Whats the word for when "velocity equals 0 and direction changes" Its 14 letters, and I have _ _ _ _ i _ _ _ _ _ h_ i _ _ t

Answers

Answer 1

Answer:

Maximum Height

Explanation:

The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.

Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.

Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.


Related Questions

1. A truck of mass 3120 kg is accelerated from rest to a speed of 22.1 m/s. How much work was done on the truck to achieve that speed?

Answers

Answer:

.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J

Explanation:

The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.

The work done on the truck is equivalent to the kinetic energy.

   Work done = Kinetic energy = [tex]\frac{1}{2} mv^{2}[/tex]

Where m is mass of truck and v is final velocity of truck.

Given that, [tex]m=3120Kg,v=22.1m/s[/tex]

Substitute values in above equation

                 [tex]Workdone=\frac{1}{2}*3120*(22.1)^{2} \\\\Workdone=0.5*3120*488.41=7.62*10^{6} KJ[/tex]

Thus,  The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.

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can someone help me please

Answers

The correct answer would be

Mile

1. Any event or situation that evokes a response is a
a. positive reinforce
b. cognitive map
c. stimulus
d. model

Answers

stimulus. Because its the only thing I can really think of that evokes.

please help me answer this​

Answers

I think it’s C, because both of them are pulling and are at equal sides

A radio transfers 270 j of energy electrically, 94.5 j is transferred by sound. Work out the efficiency of this radio. Give your answer as a decimal

Answers

Answer:

35%

Explanation:

Given data

Amount of energy transferred (Input) = 270J

Amount of energy converted to sound (Output)=  94.5J

Efficiency = output/input*100

Efficiency= 94.5/270*100

Efficiency=0.35*100

Efficiency=35%

Hence the efficiency is 35%

find the odd one out: asteroids on the asteroid belt, a comet, the moon or Saturn

Answers

Answer:

Explanation:

A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.

Saturn kakanansnqllqkshdbv

What is the gravitational potential energy of a 250 kg rock on top of a 200 meter cliff?

Answers

Answer:

500000 approx........

...

The adult house fly lives for only about 1 month, or 8 x 10^-2 y. The oldest recorded age of a tortoise was 1.8800 x 10^2 y. What is the difference between these two ages?

Answers

187.92 years

8*10^-2= .08

1.88*10^2= 188

188-.08=187.92

We have a 10 m resistance wire of the isachrom 60 type. The resistance of this wire is 5.65 Ω / m at 20 ° C. The wire has a diameter of 0.50 mm.



a. Calculate the resistivity of isachrom 60 at 20 ° C.

Answers

Answer:

[tex]\rho=1.10\times 10^{-7}\ \Omega[/tex]

Explanation:

Given that,

The length of the resistance wire, l = 10 m\

The  resistance of this wire is 5.65 Ω/m

The diameter of the wire, d = 0.5 mm

Radius, r = 0.25 mm = 0.00025 m

We need to find the resistivity of isachrom 60 at 20°C. The formula for the resistance of a wire is given by :

[tex]R=\rho\dfrac{l}{A}\\\\\rho=\dfrac{RA}{l}\\\\\rho=\dfrac{R\pi r^2}{l}\\\\\rho=\dfrac{5.65\times \pi \times (0.00025)^2}{10}\\\\\rho=1.10\times 10^{-7}\ \Omega[/tex]

The resistivity of the wire is [tex]1.10\times 10^{-7}\ \Omega[/tex].

If a person runs 68m in 8s, what is his speed?

Answers

Answer:

19.01396 mph.

Explanation:

PLEASE PLEASE HELPPPP

Answers

Answer: 8 volt battery in each device.

I think the units is 7.

Explanation:

Units 7 is the answers

Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________

Answers

Answer:

a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s

b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m

c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s

d) La altura que alcanza el bloque es de 5 metros.

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción

Explanation:

a) Los parámetros dados del bloque son;

La masa del bloque, m = 3 kg

La altura a la que se coloca el bloque, h = 5 m

La constante de resorte, k = 400 N / m

La aceleración debida a la gravedad, g = 9,8 m / s²

La energía potencial de un cuerpo, P.E. = m · g · h

Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;

P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios

P.E. = 147 julios

La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²

Dónde;

v = La velocidad del bloque cuando llega al resorte

Por lo tanto, para el bloque dado tenemos;

K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²

Por el principio de conservación de la energía, tenemos;

El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.

