What type of number -75 A)rational number B)irrational C) integer D) whole number E)natural number. Reply quickly

Answer:

common fraction is written in the form of two whole numbers, one above the ... For example 3/7 would be 3 divided by 7 = 0.428 571 .

Answer:

(2d +3d) + 3-12 equals to 5d - 9

Step-by-step explanation:

you try collecting like terms

Answer:

[tex]5d-9[/tex]

Step-by-step explanation:

Given the following question:

[tex](2d + 3) + (3d-12)[/tex]

To find the answer remove the parentheses, group like terms, and solve by using inverse of operations.

[tex](2d + 3) + (3d-12)[/tex]
[tex]2d+3+3d-12[/tex]
[tex]2d+3d+3-12[/tex]
[tex]3-12=-9[/tex]
[tex]2d+3d+-9[/tex]
[tex]2d+3d=5d[/tex]
[tex]5d-9[/tex]

Your answer is "5d - 9."

Hope this helps.

Answer:

2 may be the greatest one.

Answer:

12

Step-by-step explanation:

12

Answer:

-5/2

Step-by-step explanation:

Slope intercept form = y=mx+b

M=Slope

B=y-intercept

Answer:

-5/2 is the slope

Step-by-step explanation:

the form that it is currently in is slope intercept form

( y= mx+b ) m is the is the slope and x is a variable. -5 is the y intercept.

Answer:

Step-by-step explanation:

Given sequence

This is a GP with

Formula for nth term is:

Answer:

[D] $63.55

Step-by-step explanation:

GIven;

To FInd:

What was her after-tax total?

Note:

After-tax total = Include tax

Solve;

$59.95 × 6%=3.597

Round ⇒ 3.60

$59.95 + 3.60 = 63.55

Hence, Joan after-tax total is [D} $63.55

~Learn with Lenvy~

Cylinder volume = base area x height

                            = pi x r² x h

d = 7 yd => r = 7:2 = 3,5 yd

and h = 4 yd

to be calculed

V = 3,14 x 3,5² x 4

Answer:

xy - 3

Step-by-step explanation:

Product of x and y = xy

Required number = xy - 3

Answer:cycle-3

Step-by-step explanation:

Answer:

the 13th term, if you plug in 13 for n and solve you would get 20 :)

Answer:

13th term

Step-by-step explanation:

Answer:

4.24 hours

Step-by-step explanation:

Irina can paint 1/9 of a room in 1 hour since she can paint a room in 9 hours. 1/9x, where x is the number of hours she works and 1/9 of a room per hour is her speed, would be her part of the calculation.

Paulo can paint 1/8 of a room in 1 hour since he can paint an entire room in 8 hours. 1/8x, where x is the number of hours he works and 1/8 of a room per hour is his speed, would be his part of the equation.

1/9x + 1/8x = 1 (Irina's portion of the room plus Paulo's portion of the room equals one complete room) would be the equation.

Look for a denominator that has the same value as the numerator. Both 9 and 8 split evenly into 72 as the initial number. We multiply the top of 1/9 by 8 to convert the fraction and get 8/72x because 9*8 = 72. We multiply the top of 1/8 by 9 to convert the fraction and get 9/72x because 8*9 = 72. We have 8/72x+9/72x=1 currently.

17/72x=1

÷ both sides by 17/72:

17/72x ÷ 17/72 = 1÷17/72

∴ x=1/1 * 72/17

∴ x=72/17= 4.24

Answer:

well if a is 12 it means that would become 144/12. simplified to a whole number is 12. so 12-2.4 would = 9.6

Step-by-step explanation:

Answer:

9.6

[tex]12^{2}[/tex]/12 cancels out

12-2.4=9.6

Answer: The two numbers are 39 and 41

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Work Shown:

x = some odd number

x+2 = next odd number

eg: x = 3 and x+2 = 3+2 = 5

Add up those two expressions, set the sum equal to 80, and solve for x

(x) + (x+2) = 80

2x+2 = 80

2(x+1) = 80

x+1 = 80/2

x+1 = 40

x = 40-1

x = 39

----------

Another way to solve is to do this

2x+2 = 80

2x = 80-2

2x = 78

x = 78/2

x = 39

-----------

Either way, the solution is x = 39 which means the next odd number up is x+2 = 39+2 = 41

To check the answer, add up the two values

39+41 = 80

This confirms we have the right answer.

