Option C is correct. The image is located between F and the center of the lens, on the other side of the lens the upright than the actual object.
What is the upright image?Virtual and imaginary image is the type of upright image. A virtual picture is generated when light rays appear to meet at a certain spot following reflection from a mirror.
The picture that appears right-side-up is called an erect image. Unlike a virtual image, it is created by the real junction of light beams.
The lens in the illustration is a concave lens. The light rays that fall from the item onto the lens diverge, making it a diverging lens.
The item is held between the focus and the lens's center. At the same side of the item, an image would form between the focus and the lens's center.
The picture would be simulated, shrunk, and centered. As a result, the correct answer is: "The picture is upright."
Hence option C is correct
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Question 1 (1 point)
You pick up a box of books. The box is labeled 50N. What is the actual mass of the
box?
50N
5.1 kg
490 kg
9.8 m/s2
Answer:
[tex]actual \: mass \: of \: the \: box \: is = 5.0kg[/tex]
Explanation:
[tex]the \: actual \: mass \: of \: the \: box \: is \: m \: = \frac{w}{g} \: = \frac{50}{10} = 5.0kg[/tex]
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The isotope of an atom containing 40 protons and 51 neutrons suddenly has two neutrons added to it.
What isotope is created?
Zirconium-53
Zirconium-93
Antimony-93
Antimony-53
Answer:
Hey, the answer is Zirconium-93
Explanation:
Im very positive about this question, so i hope I helped you ;p
Answer:
Zirconium-93
Explanation:
when we add up the 40 protons and 53 neutrons it gives 93 and a protons and neutron 93 gives a Zirconium-93
Thanks theres your answer
A binary star system that is detected from the drop in luminosity as one star passes in front of the other is called ___________.
A binary star system that is detected from the drop in luminosity as one star passes in front of the other is called eclipsing. It has two stars.
What is a binary system?A binary system is a system composed of two stars that exert gravitational forces on a group of celestial bodies.
In a binary system, planets and celestial bodies can exhibit well-defined or irregular (very unstable) orbits.
The eclipsing binaries are stars where binary planets orbit in a plane containing the same line of vision, thereby eclipsing each other.
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Contrary to popular belief, a ski jumper does not achieve a large amount of "air" when doing a jump (less than 6 feet). This is because the ramp is almost horizontal while the landing is a steep hill. If a ski jumper leaves the hill at 26 m/s in the horizontal direction then travels 240 meters down the slope, what was the vertical distance (dy) that the ski jumper fell?
Answer:
The vertical distance that the ski jumper fell is 417.45 m.
Explanation:
Given;
initial horizontal velocity of the jumper, [tex]V_x[/tex] = 26 m/s
horizontal distance of the jumper, dx = 240 m
The time of the motion is given by;
dx = Vₓt
t = dx / Vₓ
t = 240 / 26
t = 9.23 s
The vertical distance traveled by the diver is given by;
[tex]d_y = V_yt + \frac{1}{2}gt^2[/tex]
initial vertical velocity, [tex]V_y[/tex], = 0
[tex]d_y = \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m[/tex]
Therefore, the vertical distance that the ski jumper fell is 417.45 m.
If you had a known sample of a mineral whose density was 7.1 grams/ml and its volume was 15 ml. What is the mass of the mineral.
Answer:
The answer is 106.5 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
volume = 15 mL
density = 7.1 g/mL
We have
mass = 7.1 × 15
We have the final answer as
106.5 gHope this helps you
If a planet's average distance from the sun is 10 AU, what is its orbital period?
The period will be 11.18 years
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|| ▼ Answer ▼ ||
The orbital period is 31.62 years when the average distance from the sun is 10AU
|| ✪ Explanation✪ ||
Given:
The average distance of the planet from the sun is r = 10 AU
To find the orbital period.
According to Kepler's third law,
[tex]T^{2}[/tex] ∞ [tex]r^{3}[/tex]
[tex]T^{2} =kr^{3}[/tex]
[tex]T=\frac{3}{2}[/tex]
Here, the constant k is taken to be 1.
Substituting the values, the orbital speed will be
[tex]T=(10)\frac{3}{2}[/tex]
[tex]=31.62~years[/tex]
Final Answer: The orbital period is 31.62 years when the average distance from the sun is 10AU
Hope this helps!
If you have any queries please ask.
A torch has 150J of energy supplied from a battery,
70J are transferred to light, 80J goes to heat, what is
the efficiency of the torch?
The efficiency of the torch light from the total energy supplied and useful energy is 46.7%.
Efficiency of the torch
The efficiency of the torch is the amount of energy used to produce light compared to the total energy supplied to the torch light. This can also be called useful energy.
Total energy supplied to the torch = 150 J
Total energy used to produce light = 70 J
The efficiency of the torch light is calculated as follows;
Efficiency = 70/150 x 100%
Efficiency = 46.7%
Thus, the efficiency of the torch light from the total energy supplied and useful energy is 46.7%.
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the unit of area is a derived unit . why?
sorry this is one side of the note
Saeed applied a force of 55 N to accelerate a 10 kg box at 3m/s2 along a horizontal surface. What is the magnitude of the frictional force?
1. 15N
2. 25N
3. 43N
4. 75N
5. 35N
the answer is 25N if u calculate it right the answer will be 25
The magnitude of the frictional force on the box is 25 N.
What is meant by frictional force ?Frictional force is defined as the opposing force that resists the relative motion between surfaces.
Here,
Mass of the box, m = 10 kg
Force applied on the box, F = 55 N
Acceleration of the box, a = 3 m/s²
The frictional force, f opposes the applied force, F. So that the applied force must over come the frictional force in order to accelerate the box.
So,
F - f = ma
Frictional force, f = F - ma
f = 55 - (10 x 3)
f = 55 - 30
f = 25 N
Hence,
The magnitude of the frictional force on the box is 25 N.
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What is the purpose of the cytoplasm
Answer:
:)
Explanation:
The cytoplasm provides a medium for the organelles to remain suspended. The cytoplasm acts as a buffer and protects the genetic material of the cell and also the cellular organelles from damage caused due to movement and collision with other cells. Cellular respiration begins in the cytoplasm with glycolysis
What wave moves in the same direction as the force that created it?
Air always moves from an area of high pressure to an area of ____________ pressure.
Answer:
low
Explanation:
This is because the energy in the air molecules in a high pressured area will constantly move and expand outwards. This is why gas leaks outside of labs, pipes, and soda bottles.
A florist has 144 roses and 312 lilies. He makes separate bunches of roses and lilies having equal number of flowers in each bunch. What is the greatest number of flowers the florist can have in each bunch
4. a.) Which is closer to the Moon-the middle of Earth or the water on t
side of Earth facing the Moon?
or
Answer:
The water on the side of the Earth facing the Moon
A force of 10 N is applied perpendicular to the end of a bar of
length 0.2 m. Calculate the torque produced by the force.
The torque produced by the force is 2 Nm
Torque
This is the turning effect of a force.
The torque of a force is given by τ = Fd where
F = force applied and d = perpendicular distance of force from action pointSince τ = Fd,
F = force applied = 10 N and d = length of bar = 0.2 mSubstituting the values of the variables into the equation, we have
τ = Fd
τ = 10 N × 0.2 m
τ = 2 Nm
So, the torque produced by the force is 2 Nm
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A 400 N force accelerates an object at 2 m/s2. What is the mass of the object?
( accidentally clicked ) , might not be the answer prolly could
Answer:
m = 200 [kg]
Explanation:
To solve this problem we must use Newton's second law, which states that the sum of forces must be equal to the product of mass by acceleration.
ΣF = m*a
where:
F = force = 400 [N]
m = mass [kg]
a = acceleration = 2 [m/s^2]
400 = m*2
m = 400/2
m = 200 [kg]
Where is the lightning rod attached to protect the building from lightning?
(a) On the top of the building
(b) On the bottom of the building
(c) In the middle of the building
(d) All of these
Answer:
On the top of the building
Explanation:
This lightning rod is called earthing This protects the building from thunder .As it accepts the lightning first and sends it down the groundHow many neutrons does krypton have
1.2 m long spring with a spring force of 200.0 N/m, 12.0 kg mass is attached to it, find the length
of the spring after extension after the mass is attached.
(hint: F = -6X)
(1 Point)
A) 1.232 m
B) O 1.788 m
C) 02.112 m
D) 2.788 m
Answer: 1.232
Explanation:I remember having this as a hw and this was the answer correct me if I was wrong
From Hooke's law, the length of the spring after extension and after the mass is attached is 1.788 meters. Option B is the answer.
HOOKE'S LAWHooke's law state that in an elastic material, the force applied is directly proportional to the extension provided that the elastic limit is not exceeded.
Given that a 12.0 kg mass is attached to 1.2 m long spring with a spring constant of 200.0 N/m.
The given parameters are:
mass m = 12kgInitial length [tex]L_{1}[/tex] = 1.2 mSpring constant K = 200 N/mExtension e = ?According to Hooke's law
F = Ke
But F = mg
mg = Ke
Substitute all the parameters into the formula to get extension e
12 x 9.8 = 200e
e = 117.6 / 200
e = 0.588 m
The length of the spring after extension and after the mass is attached will be
[tex]L_{2}[/tex] = [tex]L_{1}[/tex] + e
[tex]L_{2}[/tex] = 1.2 + 0.588
[tex]L_{2}[/tex] = 1.788 m
Therefore, the correct answer is option B because the length of the spring after extension and after the mass is attached is 1.788 meters.
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a rocket accelerates upwards from rest to a speed of 12km/s in 8 seconds calculate the acceleration
Answer: 1.5 km/s²
Explanation:
Given that,
Initial speed Vi = 0 km/s
Final speed Vf = 12km/s
Acceleration A = ?
Time taken T = 8 seconds
Recall that acceleration is the rate of change of velocity per unit time
i.e acceleration = (Vf - Vi)/T
A = (12km/s - 0km/s) / 8 seconds
A = 12km/s / 8 seconds
A = 1.5 km/s²
Thus, the acceleration of the rocket is 1.5 km/s²
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Combined gas law, A gas balloon has a volume of 106L when the temperature is 318K and the pressure is 1.5 atm. What will its volume be at 293 K and 2 atm.
P1 x v1/t1 = p2 x v2 / t2
use the given values:
1.5 x 106 / 318 = 2 x v2 / 293
Simplify:
0.5 = (2 x v2)/293
Multiply both sides by 293:
146.5 = 2 x v2
Divide both sides by 2:
V2 = 73.25 L
Answer: 73.25 L
16. Why does the spoon handle look broken where it enters the surface of the water?
A. The water magnifies the spoon
B. The water reflects the light differently
C. Light waves are refracted and speed up when they pass through the water
D. Light waves are refracted and slow down when they pass through the
water
Answer:
D.
Explanation:
A boat travels with a velocity equal to 14.0 meters per second, east in 6.15 seconds. What distance in meters does the boat travel?
Answer:
Distance, d is 86.1 meters.
Explanation:
Given the following data;
Time, t = 6.15secs
Velocity = 14m/s
Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, velocity is given by the equation;
[tex]Velocity = \frac{distance}{time}[/tex]
[tex]V = \frac{d}{t}[/tex]
[tex]d = Vt[/tex]
Substituting into the above equation;
[tex]d = 14 * 6.15[/tex]
d = 86.1m
Hence, the distance traveled by the boat is 86.1 meters.
A sport car starts from rest with an acceleration of 12 m/s2 . Calculate its final velocity after 7 s.
Answer:
Final velocity= 84 m/s
Explanation:
V final= V initial + a * t
Vf = 0+ 12 (7)
Vf= 84 m/s
The transit method of planet detection works best for.
Answer:
big planets in edge-on orbits around small stars.
Explanation:
Big planets in edge-on orbits around small stars.
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About my inequality stuff
Answer:
Sample of inequality suff:income gap,health care,and social class
Who is credited with discovering the atomic nucleus.
Answer: Ernest Rutherford's
Is it possible to apply the laws of Newton's dynamic to the motorcycle of the moon and the earth?
Answer:
Yes, it is possible
Explanation:
If possible, since Newton's laws are based on the motion of bodies that have mass. An example of how a vehicle can be moved on the moon was seen during lunar exploration where American astronauts drove a buggy-cart on the moon for a period of time.
We must remember that Newton's Second Law tells us that force is equal to the product of mass by acceleration. In this way we have:
F = m*a
where:
F = force = [N]
m = mass [kg]
a = acceleration [m/s²]
The force is produced by internal combustion or by electric action of the vehicle engine, the mass is the mass of the vehicle plus that of the crew member and the acceleration is the one that develops due to the change of speed, from rest to a certain speed.
how to calculate load
What will happen if the bar magnet remains stationary and the coil of wire is moved back and forth within the magnetic field?
(1 point)
The current will be induced