 °F

C= (96.6-32) *5/9

=116.28°C

Rounding to nearest tenth

=116.3°C

For Rectal

Temperature=100.1 °F

C= (100.1-32) *5/9

=122.58

Rounding to nearest tenth

=122.6°C

Hence, after conversion 98.2 °F=119.2°C

96.6 °F=116.3°C

100.1 °F=122.6°C

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Answer:

Step-by-step explanation:

volume of the triangular prism height times base times length so 10 times 8 times 12 = 960.

Answer:

Six Serving Men is a team exercise that examines an issue from twelve different viewpoints. It is based on the words of the poem by Rudyard Kipling: I keep six honest serving men, they taught me all I knew. Their names are What and Why and When and How and Where and Who. To use this technique in a meeting, provide 12 areas for answering questions related to the central topic

Step-by-step explanation:

The description of the box plots are as follows:

IQR = 25 - 2

= 23

The difference between the median values

= 20 - 6

= 14

That female admires those movie stars and has a large group of pals with whom she goes out on a regular basis to keep them company.

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Answer:

14

Step-by-step explanation:

The equation would be R = 5(4) - 6. Multiply 5 by 4 to get 20, then subtract 6 to get 14.

Answer:

one pound of chocolate chips = $2.75

one pound of walnuts = $3.75

Step-by-step explanation:

we can solve this by first making an equation

let's write the number of chocolate chips in c

and the number of walnuts in w

5c  + 3w = 25

7c + 9w = 53

let's first solve for c by multiplying the top equation by 3 and subtracting the bottom equation from it

(15c + 9w = 75) - (7c + 9w = 53)

8c = 22

c = $2.75

Let's now start to solve for w by inputting c into one of the equations.

(2.75)7 + 9w = 53

19.25 + 9w = 53

9w = 53 - 19.25

9w = 33.75

w = $3.75

a pound of chocolate chips  = 2.75

a pound of walnuts = 3.75

give me brainliest, please!

Hope this helps :)

Answer:

each pound of chocolate chips costs $2.75

each pound of walnuts costs $3.75

Step-by-step explanation:

let c be the cost of a pound of chocolate chips

and w be the cost of a pound of chocolate chips

For 5 pounds of chocolate chips and 3 pounds of walnuts,

the total cost is $25  means  5c + 3w = 25

For 7 pounds of chocolate chips and 9 pounds of walnuts,

the total cost is $53  means  7c + 9w = 53

Now we have to solve the system:

[tex]\begin{cases}5c+3w=25&\\ 7c+9w=53&\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}15c+9w=75&\\ 7c+9w=53&\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}15c+9w=75&\\ 8c=22&\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}15c+9w=75&\\ c=\frac{11}{4} &\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}9w=75-15 \times \frac{11}{4} &\\ c=\frac{11}{4} &\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}9w=\frac{135}{4} &\\ c=\frac{11}{4} &\end{cases}[/tex]

[tex]\Longleftrightarrow \begin{cases}w= \frac{15}{4} &\\ c=\frac{11}{4} &\end{cases}[/tex]

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textbf{Equation:}[/tex]

[tex]\mathsf{8,903 = e^{5x}}}[/tex]

[tex]\huge\textbf{Simplify:}[/tex]

[tex]\mathsf{8,903 = e^{5x}}}[/tex]

[tex]\mathsf{e^{5x} = 8,903}}[/tex]

[tex]\huge\textbf{Solve for the exponent:}[/tex]

[tex]\large\textsf{We get: }\downarrow\\\\\mathsf{2.718282^{5x}=8903}[/tex]

[tex]\huge\textbf{Take the logarithm from both sides:}[/tex]

[tex]\mathsf{log(2.718282^{5x}) = log(8,903x)}[/tex]

[tex]\large\textsf{We get:}\\\\\mathsf{5x \times log(2.718282)=log(8903)}[/tex]

[tex]\huge\textbf{Simplify it:}[/tex]

[tex]\mathsf{5x = \dfrac{log(8903)}{log(2.718282)}}[/tex]

[tex]\large\textsf{We get: }\\\\\mathsf{5x = 9.094143}[/tex]

[tex]\huge\textbf{Divide 5 to both sides:}[/tex]

[tex]\mathsf{\dfrac{5x}{5} = \dfrac{9.094143}{5}}[/tex]

[tex]\huge\textbf{Simplify it:}[/tex]

[tex]\mathsf{x= \dfrac{9.094143}{5}}[/tex]

[tex]\mathsf{x = 1.818829}[/tex]

[tex]\mathsf{x \approx 2}[/tex]

[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{x =}\frak{\ 1.818829}}\huge\checkmark[/tex]

[tex]\large\textbf{Or if you're estimating your answer}\downarrow[/tex]

[tex]\huge\boxed{\mathsf{x \approx }\frak{\ 2}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

The number of ways when the choice is not relevant is 1716

The number of letters are:

Letter, n = 13

The letter to choose are:

r = 6

Relevant choice

When the choice is relevant, we have:

[tex]Ways = ^nP_r[/tex]

This gives

[tex]Ways = ^{13}P_6[/tex]

Evaluate

Ways = 241235520

Hence, the number of ways when the choice is relevant is 1235520

Not relevant choice

When the choice is not relevant, we have:

[tex]Ways = ^nC_r[/tex]

This gives

[tex]Ways = ^{13}C_6[/tex]

Evaluate

Ways = 1716

Hence, the number of ways when the choice is not relevant is 1716

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The solution to the system of equations is: x = -4, y = -15.

Given the equations of a system as:

y = 3/4x - 12 --> eqn. 1

y = -4x - 31 --> eqn. 2

Substitute y = (-4x - 31) into eqn. 1 to find x:

-4x - 31 = 3/4x - 12

-4x - 3/4x = 31 - 12

-19/4x = 19

Multiply both sides by -4/19

x = 19(-4/19)

x = -4

Substitute x = -4 into eqn. 2

y = -4(-4) - 31

y = 16 - 31

y = -15

The solution is: x = -4, y = -15.

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