What is true about the atom? Select all that are correct.
Is made up of protons, neutrons and electrons
Make up the matter in the universe
Are found in nonliving matter only
Is found only on Earth
a is about the same size as a cell
Smallest unit of matter that keeps its chemical properties

What Is True About The Atom? Select All That Are Correct.Is Made Up Of Protons, Neutrons And ElectronsMake

Answers

Answer 1

Answer: Is made up of protons, neutrons and electrons

Make up the matter in the universe

Smallest unit of matter that keep its chemical properties


Related Questions

1. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different-colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later.
What should be kept constant throughout this experiment?
O the color of the cloth
O the temperature of the water
the amount of water in each bottle
O the temperature of the outside air

Answers

Answer: the color of the cloth

Explanation:

Which statement is true?
Every magnesium (Mg) atom has atomic number of 12.
Every magnesium (Mg) atom has a mass number of 24.
this is science but i just put physics

Answers

Answer:

Every magnesium (Mg) atom has atomic number of 12.

Explanation:

Magnesium (Mg) is a chemical element of great importance for plants, animals, and humans.

Alkaline earth metal, magnesium is obtained by electrolysis of magnesium chloride solution.

Magnesium burns with a shining flame. Magnesium is a good reducing agent. This property is used to obtain some other metals.

the ocean contains many plants and protists that can make their own food through photosynthesis. Which need do these organisms get by living near the surface that they cannot get in deep water?
shelter
oxygen
sunlight

Answers

Answer:

sunlight

Explanation:

Photosynthesis is made possible by energy from the sun.

A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?

Answers

Answer:

Explanation:

The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.

The answer is Protista.

Hope this helps. :)

---Spring Question---
A 0.84 kg ball is held at rest against a spring (k = 142 N/m) that has been compressed 0.06 m. The ball and spring are on a table and the ball is 2.0 m above the ground. If friction between the ball and the table is negligible, then how far from the edge of the table (in meters) will the ball hit the ground?

Answers

Answer:

The distance from the edge of the table at which the ball will hit the ground is approximately 0.49 meters

Explanation:

The mass of the ball = 0.84 kg

The spring constant k = 142 N/m

The compression of the spring = 0.06

Therefore, by conservation of energy, we have;

The potential energy of the spring = The kinetic energy given to the ball

The potential energy of the spring = 1/2 × k × x² = 1/2 × 142 × 0.06² = 0.2556

The potential energy of the spring = 0.2556 J

The kinetic energy given to the ball = 1/2 × m × v²

Where;

v = The final velocity of the ball

Substituting gives;

1/2 × 0.84 × v² = 0.2556

∴ v = √(0.2556/(1/2 × 0.84)) ≈ 0.78

The final velocity of the ball = v ≈ 0.78 m/s

The height of the ball above the ground, h = 2.0 m

Therefore, we have;

The time, t, it takes the ball to touch the ground from the 2.0 m height, h, is given as follows;

h = 1/2·g·t²

t = √(2·h/g)

Where;

g = The acceleration due to gravity = 9.81 m/s²

∴ By substitution, we have;

t = √(2 × 2/9.81) ≈ 0.63855

t ≈ 0.63855 s

The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground

The horizontal distance covered during before the ball hits the ground = The (horizontal) velocity of the ball × The time it takes the ball to touch the ground

∴ The horizontal distance covered during before the ball hits the ground = 0.78 × 0.62855 ≈ 0.490269 ≈ 0.49

The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground  ≈ 0.49 m

Four measurements of the file card's width are made. Of the measurements given below, the LEAST precise.
O 7.62
O 7.63
O 7.34
O 7.6

Answers

7.6 is the least precise

According to Kepler's second law of planetary motion,
O a. planets maintain constant speed around the Sun.
Ob. the area swept out by the orbit per time unit keeps changing.
O c. the speed of a planet is greatest when it is closest to the Sun.
O d. planets maintain constant acceleration around the Sun.

Answers

Answer:

c. the speed of a planet is greatest when it is closest to the Sun.

Explanation:

Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).

The three (3) laws published by Kepler include;

I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.

II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.

Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.

III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.

Answer:

A planet moves faster when it is closer to the Sun.

Explanation:

Kepler law!

A plastic ball is tied to 1 end of a long string and is swung in a horizontal circle. If it takes to complete 1 circle, what is the acceleration of the ball

Answers

Explanation:

Assuming the ball is swung with a constant velocity V and radius of circle R. Therefore, The tangential acceleration of the ball would be zero.

Considering the centripetal acceleration to be a_c . we get,

[tex]a_c= \frac{V^2}{R}[/tex]

If u drop a bar of soap on the floor then is the floor clean or is the bar of soap dirty? Lol I’m so bored i dont even know what I’m doing.

