Which function has the domain x greater-than-or-equal-to negative 11?

Answer:

b. S = AUB

Step-by-step explanation:

Since the coins are tossed  3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8

All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT

So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}

Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT

So, B = {TTT}

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪  {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S

So, S = A ∪ B

So, S = A ∪ B does not denote an abuse of notation.

The answer is b.

Answer:

2/8 because each 1/4 0f the 8 slices is equal to 2/8 by multipliction or you can say 1/4 of 8

Answer:

2/8

Step-by-step explanation:

1/4

times everything by 2 as 8 / 4 = 2

2/8

Answer:

[tex] x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]

Step-by-step explanation:

Since, given is a 30°-60°-90° triangle.

[tex] \therefore \sqrt 7 = \frac{\sqrt3}{2} \times x[/tex]

[tex] \therefore 2\sqrt 7 = \sqrt3 \times x[/tex]

[tex] \therefore x=\frac{2\sqrt 7}{\sqrt 3}[/tex]

[tex] \therefore x=\frac{2\sqrt 7(\sqrt 3)}{\sqrt 3(\sqrt 3)}[/tex]

[tex] \huge \therefore x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]

Answer:

[tex](g + f)(8) =133[/tex]

Step-by-step explanation:

Given

[tex]g(n) = 3n - 5[/tex]

[tex]f(n) = n^2 + 50[/tex]

Required

[tex](g + f)(8)[/tex]

This is calculated as:

[tex](g + f)(n) =g(n) + f(n)[/tex]

So, we have:

[tex](g + f)(n) =3n - 5 + n^2 +50[/tex]

[tex]Substitute[/tex] 8 for n

[tex](g + f)(8) =3*8 - 5 + 8^2 +50[/tex]

[tex](g + f)(8) =24 - 5 + 64 +50[/tex]

[tex](g + f)(8) =133[/tex]

Answer:

[tex]L =21.945[/tex] --- Length

[tex]W = 7.9725[/tex] --- Width

Step-by-step explanation:

Given

Let

[tex]L \to Length[/tex]

[tex]W \to Width[/tex]

So:

[tex]Area = 175[/tex]

[tex]L = 6 + 2W[/tex]

Required

The dimension of the rectangle

The area is calculated as:

[tex]Area =L*W[/tex]

This gives:

[tex]175 =L*W[/tex]

Substitute: [tex]L = 6 + 2W[/tex]

[tex]175 =(6 + 2W)*W[/tex]

Open bracket

[tex]175 =6W + 2W^2[/tex]

Rewrite as:

[tex]2W^2+ 6W -175 = 0[/tex]

Using quadratic formula:

[tex]W = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

This gives:

[tex]W = \frac{-6 \± \sqrt{6^2 - 4*2*-175}}{2*2}[/tex]

[tex]W = \frac{-6 \± \sqrt{1436}}{2*2}[/tex]

[tex]W = \frac{-6 \± 37.89}{4}[/tex]

Split

[tex]W = \frac{-6+ 37.89}{4}, W = \frac{-6- 37.89}{4}[/tex]

[tex]W = \frac{31.89}{4}, W = \frac{-43.89}{4}[/tex]

The width cannot be negative;

So:

[tex]W = \frac{31.89}{4}[/tex]

[tex]W = 7.9725[/tex]

Recall that:

[tex]L = 6 + 2W[/tex]

[tex]L =6 + 2 * 7.9725[/tex]

[tex]L =21.945[/tex]

Answer:

Step-by-step explanation:

Let Terri spent the 'x' hours in the river,

Per hour rental charged by Timmy's Tubes = [tex]\frac{\text{Rental charged}}{\text{Hours spent}}[/tex]

                                                                        = [tex]\frac{18.75}{2.5}[/tex]

                                                                        = $7.5

Charges for 'x' hours = $7.5x

Therefore, function that defines the rental of Timmy's tube will be,

f(x) = 7.5x

Another company Fred's float charges a base fee $2 plus $6.25 per hours.

For 'x' hours Fred's float will charge = 6.25x + 2

And the function that defines the charges will be,

g(x) = 6.25x + 2

1). If x = 1.5 hours,

Rental charged by Timmy's tube,

f(1.5) = 7.5(1.5)

        = $11.25

Rental charged by Fred's float,

g(1.5) = 6.25(1.5) + 2

         = $11.375

2). If Terri has $12 to spend,

For f(x) = 12,

12 = 7.5x

x = 1.6 hours

For g(x) = 12

12 = 6.25x + 2

10 = 6.25x

x = 1.6 hours

Therefore, both the companies charge the same for 1.6 hors.

Terri can opt any company to spend $12.

Answer:

Graph A (first graph from top to bottom)

Step-by-step explanation:

Given [tex]f(x)=x^3-3x^2-4x+12[/tex], since the degree of the polynomial is 3, the function must be odd and will resemble the shown shape in the graphs. The degree of 3 indicates that there are 3 zeroes, whether distinct or non-distinct. Therefore, the graph must intersect the x-axis at these three points.

Factoring the polynomial:

[tex]f(x)=x^3-3x^2-4x+12,\\f(x)=(x+2)(x-2)(x-3),\\\begin{cases}x+2=0, x=-2\\x-2=0, x=2\\x-3=, x=3\end{cases}[/tex]

Thus, the three zeroes of this function are [tex]x=-2, x=2, x=3[/tex] and the graph must intersection the x-axis at these points. The y-intercept of any graph occurs when [tex]x=0[/tex]. Thus, the y-coordinate of the y-intercept is equal to [tex]y=0^3-3(0^2)-4(0)+12,\\y=12[/tex] and the y-intercept is (0, 12).

The graph that corresponds with this is graph A.

Answer:

4:15 p.m.

Step-by-step explanation:

There's something missing in this:

Once it started, the movie lasted for 1 hour and minutes. What time was it when the movie ended?

What is the minutes because thats missing.

Also can I get Brainliest please

Answer:

5 units

Step-by-step explanation:

Center of the circle = (-3, 2)

Point on the circle = (1, 5)

Radius of the circle will be equal to the distance between the points (-3, 2) & (1, 5)

[tex] \therefore \: radius \: of \: the \: circle \\ = \sqrt{ {( - 3 - 1)}^{2} + {(2 - 5)}^{2} } \\ = \sqrt{ {( - 4)}^{2} + {( - 3)}^{2} } \\ = \sqrt{16 + 9} \\ = \sqrt{25} \\ \therefore \: radius \: of \: the \: circle = 5 \: units[/tex]

Answer:

2806

Step-by-step explanation:

→ First complete the multiplication

456 × 6 = 2736 and 35 × 2 = 70

→ Add the totals

2736 + 70 = 2806

Answer:2806

Step-by-step explanation:

^﹏^

The original table (attached to this response) shows single values as classes.

To construct a new frequency distribution for this data with 4 classes, follow these steps:

i. Starting from the least value (which is 10) create groups each of 4 values. For example, the first group will contain 10, 11, 12 and 13. Therefore, we have a class of 10 - 13.

The second group will contain 14, 15, 16 and 17. Therefore, we have a class of 14 - 17

The third group will contain 18, 19, 20 and 21. Therefore, we have a class of 18 - 21

ii. Get the frequency of these classes, we add the frequencies of the members of the class.

For example,

Class 10 - 13 will have a frequency of (1 + 3 + 7 + 18) = 29

Class 14 - 17 will have a frequency of (10 + 4 + 2 + 7) = 23

Class 18 - 21 will have a frequency of (16 + 10 + 6 + 2) = 34

The new table has been attached to this response.

Work Shown:

area of the triangle on the left = base*height/2 = 0.75*2/2 = 0.75

area of the triangle on the right = base*height/2 = 0.5*4/2 = 1

total area = 0.75+1 = 1.75 square feet

Answer:

8 3 -2 -7

Step-by-step explanation:

becoz the y values are the ranges of the function

Answer:

{y: y = –7, –2, 3, 8}

Answer: x^2+12=x+4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Intervals are always x values. When x = 5, y = 4 (look at the graph to se this); when x = 6, y = 2. The rate of change is the same thing as the slope. We can't get an exact slope here because this isn't a straight line, but we can find the average rate of change. We use the slope formula to do this: with the coordinates (5, 4) and (6, 2):

[tex]m=\frac{2-4}{6-5}=\frac{-2}{1}=-2[/tex]. Third choice down is the one you want.

Answer:

1800 ml of oil

Step-by-step explanation:

300*6

Answer:

We can conclude that her walking speed is 2.1 miles per hour.

Step-by-step explanation:

We have the relation:

Speed = distance/time.

Here we know:

She walked for 44 miles.

And she ran along the same route, so she ran for 44 miles.

The total time of travel is 22 hours, so if she ran for a time T, and she walked for a time T', we must have:

T + T' = 22 hours.

If we define: S = speed runing

                     S' = speed walking

Then we know that:

"and she ran 33 miles per hour faster than she walked."

Then:

S = S' + 33mi/h

Then we have four equations:

S'*T' = 44 mi

S*T = 44 mi

S = S' + 33mi/h

T + T' = 22 h

We want to find the value of S', the speed walking.

To solve this we should start by isolating one of the variables in one of the equations.

We can see that S is already isoalted in the third equation, so we can replace that in the other equations where we have the variable S, so now we will get:

S'*T' = 44mi

(S' + 33mi/H)*T = 44mi

T + T' = 22h

Now let's isolate another variable in one of the equations, for example we can isolate T in the third equation to get:

T = 22h - T'

if we replace that in the other equations we get:

S'*T' = 44mi

(S' + 33mi/h)*(  22h - T') = 44 mi

Now we can isolate T' in the first equation to get:

T' = 44mi/S'

And replace that in the other equation so we get:

(S' + 33mi/h)*(  22h -44mi/S' ) = 44 mi

Now we can solve this for S'

22h*S' + (33mi/h)*22h + S'*(-44mi/S')  + 33mi/h*(-44mi/S') = 44mi

22h*S' + 726mi - 44mi - (1,452 mi^2/h)/S' = 44mi

If we multiply both sides by S' we get:

22h*S'^2 + (726mi - 44mi)*S' - (1,425 mi^2/h) = 44mi*S'

We can simplify this to get:

22h*S'^2 + (726mi - 44mi - 44mi)*S' - (1,425 mi^2/h) = 0

22h*S'^2 + (628mi)*S' - ( 1,425 mi^2/h) = 0

This is just a quadratic equation, the solutions for S' are given by the Bhaskara's equation:

[tex]S' = \frac{-628mi \pm \sqrt{(628mi)^2 - 4*(22h)*(1,425 mi^2/h)} }{2*22h} \\S' = \frac{-628mi \pm 721 mi }{44h}[/tex]

Then the two solutions are:

S' = (-628mi - 721mi)/44h = -30.66 mi/h

But this is a negative speed, so this has no real meaning, and we can discard this solution.

The other solution is:

S' = (-628mi + 721mi)/44h = 2.1 mi/h

We can conclude that her walking speed is 2.1 miles per hour.

Answer:

h = 30°

Step-by-step explanation:

All angles in a triangle add up to 180°, so:

60° + 90° + h° = 180°

Solving for h, we should get 30 as our answer.

Answer:

1.333333333333

Step-by-step explanation:

Answer:

frist answer is

6080

second answer is 72 square yard

Answer:

A, L, F

Step-by-step explanation:

Quadrant ll (2) is the top left one so points A, L, F are in it. Hope this is correct!

Answer: AL

Step-by-step explanation: THE OTHER ARE ON THE AXIS AND NOT NEITHER QUADRANTS

Answer:

√7

Step-by-step explanation:

(4x²-24x)+(4y²-32y)= -72

(4x²-24x+36)+(4y²-32y+64)= -72+36+64

4(x-3)²+4(y-4)²= 28

(x-3)²+(y-4)²=7

The radius of the circle 4x² + 4y²- 24x - 32y + 72 = 0 is √7.

We know that the general equation for a circle is ( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.

The given equation is 4x² + 4y²- 24x - 32y + 72 = 0

Simplify the given equation in general equation for a circle.

(4x²-24x)+(4y²-32y)= -72

Add 100 on both side of equality

(4x²-24x)+(4y²-32y)+100= -72+100

(4x²-24x+36)+(4y²-32y+64)= 28

4(x-3)²+4(y-4)²= 28

(x-3)²+(y-4)²=7

(x-3)²+(y-4)²=(√7)²

Hence the radius of the circle is √7.

Learn more about radius here: https://brainly.com/question/24375372
#SPJ2

Answer:

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

(A n B) = {2, 4}

Step-by-step explanation:

Given the set :

U = { 1 , 2 , 3 , 4 , 5 ,6 , 7 , 8 , 9 }

A={1 , 2 , 3 , 4 } , B= {2 , 4 , 6 , 8 }

(A - B) = elements of A which are not in B

(A - B) = {1, 3}

(A - B)' = the complement of A - B ; element in the universal set which are not in A - B

(A - B)' = {2, 4, 5, 6, 7, 8, 9}

(A n B) = elements in both set A and set B

(A n B) = {2, 4}

Answer:

X=-2,-1,0,1,2,3,4,5,6,

Step-by-step explanation:

IF 8 IS LARGER THAN -3 YOU COULD GET THE FOLLOWING ANSWER

Answer:

x>5

Step-by-step explanation:

move -8 to the right side, change the sign and solve:

x > - 3 + 8

x > 5

Answer:

The formula to find the nth term of the given sequence is 54 · [tex]\frac{2}{3} ^{n}[/tex]

Step-by-step explanation:

The formula for nth term of an geometric progression is :

[tex]a_{n} = \frac{a_{1}(r^{n})}{r}[/tex]

In this example, we have [tex]a_{1}[/tex] = 36 (the first term in the sequence) and

r = [tex]\frac{2}{3}[/tex] (the rate in which the sequence is changing).

Knowing what the values for r and [tex]a_{1}[/tex] are, now we can solve.

[tex]a_{n} = \frac{a_{1}(r^{n})}{r}[/tex] = [tex]\frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} }[/tex] = 54 · [tex]\frac{2}{3} ^{n}[/tex]

Therefore, the formula to find the nth term of the given sequence is

54 · [tex]\frac{2}{3} ^{n}[/tex]

Answer:

The answer is A.

Step-by-step explanation:

Rectangles is a quadrilateral shape that has four sides, two pairs of parallel lines, and all the corners MUST be right angles for it to be a rectangle. :)

I hope this helps :DD