∴ P.E. = K.E.

147 J = 1/2 × 3 kg × v²

v² = 147 J / (1/2 × 3 kg) = 98 m² / s²

v = √ (98 m² / s²) = 7 · √2 m / s

v = 7 · √2 m / s ≈ 9,9 m / s

b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²

Dónde;

k = La constante del resorte = 400 N / m

x = La distancia a la que se comprime el resorte

Por el principio de conservación de la energía, tenemos;

La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.

∴ E = 1/2 · k · x² = P.E.

De lo que tenemos;

E = 1/2 × 400 N / m × x² = 147 julios

x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²

x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m

La distancia a la que se comprime el resorte = x ≈ 0.86 m

c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;

La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²

∴ 1/2 · k · x² = 1/2 · m · v²

∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s

La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s

d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;

P.E. = K.E.

∴ m · g · h = 1/2 · m · v²

v = 7 · √2 m / s

De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros

e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción

a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.

[tex]U = K[/tex] (1)

Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:

[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Ahora despejamos la velocidad de esa ecuación:

[tex]v = \sqrt{2\cdot g\cdot h}[/tex]

Donde:

[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.

Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:

[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]

[tex]v\approx 9.903\,\frac{m}{s}[/tex]

La velocidad final del bloque es aproximadamente 9.903 metros por segundo.

b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:

[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)

Where:

[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.

Ahora despejamos la deformación del resorte:

[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)

Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:

[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]

[tex]x \approx 0.858\,m[/tex]

El resorte se deforma 0.858 metros.

c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.

d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).

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Since the universe is infinite, the probability of events and reoccurrence is infinite. So that means that there is a chance, if not 100% chance, that SOMEWHERE there is another earth, with another you, living the same life, at the same time. What are your thoughts about this??? that's so crazy to me

Answers

Answer:

That insane it might be true because  a planet sometimes quoted to be an Earth 2.0 or Earth's Cousin based on its characteristics; also known by its Kepler Object of Interest designation KOI-7016.01) is an exoplanet orbiting the Sun-like star Kepler-452 about 1,402 light-years (430 pc) from Earth in the constellation Cygnus.

Explanation:

Which two statements are true about the wave shown?
A. The wave could be transmitting light. B. The wave is a transverse wave.
C. The wave is a mechanical wave.
D. The wave could be transmitting sound.​

Answers

Answer:

c and d

Explanation:

The wave shown in the figure is Sound waves. The sound wave is a mechanical wave. Hence, options C and D are correct.

What are sound waves?

Sound is traveled by means of vibrations of particles in the medium. Sound waves require a medium to propagate. The energy propagation by means of adiabatic loading and unloading is called sound or acoustic waves.

The sound waves produce compression and rarefaction in the air. The sound waves are called Longitudinal waves because the direction of propagation is parallel to the vibration of particles.

Sound waves are considered only as waves because they exhibit a wave nature. Light has both properties of wave and particle. Light is an electromagnetic wave and it is transverse in nature.

The sound waves require a medium like air, water, solids, etc for propagation. Hence it is called Mechanical waves. Light waves do not require a medium to propagate. From the given wave pattern,  it exhibits the property of sound waves.

Hence, the correct option is C) the wave is a mechanical wave, and D) the wave could be transmitting sound.

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How efficient is a pulley system if it enables you to lift a 700.0 Newton engine (Fr) 0.550 meters (dr) if you exerted 35.7 Newtons (Fe) of force while pulling 11.43 meters (de) of rope?

Answers

Answer:

96.3%

Explanation:

Efficiency = Work input/Work output * 100%

Work done = Force * distance\

Work done by the engine is the work output = 700 * 0.55

Work output = 423.5Nm

Work done by you is the work input = 35.7*11.43

Work input = 408.051Nm

Efficiency = 408.051/423.5 * 100

Efficiency = 0.963 * 100

Efficiency = 96.3%

Hence the efficiency of the pulley system is 96.3%

TRUE OR FALSE
1. TRUE OR FALSE: The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be.
2. TRUE OR FALSE: The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave.
3. TRUE OR FALSE: In a transverse wave the higher the wave, the LOWER the amplitude
4. Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave.
5. TRUE OR FALSE: Speed is a measure of the distance a wave travels in an amount of time
6. TRUE OR FALSE: As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media
7. TRUE OR FALSE: The highest point of a transverse wave is the crest and the lowest point is called a trough.

Answers

Answer:

Explanation:

true true fauls true fauls fauls

1 . The higher the frequency, the closer the waves are together and the LOWER the energy carried by the waves will be. FALSE

2. The greater the force that produces a wave, the greater the amplitude of the wave and the greater the energy carried by the wave. TRUE

3. In a transverse wave the higher the wave, the LOWER the amplitude FALSE

4.Wavelength is a measure of the distance from the crest on one wave to the crest on the very next wave, TRUE
5. Speed is a measure of the distance a wave travels in an amount of time TRUE

6. As a wave enters a different medium, the wave’s speed changes. Waves travel at different speeds in different media TRUE

7. The highest point of a transverse wave is the crest and the lowest point is called a trough. TRUE

What is Wave ?

A wave is a disturbance in a medium that carries energy and  as well as momentum. Energy can be transferred in the form of wave in the medium. there are two types of wave,

longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave as shown in the fig.1. Sound wave is a longitudinal wave.

Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave as shown in the fig.2. Light wave is a longitudinal wave.

1. E = hυ where υ is a frequency which shows direct relation between Energy E and frequency υ. Hence it is false.

2. True

3. In a transverse wave the higher the crest in the wave, the higher the amplitude. FALSE

4. True

5. True, Speed = Distance÷Time

6. due to change in refractive index, velocity changes TRUE

7.True

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Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob is touched if there’s a buildup of static electricity.

Answers

Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process

Explanation:

An airplane moving horizontally at 150 m/s drops a package from an altitude is 490 m. How long does it
take the package to reach the ground? How far, horizontally, from the spot over which it was dropped
does the package land?

Answers

Answer:

640

Explanation:

cause you should just add the 2

It takes 10 second the package to reach the ground.

The package reaches the ground after 10 second and  it was dropped 1500 m far from the package landing.

Given parameters:

Altitude of the plane; h = 490 m.

Initial horizontal velocity of the plane; u = 150 m/s.

We have to find; time taken by  the package to reach the ground: t =?

And,  horizontal distance covered by the package before land; d = ?

We know that a free falling object has acceleration equal to acceleration due to gravity = g = 9.8 m/s².

So,

h = 1/2gt²

⇒ t = √(2h/g) = √(2×490/9.8) second = 10 second.

In this time,

horizontal distance covered by the package before land; d = ut

= 150 m/s × 10 s

= 1500 m.

Hence, the package reaches the ground after 10 second and  it was dropped 1500 m far from the package landing.

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How do the metal aluminum coils in an air conditioner help keep a house cool? They insulate the house from outside thermal energy. They conduct thermal energy from inside the house and release it outside the house. They insulate the surrounding air from indoor thermal energy. They conduct thermal energy from outside the house and release it inside the house.

Answers

Answer:

They conduct thermal energy from inside the house and release it outside the house.

Explanation:

An air conditioner works to by conducting thermal energy or heat from inside the house and releasing this heat energy outside the house, thus making inside of the house cooler than the outside.

Warm air from inside the house is circulated around the evaporator fins. The refrigerant liquid is made to pass through the evaporator coil made of aluminum ,where the coils exchanges the heat it absorbs from the air surrounding it with the refrigerant. Aluminum metal is used in making the evaporator coils because it is a good conductor of heat. The heat absorbed by the refrigerant coverts it to vapor, which is then reconverted into liquid by the condenser removing the heat absorbed from inside the outside by means of a fan. As the heat is removed from the air, the air is cooled and blown back inside the house. This process is repeated several times until the desired temperature is attained inside the house.

Answer:

B is the answer

Explanation:

pls give me brainliest

A rock is thrown horizontally off a cliff with an initial velocity of 15 m/s. How high was the cliff if the rock lands 22 m from the base of the cliff?

Answers

Answer:

22 m

Explanation:

Answer:

cliff height = 10.55 m

Explanation:

Remarks

This is one of those questions that defies belief. The final vertical velocity is the same as if you just dropped the rock, which is amazing.Another amazing fact is that the horizontal speed has no acceleration. And  amazing fact number three is the the vertical initial speed is 0.And finally, the time taken to go horizontally = time to go vertically.

Solution

Time

So the time taken is d = r * t  

Remember, this formula can only be used when there is no acceleration.

d = 22 meters

r = 15 m/s

t = ?

t = d / r

t = 22 / 15

t = 1.467

Height of the Cliff

vi = 0 (vertially)

a = 9.8 m/s^2

t = 1.467 seconds    The time horizontally and vertically is the same.

d = ?

Formula

d = vi*t + 1/2 a t^2

Solution

d = 0 + 1/2 * 9.8 * 1.467^2

d = 10.55 meters.

need help its do today

Answers

Answer:

the answers for the first 3 are

C

A

C

Explanation:

2. A bullet was shot by a gun with an initial speed of 260 m/s and is fired at an angle of 30 to the ground. a. How much is the value Vy at the top of the bullet's trajectory? b. Calculate the time taken by the bullet to reach its maximum altitude. c. Deduce the total time taken by the bullet in the air. d. Calculate the range of the bullet.

Answers

Answer:

Explanation:

a )

the value Vy at the top of the bullet's trajectory will be zero . At the top , only the horizontal component Vx will exist .

b )

At the top Vy = 0

initial velocity will have vertical component = 260 sin30 = 130 m /s

acceleration = - g = - 9.8

v = u - gt

o = 130 - 9.8 t

t = 13.26 s .

c )

Total time = Time of ascent + time of descent

= 13.26 + 13.26 = 26.52 s

d )

Range R = u² sin2Ф / g , where u is initial velocity , Ф is angle of throw , g is acceleration due to gravity .

R = 260² sin 2 x 30 / 9.8

= 5973.8 m .

Meg has two glasses of grape juice. Glass A has 80 grams of juice at 30 °C. Glass B has 80 grams of juice at 50 °C.

Which of the following steps will make the kinetic energy of the molecules of the juice in both glasses equal?
Decrease the temperature of juice in Glass A by 20 °C
Increase the temperature of juice in Glass A by 20 °C
Decrease the temperature of juice in Glass B by 30 °C
Increase the temperature of juice in Glass B by 30 °C

Answers

Answer:

Increase the temperature of juice in Glass A by 20 °C

Answer:

lil baby

Explanation:

What is a material that electricity cannot flow through called?

Answers

Answer:

Things that electricity cant flow through are called insulators.

If Calcium has 2 valence electrons and Chlorine has 7 valence electrons, how many Cl-1 ions would need to combine with 1 Ca+2 ion?

Answers

Answer:

CALCIUM IDENINE ADEININE AND PHOSPHATE

Explanation:

A child bouncing a ball. Which law of motion does the situation describe?​

Answers

Kinetic energy evades the ball jumping higher than the kid

Calculate the wavelength of light that has a frequency of 5.2 x 1012 1/s.

Answers

Answer:

Wavelength = 5.77 * 10^-5 meters.

Explanation:

Given the following data:

Frequency of light = 5.2 *10^12 Hz

We know that the Speed of light = 3.0 * 10^8 m/s

To find the wavelength of light;

Mathematically, wavelength is calculated using this formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Substituting into the equation, we have;

[tex] Wavelength = \frac {3*10^{8}}{5.2 *10^{12}} [/tex]

Wavelength = 5.77 * 10^-5 meters.

Help with physics please! Offering a bunch of points!

Answers

3.0m because the graph starts going at a constant pace of 1m per second

Look at the image provided, it shows forces acting on a box.
What is the NET FORCE on the box?

Answers

your answer should be C

calculate the ground pressure of a 90kg gas cylinder the diameter of the cylinder is 1.1 m

Answers

Answer:

P = 928.09 Pa

Explanation:

Given that,

Mass of a gas cylinder, m = 90 kg

The diameter of the cylinder, d = 1.1 m

Radius, r = 0.55 m

We need to find the ground pressure. The pressure is equal to force per unit area. So,

[tex]P=\dfrac{F}{A}\\\\P=\dfrac{mg}{\pi r^2}\ (A\ is\ area\ of\ base)\\\\P=\dfrac{90\times 9.8}{\pi \times (0.55)^2}\\\\P=928.09\ Pa[/tex]

So, the ground pressure is 928.09 Pa.

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