Which event most likely occurs at point v? cooling erosion heating melting

Answers

Answer 1

The event which most likely occurs at point V during a rock cycle is cooling.

What is point V?

Point V is present in the rock cycle, where changes in the state or nature of rock takes place.

When mangma comes towards the surface of the earth then due to change in temperature and pressure it will concerts into the igneous rock by cooling process and coverts into the harder form.

Hence at point V, colling is occur.

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Answer 2

Answer:

A. cooling

Explanation:

edge 22'


Related Questions

Please help me................I beg you.........

Answers

Answer:

the problem is that Gary is not the smartest snail.the hypothesis is that he thinks he can get smarter by eating super snail food everyday.

hope this helps

Which energy is required when we convert an atom into an ion?

Select one:

O a. ionization energy

O b. electron affinity

O c. binding energy

O d. electronegativity

Answers

Answer:

ionization energy is the answer

A(n) ____________ acts to maintain a relatively stable concentration of hydrogen ions in a solution.

Answers

Answer:

buffer

Explanation:

i would Luke to ??​

Answers

Answer:

1 answer

Explanation:

Distinguish between electron affinity and electronegativity

Answers

The main difference between electronegativity and electron affinity is that electronegativity is the ability of an atom to attract electrons from outside as far as electron affinity is the amount of energy an atom receives when an electron. Electron negativity is applied to a single atom.

Essential Question: How will the weight of a grape change if you put it in cold and room temperature water? Can someone please help me come up with a claim for my Essential question?

Answers

Answer:

bc the water molecules freeze

Please help brainiest is award.

Answers

Answer:

2 i think if not than its 4

Explanation:

Answer:

3 if its not than 4

Explanation:

A reversible process is one that ________
[A] must be carried out at high temperature
[B] must be carried out at low temperature
[C] happens spontaneously
[D] can be reversed with no net change in either system or surroundings
[E] is spontaneous in both directions

Answers

Answer:

[D]can be reversed with no net change in either system or surroundings

A reversible process is one that can be reversed with no net change in either system or surroundings. Therefore, option (D) is correct.

What are reversible reactions?

A thermodynamic process can be reversible if the process can be turned back to both the system and the surroundings to return to their original states, with no other change in the universe.

No such processes as reversible processes can exist and these processes can easily be defined as idealizations or models of real processes.

A few examples of Reversible Processes: are the extension of springs, slow adiabatic compression or expansion of gases, electrolysis, the frictionless motion of solid, slow isothermal compression or expansion of gases

An irreversible process is a process in which the system and the surroundings do not return to their actual condition once the process is initiated. Examples of irreversible processes are Heat transfer, Diffusion, and electricity flow through a resistance.

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Any 1 might help the 1 below but if it's not there, just comment

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Your Q is not visible .Plz provide it

2. D, because transition metals have a high density.

3. B, because the properties of elements depend on the valence electrons.

4. C, because the atom emits a negatively charged electron, the atom becomes positively charged.

5. D, because hydrogen and helium are both lighter than air, but hydrogen is very reactive, that's why helium is used.

6. A, because it creates caustic soda.

7. C, because only fluorine and argon are gases, but argon is not two-molecular.

8. C, because iodine is either solid or gaseous. Solid iodine is gray and gaseous iodine is purple.

9. C, because all elements of the first main group have an odd number of protons and react violently with water.

10. D, because oxygen is air. Nitrogen is very reactive and helium is lighter than air.

11. A, because carbon has atomic number 6 and magnesium has atomic number 12.

12. B, because table salt is sodium chloride.

13. B, because sodium ions and neon have the same electron configuration.

14. C, because chloride ions and argon have the same electron configuration.

15. C, because calcium ions and argon have the same electron configuration.

16. D

17. C, because silicon has 4 valence electrons and a total of 14 electrons.

18. A

19. B, because it's sodium.

20. Number of protons and electron shells

21. first main group

22. seventh main group

23. cesium

24. fluorine

25. alkali metals

26. alkaline earth metals

27. halogens

28. from metal to nonmetal

29. valence electrons

30. electron shells

31. main group and subgroup

32. semi-metal

33. 18 groups and 7 periods

34. groups

35. periods

When the following equation is balanced:
Al + NiSO4 ® Al2(SO4)3 + Ni
the correct set of coefficients would be:

Answers

Answer:

2Al + 3NiSO4 -> Al2(SO4)3 + 3Ni

Explanation:

You just had to balance the equation by looking at Al2(SO4)3. It helps to pick the right coefficients for other components.