Solution (1):

[tex]0 > -2 + \dfrac{b}{7}[/tex]

[tex]0 + 2 > \dfrac{b}{7}[/tex]

[tex]2 > \dfrac{b}{7}[/tex]

[tex]2 \times 7 > b[/tex]

[tex]\boxed{\bold{14 > b}}[/tex]

Solution (2):

[tex]\dfrac{v}{14} - 2 < -3[/tex]

[tex]\dfrac{v}{14} < -3 + 2[/tex]

[tex]\dfrac{v}{14} < -1[/tex]

[tex]v < -1 \times 14[/tex]

[tex]\boxed{\bold{v < -14}}[/tex]

Solution (3):

[tex]13 < \dfrac{n}{4}+ 9[/tex]

[tex]13 - 9 < \dfrac{n}{4}[/tex]

[tex]4 < \dfrac{n}{4}[/tex]

[tex]4 \times 4 < n[/tex]

[tex]\boxed{\bold{16 < n}}[/tex]

Solution (4):

[tex]138 > -6+9n[/tex]

[tex]138 + 6 > 9n[/tex]

[tex]144 > 9n[/tex]

[tex]\dfrac{144 }{9} > \dfrac{9n}{9}[/tex]

[tex]\boxed{\bold{16 > n}}[/tex]

Solution (5):

[tex]-9 + \dfrac{x}{2} > -14[/tex]

[tex]\dfrac{x}{2} > -14 + 9[/tex]

[tex]\dfrac{x}{2} > -5[/tex]

[tex]x > -5 \times 2[/tex]

[tex]\boxed{\bold{x > -10}}[/tex]

Solution (6):

[tex]-6 > -9 + \dfrac{k}{4}[/tex]

[tex]-6 + 9 > \dfrac{k}{4}[/tex]

[tex]3 > \dfrac{k}{4}[/tex]

[tex]3 \times 4 > k[/tex]

[tex]\boxed{\bold{12 > k}}[/tex]

Solution (7):

[tex]-11 > \dfrac{a}{2} -2[/tex]

[tex]-11 + 2 > \dfrac{a}{2}[/tex]

[tex]9 > \dfrac{a}{2}[/tex]

[tex]-9 \times 2 > a[/tex]

[tex]\boxed{\bold{-18 > a}}[/tex]

Mr Green: [tex]4(3a+1+2b) = 12a + 4 + 8b[/tex]

Mrs Green: [tex]6(5a-a)+4(2+4b)=6*4a + 8 + 16b = 24a +16b + 8[/tex]

Keith: [tex]4(2+4b+6a) = 8 + 16b + 24a=24a+16b + 8[/tex]

Kevin: [tex]4(6a+2)+8b + 2 = 24a + 8 + 8b + 2 = 24a + 8b + 10[/tex]

Thus Mrs Green and Keith has the expression that is equivalent to

'24a + 16b + 8'

Hope that helps!

Answer:

64π Inches squared

Step-by-step explanation:

A=πr^2

Half of 16 is 8

r=8

A=π8^2

A=64π

As all of the bundles have the same content inside, so assuming that there is x number of Fiction books and y number of Non-fiction books in each bundle.

Let n be the total number of bundles that my team can send.

There are 64 Fiction books, so

nx=64 ...(i)

Or x=64/n ...(ii)

also, there are 48 Non-Fiction books, so

ny=48 ...(iii)

Or y=48/n ...(iv)

Observing that the numbers x, y, and n are counting numbers and from equations (i) and (iii), n is the common factor of 64 and 48.

The possible common factors of 64 and 48 are,

n=1,2,4,8, and 16.

So, my team can send 1,2,3,4,8 or 16 bundles of books.

Now, from equations (ii) and (iv),

For n=1:

x=64/1=64

y=48/1=48

So, for 1 bundle the number of Fiction and Non-fictions books are 64 and 48 respectively.

For n=2:

x=64/2=32

y=48/2=48

So, for 2 bundles, the number of Fiction and Non-fictions books are 32 and 24 respectively.

For n=4:

x=64/4=16

y=48/4=12

So, for 4 bundles, the number of Fiction and Non-fictions books are 16 and 12 respectively.

For n=8:

x=64/8=8

y=48/8=6

So, for 8 bundles, the number of Fiction and Non-fictions books are 8 and 6 respectively.

For n=16:

x=64/16=4

y=48/16=3

So, for 16 bundles, the number of Fiction and Non-fictions books are 4 and 3 respectively.

