When using the thin lens equation, what explains why the value for the focal length of a given lens doesn't change?


The object and image distance change inversely, but in the same ratio.

The specific material and shape of each lens determines how it refracts light rays.

The object and image distance always change in direct proportion.

The focal length is a universal constant.

Answer:

(a) α = - 1000 rad/s²

Negative sign represents deceleration.

(b) θ = 3581 rotations

(c) L = 1800 m

(d) a = - 80 m/s²  

Explanation:

(a)

using First equation of motion for angular motion:

ωf = ωi + αt

where,

ωf = Final Angular Speed = 2000 rad/s

ωi = Initial Angular Speed = 7000 rad/s

α = Angular Acceleration = ?

t = time = 5 s

Therefore,

2000 rad/s = 7000 rad/s + α(5s)

α = (2000 rad/s - 7000 rad/s)/5 s

α = - 1000 rad/s²

Negative sign represents deceleration.

(b)

Using second equation of motion:

θ = ωi t + (1/2)αt²

where,

θ = No. of Rotations = ?

Therefore,

θ = (7000 rad/s)(5 s) + (1/2)(- 1000 rad/s²)(5 s)²

θ = 35000 rad - 12500 rad

θ = (22500 rad)(1 rotation/2π rad)

θ = 3581 rotations

(c)

Length of String = L = (Circumference of Pulley)(θ)

L = [2π(0.08 m)][3581 rotations]

L = 1800 m

(d)

Tangential Acceleration = a = rα

a = (0.08 m)(-1000 rad/s²)

a = - 80 m/s²

Answer:

52.6 kg

Explanation:

KE = 1/2mv^2

400 = 1/2 x m x 3.9^2

m = 2(400 J)/ ( 3.9 m/s)^2

m = 52.6 kg

Answer:

The molten rock rises from cracks in the oceanic crust, so option B is correct.

The thinnest and most significant layer on our planet is its crust, which is made up of rocks and forms the planet's outermost layer. Despite making up less than 0.5 percent of the globe's total volume, it is essential to the majority of the natural cycles that take place all over the planet. The crust of the Earth is divided into layers, each of which contains a unique element.

Metamorphic rocks are defined as rocks that change into another rock. Sedimentary rocks are created by the deposition of material at the Earth's surface within water bodies, followed by cementation.

The crust that lies beneath land masses is known as the continental crust, whereas the crust that lies beneath the ocean's surface is known as the oceanic crust. The oceanic crust is younger and much thinner than the continental crust.

Therefore, the molten rock rises from cracks in the oceanic crust.

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Superposition is the most correct option

When two waves meet it is generally called inteference. Superposition occurs when the waves adds up to form a stronger wave. This is called constructive interference

hope this helps....

Impact force

Impact force is the force exerted by bodies when they come in contact. Impact force has same unit as force. it is similar to impulse the difference is that impulse considers time.

hope it helps...

Answer:

Explanation:

from highest to lowest frequency

gamma-ray, x-ray, ultraviolet, visible light, infrared, microwave, radio

hope this helps have a good day :)

The electromagnetic waves with the lowest frequencies are the ones we call "radio" waves.

The electromagnetic waves with the highest frequencies are the ones we call "gamma rays".

In between those are all the others . . . the microwaves, the heat ('thermal') waves, the infrared waves, the light waves, the ultraviolet waves, and the X-rays.

Answer:

The distance covered is: 824.74 meters

Explanation:

Use the formula for velocity (v) as the distance (d) covered over the time (t) it took:

v = d / t

in our case:

6.02 m/s = d / 137 s

d = 6.02 * 137 = 824.74 meters

Answer:

The two balls pass each other at a height of 5.53 m

vf1=17.97 m/s

vf2=-5.96 m/s

Explanation:

Vertical Motion

An object thrown from the ground at speed vo, is at a height y given by:

[tex]y=vo.t-g.t^2/2[/tex]

Where t is the time and [tex]g=9.8\ m/s^2[/tex]

Furthermore, an object dropped from a certain height h will fall a distance y, given by:

[tex]y=g.t^2/2[/tex]

Thus, the height of this object above the ground is:

[tex]H = h-g.t^2/2[/tex]

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.

