Answer:
Calculate the displacement of the car during the above acceleration. { ⃑ = –130 m} c. ... A 2.0 kg brick has a sliding coefficient of friction of 0.38.
Explanation:
What equal amounts of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitational attraction? Do you need to know the Moon’s distance to solve this problem? Why or why not? (b) How many metric tons of hydrogen would be needed to provide the positive charge calculated in part (a)? The molar mass of hydrogen is 1.008 g/mol.
Answer:
Fg = G M m / R^2 gravitational attraction
Fe = k Q^2 / R^2 electric repulsion
G M m = k Q^2
Q = (G M m / k)^1/2
Since m = .0123 M
Q = (.0123 G / k)^1/2 * M
Q = (.0123 * 6.67 * 10E-11 / 9 * 10E9)^1/2 * 5.98 * 10E24
Q = 5.71 * 10E13 C charge required on each body
n = 5.71 * 10E13 / 1.6 * 10E-19 = 3.57 * 10E32 atoms
N = 3.57 * 10E32 / 6.02 * 10E23 = 5.93 * 10E8 g-mol = 5.93 * 10E*5 kg-mol
Since 1 metric ton = 1000 kg
One would need 593 metric tons of hydrogen
Equation of Motion Problems
Displacement. Distance. Speed and Velocity
1. Donovan Bailey ran the 100 m dash at the Atlanta Olympics in 9.84 s. Michael Johnson ran the 200 m in 19.32
s and the 400 m in 43.49 s. Find their average speed in each case.
Wom
kilometrom
Answer:
Below in bold.
Explanation:
1. Speed = distance / time
= 100 / 9.84
= 10.16 m/s.
Speed = 200/19.32 = 10.35 m/s.
Speed = 400/43.49 = 9.20 m/s.