What wor? Edono by Jork time 0f 2.0 seconds? boy e pulls a sled with J force of 47 N at an angle of 45 degrees with the horizontal. How much work Is done on the sled in moving the sled disuance of 18 m? Refcr to the informution here for 0}-4 AZC0.kg motorcycle travels down the road at 25 m/s Calculate the kinetic energy of the motorcycle

Answers

Answer 1

The work done on the sled is approximately 597.14 J, and the kinetic energy of the motorcycle is approximately 125,000 J.

The work done on the sled in moving it a distance of 18 m by a boy who pulls it with a force of 47 N at an angle of 45 degrees with the horizontal is 596.14 J. The kinetic energy of a 0.4 kg motorcycle traveling down the road at 25 m/s is 156.25 J.
To calculate the work done on the sled, we need to consider the horizontal component of the force and the distance moved. The horizontal component of the force can be calculated using the given force (47 N) and angle (45 degrees):
Horizontal force = 47 N * cos(45°) ≈ 33.23 N
Now, we can calculate the work done using the formula:
Work = Force * Distance * cos(θ)
In this case, the angle between the horizontal force and the distance is 0 degrees, so cos(0) = 1.
Work = 33.23 N * 18 m * 1 ≈ 597.14 J (joules)
For the 400 kg motorcycle traveling at 25 m/s, we can calculate the kinetic energy using the formula:
Kinetic energy = 0.5 * mass * (velocity)^2
Kinetic energy = 0.5 * 400 kg * (25 m/s)^2 ≈ 125,000 J

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Related Questions

You are raising up a big bucket of water from a 22.5 m deep well. The combined mass of the water and the bucket is 11.3 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 17.9 kg. How much work do you perform during the lifting process? Tries 0/12 If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?

Answers

The amount of work done during the lifting process is 4465.125 J and our average power will be 42.525 W.

Given:

Depth of the well, h = 22.5m

Mass of heavy-duty steel chain, M = 17.9 kg

The combined mass of the water and bucket, m = 11.3 kg

time taken to raise the bucket out of the water, T = 1.75 min = 105 s

Calculation:

Consider that the center of mass of the steel chain is at the midpoint of the depth of the well.

Now, the work done during the lifting process can be calculated as:

W.D = (Work done in lifting bucket filled with water) + (work done to lift    

                                                                                              the steel chain)

W.D = mgh + Mg (h/2)      -( 1 )

where g is the acceleration due to gravity

Applying values in the above equation we get:

W.D = mgh + Mg (h/2)

       = (11.3 kg)(9.8 m/s²)(22.5 m) + (17.9 kg)(9.8 m/s²)(22.5 m / 2)

       = 2491.65 + 1973.475

       = 4465.125 J

We know that the average power is given as:

P_avg = W.D / T     - ( 2 )

where W.D is the work done during the lifting process

            T is the time taken to raise the bucket out of the well

Applying values in the above equation, we get:

P_avg = W.D / T

           = (4465.125 J)/(105 s)

           = 42.525 W

Therefore, the amount of work done during the lifting process is 4465.125 J and our average power will be 42.525 W.  

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A ball of mass 4 kg is initially traveling at 2 m/s and has a 5 N force applied to it for 3 s. What is the final velocity of the ball?
A. 4 m/s
B. 12 m/s
C. 5.75 m/s
D. 3.25 m/s

Answers

Answer:

the answer to your question will be D

Explanation:

5 N* 3S =3.25

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.

Answers

(a) The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

(b) The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

What is  kinetic energy?

The kinetic energy of an object is the energy that it possesses due to its motion.

It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Formula of KE:

K.E = 1/2mv²

mv² = 2 K.E

v = sqrt( 2*KE / M)

Here,

(a)

The KE of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

Now the centripetal force:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

diameter d = 2r,

d= 2(0.19415  m)

d= 0.39 m ≅ 39 cm

(b)

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Thus, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71  ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

Two men standing on the same side of wall and at the same distance from It, such that they are 4oom apart when one fires a gun the other hears the first report in 1.2s and the second in 0.5s after the first. calculate 1) Velocity of sound in air . 2)the perpendicular distance of the men from the wall.

Answers

Answer:

1. 571.43m/s

2. 142.9m and 342.9m

Explanation:

1.Take the difference in time.

1.2-0.7=0.7 seconds

Take the distance between them and divide with differnce in time.