Answers

Answer:

CLEAN

Explanation:

Answer:

I just wash mine with water when I drop it . That is a good question tho :)

Explanation:

While delivering 125 kg blocks of ice to a local village, Kristoff and his family (and Sven too) come upon a cliff that is 5.7 m above them. To solve their problem, they build a catapult that will launch their blocks of ice with an initial velocity of 15 m/s and at an angle of 45 degrees above the ground.


Prove that the catapult will successfully launch the ice blocks up to the top of the cliff. Quantities you will need to solve for will be initial vertical velocity, horizontal velocity, the distance the catapult is from the cliff, and the amount of time it takes the ice to reach the cliff. Assume that they are experts and have arranged everything so that the ice blocks just barely reach the top of their parabolic path when they land at the top of the cliff and make a smooth landing. Draw a picture of the scene to help you visualize what is happening.


After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.

What is the rate of acceleration while the blocks slow to a stop?


How long do the blocks take to slow to a stop?


What is the amount of friction between the ice and the snowy ground?



How long do the blocks take to slow to a stop?


What is the amount of friction between the ice and the snowy ground?

Answers

Answer:

a. Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

b. -2.81 m/s²

c. 3.78 s

d. -351.25 N

Explanation:

a. After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.

For the block of ice to reach the top of the cliff, its maximum height, h should be greater than or equal to 5.7 m. That is, h ≥ 5.7 m.

The maximum height of a projection h, projected with an initial velocity v at an angle Ф is h = v²sin²Ф/2g where g = acceleration due to gravity = 9.8 m/s².

For the block of ice, v = 15 m/s and Ф = 45°. So,

h = v²sin²Ф/2g

= (15 m/s)²sin²45/(2 × 9.8 m/s²)

= 225 (m/s)²(1/√2)²/19.6 m/s²

= 225 (m/s)²(1/2)/19.6 m/s²

= 112.5 (m/s)²/19.6 m/s²

= 5.74 m

Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.

The graph is in the attachment.

b. What is the rate of acceleration while the blocks slow to a stop?

Using v² = u² + 2as where u = initial horizontal velocity of block = 15m/scos45° = 10.61 m/s, v = final velocity of block = 0 m/s since it stops, a = acceleration and s = distance block moves = 20 m

So, a =  (v² - u²)/2s

substituting the variables into the equation, we have

a =  ((0 m/s)² - (10.61 m/s)²)/2(20 m)

= - 112.57 (m/s)²)/40 m

= -2.81 m/s²

c. How long do the blocks take to slow to a stop?

Using v = u + at where u = initial horizontal velocity of block = 10.61 m/s v = final velocity of block = 0 m/s since it stops, a = acceleration = -2.81 m/s² and t = time it takes block of ice to stop

So, making t subject of the formula,

t = (v - u)/a

substituting the values of the variables, we have

t = ( 0 m/s - 10.61 m/s)/-2.81 m/s²

= -10.61 m/s/-2.81 m/s²

= 3.78 s

d.  What is the amount of friction between the ice and the snowy ground?

The frictional force, f = net force on block of ice

f = ma where  m = mass of bock = 125 kg and a = acceleration of block = -2.81 m/s²

f = ma

= 125 kg(2.81 m/s²)

= -351.25 N

The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m and it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.

Answers

Solution:

The magnitude of A vector is 84.9 m in the positive y-axis direction.

So the X component of A =0

     the Y component of A = 84.9 m

Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.

So  the X component of B = B cos 41°

                                           = 195 x cos 41°

                                           = 195 x 0.75   = 146.25 m

   the Y component of B = B sin 41°

                                           = 195 x sin 41°

                                           = 195 x 0.65   = 126.75 m

Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.

So the X component of C =126.2 m

     the Y component of C = 0

Comparing all these, we get

1. B vector has the largest X component

2. B vector has the largest Y component

Alex wants to learn how to surf, but he is not a strong swimmer. He knows he needs to increase his ability to paddle out in order to catch the best waves. Which piece of advice would you give to help him get started on reaching his goal? He should swim at least three times a week at the community pool to build stamina. He should tread water every day to get more comfortable in the water. He should purchase the best surfboard he can afford because it will help him paddle faster. He should watch your friend who is a competitive surfer practice to learn her technique.

Answers

Answer:

He should swim at least three times a week at the community pool to build stamina.

Explanation:

PLS HEP WILL GIVE BRAINLIEST TO FIRST ANSWER SCIENCEE!!

Answers

Answer:

Claim: The heart pumps more blood throughout the body when one exercises because exercise takes a lot of energy from the body.

Evidence: Heart rate went from 80 bpm to 120 bpm

Reasoning: Doing exercise takes a lot of energy to do, causing the circulatory system to have to work harder and pump more blood throughout the body in order to allow someone to be able to do a task that involves so much movement and energy.