The correct set of coefficients for the balanced equation is: 2, 3, 1, 3.

When balancing the equation:  2Al + 3NiSO₄ → Al₂(SO₄)₃ + 3Ni .The coefficients indicate the number of each compound or element required for the equation to be balanced. In this case, the equation is balanced by ensuring that the number of atoms of each element is the same on both sides of the equation.

By placing the coefficients 2 and 3 in front of Al and NiSO₄, respectively, it ensures that there are an equal number of aluminum and nickel atoms on both sides. Additionally, the coefficient 3 in front of Ni and Al₂(SO₄)₃ ensures an equal number of nickel and sulfate groups.

Balancing equations is important because it follows the principle of conservation of mass, ensuring that no atoms are gained or lost during a chemical reaction. The set of coefficients chosen allows for the equation to meet this principle and maintain a balanced representation of the chemical reaction.

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Can some one please help

Answers

Answer:

Chadwick-he discovered the neutron. He discovered this by demonstrating a neutral particle with a mass the same as a proton through a reaction between gramma Ray's and a wax sample.

Rutherford-he discovered the concept of radioactive half-life, the radioactive element radon, and named alpha and beta radiation.

j.j.Thompson discovered that atoms where made up of smaller components. This had major effects for the field of physics.

:)

Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kj of heat. the bomb calorimeter has a mass of 1.30 kg and a specific heat of 3.41 j/(gi°c). if the initial temperature of the calorimeter is 25.5°c, what is its final temperature? use q equals m c subscript p delta t.. 30.9°c 34.5°c 44.0°c 51.5°c

Answers

The final temperature of the bomb calorimeter is 30.9°C.

What is combustion reaction?

Combustion reactions are those reactions in which a compound completly decompose in to carbon dioxide and water molecule.

The final temperature will be calculated by using the equation:

Q = mc(T₂ – T₁), where

Q = relesed heat from calorimeter = 24kJ = 24000J

m = mass of calorimeter = 1.30kg = 1300g

c = specific heat of calorimeter = 3.41 J/(g°C)

T₁ = initial temperature of calorimeter = 25.5°C

T₂ = final temperature of calorimeter = to find?

On putting all these values on the above equation and calculate for T₂, we get

T₂ = 24000/(1300)(3.41) + 25.5

T₂ = 30.9°C

Hence, correct option is (1) i.e. 30.9°C.

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Answer:

30.9

Explanation:

right on edge 2022

how many carbon monoxide molecules are in .75 moles of carbon dioxide? just need answer

Answers

Answer:

A standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.

All the data is given in the question and these are as follows:-

Moles - 0.75

Na - 6.022*10^{23

The formula we are using to find the molecules is as follows:-

n = \frac{molecule}{Na}n=

Na

molecule

After, putting the value and solving it. we will get

0.75 * 6.022*10^2^3 = 4.5165*10^{23

How do you use Reference Point in Science

Answers

Explanation:

A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. Objects that are fixed relative to Earth – such as a building, a tree, or a sign - make good reference points.

weaving nearly died out because factories can make fabrics faster than people who create them by hand. question 2 options:

true OR false​

Answers

Answer:

True

Explanation:

A hand weavers would take much more time in their craft than large factories did, their industry began to decline and be replaced by industrial machines.

A car with a mass of 700 kg is moving with a speed of 20m/s.
Calculate the kinetic energy of the car.

Answers

Answer:

The answer is 140,000 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]KE = \frac{1}{2} m {v}^{2} \\ [/tex]

where

m is the mass

v is the velocity

From the question we have

[tex]KE = \frac{1}{2} \times 700 \times {20}^{2} \\ = 350 \times 400[/tex]

We have the final answer as

140,000 J

Hope this helps you

How does temperature, pressure, and density impact the core of the Earth?

Answers

Answer:

temperatures within the outer core range from 7,200 to 9,000 F. Pressure also increases in the outer core due in part to the weight of the crust and mantle above.The Earth's magnetic field is generated by the outer core.

Explanation:

what would the formula be if the products RbCI decomposed

Answers

A decomposition reaction occurs when one reactant breaks down into two or more products. It can be represented by the general equation: AB → A + B. In this equation, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction.

RbCI = rubidium chloride

What is the volume of an unknown object that has a mass of 5.0 g and density of 4.5 g/mL ?

Answers

I think it may be 1.11 but I may be wrong

What’s the type of reaction and word equation for: C2H6O+2O2= 2CO2 + 3H2O

Answers

Answer:

Ethenol + Oxygen = water + Carbon Dioxide C2H5OH + 3O2 = 2CO2 + 3H2O

Explanation:

plzzzz ...... Why is the result of CO2 bonds zero?​

Answers

Answer:

this is right because carbon and oxygen complete its octet

The C-O bonds in carbon dioxide are polar and yet the dipole moment is zero because the 2 bond dipoles cancel each other.

PLEASE HELP ME!!


Write formulas for the following compounds:

a. lithium fluoride, lithium chloride, lithium bromide, lithium iodide, lithium oxide, lithium sulfide

b. sodium fluoride, sodium chloride, sodium bromide, sodium iodide, sodium oxide, sodium sulfide

c. potassium fluoride, potassium chloride, potassium bromide, potassium iodide, potassium oxide, potassium sulfide

d. ammonium fluoride, ammonium chloride, ammonium bromide, ammonium iodide, ammonium sulfide

Answers

Answer:

a).

lithium fluoride => LiF

lithium chloride =>LiCl

lithium bromide => LiBr

lithium iodide => Lil

lithium oxide =>Li₂O

lithium sulfide => Li₂

b).

sodium fluoride => NaF

sodium chloride => NaCl

sodium bromide => NaBr

sodium iodide => Nal

sodium oxide => Na₂O

sodium sulfide => Na₂S

c).

potassium fluoride => KF

potassium chloride => KCl

potassium bromide => KBr

potassium iodide => KI

potassium oxide => K₂O

potassium sulfide => K₂S

d).

ammonium fluoride =>NH₄F

ammonium chloride => NH₄Cl

ammonium bromide => NH₄Br

ammonium iodide => NH₄I

ammonium sulfide => (NH₄)₂S

Can somebody list only 2 ways whales are different from fish?
(Make it only like 1 sentence)
(WILL MARK BRAINLIEST)
:D

Answers

Answer:

1. whales  are mammals and fish are not

2. Fish have gills which extract oxygen from the water and thus allow it to live underwater its entire life. Whales on the other hand do not have gills but instead have one or two blowholes

3. whales provide milk to their young and fish do not!

Explanation:

The diagram shows two molecules (A and B) with different
rates of travel on silica gel plate. Which method of separation
would be most effective to separate a mixture of A and B?

Answers

Answer: chromatography

Explanation:

How much heat is absorbed when a 10.0-g sample of water is changed from 23.0⁰C to 32.0⁰C?

Answers

Answer:

376.56J

Explanation:

The amount or quantity of heat absorbed can be calculated using the formula:

Q = m × c × ∆T

Where; Q = amount of heat absorbed (J)

m = mass of water (g)

c = specific heat capacity of water (J/g°C)

∆T = change in temperature (°C)

According to the provided information in this question; m = 10.0g, c = 4.184J/g°C, final temperature = 32°C, initial temperature = 23°C

Q = m × c × ∆T

Q = 10 × 4.184 × (32 - 23)

Q = 41.84 × 9

Q = 376.56J

What is the chemical equations for: Steam to
hydrogen using buring magnesium.

Answers

[tex]\huge\bold\red{Answer:-}[/tex]

It’s the same as when magnesium reacts with liquid water, only faster:

Mg + 2H₂O → MgO + H₂.

The difference is that in water, the reaction has a second step, converting MgO to Mg(OH)₂.

HOPE IT HELPS♥

how many millimoles of solid naoh must be added to 50.0 milliliters of 0.20 molar hocl to obtain a buffewr solution that has a ph of 7.49

Answers

The amount of millimoles of solid naoh that must be added to 50.0 milliliters is: 5.0 mmol of NaOH.

Millimoles of solid naoh

The [H+] at pH 7.49 is:

[H+] = 10–^7.49

[H+]= 3.24×10–^8 M

And when the solution is half-neutralized pH will be:

pH = pKa while  [OCl– ]÷[HOCl] = 1

Now let find the millimoles of solid naoh:

0.20 mol HOCl÷1 L× 50.0 mL

= 10.0 mmol HOCl

Half of 10.0 mmol HOCl will be added

Millimoles of solid naoh=10.0 mmol HOCl÷2

Millimoles of solid naoh= 5.0 mmol of NaOH

Inconclusion the amount of millimoles of solid naoh that must be added to 50.0 milliliters is: 5.0 mmol of NaOH.

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-
use the following equation for the combustion of methane gas.
ch4(8) + 202(g) → co2(g) + 2h2o(1)
in a certain reaction at stp, 29.2 l of methane is combusted
with 63.3 l of oxygen.
what volume of excess reactant remains after the reaction is
complete?
lo2

Answers

Considering the definition of STP conditions and reaction stoichiometry, the volume of excess reactant that remains after the reaction is complete is 4.928 L.

Definition of STP condition

The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.

Reaction stoichiometry

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CH₄: 1 mole O₂: 2 moles  CO₂: 1 mole H₂O: 2 moles

Volume of excess reactant

You know that in a certain reaction at STP, 29.2 L of methane CH₄ is combusted with 63.3 L of oxygen O₂.

Considering the definition of STP, you can apply the following rules of three:

if by definition of STP conditions 22.4 liters are occupied by 1 mole of methane, 29.2 L are occupied by how many moles of methane?

[tex]amount of moles of methane=\frac{29.2 Lx1 mole}{22.4 L}[/tex]

amount of moles of methane= 1.30 moles

if by definition of STP conditions 22.4 liters are occupied by 1 mole of oxygen, 63.3 L are occupied by how many moles of oxygen?

[tex]amount of moles of oxygen=\frac{63.3 Lx1 mole}{22.4 L}[/tex]

amount of moles of oxygen= 2.82 moles

Now you can apply the following rule of three to determine the excess reagent: if by stoichiometry 2 moles of O₂ reacts with 1 mole of CH₄, if 2.82 moles of O₂ react, how much moles of CH₄ will be needed?

[tex]moles of CH_{4} =\frac{2.82 moles of O_{2}x 1 moles of CH_{4}}{2 moles of O_{2}}[/tex]

moles of CH₄= 1.41 moles

But 1.41 moles of CH₄ are not available, 1.30 moles are available. Since you have less moles than you need to react with 2.82 moles of O₂, methane CH₄ will be the limiting reagent. And oxygen O₂ is excess reagent.

Now you can apply the following rule of three to the amount of O₂ that reacts when the limiting reactant reacts completely: if by stoichiometry 1 mole of CH₄ reacts with 2 moles of O₂, if 1.30 mole of CH₄ react, how much moles of O₂ will be needed?

[tex]moles of O_{2} =\frac{2 moles of O_{2}x 1.30 moles of CH_{4}}{1 moles of CH_{4}}[/tex]

moles of CH₄= 2.60 moles

So, after the reaction is complete, the moles of excess reactant that remains are calculated as:

2.82 moles - 2.60 moles= 0.22 moles

Finally, considering the definition of STP, you can apply the following rule of three: if by definition of STP conditions 1 mole of O₂ occupies a volume of 22.4 liters, 0.22 moles occupies how much volume?

[tex]volume=\frac{0.22 molesx22.4 L}{1 mole}[/tex]

volume= 4.928 L

In summary, the volume of excess reactant that remains after the reaction is complete is 4.928 L.

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The bond line formula,
represents the molecular formula
B
A
C8H18
C8H15

Answers

A. Is the answer C8H15

Answer:

C8H18

Explanation:

Identify the products of the complete combustion of methane. ............................................................... and ...............................................................

Answers

carbon(iv) oxide and water.

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