400÷0.7=571.43 seconds.

2.Take the time of the two men and divide by two.

0.5÷2= 0.25 secs

1.2÷2= 0.6 secs

multiply each with the velocity.

0.25×571.43=142.9m

0.6×571.43=342.9m

Which of the zodiac constellations will be highest at midnight?

Answers

Answer:

Virgo will be the highest zodiac constellations at night.

If themass is 50kg, what weight of water is to be displaced to float on water? why

Answers

Answer:if youre looking for the weight of the thermas in genral it should be 500n

Explanation:using the formula w=mg

w=500x10

giving us 500 newtons which is the weight.

Which of the following, if eliminated, would completely prevent the greenhouse effect from occurring on earth?
Group of answer choices

a. Atmosphere

b. Acid rain

c. Fossil fuels

d. Clouds

Answers

The substance, if eliminated, that would completely prevent the greenhouse effect from occurring on earth is fossil fuels (option C).

What is greenhouse effect?

Greenhouse effect is the process by which a planet is warmed by its atmosphere.

Greenhouse effect is caused by greenhouse gases that deplete the ozone layer.

Fossil fuels, when burned, will release greenhouse gases such as carbon etc. to the atmosphere.

Therefore, the substance, if eliminated, that would completely prevent the greenhouse effect from occurring on earth is fossil fuels.

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question down below need rply fast

Answers

The resultant magnitude and direction of the vectors are as follows:

A. A = 6.6; θ = 30.8° from the x-axisB. B = 10.4; θ = 196.7° from the x-axisC. C = 23.3; θ = 300° from the x-axisD. D = 40.4; θ = 138° from the x-axisE. E = 49.5; θ = 346° from the x-axis

What is the resultant magnitude and direction of the given vectors?

The resultant magnitude and direction of the vectors are as follows:

A. A = √(5.7² + 3.4²)

A = 6.6

θ = tan⁻¹(3.4/5.7)

θ = 30.8° from the x-axis

B. B = √{(-10)² + (-3²)}

B 10.4

θ = tan⁻¹(3/10) + 180

θ = 16.7° + 180°

θ = 196.7° from the x-axis

C. C = √{(12)² + (-20²)}

C = 23.3

θ = 360° - tan⁻¹(20/12)

θ = 300° from the x-axis

D. D = √{(-30)² + (27²)}

D = 40.4

θ = 180 - tan⁻¹(27/30)

θ = 138° from the x-axis

E. E = √{(48)² + (12²)}

E = 49.5

θ = 360° - tan⁻¹(12/48)

θ = 346° from the x-axis

In conclusion, the resultant of the vectors and direction are obtained using the resultant vector formula.

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If a star appears to move relative to other stars over a one-year period, this motion is due to the star's: Doppler shift. radial motion. parallax shift. transverse motion. true space motion.

Answers

If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.

What is the proper motion of stars?

Proper motion is the angular change in position of a star across our line of sight, measured in arc seconds per year, and symbolized with the letter  μ.

Proper motion is generally measured by measuring the movement of the image of a star with respect to more distant background stars over that time period.

Here we are told that star appears to move relative to other stars over 1 year period.

So we know that,

True space motion is the annual apparent motion of a star across the sky.

True Space Motion is Combination of radial velocity, proper motion, and distance.

Hence,

If a star appears to move relative to other stars over a one-year period, this motion is due to the star's true space motion.

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What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects an electron with 7.74 × 10−20 j kinetic energy?

Answers

The threshold frequency for sodium metal is

5.49 x 10^14 s-1

Given:

photon with frequency = 6.66 × 10^14 s−1

kinetic energy = 7.74 × 10−20 j

To Find:

threshold frequency

Solution: The threshold frequency is defined as the minimum frequency of incident radiation below which the photoelectric emission is not possible completely. irrespective of the intensity of incident radiation

We know, relation between threshold frequency, kinetic energy and frequency s given by :

K.E = hv - hvo

Here h is plank's constant and vo, is threshold frequency.

Putting all these value in above equation we get:

7.74 x 10^-20 = (6.66 × 10^14-vo) x 6.626 x 10^-34

vo = 5.49 x 10^14 s^-1

Hence, the threshold frequency for sodium metal is 5.49 x 10^14 s-1

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what behavior is mostly strongly associated with introversion in a personality.