Explanation:

Your family is going to drive to your grandma's house for Christmas dinner. You set the car's odometer to 0 before you leave. When you arrive, the odometer reads 42.6 miles. Looking at a map, you see the direct, straight-line distance is 30 miles due east. When you return home, what will be your distance and displacement for the round trip, in that order?

Answers

Answer:

Distance = 85.3 miles

displacement = 0

Explanation:

The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;

Total distance for the round trip = 42.6 + 42.6 = 85.2 miles

Since the trip was a round trip, the displacement is zero because the family returned to their initial location.

What is thermodynamics?
a) the way energy changes
b) the classification of energy
c) the movement of energy
d) the movement of heat

Answers

Answer:

I think it is D

Explanation:

Answer:

D :D lol

Explanation:

a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.​

Answers

Answer:

What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true


1) If a projectile launched at a speed of 20m/s above the horizontal axis of an angle 53 ;(usin g=10mls sin 53=0.8 cos 53=0.6)
find
a the displacement at 2sec
b) the velocity of 2sec
c) total time
d) maximum time
e) Range
f) maximum height

Answers

Answer:

(a) 26.83 m

(b) 12.65 m/s

(c) 3.2 seconds

(d) 3.2 seconds

(e) 38.4 m

(f) 12.8 m

Explanation:

Given that a projectile launched at a speed of 20m/s above the horizontal axis at an angle of 53 degrees.

The vertical component of the velocity in the upward direction,

u= 20 sin 53= 20 x 0.8 = 16 m/s.

The horizontal component of the initial velocity,

s=20 cos53 = 20x0.6=12 m/s.

As the gravitational force acts in the vertical direction, so it will only change the vertical component of the initial velocity while the horizontal component of the initial velocity remains unchanged.

(a) The displacement at 2 seconds:

The horizontal distance covered in 2 seconds = 12x2= 24 m

By using the equation of motion, s= ut +1/2 at²

Here, a= -10 m/s² (as g=10m/s² acts in the downward direction)

the vertical displacement s= 16x2- 1/2 x 10 x 2²=12 m

Hence, the displacement after 2 seconds = [tex]\sqrt{24^2+12^2}[/tex]=26.83 m

(b) The velocity at 2 seconds:

As the horizontal component of the velocity is not changing, so the horizontal component of the velocity = 12 m/s

By using the equation of motion, v=u+at

The vertical component of the velocity, v= 16 - 10x2=-4m/s

The negative sign shows that the vertical component of the velocity is in the downward direction.

So, the the velocity at 2 seconds = 12 i - 4 j m/s

The magnitude of the velocity = [tex]\sqrt{12^2+(-40^2}[/tex]=12.65 m/s

(c) Total time of flight:

Total time of flight = 2 x (time to reach the maximum height)

At maximum height, the vertical component of the velocity = 0

So, by using the equation of motion, v=u+at

0= 16-10 t

t= 16/10=1.6 seconds

Hence, the total time of flight= 2 x 1.6 = 3.2 seconds.

(d) Maximum time:

This is the same as the total time of flight, so the maximum time = 3.2 seconds.

(e) Range:

Range = Horizontal component of the velocity x total time of flight

= 12 x 3.2 = 38.4 m

(f) Maximum height:

As the time to reach the highest point = 1.6 seconds

So, by using the equation of motion s = ut + 1/2 at²

The maximum height, s = 16 x 1.6 + 1/2 (-10)1.6² =12.8 m

Hence, the maximum height is 12.8 m.

Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates for twice as long as Jim. Describe the final speed of Joe compared to Jim.

Answers

Answer:

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

Explanation:

First, we analyze the final speed of Jim by using first equation of motion:

Vf₁ = Vi + at

where,

Vf₁ = final speed of Jim

Vi = initial speed of Jim = 0 m/s

a = acceleration of Jim

t = time of acceleration for Jim

Therefore,

Vf₁ = at   ---------------- equation (1)

Now, we see the final speed of Joe. For Joe the parameters will become:

Vf = Vf₂

Vi = 0 m/s

a = a

t = 2t

Therefore,

Vf₂ = 2at  

using equation (1):

Vf₂ = 2 Vf₁

It shows that final speed of Joe is twice the final speed of Jim.

what is not a raquet sport

Answers

Answer:

what

Explanation:

Racket sports include tennis, badminton, squash or any other sport where you use rackets to hit a ball or shuttlecock to play. They can be played competitively or just for fun and are a great form of physical activity.

Waves are often caused by
a
vibrating objects.
b
colliding objects.
c
potential energy.
d
mechanical energy.

Answers

Answer:

vibrating objects.

I think

Waves are often caused by vibrating objects. Based on the type of vibrational motion, there are different types of waves. Hence, option a is correct.

What are waves ?

Waves are disturbances in air or the passage of energy through vacuum or through a medium. Waves are caused by vibration of objects. Three are two types of waves broadly, mechanical waves and electromagnetic waves.

Electromagnetic waves are those associated with combined electric and magnetic field. They can pass through both vacuum and mediums. Mechanical waves need a medium to pass and does not transfer through vacuum.

Based on the vibrational motion, there are two types of waves longitudinal waves and transverse waves. In transverse waves, the vibrational motion of particles is perpendicular to the wave propagation.

In the case of transverse waves, the particle vibration is along the wave propagation. Hence, option A is correct.

Find more on waves:

https://brainly.com/question/3639648

#SPJ2

A 10 kg object experiences an acceleration of 2 m/s squared. What net force was applied to the object?

Answers

F = ma

= 10kg × 2m/s

= 20N

Answer : 20N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s)

A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy

Answers

Answer:

42.69J

Explanation:

The question is not complete, here the complete one

A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy

and it velocity vx= -3.4m/s

Step one:

given

mass m= 2.3kg

spring constant k= 120 N/m

x= 0.7m

vx=-3.4m/s

Step two:

The expression for the total energy is

[tex]Energy= 1/2mv^2 + 1/2Kx^2[/tex]

substituting we have

[tex]Energy= 1/2*2.3*3.4^2+1/2*120*0.7^2[/tex]

[tex]Energy= 13.29+29.4\\\\Energy=42.69J[/tex]

As you travel downhill, your vehicle needs less power to reach the bottom and your stopping _________ increases.

Answers

Answer: Distance

Explanation:

When driving, it is important for one to always use safety belt and obey traffic rules.

During a collision, it is vital to always adhere to safety belts and also use occupant protection systems in order to help reduce the impact that an be felt during a collision. As you travel downhill, your vehicle needs less power to reach the bottom and your stopping distance increase.

Determine the energy lost, due to friction, as an 8000 N car that skids to a stop, if its initial velocity was 12 m/s.

Answers

Answer:

58,800Joules

Explanation:

The energy lost is equal to the workdone by the car as it skids.

Workdone = Force * Distance

Given

Force = 8000N

Get the distance using the equation of motion

v² = u² - 2gS

0² = 12² - 2(9.8)S

-12² =  - 2(9.8)S

-144 = -19.6S

S = 144/19.6

S = 7.35m

Calculate the required energy

Workdone = 8000 * 7.35

Workdone = 58,800Joules

Hence the energy lost due to friction is 58,800Joules

Which best defines gravity?

A. The tendency of objects to fall from trees

B. An attractive force between two objects due to their mass

C. The amount of matter in an object

D. The rate at which objects fall to earth

Answers

Answer:

B. An attractive force between two objects due to their mass

Explanation:

Answer:

B

Explanation:

Gravity is a force that pulls 2 objects towards each other and varies depending on mass. The earth for example is large enough to have a gravitational force that keeps us down. The sun has a gravitational force that keeps the Earth in orbit.

9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water

Answers

Answer: 4

Explanation:

The dependent variable is the temperature of the water.

Question
3.2
Calculate the value of critical angle for light passing from glass to air (given that refractive index of
glass - 1.5)​

Answers

Answer:

42°

Explanation:

From the question given above, the following data were obtained:

Refractive index (n) = 1.5

Critical angle (C) =?

The refractive index and the critical angle are related according to the following reaction:

n = 1 / Sine C

Thus, with the above formula, we can obtain the critical angle as follow:

Refractive index (n) = 1.5

Critical angle (C) =?

n = 1 / Sine C

1.5 = 1 / Sine C

Cross multiply

1.5 × Sine C = 1

Divide both side by 1.5

Sine C = 1 / 1.5

Sine C = 0.6667

Take the inverse of sine

C = Sine¯¹ (0.6667)

C = 41.8 ≈ 42°

Thus, the critical angle is approximately

42°.

Why must the rockets use great force to get into outer space?

Answers

Because of the gravity that is weighing down the rocket

URGENT! 40 POINTS! For each situation below, find the work done on the box using both energy and forces.

1. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.

2. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.

3. A 2 kg box is dropped from an initial height of 10 m.


I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.

Answers

Answer:

i’m not sure one second let me try to figure it out

Explanation:

Work is a _______ acting upon an object for a given ______. The amount of work done is equal to the change in ________ of the object.

Answers

Answer:

Work is a FORCE acting upon an object for a give DISTANCE. The amount of work done is equal to the change in KINETIC ENERGY of the object.

Explanation:

The answer is from the definition and equations for work:

Work = force*distance = change in kinetic energy

Answer:

energy

Explanation:

i took the quiz

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