whats the answerrrr giving brainliest

In every 100g of that compund there is 50.84 g of C, 8.53 g H and (100-59.37) g = 40.63 g of O.

Step 1: Convert each element's mass in moles. To do that we need to divide each element's mass by their respective molar mass.

For Carbon.

[tex]C = \frac{50.84}{12} = 4.24 mol [/tex]

For Hydrogen.

[tex]H = \frac{8.53}{1} = 8.53 mol [/tex]

For Oxygen.

[tex]O = \frac{40.63}{16} = 2.54 mol [/tex]

Step 2: Divide each of the numbers by the smallest number.

For Carbon.

[tex]C = \frac{4.24}{2.54} = 1.7 [/tex]

For Hydrogen.

[tex]H = \frac{8.53}{2.54} = 3.36 [/tex]

For Oxygen.

[tex]O = \frac{2.54}{2.54} = 1 [/tex]

Step 3: So the empirical formula will be.

[tex] C_{1.7} H_{3.36} O_1 [/tex]

But using decimal will be messy. So we multiply the numbers by 3. The right empirical formula will be.

[tex] C_{5} H_{10} O_3 [/tex]

The empirical formula of an organic compound that contains 50.84% C, 8.53% H, and the rest oxygen is C₅H₁₀O₃.

First, we have to determine the mass percentage of oxygen, knowing that C, H and O amount to the 100% of the compound.

[tex]C + H + O = 100\%\\O = 100\% - C - H\\O = 100\% - 50.84\% - 8.53\% = 40.63\%[/tex]

Then, we divide each mass percentage by the atomic mass of the element.

[tex]C: 50.84/12.01 = 4.23\\H: 8.53/1.01 = 8.45\\O: 40.63/16.00 = 2.54[/tex]

Afterwards, we divide all the numbers by the smallest one, i.e. 2.54.

[tex]C: 4.23/2.54 = 1.66\\H: 8.45/2.54 = 3.33\\O: 2.54/2.54 = 1[/tex]

Finally, we multiply all the numbers by 3, so that they are all integers.

[tex]C: 1.66 \times 3 \approx 5\\H: 3.33 \times 3 \approx 10\\O: 1 \times 3 = 3[/tex]

The empirical formula of the organic compound is C₅H₁₀O₃.

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A.

H₃C-CH₃

this is called ethane

B.

H₃C-CH₂-CH₂-CH₃

this is called butane

C.H₃C-CH₂-CH₂-CH₂-CH₂-CH₃

this is called hexane

D.

H₃C-CH₂-CH₂-CH₂-CH₂-CH₂-CH₃

this is called heptane

Answer:

1. a) Ethane (C2H6)

2. b) Butane (C4H10 )

3. c) Hexane (C6H14)

4. d) Heptane (C7H16)

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 2.01 × 3.77 = 7.5777

We have the final answer as

Hope this helps you

Answer: A property closely related to an atom's mass number is its atomic mass. The atomic mass of a single atom is simply its total mass and is typically expressed in atomic mass units or amu. By definition, an atom of carbon with six neutrons, carbon-12, has an atomic mass of 12 amu.

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!! :D

Answer:

From the plastic cup to the water

Explanation:

The thermal energy is transferred from the plastic cup to the water inside the cup.

This is because thermal energy moves from a body at high temperature to one at lower temperature.

Answer:

receptors which detect stimuli changes in the environment

Explanation:

Answer:

A catalyst is a substance that can be added to a reaction to increase the reaction rate without getting consumed in the process. Catalysts typically speed up a reaction by reducing the activation energy or changing the reaction mechanism.

Explanation:

[tex]\huge\boxed{3.2 Grams}[/tex]

Moles is the unit which measures the amount of substance in the System International (SI). A mole is the amount of substance that contains the same amount of substance as the amount of substance exactly in exactly 12 g of carbon-12. C-12 is the standard to measure moles.

I have attached the Equations for moles.

For this question we will use the formula,

                                      [tex]Moles = \frac{Given Mass}{Atomic Mass}[/tex]

Rearrange the equation,

                                      [tex]Mass = (Moles)x(Atomic Mass)[/tex]

Given:

          Moles = 0.2

          Molecular Mass of Oxygen Atom(Not molecule) = 16

Thus,

                                        [tex]Mass = (0.2)x(16)\\\\Mass = 3.2 grams[/tex]

The mass of 0.2 moles of oxygen atom is 3.2 grams.

