Given that –
pH = 12.5We know that –
pH + pOH = 14Then –
[tex]\qquad[/tex][tex]\bf\longrightarrow pOH = 14 -12.5 [/tex]
[tex]\qquad[/tex][tex]\sf \longrightarrow pOH = 1.5[/tex]
[tex]\qquad[/tex][tex]\sf \longrightarrow [OH^- ] = 10^{-1.5 }[/tex]
[tex]\qquad[/tex][tex]\bf \longrightarrow [OH^-] = 3.16 × 10^{-2}[/tex]
Now the number of moles of KOH need to ensure that concentration of Hydroxide anions is equal to –
[tex]\qquad[/tex][tex]\bf \longrightarrow 3.74\: L \times \dfrac{3.16× 10^{-2}}{1 \: L }[/tex]
[tex]\qquad[/tex][tex]\bf \longrightarrow 1. 18 × 10^{-1 }M [/tex]
Volume of the solution contains the need number of moles of Hydroxide anions –
[tex]\qquad[/tex][tex]\sf \longrightarrow \dfrac{ 1.18×10^{-1} \: moles \: OH^-}{0.826 \: moles \: OH^-}[/tex]
[tex]\qquad[/tex][tex]\sf \longrightarrow 0.143 L [/tex]
[tex]\qquad[/tex][tex]\sf \longrightarrow 0.143 \times 1000[/tex]
[tex]\qquad[/tex][tex]\pink{\bf\longrightarrow 143 mL }[/tex]
______________________________________
The ion of aluminum is
Al+
Al2-
Al2+
Al3+
Al3-
Answer:
A13+
Explanation:
I took a test that had this question.
please help
write the correct IUPAC name for these componds
Answer:
A. 4,6-dimethyloct-1,4,6-yne
B. deconic acid
C. 3-ethyl-4-methyl-7-bromocyclohexene
D. 2,2,3-trimethyl-4-butyl-heptane
E. 3-methylhexane
F. ethyl hexanoate
G. butanal
H. propyne
J. 2,4-dimethyl-pent-2-ene
Explanation:
sorry i didn't have time to do I
How to find total mass of water in final solution
Answer:
Explanation:
Just like a solid, the density of a liquid equals the mass of the liquid divided by its volume; D = m/v. The density of water is 1 gram per cubic centimeter.
Van der Waals bonds initiate
a) Between non-metals
b) Within ionic binds
c) Between metals
d) With H-bond
e) All of the above
I think e no
I am giving you hint
Need ASAP will give brainlist
Answer:
A.
The answer is A :)
What does Bromine-80 decays by beta decay to?
Answer:
beta to Kr-80 or Se-80
Explanation:
sorry if wrong
A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.
a
24.0 L
b
12.0 L
c
6.0 L
d
3.0 L
Will the following replacement reaction occur? MgCl2 + I2 → ?
Yes, it will because chlorine is less reactive than iodine.
No, it will not because iodine is less reactive than chlorine.
No, it will not because iodine and chlorine will not bond.
Yes, it will because the iodine will replace the magnesium.
The replacement reaction will not occur because iodine is less reactive than chlorine.
REPLACEMENT REACTION:A replacement reaction is a type of reaction in which one element is replaced by another in a compound.
The principle behind one element replacing the other is based on the reactivity of an element. A more reactive element will displace a less reactive one.
According to this question, the following displacement reaction is given: MgCl2 + I2 → ?
This reaction will not occur because chlorine is more reactive/electronegative than iodine, hence, iodine cannot displace it.
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Pls help plz answer this question
Answer:
A) Carbon dioxide and Oxygen
Explanation:
Percentage of gases in the Planet's atmosphere:
Carbon dioxide = 4 % Nitrogen = 72 % Oxygen = 24 %Percentage of gases in the Earth's atmosphere:
Carbon dioxide = 0.036 % (traces)Nitrogen = 78 % Oxygen = 21 %___________________
On observing the percentage composition of the atmospheres of the two Planets, we get:
The newly discovered planet has more percentage of Oxygen than The Earth. Percentage of Carbon dioxide is more in the planet than in the EarthNitrogen is less in the planet than in the Earth.___________________
Answer:
What's asked is the name of the gases that are in higher amounts in the atmosphere of the newly discover planet
Therefore,
A) Carbon dioxide and Oxygen-- --- .-. ... . / -.-. --- -.. . / .. ... -. .----. - / - .... .- - / ..-. ..- -. / .- -. -.. / .. .----. -- / ..- ... .. -. --. / .- / - .-. .- -. ... .-.. .- - --- .-. / - --- --- / ... --- what did I say in Morse code?
