which statement best describes the set 14 16 18 20 22​

Answer:

x=1/3

Step-by-step explanation:

Answer:

$20

Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

Answer:

<1 = 77

<2 = 103

<3 = 77

Step-by-step explanation:

<1 = 77 (180-103) by Linear Pair Postulate

<2 = 103 by Vertical Angles Theorem

<3 = 77 by Vertical Angles Theorem

Origin = [tex](0, 0)[/tex]

Point = [tex](-18, 24)[/tex]

Distance = [tex]\sqrt{(24 - 0)^2 + (-18 - 0)^2} = \sqrt{24^2 + (-18)^2} = \sqrt{576 + 324} = \sqrt{900} = 30[/tex]

The distance from the origin to the point (-18, 24) is 30 units.

To find the distance from the origin (0, 0) to the point (-18, 24), we can use the distance formula in two-dimensional Cartesian coordinates.

The distance formula between two points [tex](x_1, y_1) and\ (x_2, y_2)[/tex] is given by:

[tex]\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\][/tex]

In this case, the coordinates of the origin are (0, 0) and the coordinates of the point are (-18, 24). Plugging these values into the distance formula, we get:

[tex]\[d = \sqrt{(-18 - 0)^2 + (24 - 0)^2} = \sqrt{(-18)^2 + 24^2} = \sqrt{324 + 576} = \sqrt{900} = 30\][/tex]

So, the distance from the origin to the point (-18, 24) is 30 units.

To know more about distance, refer here:

https://brainly.com/question/30717348

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[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$8911\\ r=rate\to 7.71\%\to \frac{7.71}{100}\dotfill &0.0771\\ t=years\dotfill &20 \end{cases} \\\\\\ A=8911e^{0.0771\cdot 20}\implies A=8911e^{1.542}\implies A\approx 41649.38[/tex]

Answer: 0.29

Step-by-step explanation:

The probability of the first being blue is 6/17, the second is 5/16 and the third is 4/15.  Multiply these together to get the total probability:

6/17 x 5/16 x 4/15 = .029

One way to make it easier to multiply, pick a number from a multiplication problem. Then, add the amount of times of the other number.

Example:

6 x 8 = ?

8 = Chosen Number

So, add 8, 6 times.

8 + 8 + 8 + 8 + 8 + 8 = ?

? = 48

Which, 6 x 8 does equal 48.

Answer:

7.011%

Step-by-step explanation:

61/(300+100+7+61+402) = 0.07011

Multiply the result of that by 100 to get 7.011%.

Answer: -3

Step-by-step explanation:

For the integral ∫asin(x)dx, use integration by parts ∫udv=uv−∫vdu.

Let u=asin(x) and dv=dx.

Then du=(asin(x))′dx=[tex]\rm \dfrac{dx}{ \sqrt{1 - {x}^{2} } } [/tex] and v=∫1dx=x

So,

[tex] \rm{\int{\operatorname{asin}{\left(x \right)} d x}}=\color{h}{\left(\operatorname{asin}{\left(x \right)} \cdot x-\int{x \cdot \frac{1}{\sqrt{1 - x^{2}}} d x}\right)}=\color{h}{\left(x \operatorname{asin}{\left(x \right)} - \int{\frac{x}{\sqrt{1 - x^{2}}} d x}\right)} \\ [/tex]

Let u=1−x2.

Then du=(1−x2)′dx=−2xdx and we have that xdx=−du/2.

The integral can be rewritten as

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{g}{\int{\frac{x}{\sqrt{1 - x^{2}}} d x}} = x \operatorname{asin}{\left(x \right)} - \color{j}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} \\ [/tex]

Apply the constant multiple rule ∫cf(u)du=c∫f(u)du with c=-1/2 and f(u)=[tex] \frac{1}{ \sqrt{u} } [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{h}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} = x \operatorname{asin}{\left(x \right)} - \color{h}{\left(- \frac{\int{\frac{1}{\sqrt{u}} d u}}{2}\right)} \\ [/tex]

Apply the power rule

[tex] \rm\int u^{n}\, du = \frac{u^{n + 1}}{n + 1} \\ [/tex]

with n=−1/2

[tex] \rm x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\int{\frac{1}{\sqrt{u}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\int{u^{- \frac{1}{2}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\frac{u^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\left(2 u^{\frac{1}{2}}\right)}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\left(2 \sqrt{u}\right)}}{2} \\ [/tex]

[tex] \rm Recall \: that  \: u=1− {x}^{2} [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} + \sqrt{\color{re}{u}} = x \operatorname{asin}{\left(x \right)} + \sqrt{\color{rd}{\left(1 - x^{2}\right)}} \\ [/tex]

Therefore,

[tex] \rm\int{\operatorname{asin}{\left(x \right)} d x} = x \operatorname{asin}{\left(x \right)} + \sqrt{1 - x^{2}}+C \\ [/tex]

Answer:

none

Step-by-step explanation:

plug it in, it doesnt add up

Answer:

5/4

Step-by-step explanation:

[tex] \frac{10}{12} \div \frac{4}{6} \\ \\ = \frac{10}{12} \times \frac{6}{4} \\ \\ = \frac{5}{2} \times \frac{1}{2} \\ \\ = \frac{5}{4} [/tex]

Answer:

3

Step-by-step explanation:

3 because their is a rule which states: 1-4 stay on the floor 5-9 climb up the vine this means if it is 4 or less than round down and if it is 5 or more round up

Answer:

me sandip is a jokeerrrr..........

Step-by-step explanation:

no god sucks......... **** brainly

Answer:

-1

Step-by-step explanation:

5-2=3

2-3=-1

The surface area of the globetrotters must work with is 283.4 square inches

The formula for calculating the surface area of a sphere is expressed as:

S = 4πr²

where r is the radius of the sphere

Given that

d = 9.5in

r = 4.75in

Substitute the given parameters into the formula

S = 4π(4.75)²

S = 283.385 square inches

The surface area of the globetrotters must work with is 283.4 square inches

Learn more on the surface area of the sphere here: https://brainly.com/question/1293273

Answer:

t(d(n)) = 12n + 7

Step-by-step explanation:

t(d(n)) = t(4n + 2)

Substitute the function d(n) into the function t(d) for the variable d.

t(4n + 2) = 3(4n + 2) + 1  

t(d(n)) = 12n + 7

Answer:

787 times 2554 equals 2,009,998

Step-by-step explanation:

Hope that helps!

Answer:

hello the data required is missing attached below is the missing data and solution

Answer : Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population

Step-by-step explanation:

At 5% level of significance the conclusion of this test is  Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population.

The value of the test statistic tcal = 0.7402 lies between the critical values

±[tex]t_{\frac{0.05}{2.2} }[/tex] = ±2.086

attached below is the detailed solution and missing part of the question

You would use the ratio to solve this problem.

12:15=4:5

Since the ratio of expected numbers of games they would win to the total number of games they will play is equal to the ratio of number of games they won to the total number of games they played, the answer would be YES.

Answer:

abcd = -24

Step-by-step explanation:

First, remember that the default operation in algebra is multiplication, so we have to multiply a and b and c and d together to get the answer:

abcd = a × b × c × d

Plugin your values to get the total of:

3 x -2 × 4 × 1 = -24

So the answer to this problem is -24

Answer:

10x5.08

Step-by-step explanation:

Answer:

I am pretty sure it is

y >_ 20(0.061)^t

t >_ 0

Step-by-step explanation:

The volume of the rectangular prism with the dimensions given are as follows:

v = 72 inches³

v = 36 inches³

v =  80 inches³

v = 54 inches³

where

l = length

w = width

h = height

Therefore,

a.  

b.

c.

d.

learn more on rectangular prism here: https://brainly.com/question/13512346

Answer:

Probability of drawing a yellow candy: 10/36= 5/18

Something besides a yellow candy: for ecample: the red candies: 8/36= 2/9

Step-by-step explanation:

Probability of drawing yellow candies equals the sum of candies over yellow candies.

[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}lr[/tex]

[tex]\\ \sf\longmapsto Area=\dfrac{1}{2}(5.4)(6)[/tex]

[tex]\\ \sf\longmapsto Area=16.2cm^2[/tex]

Answer:

C

Step-by-step explanation:

If you put 2 different values in for x and it happens 2 times, the eqyations must be equivilent :)

Have an amazing day!!

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Answer:

36 Minutes

Step-by-step explanation:

150/8=18.75

675/18.75=36

So hence, your answer is 36 Minutes

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