Answers

Answer:

Need quiet to concentrate

Are reflective

Are self-aware

Take time making decisions

Feel comfortable being alone

Don’t like group work

Prefer to write rather than talk

And maybe even feel tired after being in a crowd

Explanation:

Consider two copper wires. one has twice the length and twice the cross-sectional area of the other. how do the resistances of these two wires compare?

Answers

Answer:

R = ρ L / A     where R is the resistance and ρ the resistivity:

R2 / R1 = (L2 / A2) / (L1 / A1) = L2 * A1 / (L1 * A2)

R2 / R1 =  (2 L * A) / (L * 2 A) = 1

Their resistances should be the same.

Car A is traveling with a constant speed of 80 km>h due north, while car B is traveling with a constant speed of 100 km>h due east. Determine the velocity of car B relative to car A

Answers

Answer:

80J

Explanation:

K.E = ½ mv²

k.e = ½ * 80*

100²

ke= 4*20

ke= 80 J

What type of energy drives plate motion?
a) external
b) internal
c) gravitational
d) radiative

Answers

b) internal energy drives plate motion

Lithospheric plates are part of a planetary scale thermal convection system. The energy source for plate tectonics is Earth’s internal heat while the forces moving the plates are the “ridge push” and “slab pull” gravity forces.

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere.

The motion of tectonic plates is driven by convection in the mantle. Convection: The process of heat transfer from one part of a fluid to another part by the actual movement of the particles of the fluid is called convection. Liquid and gases are heated by the process of convection.

In simple terms, convection is the idea that dense, cold things sink, and buoyant, warm things rise. In the earth the cold sinking things are slabs (subducting plates) and the warm things are plumes, or just rising material from deeper in the mantle.

hence , correct option is b) internal

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2. A ball is tossed straight upwards with a velocity of 60m/s. Using an estimate of gravity of -10m/s², about how many seconds would it take to reach the peak (top of the flight). A.) 10 seconds B.) 3 seconds C.) 6 seconds D.) 12 seconds​

Answers

Answer: A

Explanation:

How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?.

Answers

The thicker wire has one-fourth the resistance of the thinner wire.

What are resistance and resistivity?

The characteristic of a substance that prevents the flow of current is known as resistance. The free electrons begin to move in a specific direction when a voltage is applied across the conductor. These electrons collide with atoms or molecules as they move, creating heat in the process. These atoms or molecules prevent free electrons from moving through a substance. Resistance is represented by the symbol R.

Specific resistance is another name for resistivity. A substance with certain dimensions, such as one meter in length and a cross-sectional area of one square meter, has a resistance that is represented by its resistivity. Resistivity or specific resistance is represented by ρ.

The relation between resistance R and resistivity ρ is given as:

                                              R = ρL/A

where,

R = resistance of the conductor

ρ =  resistivity of the material

L = length of the conductor

A = cross-sectional area of the conductor

Calculation:

Given,

r₁ = 2r₂

L₁ = L₂

where

r₁ = radius of the first conductor

r₂ = radius of the second conductor

L₁ = length of the first conductor

L₂ = length of the second conductor

To find

R₁/R₂ =?  (the ratio of R₁ and R₂)

If the radius is twice the other then the area will become,

A₁ = π r₁²

A₂ = π r₂²

A₁ = π (2r₂)²

   = 4π r₂²

Therefore,

A₁ = 4 A₂

Now put the values in the formula,

R = ρL/A

R₁/R₂ = ρ L₁ A₂/  ρ L₂ A₁

R₁/R₂ = L A₂/ L (4A₂)

R₁/R₂ = 1/4

R₁ = R₂/4

Hence, the thicker wire with twice the radius of the thin wire has one-fourth the resistance of the thinner wire.

I understand the question you are looking for is this:

How do the resistances of two conducting wires compare if they have the same length, but one is twice the radius of the other?

(a) The thicker wire has half the resistance of the thinner wire

(b) The resistance is the same in both wires

(c) The thicker wire has one-fourth the resistance of the thinner wire

(d) The thicker wire has twice the resistance of the thinner wire.

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Some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. What force must an 85.0-kg grouper exert to stay submerged in salt water if its body density is

Answers

The force require to keep grouper submerged is 8.207N.

According to Archimedes principle  buoyant force of any object must equal to weight of fluid it displaced.