Answer:
MORSE CODE ISN'T THAT FUN AND I'M USING A TRANSLATOR TOO SO
Explanation:
That is what is says in morse code.
Answer:
MORSE CODE ISN'T THAT FUN AND I'M USING A TRANSLATOR TOO SO
Explanation:
A 33.4−L volume of methane gas is heated from 22°C to 66°C at constant pressure. What is the final volume of the gas?
Answer:
38.38 L (3 d.p.)
Explanation:
In response to questions addressing the expansion of gas via heating, Charles's Law should be considered. Charles's Law is an experimental gas law explaining the tendency of gases to expand when heated.
The law states that the volume ([tex]V[/tex]) of a gas is directly proportional to its temperature ([tex]T[/tex]) given that the pressure ([tex]P[/tex]) and the amount of gas ([tex]N_{A}[/tex]) are constant.
[tex]\displaystyle\frac{V}{T} \ = \ k \ \ \ \ \ \ \ or \ \ \ \ \ \ \ V \ = \ kT[/tex], where k is a proportionality constant.
*Note that when substituting temperature into the equation, the temperature must be in terms of the Kelvin scale and not in degrees Celsius. The relation between the Kelvin scale and the Celsius scale is [tex]\mathrm{K} \ = \ ^{\circ}\mathrm{C} \ + \ 273[/tex].
Charles's law can be used to compare changing conditions of a particular gas. Let [tex]V_{1}[/tex] and [tex]T_{1}[/tex] be the initial volume and temperature for the gas, while [tex]V_{2}[/tex] and [tex]T_{2}[/tex] be the final volume and temperature. The mathematical relationship of Charles's law becomes:
[tex]\displaystyle\frac{V_{1}}{T_{1}} \ = \ \displaystyle\frac{V_{2}}{T_{2}}[/tex].
In accordance with the question,
[tex]V_{1} \ = \ 33.4 \ \mathrm{L}, \ T_{1} \ = \ (22 \ + \ 273) \ \mathrm{K} \ = \ 295 \mathrm{K}, \ T_{2} \ = \ (66 \ + \ 273) \ \mathrm{K} \ = \ 339 \ \mathrm{K}[/tex]
while [tex]V_{2}[/tex] is the final volume of the gas that we would like to find. Therefore,
[tex]V_{2} \ = \ \displaystyle\frac{V_{1} \ \times \ T_{2}}{T_{1}} \\ \\ V_{2} \ = \ \displaystyle\frac{33.4 \ \mathrm{L} \ \times \ 339 \ \mathrm{K}}{295 \ \mathrm{K}} \\ \\ V_{2} \ = \ 38.38 \ \mathrm{L}[/tex].
Pls answer this question
Answer:
A carbon dioxide and oxygen
Need help ASAP!!!!!!
Answer:
option D 17proton ,17electron and 18 neutrons
Check all of the following below which describe experimental errors that would affect the percent chloride you report in your experimental results: ____________
a) The solid product was wet when you weighed the final mass
b) You added excess silver nitrate into the reaction mixture
c) The liquid collected from the filtration was cloudy
d) The transfer from the reaction beaker to the filter funnel was imperfect (you lost some of the reaction solution or some was left in the beaker)
e) Extra water was used to dissolve the original unknown solid
The options that describe the experimental errors that would affect the percent of chloride reported are:
B (You added excess silver nitrate into the reaction mixture) and D (The transfer from the reaction beaker to the filter funnel was imperfect).While performing experiments, there are some errors that occur which are generally known as experimental errors.
These experimental errors are the difference between the true measurement and what we measured.
There are three types of experimental errors they include:
systematic, random, and human error.Human errors occur due to carelessness of the observer.
Examples are:
when you added excess silver nitrate into the reaction mixture when the transfer from the reaction beaker to the filter funnel was imperfect due to lost of some of the reaction solution.Therefore, the options describe the experimental errors that would affect the percent of chloride reported are B and D.