We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

[tex]vo.t-g.t^2/2=h-g.t^2/2[/tex]

Simplifying:

[tex]vo.t=h[/tex]

Solving for t:

[tex]t=h/vo=22/12=1.833\ s[/tex]

The height of ball 1 is:

[tex]H = 22-9.8.(1.833)^2/2[/tex]

H = 5.53 m

The height of ball 2 is:

[tex]y=12\cdot(1.833)-9.8\cdot(1.833)^2/2[/tex]

y=5.53 m

As required, both heights are the same.

The speed of the first ball is:

[tex]vf1=g.t=9.8\cdot 1.833=17.97\ m/s[/tex]

vf1=17.97 m/s

The speed of the second ball is:

[tex]vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s[/tex]

vf2=-5.96 m/s

This means the second ball is returning to the ground when both balls meet

Answer:

The person's hand will warm up the jar

Explanation:

Thermal energy will be conducted from his hand to the jar

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 600 N

distance = 4 m

We have

work done = 600 × 4

We have the final answer as

Hope this helps you

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\ [/tex]

From the question we have

[tex]volume = \frac{100}{50} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Answer:

a feat

Explanation:

cause the mf already 7ft on the dot there is no such thing as 6 ft 12

The range of frequencies  of visible light in a vacuum is mathematically given as

Fmin=4.19*10^14Hz  to Fmax=1*10^15Hz

Question Parameters:

The wavelengths of visible light vary from about 300 nm to 700 nm.

Generally, the equation for the frequency   is mathematically given as

F=C/\lambda

Therefore

For Fmax

[tex]Fmax=\frac{300*10^8}{3*10^9}[/tex]

Fmax=1*10^15Hz

Where

[tex]Fmin=\frac{3*10^8}{700*10^9}[/tex]

Fmin=4.19*10^14Hz

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Answer:

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest. ... The gravitational pull of the sun and moon on the earth also causes waves.

First calculate a, the acceleration of the plane, given by the equation;

[tex] \alpha = \frac{vf - vi}{t} = \frac{100 - 40}{10} = \frac{60}{10} = 6[/tex]

The use the relation given by

Vf²-Vi²=2ad

[tex]d = \frac{100 {}^{2} - 60 {}^{2} }{2 \times 6} = \frac{10000 - 3600}{12} = \frac{6400}{12} = 533.33 \: meters[/tex]

Answer:

25 kg m^2/s

Explanation:

The angular acceleration due to the application of torque to the grinding wheel is:

[tex]\tau=I\alpha \rightarrow \alpha=\frac{2.5}{2}=1.25[/tex] (in radian per square second)

So, by the basic equation of the angular acceleration, we can get the angular velocity at t = 10 s as follows:

[tex]\omega=\omega_{o}+\alpha t \rightarrow \omega =0+(1.25)(10) =12.5[/tex] rad/s.

So, the angular momentum at t = 10 s:

[tex]L=I\omega=(2)(12.5) = 25[/tex]  kg m^2/s

Answer:

Asalamalikum maryam

Following are the characteristics that help to distinguish between man's and women's voice

Answer:

Explanation:

How many atoms of each element are present in the formula for bromoethane

Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at

while the Invalid expressions are;  v = a/t and  d = at

Explanation:

Given expressions

1) v = a/t

2) t = ∛(d²/va)

3) d = at

4) a = d/t²

5) a = √(vd/t³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/s²

so

1)

v = a/t

we substitute in our units of parameters

v = m/s² / s = m/s² × 1/s = m/s³

v ≠ m/s³

therefore it is false

2)

t = ∛(d²/va)

we substitute

t = ∛(m² / m/s × m/s²)

t = ∛(m² / m²/s³)

t = ∛(s³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/s² × s

d = m/s² × s/1 =  ms/s² = m/s

d ≠ m/s (because d = m)

so expression is false

4)

a = d/t²

we substitute

a = m / s² = m/s²

correct

the expression is true

5)

a = √(vd/t³)

we substitute

a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³)  = √(m²/s⁴) = m/s²

so a = m/s²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/s² × s = m/s² ×s/1 = ms/s² = m/s

v = m/s

correct

the expression is correct

Answer:

30 j

Explanation:

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The kinetic energy of an object is 50 J, and the potential energy is 20 J. The total energy of the object is 30J.

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Answer:

value is obtained than the real one.

        ρ >  ρ_real

Explanation:

A widely used method to determine the density of a body is to measure its mass and measure its volume by immersing it in a transparent liquid, to measure its volume by the difference in volumes of the liquid then use the relationship

        ρ = m / V

In this case, part of the body remains the force of the liquid, in this case using Archimedes' principle that establishes that the weight of the desalted liquid is equal to the thrust, let's use the equilibrium equation

              B - W = 0

              B = W

              ρ_liquid  g V_submerged = ρ_body g V_body

              V_submerged = (ρ_body /ρ-liquid)   V_body

We can see that the volume is only a fraction of the volume of the body, therefore when performing the division a higher value is obtained than the real one.

Answer:

We are given:

u = 2.5 m/s

a = 0.2 m/s/s

t = 25 seconds

v = v m/s

Solving for 'v':

From the first equation of motion:

v = u + at

Replacing the values

v = 2.5 + (0.2)(25)

v = 2.5 + 5

v = 7.5 m/s

Answer:

Destructive interference

Explanation:

Destructive interference occurs when two waves traveling along the same medium meet and cancel each other out. The resultant wave has a smaller amplitude than the individual waves. In this case, the maxima of two waves are 180 degrees out of phase.

Hence, the correct option is (A) "destructive interference"

Answer: the answer is A. Destructive inference

Explanation: I took the test

Answer:

All of Above

Explanation:

Answer:

the speed of the cheetah at the end of the 3 seconds is: 19.5 m/s

Explanation:

Let's use the equation that relates speed with acceleration:

vf = vi + a * t

where vf stands for final velocity, vi stands for initial velocity, a for acceleration, and t for the time acceleration is applied. Then, in our case we have:

vf = 0 + 6.5 (3)

vf = 19.5 m/s

Answer:

0.5 amps

Explanation:

the amps will be constant no matter what

Answer:

Using Newton's second law of motion;

F=ma

25=0.25a

a=25/0.25=100 m/s²

After 20 minutes;

Vf=at+Vi

Vf=100(1200)+0

Vf=120000 m/s

d=at²/2 +Vi×t

d=100(1200)²+0

d=144 000 000 meters

Answer:

a)   m =1  θ = sin⁻¹  λ  / d,  m = 2        θ = sin⁻¹ ( λ  / 2d) ,   c)     m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

         d sin θ = m λ

the maximum for m = 1 is at the angle

          θ = sin⁻¹  λ  / d

the second maximum m = 2

          θ = sin⁻¹ ( λ  / 2d)

the third maximum m = 3

        θ = sin⁻¹ ( λ  / 3d)

the fourth maximum m = 4

       θ = sin⁻¹ ( λ  / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

       I = I₀ cos² (Ф) (sin x / x)²

       Ф = π d sin θ /λ

       x = pi a sin θ /λ

where a is the width of the slits

with the values ​​of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference       d sin θ = m λ

first diffraction minimum    a sin θ = λ

we divide the two expressions

                       d / a = m

In our case

                   3a / a = m

                    m = 3

order three is no longer visible

(a)  The next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

(b)   With the values ​​of part a are the expression of intensity of each maximum can be calculated accordingly.

(c)   The third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

a)

In the interference phenomenon the maxima are given by the expression

d sin θ = m λ

Here,

d is the slit separation and m is the order of interference.

The maximum for m = 1 is at the angle is,

θ = sin⁻¹  λ  / d

For the second maximum m = 2

θ = sin⁻¹ ( λ  / 2d)

For the third maximum m = 3

θ = sin⁻¹ ( λ  / 3d)

For the fourth maximum m = 4

θ = sin⁻¹ ( λ  / 4d)

Thus, we can conclude that the next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

b)

Considering the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

I = I₀ cos² (Ф) (sin x / x)²

Where Ф is the phase angle, and its value is,

 Ф = π d sin θ /λ

x = π  a sin θ /λ

Here a is the width of the slits

Thus, with the values ​​of part a are introduced in the expression the  intensity of each maximum can be calculated accordingly.

c)

The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present.

For the maximum interference:        

d sin θ = m λ

For the first diffraction minimum:    

a sin θ = λ

Dividing both the expressions as,

d / a = m

Since, d = 3a. Then,

3a / a = m

m = 3

Thus, we can conclude that the third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

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Answer:

I think it's just 100+70+140