Answer:

9.4 mol CO₂

General Formulas and Concepts:

Chemistry - Gas Laws

Explanation:

Step 1: Define

210 L CO₂ at STP

Step 2: Identify Conversions

22.4 L = 1 mol at STP

Step 3: Convert

[tex]210 \ L \ CO_2(\frac{1 \ mol \ CO_2}{22.4 \ L \ CO_2} )[/tex] = 9.375 mol CO₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

9.375 mol CO₂ ≈ 9.4 mol CO₂

Explanation:

It's a triple bond for nitrogen,double bond for oxygen(just saying)

Answer:

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is [tex]0.5 \frac{moles}{L}[/tex]

Explanation:

Molarity or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

In this case:

So, the molar mass of Mg(NO₃)₂ is:

Mg(NO₃)₂= 24.3 g/mole + 2*(14 g/mole + 3*16 g/mole)= 148.3 g/mole

So, if you have 3.744 g of Mg(NO₃)₂, you can apply the following rule of three: if 148.3 grams of Mg(NO₃)₂ are present in 1 mole, 3.744 grams in how many moles are present?

[tex]moles=\frac{3.744 grams*1mole}{148.3 grams}[/tex]

moles= 0.025

Then you have:

Replacing in the definition of molarity:

[tex]molarity=\frac{0.025 moles}{0.05 L}[/tex]

you get:

[tex]molarity=0.5 \frac{moles}{L}[/tex]

The molar concentration of a solution made with 3.744 g of Mg(NO₃)₂ dissolved in enough water to make 50.0 mL of solution is [tex]0.5 \frac{moles}{L}[/tex]

The molar concentration of the solution is 0.506 M

The molar concentration of a solution is known as molarity. The molarity of a solution is defined as the moles of a solute per liter of a solution.

It can be expressed as:

[tex]\mathbf{Molarity = \dfrac{moles \ of \ solute}{volume \ of \ the \ solution}}[/tex]

The relation used in determining the number of moles is:

[tex]\mathbf {number \ of \ moles = \dfrac{mass}{molar \ mass}}[/tex]

[tex]\mathbf {number \ of \ moles = \dfrac{3.744 \ g}{148.3 \ g/mol}}[/tex]

[tex]\mathbf {number \ of \ moles = 0.0253 \ g/mol}[/tex]

∴

[tex]\mathbf{Molarity = \dfrac{moles \ of \ solute}{volume \ of \ the \ solution}}[/tex]

[tex]\mathbf{Molarity = \dfrac{0.0253 \ g/mol}{0.05 \ L}}[/tex]

[tex]\mathbf{Molarity =0.506 \ M}[/tex]

Therefore, we can conclude that the molar concentration of the solution is 0.506 M

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Answer:

If I'm correct i believe that the answer is A.

Answer:

A. Where warm moist air masses traveling north collide with cool dry air masses traveling south

Explanation:

I got it right

Answer:

Most likely A. Molten lava, since it straight up melts the equipment which is much faster than chemicals dissolving the equipment like hydrochloric acid and nitric acid.

Explanation:

Hope this helped!

P.S. Sure, why not?

The enthalpy change accompanying the reaction of 0.95 g of S is -11.85 kJ

Given

ΔH° for the reaction is -790 kJ

Required

The enthalpy change

Solution

Reaction

2S (s) + 3O₂(g) = 2SO₃ (g)

mol of S(MW=32 g/mol) :

[tex]\tt mol=\dfrac{0.95}{32}=0.03[/tex]

For 2 mol S, the entalphy = -790kJ

The enthalpy change for 0.03 mol :

[tex]\tt \dfrac{0.03}{2}\times -790~kJ=-11.85~kJ[/tex]

The enthalpy change accompanying the reaction will be "-11.85 kJ".

Given:

Value of ΔH°,

According to the question,

→ [tex]2S(s) +3O_2(g) =2SO_3(g)[/tex]

Mol of S will be:

= [tex]\frac{0.95}{32}[/tex]

= [tex]0.03[/tex]

hence,

The enthalpy change for 0.03 mol will be:

= [tex]\frac{0.03}{2}\times -790[/tex]

= [tex]-11.85 \ kJ[/tex]

Thus the answer above is correct.

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Answer:

V = 1.57 L

Explanation:

Given data:

Mass of iron(III) carbonate = 50.0 g

Volume of CO₂ formed = ?

Temperature = standard = 273 K

Pressure = standard = 1 atm

Solution:

Chemical equation:

Fe₂(CO₃)₃     → Fe₂O₃ + 3CO₂

Number of moles of Fe₂(CO₃)₃ :

Number of moles = mass/molar mass

Number of moles = 50.0 g /235.8 g/mol

Number of moles = 0.21 mol

Now we will compare the moles of Fe₂(CO₃)₃  and CO₂.

                          Fe₂(CO₃)₃         :             CO₂

                              1                    :               3

                            0.21                :            1/3×0.21 = 0.07 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm × V =0.07 mol × 0.0821 atm.L/mol.K × 273 K

V = 1.57 atm.L / 1 atm

V = 1.57 L

Answer:

Here you go!!

Explanation:

Answer:

Explanation:

Deforestation has an adverse affect on air by reducing the amount of oxygen and increasing the amount of carbon dioxide as well as contributing to global warming.

Answer:

Reactant Side = Al + Cl₂  

Product Side = AlCl₃

Oxidizing Agents  = chlorine

Reducing Agent = aluminum

Explanation:

Chemical equation:

2Al + 3Cl₂     →      2AlCl₃

In this chemical equation Al and Cl₂ are reactants while AlCl₃ is product.

2Al° + 3Cl₂°     →      2Al⁺³Cl⁻¹₃

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

In given reaction Al is oxidized because oxidation increase from zero to +3. It is thus reducing agent.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

In given reaction chlorine is reduced because its oxidation state is decreased from zero to -1. Chlorine is oxidizing agent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

Answer:

12 molcules

Explanation:

distruibtive property.

Answer:

[tex]\Delta _{fus}H=332 \frac{J}{g}[/tex]

Explanation:

Hello!

In this case, since the heat of fusion of a solid substance stands for the energy required to melt it, which is a phase transition from solid to liquid, we can see that the heat lost by water is that gained by the solid, so we can write:

[tex]Q_{solid}=-Q_{w}[/tex]

Thus, by using the water data and its specific heat (4.184), we obtain:

[tex]Q_{solid}=-m_{w}C_{w}(T_f-T_i)\\\\Q_{solid}=-425g*4.184\frac{J}{g\°C}*(30.0-85.1)\°C\\\\ Q_{solid}=97,978.82J=98.0kJ[/tex]

Next, since the heat of fusion of a substance is usually represented in terms of energy per amount of substance, we use the mass of solid to obtain:

[tex]\Delta _{fus}H=\frac{98.0kJ}{295.5g}\\\\ \Delta _{fus}H=0.332\frac{kJ}{g}=332 \frac{J}{g}[/tex]

Best regards!

The heat of fusion of the solid is 0.332 KJ/g or 332 J/g

We'll begin by calculating the heat loss by the water. This can be obtained as follow:

Mass of water (M) = 425 g

Initial temperature of water (T₁) = 85.1 °C

Final temperature (T₂) = 30 °C

Change in temperature (ΔT) = T₂ – T₁ = 30 – 85.1 = –55.1 °C

Specific heat capacity of water (C) = 4.184 J/gºC

Q = MCΔT

Q = 425 × 4.184 × –55.1

Q = –97978.82 J

Divide by 1000 to express in KJ

Q = –97978.82 / 1000

Heat loss by water = –97.98 KJ

Heat gained by the solid (Q) = 97.98 KJ

Mass of solid (m) = 295.5 g

Q = m•Hf

97.98 = 295.5 × Hf

Divide both side by 295.5

Hf = 97.98 / 295.5

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Answer:

from the Sun to the surface of the Earth, where it is absorbed or reflected

Explanation:

The solar radiation that emerges out of the sun and that reaches the surface of the Earth is sunlight. There are numerous constituents and particles present in the atmosphere that absorbs the solar radiation. These radiations are weakened by these constituents. Later, these radiations gets scattered in the atmosphere. Some amount of he solar radiation that reaches the Earth's surface is absorbed and some is reflected back.

Answer:

B

Explanation:

Answer:  The oxidation number of chlorine in [tex]Cl_2[/tex] is zero

Explanation:

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Rules for Oxidation Numbers are :

1.  The oxidation number of a free element is always zero.

2. The oxidation number of a monatomic ion equals the charge of the ion.

3. The oxidation number of  oxygen (O)  in compounds is usually -2.

4. The oxidation number of a Group 17 element in a binary compound is -1.

5. The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

6. The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

7. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

As [tex]Cl_2[/tex] exists as a free molecule, its oxidation state is zero.

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

The element will lose electrons to become stable if the valence shell contains 3 or fewer electrons. The production of cations is a sign of electron loss. The species having positive charge are called cations. As a result, the ion will get a positive charge.

An atom or molecule with a net electrical charge is known as an ion. Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive.

An atom will shed its valence electrons in order to become a charged ion and create an ionic bond with another atom if it lacks one to three of them.

A positive ion is created by taking electrons from a neutral atom, whereas a negative ion is created by adding electrons to a neutral atom. The quantity of protons remains constant during the formation of an ion.

Thus, the ion will get a positive charge.

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Answer:

10.35%

Explanation:

Find the molar mass of water, using your periodic table: 18.02 g. Then find the molar mass of the total substance: 174.10 g.

Divide the molar mass of water by the molar mass of the total substance and multiply 100%. Doing this, you get 10.35%.

Explanation:

a. Write the molecular formula of the compound.

Acetaminophen contains 8 carbon atoms, 9 Hydrogen atoms, 1 Nitrogen atom and 2 Oxygen atoms.

The molecular formular is given as;  C8H9NO2

b. What is the hybridization state of each C, N, and O atom?

From the image attached;

All the carbon atoms in the benzene ring has hybridization of sp2.

The carbon that is doubly bonded (carbonyl) to the oxygen has hybridization of sp2

The last carbon to the right has hybridization of sp3

The hybridization of nitrogen in the compound is sp3 hbridized.

Oxygen atom in alcohol  is sp3 hybridised

Oxgen in the carbonyl group is sp2 hybridized.

Answer:

6.02 x 10²³ atoms

Explanation:

Given parameters:

Number of moles CaSO₄ = 1 mole

Unknown:

Number of Ca atoms in the given compound = ?

Solution:

The given compound is:

          CaSO₄

     1 mole of CaSO₄  is made up of 1 mole of Ca atoms

Now;

   1 mole of any substance contains 6.02 x 10²³ atoms

  1 mole of Ca atoms will also contain 6.02 x 10²³ atoms

Explanation:

Moles of Co = 24.63 / 58.9 = 0.418

Moles of O = (31.32 - 24.63) / 16 = 0.418

Since the mole ratio is 1 : 1, the empirical formula is CoO.

The empirical formula of the metal oxide is CaO₂.

The empirical formula is the simplest ratio of the number of atoms participating in the formation of a compound.

The chemical formula of any compound is based on two types of formula one is molecular formulas and another one is empirical formulas. Both the molecular formula and empirical formula represent the identity and number of the atom.

Given, the mass of the sample of the cobalt = 24.63g

The mass of the metal oxide = 31.32g

From the law of the conservation of mass:

The mass of the metal oxide - Mass of cobalt = mass of the oxygen

So the mass of the oxygen = 31.32 - 24.63 = 6.69 g

If mass 59 grams of the cobalt has moles = 1

Then 24.63 g of Cobalt will have moles = 24.63/59 = 0.417 mol

Similarly, 8 grams of the oxygen gas moles = 1

Then 6.69g of the oxygen has moles = 6.69/8 = 0.8362 mol

The simplest ratio of moles for Co = 0.417/0.417 = 1

For oxygen = 0.8362/0.417 = 2

Therefore the empirical formula of the metal oxide is CaO₂.

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Answer:

Explanation:

THe GrEen OnEs

Answer:

They are in the green "staircase"

Explanation:

these elements are the dividers between metals (on the left of them) and non metals (on the right of them), they have some of the properties of both groups