The expression for the force exerted to stay submerged in salt water is

           F = F(b) - w(fish)

 where F(b) = buoyant force

              w(fish) = weight

      now substitute w(b) for F(b)

   →  F = Vρg - w(fish)

where  V = volume of sea water

             ρ = density of sea water

Now by Archimedes principle   V = m(fish)  / ρ(fish)

    →    F = (m(fish) / ρ (fish) ) ρg - m(fish)g

           F =   (85 kg/1015 kg-m^-3) (1.025× 10³ kg-m^-3) (9.8 m/s^2)

                                  -   (85kg)  × 9.8 m/s^2

           F = 841.207N - 833N

           F = 8.207 N

  Hence, the force require to keep grouper submerged is 8.207N.

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What is the acceleration of a 2-kg mass if a 100-N force acts on it?

Answers

SOLUTION:

Acceleration = Force/mass

= 100N / 2 kgs

= 50 m/s

.

.

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What is the energy of an electromagnetic wave that has a wavelength of
7.0 x 10-12 m? Use the equation E= hc where hc = 1.99 × 10-25 J-m.
OA. 2.8 × 10-14 J
OB. 1.4 x 10-36 J
OC. 9.0 x 10-37 J
OD. 7.2 x 1035 J
SUBMIT

Answers

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

[tex]\qquad \sf  \dashrightarrow \:E = \dfrac{hc}{\lambda} [/tex]

here,

[tex] \sf{hc = 1.99 × {10}^{-25} J - m} [/tex]

[tex] \sf{\lambda = 7.0 × {10}^{-12}} [/tex]

____________________________________

[tex]\qquad \sf  \dashrightarrow \: E = \cfrac{1.99 \times 10 {}^{ - 25} }{7 \times 10 {}^{ - 12} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: E= \cfrac{1.99}{7} \times 10 {}^{ (- 25 + 12)} { } [/tex]

[tex]\qquad \sf  \dashrightarrow \:E= 0.284 \times 10 { }^{ - 13} [/tex]

[tex]\qquad \sf  \dashrightarrow \: E= 2.84 \times 10 { }^{ - 14\:\; } J\: \: [/tex]

so, correct choice is A

An object at rest has no ________ energy, but it may have ________ energy resulting from its location or structure. An object at rest has no ________ energy, but it may have ________ energy resulting from its location or structure. chemical; potential kinetic; potential kinetic; heat potential; kinetic

Answers

Answer: An object at rest has no kinetic energy, but it may have potential energy resulting from its location or structure.

Explanation: To find the answer, we need to know more about the kinetic and potential energies.

What is kinetic energy of a body?Kinetic energy is a form of mechanical energy possessed by a body by virtue of its motion.Kinetic energy of a body of mass m moving with a velocity v is given by,

                           [tex]KE=\frac{1}{2}mv^2[/tex]

What is potential energy?Potential energy is a form of mechanical energy possessed by a body by virtue of its position in the field or configuration.PE is always associated with a conservative force.There cannot be potential energy due to frictional or viscous forces.

Thus, we can conclude that, an object at rest has no kinetic energy, but it may have potential energy resulting from its location or structure.

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A man pushes a box across a floor. as he increases the force he applies horizontally to the box

a) the kinetic friction decreases
b) the kinetic friction may increase or decrease depending on the velocity of the box
c) the kinetic friction remains the same
d) the kinetic friction increases

Answers

When a man pushes a box across a floor, as he increases the force he applies horizontally to the box, then the kinetic friction remains the same.

To find the answer, we need to know about friction.

What is friction?Whenever a body moves, over the surface of another body, a force comes into play which acts parallel to the surface of contact and opposes the relative motion. This opposing force is called friction.There are two frictions acting on a surface.Static friction:  It come into play between two bodies before when it starts moving. Self-adjusting force and the max value of it is called limiting static friction.Kinetic friction:  It come into play between two bodies when it starts moving. It is not a self-adjusting force.As we increase applied force, kinetic friction will remain same.

Thus, we can conclude that, kinetic friction remains the same when we increase the applied force.

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As a guy pushes a box across a floor, the kinetic friction stays constant no matter how much force is applied on the box horizontally.

We must understand friction if we are to find the solution.