Answer: 1/4

Step-by-step explanation:

Hope this helps

The 0.25 is equivalent to 1/4, where the numerator is 1 and the denominator is 4.

The fraction that is equal to 0.25 is 1/4. To understand this, examine the decimal representation of 0.25. The decimal point separates the whole number part from the fractional part. In 0.25, the digit 2 is in the tenths place, and the digit 5 is in the hundredths place. As a fraction, the number 2 in the tenths place can be written as 2/10, and the number 5 in the hundredths place written as 5/100. Simplifying these fractions, find that 2/10 reduces to 1/5 and 5/100 reduces to 1/20.

To know more about equivalent here

https://brainly.com/question/25197597

#SPJ6

Answer:

s=33

r=57

Step-by-step explanation:

12x-3+7x-2+90

19x-5=90

19x=95

x=5

12(5)-3=57

7(5)-2=33

Answer:

x=8.2

Step-by-step explanation:

First, figure out which trig function you are going to use.

In this problem you are dealing with the opposite side to the angle and the hypotenuse, and if you remember SOH CAH TOA, this requires sine.

sin (55) =opposite/hypotenuse

sin (55) =x/10

multiply both sides by 10 to get 10 * sin (55) = x

10 * sin (55) = 8.2

Answer:

26.17

Step-by-step explanation:

a^2+b^2=c^2

Answer:

A. Line of reflection is a perpendicular bisector

B. 90 degree angles, equal lines

C. Pre-image an image are on the same circle.

Step-by-step explanation:

I hope this helped you in any way possible. :)

Hey there!

Option answer: C

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Answer:

a = 9 + b - c → D

Step-by-step explanation:

To cancel the square root of one side of an equation square the two sides

Examples:

If [tex]\sqrt{x}[/tex] = 5, to find x square the two sides to cancel the square root

([tex]\sqrt{x}[/tex] )² = (5)², then x = 25

If [tex]\sqrt{a+b}[/tex] = 7, to find a + b square the two sides to cancel the square root

([tex]\sqrt{a+b}[/tex] )² = (7)², then a + b = 49

Now let us solve the question

To solve it for a square the two sides then keep a on the left side and move b, c to the other side

∵ [tex]\sqrt{a-b+c}[/tex] = 3

→ Square the two sides to cancel the square root

∴ ([tex]\sqrt{a-b+c}[/tex])² = (3)²

∴ a - b + c = 9

→ Add b to both sides to move b from the left side to the right side

∴ a - b + b + c = 9 + b

∴ a + c = 9 + b

→ Subtract c from both sides to move c from the left side to the right side

∴ a + c - c = 9 + b - c

∴ a = 9 + b - c

Answer:

4080.01

Step-by-step explanation:

V = 6 A2/3/36 square rooted = 6 × 1532 2/3/36 square rooted = 4080.01042

Responder:

$ 288750

Explicación paso a paso:

Dados los ingresos mensuales de los pesos chinos expresados ​​como;

I (x) = 20.000x - 50x² donde;

x es el número de relojes reparados.

Para calcular los ingresos obtenidos si se reparan 15 relojes, simplemente sustituiremos x = 15 en la ecuación modelada como se muestra;

Yo (15) = 20.000 (15) - 50 (15) ²

Yo (15) = 300 000-50 (225)

Yo (15) = 300.000-11250

I (15) = $ 288,750

Answer:

320$

Step-by-step explanation:

Since it's 4%
4000 * 0.04 = 160

24 months = 2 years

annually = 1 year

160 * 2 = 320$

Hope this helps!

Answer:

4000*0.04 = 160

24/12=2

160*2 = 320 interste receveid after 24 mounths

4000+320=4320

Step-by-step explanation:

Answer:

(j-8)years is the answer to the question

Answer:

I wish I've known, but try using Symbo-Lab or Math-Way. They help a lot.

Step-by-step explanation:

Answer:

The first transformation occurs when we add a constant d to the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​ , giving us a vertical shift d units in the same direction as the sign. For example, if we begin by graphing a parent function, \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​ , we can then graph two vertical shifts alongside it, using \displaystyle d=3d=3: the upward shift, \displaystyle g\left(x\right)={2}^{x}+3g(x)=2

​x

​​ +3 and the downward shift, \displaystyle h\left(x\right)={2}^{x}-3h(x)=2

​x

​​ −3. Both vertical shifts are shown in Figure 5.