Learn more about experimental errors here:
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Help i dont get it
Answer:
2. Products; FeCl2 and H2S
Reactants; FeS and HCl
3. a) 36g of water
b) 64g of oxygen
How do you out pizza the hut?
For a reversible reaction, what would a large equilibrium constant indicate? Question 9 options: A) At equilibrium, the concentration of the reactants will be much higher than the concentration of the products. B) At equilibrium, the concentration of the products will be about the same as the concentration of the reactants. C) At equilibrium, the concentration of the products will be much higher than the concentration of the reactants. D) At equilibrium, there will be no reactants left because they will all have been turned into products.
Please give help and label them giving brainiest
Answer:
huh
Explanation:
Why would other scientist want to see observations from your three trials
Answer:
When we do multiple trials of the same experiment, we can make sure that our results are consistent and not altered by random events and are reliable. Multiple trials can be done at one time. E.g. If we were testing a new fertilizer, we could test it on lots of individual plants at the same time.
Hope that helped.x
Heart, 5 stars, and Brainiest to first right answer!
Which of these is a likely impact of stronger than normal trade winds in the Pacific Northwest of the United States?
A. Jet stream would be displaced northwards causing drought
B. Jet stream would be displaced southwards causing drought
C. Jet stream would be displaced southwards causing heavy rain and flooding
D. Jet stream would be displaced northwards causing heavy rain and flooding
I think correct answer is C.Jet stream would be displaced southwards causing heavy rain and flooding
The statement that is a likely impact of stronger than normal trade winds in the Pacific Northwest to the United States is Jet stream would be displaced southwards causing heavy rain and flooding.
the weak base ionization constant (ka) for h2c2o4 is equal to what?
The acid ionization constant is the quantitative measure of the acidic strength. For oxalic acid, Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]
What is acid dissociation?Acid dissociation (Ka) is the ratio of the concentration of the conjugate base and hydrogen ion to the concentration of the chemical.
Oxalic acid is a weak acid and gets dissociated as:
H₂C₂O₄ ⇌ H⁺ + HC₂O₄⁻
or
HC₂O₄⁻ ⇌ H⁺ + C₂O₄²⁻
The acid ionization constant for the reactant and the product is given as:
Ka = [H⁺] [A⁻] / [HA]
Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]
Therefore, the ionization constant for oxalic acid is given as Ka = [H⁺] [HC₂O₄⁻] / [H₂C₂O₄]
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Y’all what’s this I don’t feel like doing it and I’ll give brainlist too
1. How does the figure below illustrate Hund's rule?
Answer:
it indicates that the lower orbitals are filled first and they have the maximum number of electrons compared to the higher orbitals
How many moles of chlorine could be produced by decomposing 157g NaCl? 2NaCl --> 2Na+Cl2
By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.
To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.
The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.
Now, we can calculate the number of moles of NaCl:
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
Moles of NaCl = 157 g / 58.44 g/mol
Moles of NaCl ≈ 2.69 mol
According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.
Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:
Moles of Cl₂ = (Moles of NaCl / 2) × 1
Moles of Cl₂ = 2.69 mol / 2
Moles of Cl₂ ≈ 1.35 mol
Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.
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I have a hard time telling the difference between convection, conduction, and radiation, anybody got any tips?
soaps do not work well in hard waters. But they can still be effected it large quantities of soap are added to water. Explain why.
Calculate the weight of a 1 kg object on Earth which has a gravitational acceleration of 9.8 m/s2?
A. 0.1 kg
B. 9.8 kg
C. 10.8 N
D. 9.8 N
[tex] = 1kg \: \: \times 9.8 {ms}^{ - 2} \\ = 9.8 \: \: N[/tex]
Answer:B. 9.8 N
Hope you could get an idea from here.
Doubt clarification - use comment section.
find the molar mass of 8.54 x 10²⁴ g A₂O₃
Very Very sorry
graph
1. You represented the allele for green peas with green clay and the allele for yellow peas with yellow clay. Are the alleles really these colors?
Answer:
pure-bred green with pure-bred yellow peas. Since yellow is dominant to green, all of the offspring were yellow. The green phenotype had disappeared. ... When a pure-bred green plant is crossed with a pure-bred yellow plant, the offspring inherit one allele of the color gene from each parent.
Explanation:
Ppbag at it again
Answer to question in picture
Answer:
methyl 2-methyl-ethane
Explanation: