Answer:
30 m/s.
Explanation:
can somebody explain it to me please?
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones
[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO
[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
Done
Option B is correct
El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?
E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?
E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?
E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.
a. What is the work done by the force applied by the rope?
b. What is the work done by the frictional force?
c. What is the total work done on the crate?
The same formula of work can be applied to all the questions. The answers are:
E1. 100J
E2. 40N
E3. 5m
E4. a.) 360 J b.) 240 J c.) 120 J
El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be
Work done = force x distance
Work done = 40 x 2.5
Work done = 100 J
E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.
Work done = force x distance
160 = 4F
F = 160/4
Force F = 40 N
E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.
Work done = force x distance
300 = 60 x distance
distance = 300/60
Distance = 5 m
Therefore, the chair moved 5m away.
E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.
a. The work done by the force applied by the rope can be found by
W = F x S
W = 180 x 2
W = 360 J
b. What is the work done by the frictional force?
W = [tex]F_{r}[/tex] x s
W = 120 x 2
W = 240 J
c. What is the total work done on the crate?
W = (F - [tex]F_{r}[/tex]) x distance
Where [tex]F_{r}[/tex] = frictional force
Substitute all the parameters
W = (180 - 120) x 2
W = 60 x 2
W = 120 J
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Starting from rest an object accelerates on a straight line at rate of 2ms‐² for 10 seconds. what is the speed of the object at the end of the 10 seconds
Answer:
20 meters/sec
Explanation:
See attachment.
2m/s^2 = (v - 0)/10s
v = 20 m/s
Which would ba another example of newtons first law?
a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with
Answer:
papi sus
Explanation:
A car has a kinetic energy of 41.6 kJ.
The speed of the car is 8.0m/s.
Calculate the mass of the car.
how to read a micrometer on a clark cm-100 vickers hardness tester
Answer:
Explanation:
Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material
and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is
covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any
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be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER
REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO
THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR
OTHERWISE.
Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by
this warranty.
LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our
satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This
obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,
neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods
exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR
CONSEQUENTIAL DAMAGES WHATSOEVER.
All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the
facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other
parts. This warranty is voided by failure to comply with these notice requirements.
NOTICE
The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.
Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the
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LECO'" is a registered trademark of the LECO Corporatio
Definition of main energy level
Answer:
the orbital in which the electron is located relative to the atom's nucleus.
Explanation:
Answer:
the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
What is the half-life of an isotope if after 30 days you have 31.25 g remaining from a 250 g beginning sample size?
The half-life of the given isotope will be 10 days, if after 30 days only 31.25 grams are remaining from a sample of 250 grams of the sample size taken in the beginning.
What is Half-life of an element?
The Half-life is the time which is required for a quantity to reduce the content to half of the amount present as its initial value. The term is used in nuclear physics to describe how quickly an unstable atom undergo radioactive decay or how long does stable atoms survive. The term is also used generally to characterize any type of exponential decay.
The half-life of the isotope can be calculated by the formula:
FR = 0.5n
FR = Fraction Remaining = 31.25 g / 250.0 g = 0.1250
n = number of half lives elapsed = ?
0.125 = 0.5n
log 0.125 = n log 0.5
-0.9031 = -0.3010 n
n = 3.000 half lives have elapsed
3 half lives = 30 days
1 half live = 10 days
Therefore, the half-life of the isotope will be 10 days.
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in what direction will the seesaw rotate and what will the sign of the angular acceleration be?
Answer:
It can rotate in any direction. The sign of the angular acceleration depends on how you set the reference system, it can be both negative or positive.
Which of the following is an example of physical weathering?
O calcium carbonate in limestone changes to calcium hydrogen carbonate
O flow water carves erosion channels in a hillside
Ostalactites precipitate in a cave
O acid rain corrodes a monument
Answer:
acid rain corrodes a monument. d.
Explanation:it only makes sense because its doing something to a physical object.and the other ones aren't.
Which is the correct answer
Answer:
C
Explanation:
All of the other options are affecting the gravitational force and opposing force that pushed upwards, the diagram represents an object that is not moving up or down.
The normal force of a parked car on a level surface is 15,000 Newtons. What is the force of the car?
Answer:
The force of the car is 15000N.
Explanation:
The unit of force is Newtons (N), so based on the question, the force is 15000 Newtons.
please help me !! i’ll mark brainliest if you’re right!
I desperately need help with my Physics Exam I am failing this class will mark Brainliest to whoever helps the most: PART 1 (I don't want to overwhelm anyone so I'm posting my questions in parts) Also the questions marked are incorrect, so just work with the 3 remaining answers.
10000000 thank you's
A 7.5 kg beaver dives horizontally off a 50 kg log at a speed of 4 m/s. What is the speed of the log?
Answer:
[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.
Explanation:
The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].
If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.
The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].
The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
(The new velocity of the log is negative because the log would be moving away from the beaver.)
The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].
describe how visible light is used with solar photovoltaic panels to produce electricity
Photovoltaic panels are used to produce alternating current using sunlight. It uses solar cells which are photoactive and produce a photoelectric effect and thereby a potential is created.
What is photoelectric effect?When photons from the light energy is hit on a metallic surface the photon collides with the electrons of the metals and electrons are ejected from the metal surface. This phenomenon is called photoelectric effect.
In a solar photovoltaic panel, photovoltaic cells layers of semi-conducting materials, such as silicon, are sandwiched photovoltaic cells. When photons from sunshine strike each layer, its unique electronic properties energise and produce an electric field.
The current required to generate electricity is produced through what is known as the photoelectric effect. Electricity produced by solar panels is in the direct current form. This is then transformed into an alternating current by passing via an inverter.
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If the road becomes wet or crowded, you should ____. slow down and increase your following distance All choices are incorrect. maintain your speed and following distance speed up and decrease your following distance Submit answer
Answer:
The first one.
If the road becomes wet or crowded, you should ___ slow down and increase your following distance_
What is meant by surface distance ?
The safe distance between vehicles traveling in column specified by the command in light of safety requirements
The slower speed will help you save gas and avoid potential accidents. You can easily eliminate chances of rear end collision by maintaining a safe distance between your car and the vehicles ahead.
hence , a) slow down and increase your following distance is a correct option
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What does it mean when a wave’s amplitude increases?
The wave’s wavelength gets longer.
The wave is moving through a denser medium.
The wave is carrying more energy.
The wave’s frequency also increases.
Answer:
the wave is carrying more energy
Explanation:
trust me broski
Answer:
a
Explanation:
A balance of forces is demonstrated by an object which is slowing to a stop true or false
Answer:
its true since i already did this last year, if i am wrong i apologize
Explanation:
Why is kinetic energy lost in an inelastic collision?
Answer:
This is because some kinetic energy had been transferred to something else.
Explanation:
An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.
The gravitational potential energy of a cucumber-harth system changes when which factor changes?
A) the cucumber's speed
B) the cucumber's mass
c) the cucumber's temperature
D) the length
define nuclear energy
Answer:
Nuclear energy is the energy stored in atoms that can produce electricity.
Hope that helps. x
What is number 10 for this?
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
please help me with this
Answer:
>400N is needed to balance that lever
Which type of border shows the division between Sonora and Chihuahua?
National border
State border
Physical boundary
Natural boundary
A car travels 80 km at an avarage speed of 40 km/h. It travels the remaining distance in 3h. What is its dis placement if the average speed of the car is 30 km/h.? And explain
A) 100 km
B)120 km
C)150km
D)180km
When traveling with average speed 40 km/h, the car would cover a distance of 80 km in time t such that
40 km/h = (80 km) / t ⇒ t = 2 h
so the total travel time is 2 h + 3 h = 5 h.
Average speed is defined as the total distance traveled divided by the time it took to cover that distance. So if the overall average speed was 30 km/h, then
30 km/h = (80 km + x) / (5 h) ⇒ x = 70 km
where x is the distance traveled in the last 3 h of the trip.
Then the total displacement of the car is 80 km + 70 km = 150 km.
PLEASE HELP!!
5. A 700 kg race car travels
around the track at 65 m/s. The track has a radius of 75 m.
a. What is the centripetal acceleration?
b. What is the centripetal force?
c. Is the net force on the car less than, equal to, or greater than the centripetal force? Why?
Hi there!
a.
The equation for centripetal acceleration is as follows:
[tex]\large\boxed{a_c = \frac{v^2}{r}}}[/tex]
Plug in the given values to solve:
[tex]\large\boxed{a_c = \frac{(65)^2}{75} = 56.33 m/s^2}[/tex]
b.
According to Newton's Second Law:
[tex]\large\boxed{\Sigma F = ma}}[/tex]
The acceleration is v²/r, so the net force is:
[tex]\large\boxed{\Sigma F = m(\frac{v^2}{r})}}[/tex]
Multiply by the given mass:
[tex]\large\boxed{\Sigma F = 700(56.33) = 39433.33 N}}[/tex]
c.
There is NO net force in the vertical direction since the object is NOT accelerating in the vertical direction (normal force and weight cancel).
Thus, the ONLY net force experienced by the object is in the horizontal direction and is EQUAL to the centripetal force.
A truck moves 60 kilometers east from point A to point B. At point B, It turns back west and stops 15 kllometers away from point A. What are the
total distance and total displacement of the truck?
Answer:
a). The truck's distance covered for the trip is
(60) + (60 - 15) = 105 kilometers .
b). Its displacement for the whole trip is the distance
and direction from the start-point to the end-point.
15 kilometers east .
Explanation: