Step-by-step explanation:
2x+1
x = 5
2(5)+1
=10+1=11
Answer:
2(5)+1
10+1
11
Hope This Helps!!!
Given the figure below as marked, which term best describes EF?
A. angle bisector
B. median
C. perpendicular bisector
D. altitude
Answer:
B
median
hope its help you
Answer: B. Median
Step-by-step explanation:
its the middle line.
Help me with this question too
Answer:
The one on the right
Step-by-step explanation:
Because it is 4 then 3
Answer:
the second one (the one to the right)
Step-by-step explanation:
Simplify exponents. A, B, or C and explain.
Answer:
[tex]8^{-3}[/tex]
Step-by-step explanation:
[tex]\frac{8^3}{8^6}[/tex]
in division f the base are same u can subtract their exponents
8^3-6
8^-3
Michelle invested $10,000 for one year, part at 8% interest and the rest at 12% annual interest. Her total interest for the year was $944. How much money did she invest at 12% interest?
Step by step please.
Answer:
Michelle invested $ 6,400 at 8% and $ 3,600 at 12%.
Step-by-step explanation:
Given that Michelle invested $ 10,000 for one year, part at 8% interest and the rest at 12% annual interest, and her total interest for the year was $ 944, to determine how much money did she invest at 12% interest, the following calculation must be done:
10,000 x 0.08 + 0 x 0.12 = 800
8,000 x 0.08 + 2,000 x 0.12 = 880
4,500 x 0.08 + 5,500 x 0.12 = 1,020
6,000 x 0.08 + 4,000 x 0.12 = 960
6,500 x 0.08 + 3,500 x 0.12 = 940
6,400 x 0.08 + 3,600 x 0.12 = 944
Therefore, Michelle invested $ 6,400 at 8% and $ 3,600 at 12%.
Can someone help me? Which of the following verifies that triangle YXZ is similar to triangle QPR?
Answer:
a
Step-by-step explanation:
Plz solve this question correctly.
Show the steps needed to solve it.
Answer: 378y^3
Step-by-step explanation:
the formula for volume is V = L * w * h , where V=volume, L=length, W=width, and H=height
if we plug the numbers from the picture in, the formula would look like this:
V = 9y * 7y * 6y
to solve you just multiply them together
V = 378 y^3
simplify the question
Answer:
=−4√2
I got this when simplified.
Louise begins factoring the polynomial, which has four terms. 8x3+24x2+10x+30 2(4x3+12x2+5x+15) 2[4x2(x+3)+5(x+3)] Which is the completely factored form of her polynomial? 8x2(x + 3)2 2x(4x2 + 5) 2(4x2 + 5) (x + 3) 2(4x2 + 5) (x + 3)2
Answer:
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
Step-by-step explanation:
Given
[tex]8x3+24x2+10x+30= 2(4x^3+12x^2+5x+15)[/tex]
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Required
The complete factored form
We have:
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Factor out x + 3
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
The above represents the completely factored form
Answer:
C on edge
Step-by-step explanation:
I took the test
Which ordered pair is a solution of the equation y = -7x + 2
A. (1,2)
B. (8, -54)
C. (5, -35)
D. (1, -7)
Answer:
B. (8, -54)
Step-by-step explanation:
y = -7x + 2
Check to see if the point makes the equation true
A. (1,2) 2 = -7(1)+2 = -7+2 = 5 False
B. (8, -54) -54 = -7(8)+2 = -56+2 = -54 True
C. (5, -35) -35 = -7(5) +2 = -35+2 = -33 False
D. (1, -7) -7 =-7(1)+2 = --7+2 = -5 False
Calculus 2. Please help
Answer:
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}}} \, dx = \infty[/tex]
General Formulas and Concepts:
Algebra I
Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Calculus
Limits
Right-Side Limit: [tex]\displaystyle \lim_{x \to c^+} f(x)[/tex]Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integrals
Definite IntegralsIntegration Constant C
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
U-Solve
Improper Integrals
Exponential Integral Function: [tex]\displaystyle \int {\frac{e^x}{x}} \, dx = Ei(x) + C[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integral] Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \int\limits^1_0 {\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Rewrite [Improper Integral]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \int\limits^1_a {\frac{e^{-x^2}}{x} \, dx[/tex]Step 3: Integrate Pt. 2
Identify variables for u-substitution.
Set: [tex]\displaystyle u = -x^2[/tex]Differentiate [Basic Power Rule]: [tex]\displaystyle \frac{du}{dx} = -2x[/tex][Derivative] Rewrite: [tex]\displaystyle du = -2x \ dx[/tex]Rewrite u-substitution to format u-solve.
Rewrite du: [tex]\displaystyle dx = \frac{-1}{2x} \ dx[/tex]Step 4: Integrate Pt. 3
[Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {-\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Substitute in variables: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {\frac{e^{u}}{-2u} \, du[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}\int\limits^1_a {\frac{e^{u}}{u} \, du[/tex][Integral] Substitute [Exponential Integral Function]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(u)] \bigg| \limits^1_a[/tex]Back-Substitute: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-x^2)] \bigg| \limits^1_a[/tex]Evaluate [Integration Rule - FTC 1]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-1) - Ei(a)][/tex]Simplify: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{Ei(-1) - Ei(a)}{2}[/tex]Evaluate limit [Limit Rule - Variable Direct Substitution]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \infty[/tex]∴ [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex] diverges.
Topic: Multivariable Calculus
please help me 2 The two lines shown below are perpendicular. If the slope of the red line is 5 what is the slope of the green line? Use a slash mark (/) as a fraction bar if necessary. 15 O A. O OB. 5 min O c. O c tole D. O
Answer:
-5/2
Step-by-step explanation:
Perpendicular slope is always the negative reciprical. This basically means the opposite sign and the nubers are flipped.
A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the stunt diver above the water, is modeled by h=-4.9t^2+12t+5, where t is the time in seconds after starting the dive.
a) How long is the stunt diver above 15 m?
b) How long is the stunt diver in the air?
Answer:
a) 0 seconds.
b) The stunt diver is in the air for 2.81 seconds.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
Height of the diver after t seconds:
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
a) How long is the stunt diver above 15 m?
Quadratic equation with [tex]a < 0[/tex], so the parabola is concave down, and it will be above 15m between the two roots that we found for [tex]h(t) = 15[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]15 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t - 10 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = -10[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(-10) = -52[/tex]
Negative [tex]\Delta[/tex], which means that the stunt diver is never above 15m, so 0 seconds.
b) How long is the stunt diver in the air?
We have to find how long it takes for the diver to hit the ground, that is, t for which [tex]h(t) = 0[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]0 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t + 5 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = 5[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(5) = 242[/tex]
[tex]x_{1} = \frac{-12 + \sqrt{242}}{2*(-4.9)} = -0.36[/tex]
[tex]x_{2} = \frac{-12 - \sqrt{242}}{2*(4.9)} = 2.81[/tex]
Time is a positive measure, so we take 2.81.
The stunt diver is in the air for 2.81 seconds.
PLS I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!
Answer:
5. 2 hours 45 minutes 6. 7:23 7. 10:05 8. 1 hour 34 minutes
Step-by-step explanation:
I mean u gotta be lying about staying up all night to do these 4 problems but heres the answers
Answer:
5. 2 hours 45 mins
6. 7:23 start
7. 10:05
8. 1 hour 34 mins
PLZ HELP ILL GIVE BRAINLIEST IF RIGHT!!!
Rosa has already written 11 pages ,and she expects to write 3 pages for every additional hour spent writing. How many hours will Rosa have to spend writing this week in order to have written a total of 47 pages?
Answer:
12 hours
Step-by-step explanation:
pages total = pages written + pages per hour * number of hour
47 = 11 + 3*h
Subtract 11 from each side
47 -11 = 11 +3h -11
36 = 3h
Divide by 3
36/3 = 3h/3
12 = h
How much almond milk does James use per teaspoon of cashew butter
HELP NEEDED ASAP!! Find the sine of B
HELP PLZ
Possible values for the area A of the rectangle shown are 12 - As 36. Write and
solve a compound inequality to find the possible values of x. Are these values all
viable in this situation?
2x + 1
3
Answer:
i had the exact same question as this, dm me on discord so i can screenshare my answer
Step-by-step explanation:
jey0001 is my discord
If David walks 1/2 mile in 1/4 hour, then how fast does David walk in one hour? (In other words, what is David's "unit rate"?)
CAN SOMEONE HELP ME OUT WITH THIS PLEASE AND THINK YOU
Answer:
[tex]10\frac{7}{18}[/tex]
Step-by-step explanation:
First revert it to improper fraction.
[tex]\frac{13}{2} +\frac{35}{9} \\\\[/tex]
Now put them to a common denominator.
[tex]\frac{187}{18}[/tex]
=> [tex]10\frac{7}{18}[/tex]
Evaluate (xy) ^-6 if x = 3 and y = -1.
A. 3
B. -1/729
C. 1/73
D. 1/729
căn bậc hai của (x^2-2x-3)
[tex]heres \: the \: answer \: i \: hope \: it \: help[/tex]
I need help, please!! I'll give a brainliest
Answer:
metals or metalloids
Step-by-step explanation:
I'm built different i dont know if im right about the question. im just not sure if i understood the question correctly
Complete the synthetic division to find the quotient of 3x^3-25x^2+12x-32 and x-8
Answer:
Explanation:
Hey there!
Please see your required solution in picture.
Quotient Q(X) = 3x²-x+4
Hope it helps!
Answer:
see image
Step-by-step explanation:
Plato/Edmentum
А
E
F
B1
2
2x
135°
750
2x -15°
12
G
H
I
C3
D
Determine the value of x.
i wonder this is math problem or code word for treasure
Answer:
Step-by-step explanation:
(2x-15) = 45
Step-by-step explanation:
When two angles lie on a straight line, they are supplementary
what this mean is that the add up to equal 180 degrees
Mathematically, we have this as:
(2x-15) + 135 = 180
(2x-15) = 180-135
(2x-15) = 45
Two friends Vicky and Micky start a business together. They decided to share their capitals depending up on the variable expenditure. The capital of the two partners together is given by polynomial 6x² + 11x – 35 which is the product of their individual share factors.
a-The value of x, when their total share is equal to 0?
b-The total expenditure of Vicky and Micky when x = 10 is (in Rs
c-The sum of their expenditure is
Answer:
a- x = 5/3, or x = -7/2
b- 675
c - 5·x + 2
Step-by-step explanation:
The polynomial representing the capital of the two partners = 6·x² + 11·x - 35
a. The total share is the capital of the two partners together = 6·x² + 11·x - 35
∴ When their total share is equal to 0, we have;
6·x² + 11·x - 35 = 0
Factorizing the above equation with a graphing calculator gives;
(3·x - 5)·(2·x + 7)
Therefore;
x = 5/3, or x = -7/2
b- The total expenditure, when x = 10 is given by substituting the value of x in the polynomial 6·x² + 11·x - 35, as follows;
When x = 10
6·x² + 11·x - 35 = 6 × 10² + 11 × 10 - 35 = 675
The total expenditure of Vicky and Micky when x = 10 is 675
c - The sum of their expenditure is (3·x - 5) + (2·x + 7) = 5·x + 2
Find the equation of the line with slope -2 which goes through the point (9,-7).
Give your answer in slope-intercept form y = mx + b.
An unknown number y is 10 more than an unknown number x. The number y is also x less than 3. The equations to find x and y are shown
below.
y = x + 10
y=-x+3
Which of the followine statements is a correct step to find x and y?
A add the equations to eliminate x
B multiply the equations to eliminate y
C write the points where the groans of the equation intersect the x axis
D write the points where the graphs equation intersect the y axis
Answer:
a. add the equations to eliminate x
Step-by-step explanation:
this is called process of elimination
Play the four digit 3,5,7,and 9 into the boxes pure in the position that would give the greatest results in the true numbers are multiplied
- 73X95
- 79X53
-97X35
-93X75
- 9 3 x 7 5
Step-by-step explanation:To get the combination that would yield the greatest result if the true number are multiplied,
i. multiply each given combination
73 x 95 = 6935
79 x 53 = 4187
97 x 35 = 3395
93 x 75 = 6975
ii. get the largest result from the results calculated above in (i)
The greatest of the results is 6975, therefore the digits should be placed like so;
9 3
7 5
The angle of elevation to a nearby tree from a point on the ground is measured to be 61 ∘ ∘ . How tall is the tree if the point on the ground is 59 feet from the tree? Round your answer to the nearest hundredth of a foot if necessary.
Answer:
106.44 ft
Step-by-step explanation:
tan = opp/adj
tan61 = opp/59
59*tan61 = opp
opp = 106.438817561014012
Rounded
106.44 ft
log2 1 is defined
True
False
Answer: True
Through the change of base formula, we can say,
[tex]\log_{2}(1) = \frac{\log(1)}{\log(2)} = \frac{0}{\log(2)} = 0[/tex]
So in short,
[tex]\log_{2}(1)=0[/tex]
It turns out that
[tex]\log_{b}(1) = 0[/tex]
for real numbers b such that b > 0 and [tex]b \ne 1[/tex]