Describe friction?A force that works parallel to the surface of contact and opposes the relative motion is always present whenever a body moves over the surface of another body. Friction is the name for this opposing force.On a surface, there are two frictions operating.Static friction: It occurs between two bodies before motion is initiated. Limiting static friction is the term used to describe the maximum amount of self-adjusting force.As soon as two bodies begin to move, kinetic friction is triggered. It is not a force that adjusts itself.The amount of kinetic friction will not change when we apply more force.

We can therefore draw the conclusion that kinetic friction does not change as the applied force is increased.

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The lion has a kinetic energy of 5000 j. What is the speed of the lion?

Answers

The lion has a kinetic energy of 5000 j, the speed of the lion is  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

What is kinetic energy ?

Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy or Kinetic energy is the energy that an object possesses due to its motion. It is basically the energy of mass in motion. Kinetic energy can never be negative and it is a scalar quantity i.e. it provides only the magnitude and not the direction.

given

kinetic energy = 5000 J

speed = ?

since , mass is not given in the question

Let mass of lion will be = M1

kinetic energy = 1/2 * M1 * [tex]v^{2}[/tex]

             5000 J = 1/2 * M1 *  [tex]v^{2}[/tex]

             [tex]v^{2}[/tex] = [tex]\sqrt{10,000 / M1}[/tex]  m/s

              v = 100 / [tex]\sqrt{M1}[/tex]  m/s

The speed of the lion =  v = 100 / [tex]\sqrt{M1}[/tex]  m/s

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An 80-N crate is pushed at constant speed for a distance of 5.0 m upward along a smooth inclined plane that makes an angle of 30o with the horizontal. If the force on the crate is parallel to the slope, what is the work done by the pushing force? Group of answer choices 260 J 200 J 61 J 140 J -200 J

Answers

The work done by the pushing force is 200 J; option B.

What is work done in an inclined plane?

The work done in an inclined plane is given by the formula below:

Work done = Force * distance

Force, F = mgsinθ + ma

where a = 0

Work done = 80 * 5 * sin 30°

Work done = 200 J

In conclusion, work done is the product of force and distance.

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A car approaches a stationary police car at 36 m/s. The frequency of the siren (as heard in the police car) is 500 Hz. What is the frequency (in Hz) heard by an observer in the moving car as he approaches the police car

Answers

The frequency heard by an observer in the moving car as he approaches the police car is 558.6 Hz.

Frequency hear by the observer

The frequency heard by the observer is calculated by applying the principle of Doppler effect.

f₀ = f'[(v/v - vs)]

where;

f₀ is the observed frequencyv is speed of sound = 343 m/svs is the speed of the source

f₀ = 500[(343 / 343 - 36)]

f₀ = 500(343/307)

f₀ = 558.6 Hz

Thus, the frequency heard by an observer in the moving car as he approaches the police car is 558.6 Hz.

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When a 3.0 N weight is attached to a vertical coil spring, it stretches 5.0 cm. What weight would be required to stretch the spring 12.5 cm?
Group of answer choices

a. 7.5 N

b. 15 N

c. 4.5 N

d. 1.2 N

Answers

The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)

Data obtained from the questionInitial weight (W₁) = 3 N Initial Length (L₁) = 5 cmNew length (L₂) = 12.5 cmNew Weight (W₂) =?

How to determine the new weight

The new weight required to stretch the spring can be obtained as follow:

W₁ / L₁ = W₂ / L₂

3 / 5 = W₂ / 12.5

Cross multiply

W₂ × 5 = 3 × 12.5

Divide both sides by 5

W₂ = (3 × 12.5) / 5

W₂ = 7.5 N

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Why do we tallk about radio waves as a group and not the frequeny of radio waves

Answers

Because radio waves are important and everyone should know because without them y=my+D

A 55 kg track and field athlete has an average power output of 5.4 kW during the 200 meter dash. How quickly did she finish the race?
Group of answer choices

a. 20 s

b. 22 s

c. 23 s

d. 18 s

Answers

The time taken for the athlete to finish the race is 20 s (Option A)

What is power?

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = weight × distance

Therefore,

Power = (weight × distance ) / time

How to determine the time Mass (m) = 55 KgAcceleration due to gravity (g) = 9.8 m/s²Weight = mg = 55 × 9.8 = 539 NPower (P) = 5.4 KW = 5.4 × 1000 = 5400 WDistance (d) = 200 mTime (t) =?

Power = (weight × distance ) / time

5400 = (539 × 200) / t

5400 = 107800 / t

Cross multiply

5400 × t = 107800

Divide both side by 5400

t = 107800 / 5400

t = 20 s

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Two objects X and Y move directly towards each other. The objects have the same mass.
Object X has a velocity of 5.0 m/s to the right. Object Y has a velocity of 3.0 m/s to the left.
Object X and object Y collide and stick together.
What is their velocity after colliding?

Answers

X and Y are two things that travel in the same direction. The mass of the things is the same. 5.0 m/s is the velocity of object x as it moves to the right. The velocity of object y to the left is 3.0 m/s. Objects x and y collide and adhere to one another. Following their collision, they both move at a speed of 1.0 m/s to the right.

Their velocity after colliding is 1.0 m / s to the right.

What is the velocity during the collision?

In a collision, the velocity change is always computed by subtracting the initial value from the final value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.Inelastic collisions occur when only the momentum is conserved but not the system's kinetic energy. Perfectly inelastic collisions happen when objects stick together and have a common velocity after collision. To solve for the final velocity in perfectly inelastic collisions, use v' = (m1v1 + m2v2)/m1 + m2.The magnitude of the relative velocity is the same before and after the collision.

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A solenoid 6.00 cm in diameter and 10.0 cm long has 750 turns and carries a current of 15.0 A. Calculate the magnetic flux through the circular cross-sectional area of the solenoid.

Answers

The magnetic flux through the circular cross-sectional area of the solenoid is 0.00066 Weber or (Tm²).

What is a solenoid?

A wire tightly twisted in a lengthy, thin coil is a solenoid. Due to its design, the solenoid will have an electromagnet inside of it and a weak magnetic field surrounding it if we pass a current through it.

Equation of solenoid's magnetic field:

The simplest solenoid to describe is one with unlimited length. An infinite solenoid's magnetic field has a constant within and a precise zero value outside. If we can accept that the magnetic field near the ends will be different from what is calculated for just an infinite solenoid, the unlimited solenoid is frequently a rough estimate of an actual, finite-length solenoid.

By utilizing the convolution operation as well as right hand rule, the magnetic field within a large solenoid is appropriately computed, but all of that can be condensed into:

B = (µ₀ × N × I )/ L

where

B = magnetic field (Tesla)

µ₀ = [tex]\pi[/tex]× 10^-7 (Tm/A ) is the vacuum permeability,

N = number of turns on solenoid,

I = electric current (Ampere)

L = length of the solenoid (m)

According to the question;

A diameter of solenoid 6.00 cm.

A radius of solenoid is 3 cm = 0.03m

Number of turns = 750

The length of solenoid is 10cm = 0.1m

Substitute all the values in equation to fine mangetic filed.

B = ([tex]\pi[/tex]×[tex]10^{-7}[/tex] × 750× 15 )/ 0.1

B = 0.035 Tesla

The formula for magnetic flux is

Ф = B×A

   = B×([tex]\pi[/tex][tex]r^{2}[/tex])

   = 0.035×[tex]\pi[/tex]×[tex].03^{2}[/tex]

Ф = 0.000099

Ф = 99×[tex]10^{-6}[/tex] Weber

Therefore, the magnetic flux through the circular cross-sectional area of the solenoid. is 99×[tex]10^{-6}[/tex] Weber.

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Two large parallel conducting plates are 9.0 cm apart and carry equal but opposite charges on their facing surfaces. The magnitude of the surface charge density on either of the facing surfaces is 3.7 nC/m 2. Determine the magnitude of the electric potential difference between the plates.

Answers

The magnitude of the electric potential difference between the plates is 37.63 V.

Given:

Distance between the plates, d = 9 cm

Surface charge density, ρ = 3.7 nC/m² = 3.7 × 10⁻⁹ C/m²

Calculation:

For two parallel plate conductors, the electric field is given as:

E = ρ/ε₀

where ρ is the charge density

           ε₀ is the permeability of free space

Applying values in the above equation we get:

E = ( 3.7 × 10⁻⁹ C/m²)/(8.85 × 10⁻¹² C²/m)

  = 418.08 V/m

Now, the potential difference between the plates separated by a distance 'd' is given as:

ΔV = Ed

where E is the electric field

           d is the distance of separation between the plates

Applying values in the above equation we get:

ΔV = (418.08 V/m) × (0.09 m)

     = 37.63 V

Therefore, the magnitude of the electric potential difference between the plates is 37.63 V.

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