what is cheetah speed and strength?
Answer:
Speed: 109.4–120.7 km/h (68.0–75.0 mph)
Strength: Couldn't find out.
Explanation:
pls pls pls help i need to know the correct answer and why it’s correct, thanks in advance
What is the relationship between power, work, and time?
A
As the amount of time increases,
power and work both increase.
B
As the amount of time increases,
power and work both decrease.
С
As the amount of time increases,
power increases and work is not affected. D. As the amount of time increases power decreases and work is not affected.
Answer:
it's ans is D because all three are wrong
How to calculate angular velocity.
Answer:
Answer below
Explanation:
We can rearrange this statement to get the angular velocity equation: = r v / |r|2, where all of these variables are vectors and |r| is the radius's absolute value. The angular velocity is really a pseudovector with a direction perpendicular to the plane of rotational movement.
The rotating movement of bodies is described by angular velocity. It determines how quickly they rotate around a central point. Rotations may be divided into two categories. The first explains the motion of an object's centre of mass around a certain point in space, which is referred to as an origin. Planets orbiting the Sun, for example, or an automobile exiting a roadway are two instances.
The first angular velocity equation is similar to the linear velocity equation: = (2 - 1) / t = / t, where 1 and 2 are two values of angles on a circle, and is the difference between them. t is the time it takes for the angle to shift. As you can see, there is a ratio of the positional change in a period for normal velocity, but we utilise angle instead of distance here. Definition of angular velocity using linear velocity The second angular velocity formula, v = r, may be obtained from the linear velocity and radius relationship using the cross product.
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(Hope this helps can I pls have brainlist (crown)☺️)
During a collision, a 63.9-kilogram driver of a car moving at 24 m/s is brought to rest by an inflating airbag in 1.2 seconds. What is the magnitude of the force exerted on the driver by the airbag?
Hi there!
We can use impulse for this situation:
I = Δp = mΔv
Impulse = Force × time, so:
I = 63.9(24) = 1533.6 Ns
Find force by dividing by time:
I/t = 1533.6/1.2 = 1278 N
an astronomer looking out into space will observe that
Answer:
The farther out a galaxy is from Earth, the faster it is moving away.
Explanation:
A car traveling at 35.6m/s crashes into a concert barrier and comes to a stop in 0.35 seconds. Calculate the average force applied to the 75kg driver.A 3.2kg steel ball traveling at 4.1m/s strikes a second ball of a mass 2.3kg Initially at rest. Calculate the velocity of the second ball when the first one continues traveling in the same direction with a speed of 1.5m/s2 balls of putty are shot towards one another. Ball 1 has a mass of 4.3kg and is moving at 18.6m/s . Ball 2 has a mass of 5.8kg and is moving at 9.5m/s. They collide and stick together. Calculate their final combine velocity.I really appreciate those attempting the problems. I do know the answers but I’m unaware of the steps to get there. Please include all formulas in your response and steps so I can learn and understand.Check your answer:7629N3.6m/s2.46m/sThank you all!
The force on the driver is 7629 N. The velocity of the second ball is 3.6 m/s. The combined velocity of the balls is 13.37 m/s.
We have to find the acceleration using;
v = u - at
v = final velocity = 0 m/s
u = initial velocity = 35.6m/s
a = acceleration = ?
t = time = 0.35 s
u = at
a = u/t = 35.6m/s / 0.35 s
a = 101.7 ms-2
The force on the driver = 75kg × 101.7 ms-2 = 7629 N
Using the principle of conservation of momentum;
Momentum before collision = momentum after collision
m1u1 +m2u2 = m1v1 + m2v2
Hence
(3.2 × 4.1) + 0 = (3.2 × 1.5) + 2.3v2
13.12 = 4.8 + 2.3v2
13.12 - 4.8 = 2.3v2
v2 = 13.12 - 4.8/2.3
v2 = 3.6 m/s
Using the principle of conservation of linear momentum;
m1u1 + m2u2 = m1v1 + m2v2
(4.3 × 18.6) + (5.8 × 9.5) = (4.3 + 5.8) v
v = 79.98 + 55.1/10.1
v = 13.37 m/s
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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation:
Two towers of height 40 m and 30 m respectively support a transmission line conductor at water crossing. The horizontal distance between the towers is 300 m. If the tension in the conductor is 1590 kg, find the clearance of the conductor at a point mid-way between the supports. Weight of conductor is 0·8 kg/m. Bases of the towers can be considered to be at the water level.
The sag in the tensioned cable depends on the weight of the cable and
the applied tension.
The clearance midway between the support is approximately 29.34 metersReasons:
The given parameters are;
Height of the towers are; h₁ = 40 m and h₂ = 30 m
Horizontal distance between the towers, l = 300 m
The tension in the conductor, T = 1,590 kg
Weight of the conductor, w = 0.8 kg/m
Required:
The clearance space of the conductor mid-way between the support
Solution:
The distance, x₁, to the lowest point on the conductor, from the tower, h₁, is given by the formula;
[tex]\displaystyle x_1 = \mathbf{ \frac{l}{2} -\frac{T \cdot h}{w \cdot l}}[/tex]
Where;
h = h₂ - h₁ = 40 m - 30 m = 10 m
Which gives;
[tex]\displaystyle x_1 = \frac{300}{2} -\frac{1590 \times 10}{0.8 \times 300} = \mathbf{83.75}[/tex]
The sag at the lowest point is give by the formula;
[tex]\displaystyle d_1 = \mathbf{ \frac{W \cdot x_1^2}{2 \cdot T}}[/tex]
Therefore;
[tex]\displaystyle d_1 = \frac{0.8 \times 83.75^2}{2 \times 1590} = \frac{4489}{2544} \approx 1.765[/tex]
The lowest point sag, s₁ = 30 m - 1.765 m = 28.235 m
The distance of the midpoint from the lowest point, x, is therefore;
[tex]\displaystyle x = \frac{l}{2} - x_1 = \frac{300}{2} - 83.75 = \mathbf{ 66.25}[/tex]
Which gives;
[tex]\displaystyle d_x = \frac{0.8 \times 66.25^2}{2 \times 1590} = \frac{53}{48} \approx 1.104[/tex]
The clearance midway between the support ≈ 28.235 + 1.104 ≈ 29.34
The clearance midway between the support ≈ 29.34 m
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What water pressure must a pump that is located on the first floor supply to have water on the thirteenth of a building with a pressure of 35 lb/in2 Assume that the distance between each floors is 10ft.
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
Pressure on the 13 th floor, P₁ = 35 PSIDistance between each floor, d = 10 ftThe vertical pressure of the water is calculated as follows;
[tex]P = \rho gh\\\\\frac{P}{h} = \rho g\\\\\frac{P}{h} = k\\\\\frac{P_1}{h_1} = \frac{P_2}{h_2} \\\\[/tex]
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
[tex]P_1 = \frac{P_2 h_1}{h_2} \\\\P_1 = \frac{35 \times 130}{10} \\\\P_1 = 455 \ PSI[/tex]
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
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Tommy does 45 Joules of work to push the pencil over 3 meter. How much force did he use?
Answer:
Work = Force × Distance
Therefore Force = Work/Distance
= 45 joules/3 metres
= 15 newton
Explanation:
Answer:
15
Explanation:
15
What feature of a planet's orbit does Kelper's first law of motion describe?
A. the time required for each orbit
B. the shape
C. the distance from the aphelion to the perihelion
D. the distance to the sun
True or False: Objects fall at a constant speed.
Answer:
Explanation:
true
differential rotation is when a planet's equator and polar regions rotate at different rates. True False
in terms of the wavelength of the sound wave, about how far below the open end of the resonance tube is the first resonant position?
The first resonant position below the open end of the resonance tube is; one-quarter of the wavelength
In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.
However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.
This means that the standing wave will have one-quarter of the wavelength in the test tube.
Thus;
L = ¼λ
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a gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3 before returning to its initial state as shown in the figure below. how much work is done in one cycle?
The work done on the given gas in one cycle is -405.3 kJ.
The given parameters;
initial pressure of the gas, P₁ = 2 atmfinal pressure of the gas, P₂ = 6 atminitial volume of the gas, V₁ = 1 m³final volume of the gas, V₂ = 3 m³Convert the pressure to Pascal (N/m²);
1 atm = 101325
The work done in one cycle is the area of the triangle and it is calculated as follows
[tex]Area = \frac{1}{2} \times base \times height\\\\Area = \frac{1}{2} \times (3 \ m^3\ -\ 1 \ m^3)\times (6 \ atm \ - \ 2 \ atm)\\\\Area = 4 \ atm -m^3\\\\Area = 4 \ atm -m^3 \ \times \frac{101325 \ Pa}{1 \ atm} \\\\Area = 405,300 \ m^3.Pa\\\\Area = 405,300 \ m^3. (N/m^2)\\\\Area = 405,300 \ Nm\\\\Area = 405,300 \ J\\\\Area = 405.3 \ kJ[/tex]
the net work done on the gas = - 405.3 kJ
Thus, the work done on the given gas in one cycle is -405.3 kJ.
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someone throws a rubber ball vertically upward from the roof of a building 8.2m in height. the ball rises, then falls.it just misses the edge of the roof, and strikes the ground.if the ball is in the air for 6.2s, what was its initial velocity?(disregard air resistance. a=-g=-10m/s²
Answer:
H = V t - 1/2 g t^2 V and g are in different directions
-8.2 = V * 6.2 - 1/2 * 10 * 6.2*2 = 6.2 V - 192.2
V = 184 / 6.2 = 29.7 m/s
Check: find time for ball to return to zero height
0 = 29.7 T - 5 T^2
T = 29.7 / 5 = 5.94 sec
The ball must have fallen 8.2 m in (6.2 - 5.94) sec = .26 sec
S = 29.7 * .26 + 5 * .26^2 = 8.1
Calculate torque using angular momentum
Answer:
The equation net τ=ΔLΔt net τ = Δ L Δ t gives the relationship between torque and the angular momentum produced.
what tool had allowed scientists to learn about the characteristics of eaths layers???
Answer:
seismic waves
Explanation:
i think thats the answer
A campfire is a good example of all three types of heat transfer. The molecules of the fire touching the pot and heating it up is __________________. The air above the fire heating up, becoming less dense and rising is an example of _________________. All around the campfire you can feel the waves of heat because of _____________.
NO LINKS! What are the definitions of initial horizontal velocity and initial vertical velocity? Please help! This like is my 20th time asking this question because many people have been scamming me...
Answer:
answer
Explanation:
The initial horizontal velocity canbe determined by measuring the diameter of the ball and dividing by the time that it takes for the ball to move across the photogate. That is Vo = d/t.
When Vertical velocity refers to the speed of an object's movement in a vertical direction.
what are the three examples that show relation between pressure and area in daily life.
Answer: The area of the edge of a knife's blade is extremely small.
Syringes are used to take blood for blood tests.
When air is sucked out of a drinking straw, the air pressure inside if decreases and the atmospheric pressure outside forces the liquid to go inside the straw.
Explanation:
A car starts from rest and accelerates at 2.5m/s^2 for 2s. What is the final velocity of the car
Answer:
5m/s ez
Explanation:
plz make me brainliest
a girl on a bridge throws a rock straight down at -12.5 m/s. it hits the ground 38.4 m below. How much time did it take?
The acceleration of both the rocks is only due to the gravitational force acting on them. Even though the speed of thrown rock would be greater than that of dropped rock, the acceleration of both the rocks would be g downwards.
Answer:
1.80
Explanation:
38.4=-12.5(a)-1/2(-9.80)(a)^2
a= acceleration
^2 is the exponent
What is the ideal temperature for a lithium-ion battery?.
Answer:
16 to 25 degrees f
Explanation:
A chemist is studying an unknown substance and could break the substance into its elemental components only by using chemical means. Based on this observation, how should the unknown substance be classified?
A. impure substance
B. solution
C. mixture
D. pure substance
The answer is D
I took the quiz lol
Ten seconds after starting from rest, a freely-falling object will have a speed of about ________________________
Answer:
100 m/s
Explanation:
Speed increases at a rate of 10 m/s (actually 9.8 m/s) every second. Thus after 10 seconds, the speed is 10 x 10 = 100 m/s.
A ball is fired from a cannon at point 1 and follows the trajectory shown in the figure below. Air
resistance may be neglected. Five possible vectors are also shown in the figure; the letter E represents
the zero vector.
D
E:
C
B
a
Which vector best represents the ball's velocity at position 2?
Which vector best represents the ball's acceleration at point 2?
Which vector best represents the ball's velocity at position 3?
Which vector best represents the ball's acceleration at point 3?
du
b)
A
d)
In trajectory, acceleration vector is not the same with the velocity vector but it depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path. The Correct answers are:
a.) D
b.) B
c.) C
d.) A
A Vector is a quantity that has both magnitude and direction.
Given that a ball is fired from a cannon at point 1 and follows the trajectory shown in the figure.
a.) The vector best represents the ball's velocity at position 2 is D
b.) The vector best represents the ball's acceleration at point 2 is B
c.) Which vector best represents the ball's velocity at position 3 = C
d.) Which vector best represents the ball's acceleration at point = A
In trajectory, acceleration vector is not the same with the velocity vector but depends on the change in velocity. The acceleration path is perpendicular to the velocity vector path.
At point 3, since the ball path is parabolic, the velocity at that point is not equal to zero but will tend to take a horizontal path.
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What electromagnetic wave is used in nuclear research and mineral exploration?.
The electromagnetic wave used in nuclear research and mineral exploration are gamma rays.
Electromagnetic waves refer to those rays that are found in the electromagnetic spectrum. They are collectively called light. Electromagnetic waves are used for different purposes.
Gamma rays are useful in nuclear research especially in identifying decaying radionuclides. Also, gamma rays are used for geologic mapping, mineral exploration, and identification of environmental contamination.
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Agatha the snake is 50 centimeters long.3 years from now she will be 152 centimeters long and fully grown. If Agatha grows at constant rate, how much does she grow in length each year
Answer: 34cm each year
Explanation:
Where does the energy released in a nuclear decay reaction come from
A. Electrons
B. Chemical bonds
C. Positrons
D. The binding energy of the nucleus