Graph of three functions, g(x) = 2^x+3 in blue with an asymptote at y=3, f(x) = 2^x in orange with an asymptote at y=0, and h(x)=2^x-3 with an asymptote at y=-3. Note that each functions’ transformations are described in the text.

Figure 5

Observe the results of shifting \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​  vertically:

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞) remains unchanged.

When the function is shifted up 3 units to \displaystyle g\left(x\right)={2}^{x}+3g(x)=2

​x

​​ +3:

The y-intercept shifts up 3 units to \displaystyle \left(0,4\right)(0,4).

The asymptote shifts up 3 units to \displaystyle y=3y=3.

The range becomes \displaystyle \left(3,\infty \right)(3,∞).

When the function is shifted down 3 units to \displaystyle h\left(x\right)={2}^{x}-3h(x)=2

​x

​​ −3:

The y-intercept shifts down 3 units to \displaystyle \left(0,-2\right)(0,−2).

The asymptote also shifts down 3 units to \displaystyle y=-3y=−3.

The range becomes \displaystyle \left(-3,\infty \right)(−3,∞).

Graphing a Horizontal Shift

The next transformation occurs when we add a constant c to the input of the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​ , giving us a horizontal shift c units in the opposite direction of the sign. For example, if we begin by graphing the parent function \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​ , we can then graph two horizontal shifts alongside it, using \displaystyle c=3c=3: the shift left, \displaystyle g\left(x\right)={2}^{x+3}g(x)=2

​x+3

​​ , and the shift right, \displaystyle h\left(x\right)={2}^{x - 3}h(x)=2

​x−3

​​ . Both horizontal shifts are shown in Figure 6.

Graph of three functions, g(x) = 2^(x+3) in blue, f(x) = 2^x in orange, and h(x)=2^(x-3). Each functions’ asymptotes are at y=0Note that each functions’ transformations are described in the text.

Figure 6

Observe the results of shifting \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​  horizontally:

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), remains unchanged.

The asymptote, \displaystyle y=0y=0, remains unchanged.

The y-intercept shifts such that:

When the function is shifted left 3 units to \displaystyle g\left(x\right)={2}^{x+3}g(x)=2

​x+3

​​ , the y-intercept becomes \displaystyle \left(0,8\right)(0,8). This is because \displaystyle {2}^{x+3}=\left(8\right){2}^{x}2

​x+3

​​ =(8)2

​x

​​ , so the initial value of the function is 8.

When the function is shifted right 3 units to \displaystyle h\left(x\right)={2}^{x - 3}h(x)=2

​x−3

​​ , the y-intercept becomes \displaystyle \left(0,\frac{1}{8}\right)(0,

​8

​

​1

​​ ). Again, see that \displaystyle {2}^{x - 3}=\left(\frac{1}{8}\right){2}^{x}2

​x−3

​​ =(

​8

​

​1

​​ )2

​x

​​ , so the initial value of the function is \displaystyle \frac{1}{8}

​8

​

​1

​​ .

A GENERAL NOTE: SHIFTS OF THE PARENT FUNCTION \DISPLAYSTYLE F\LEFT(X\RIGHT)={B}^{X}F(X)=B

​X

​​

For any constants c and d, the function \displaystyle f\left(x\right)={b}^{x+c}+df(x)=b

​x+c

​​ +d shifts the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​

vertically d units, in the same direction of the sign of d.

horizontally c units, in the opposite direction of the sign of c.

The y-intercept becomes \displaystyle \left(0,{b}^{c}+d\right)(0,b

​c

​​ +d).

The horizontal asymptote becomes y = d.

The range becomes \displaystyle \left(d,\infty \right)(d,∞).

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), remains unchanged.

HOW TO: GIVEN AN EXPONENTIAL FUNCTION WITH THE FORM \DISPLAYSTYLE F\LEFT(X\RIGHT)={B}^{X+C}+DF(X)=B

​X+C

​​ +D, GRAPH THE TRANSLATION.

Draw the horizontal asymptote y = d.

Identify the shift as \displaystyle \left(-c,d\right)(−c,d). Shift the graph of \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​  left c units if c is positive, and right \displaystyle cc units if c is negative.

Shift the graph of \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​  up d units if d is positive, and down d units if d is negative.

State the domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), the range, \displaystyle \left(d,\infty \right)(d,∞), and the horizontal asymptote \displaystyle y=dy=d.

Step-by-step explanation: