Which statement(s) is/are TRUE about photons?
SELECT ALL THAT APPLY
a Photons have greater mass than electrons.
b Photons are particles of light.
с
Photons carry a very specific quantum of
energy.
d Photons have zero mass.

Answer:

What’s the question??

Explanation:

That depends on the car's speed at the moment of impact, and how long it takes to stop after the impact.

It is NOT 8,000N. That answer would come from a totally incorrect application of " F = m a " . 8,000 Newtons is what it takes to accelerate that car in the first place, long before it hits the tree.

Force can be described as either a pull or a push

Now when a body with mass and acceleration hits an object, we say a collision has taken place, hence there will be transfer of energy within the system

Give data

mass = 4000kg

acceleration = 2m/s^2

We know that force is given as

Force = mass x acceleration

Substitute our given data into the expression for force

Force = 4000 x 2Force = 8000N

For more information on force kindly visit

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Answer:

It can be either, depending on how much and how you add the electrons

Answer:

c,B,a,d i guess i m not sure it is the guessing

Answer:

it's a Bugatti

Explanation:

I seen pictures and videos of one for what they look like from the inside or the outside

Answer:

B . a heat transfer caused

Answer:

the mug will moveforwards

Answer:

Plankton is the correct answer I think

Answer:

a

[tex]T_2 =  276.1 \ K[/tex]

b

  [tex]V_2  = 2.13 *10^{3} \ m^3 [/tex]

c

   [tex]\Delta U =  -1.25 *10^{7} \  J  [/tex]

Explanation:

From the question we are told that

  The  volume of the balloon is  [tex]V  =  2.00 * 10^3 \ m^3[/tex]

   The  pressure of  helium is  [tex]P_1 =   1.00 \ atm=  1.0 *10^{5} \  Pa [/tex]

   The  initial  temperature is  [tex]T_1   =  15.0^oC =  288 \  K [/tex]

   The  pressure of  atmosphere is [tex]P_a  =  0.900 \ atm[/tex]

 Generally the equation representing the  adiabatic process is mathematically represented as

      [tex]P_1 V_1 ^{\gamma }=  P_2 V_2 ^{\gamma }[/tex]

=>    [tex]V_2 ^ {\gamma } =  \frac{ V_1 ^{\gamma } *  P_1 }{P_2}[/tex]

Generally [tex]\gamma[/tex] is a constant with value [tex]\gamma  =\frac{5}{3}[/tex] for an ideal  gas

So  

     [tex]V_2 ^ {\frac{5}{3} } =  \frac{ ( 2.0 *10^{3}) ^{ \frac{5}{3}  } *   1.00 }{0.900}[/tex]

        [tex]V_2  =  (\sqrt[5]{103.14641852} )^3[/tex]

=>      [tex]V_2  = 2.13 *10^{3} \ m^3 [/tex]

Generally the adiabatic process can also be mathematically represented as

     [tex]T_1 V_1 ^{\gamma -1 } = T_2 V_2^{\gamma -1 }[/tex]

=>  [tex]T_2  =  288 *  [\frac{2 *  10^{3}}{ 2.13 *10^{3}} ]^{ \frac{5}{3} -1 }[/tex]

=>    [tex]T_2 =  276.1 \ K[/tex]

Generally the ideal gas equation is mathematically represented as

        [tex]P_1 V_1 = nRT_1[/tex]

Here  R is the  gas constant with value  [tex]R  =  8.314\  J  /mol \cdot  K[/tex]

     [tex]n  =  \frac{P_1 V_1 }{RT _1}[/tex]

=>  [tex]n  =  \frac{1.0 *10^{5} *  2.0 *10^{3}}{8.314 * 288[/tex]

=>  [tex]n  =  84362 \  mol[/tex]

Generally change in internal energy i mathematically represented  

        [tex]\Delta U =  n C_v  \Delta  T[/tex]

Here  [tex]C_v[/tex] is  the  specific heats of gas at constant volume and the value is  [tex]C_v  =  12.47 J/mol \cdot  K[/tex]

         [tex]\Delta U =  84362 *   12.47 * [T_2 - T_1 ]  [/tex]

         [tex]\Delta U =  84362 *   12.47 * [276.1 - 288 ]  [/tex]

          [tex]\Delta U =  -1.25 *10^{7} \  J  [/tex]

Answer:

Object A runs into Object B. The force that object A has will transfer from Object A to Object B. But during this transfer you will loose some energy, therefore object B will not travel as fast.

Explanation:

Answer:

The description is outlined throughout the clarification section following, and according to the given word.

Explanation:

Answer:

T₂ is greater than T₁ by an amount independent of velocity

Explanation:

This is an exercise on Newton's second law

for block of mass m1

            T₁ = m₁ a

for block of mass m²

            T₂ = m₂ a

as it indicates that m₂> m₁

the tension T₂> T₁ also we see that in this equation there is no dependence with the velocity, but with the acceleration

the voltage difference does not depend on the speed of the vehicles

When reviewing the answers, the correct one is B

    T₂ is greater than T₁ by an amount independent of velocity

Answer:

B.  a hearing by a federal court of appeals

If any state tribunal decides a federal question and the litigant has no further remedy within the state court system, a hearing by a federal court of appeals.

Oral argument in the court of appeals is a prearranged conversation between the judges and the appellate attorneys that focuses on the legal principles at issue. Each party has a limited amount of time usually around 15 minutes to make their case to the judge.

If a litigant loses in a federal court of appeals or in the highest court of a state, they may ask the supreme court to reconsider the case by filing a petition.

Only when a case concerns an extremely significant legal concept or when two or more federal appellate courts have disagreed on how to interpret a statute will the court normally consent to consider it. Additionally, there are a few rare instances where the Supreme Court is mandated by the law to consider an appeal.

Find more on federal court :

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Answer:

Diagram B.

Explanation:

We'll begin by defining potential energy.

This is given below:

Potential energy is the energy stored in an object due to its position. Mathematically, it is expressed as:

P.E = m × g × h

Where:

P.E is the potential energy.

m is the mass of the object.

g is the acceleration due to gravity.

h is the height to which the object is located.

From:

P.E = m × g × h

We can say that the potential energy (P.E) is directly proportional to the height (h) to which the object is located. This implies that as the height increase, the potential energy of the object will also increase and as the height decrease, the potential energy of the object will also decrease.

Now, considering the question given above, we can see that the height of the object is greater in diagram B. Therefore, The potential energy of the object is greater in diagram B.

Answer:

The answer s B

Explanation:

Answer:

1. (b) 2.5 eV

2. (c) 430000 m/s

3. (a) The maximum velocity of any ejected electrons will decrease.  

Explanation:

1)

From Einstein's Photoelectric Equation:

hc/λ = K.E + ∅

∅ = hc/λ - K.E

∅ = hc/λ - eV

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Stopping Potential = 0.52 volts

h = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 405 nm = 4.05 x 10⁻⁷ m

∅ = Work Function = ?

Therefore,

∅ = (6.625 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(4.05 x 10⁻⁷ m) - (1.6 x 10⁻¹⁹ C)(0.52 volts)

∅ = 4.9 x 10⁻¹⁹ J - 0.832 x 10⁻¹⁹ J

∅ = (4.075 x 10⁻¹⁹ J)(1 eV)/(1.6 x 10⁻¹⁹ J)

∅ = 2.5 eV

therefore, correct answer is"

(b) 2.5 eV

2)

K.E = (1/2)mv² = eV

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed = ?

therefore,

(1/2)(9.1 x 10⁻³¹ kg)v² = (1.6 x 10⁻¹⁹ C)(0.52 volts)

v = √(0.18 x 10¹² m²/s²)

v = 0.43 x 10⁶ m/s = 430000 m/s

Correct option is:

(c) 430000 m/s

3.

The decrease in power at constant wavelength means decrease in voltage, that results in the decrease of kinetic energy of electrons. So, correct option is:

(a) The maximum velocity of any ejected electrons will decrease.

Answer:

Explanation:

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Answer:

In physics, mass–energy equivalence is the principle that anything having mass has an equivalent amount of energy and vice ve

Answer:

λ₀= 495.88 nm

Explanation:

To analyze this constructive interference interference experiment by reflection, let's look at two important aspects:

* when a ray of light passes from a medium with a lower index, they refact to another medium with a higher index, the reflected ray has a phase difference of pyres

* When a beam penetrates a material medium, the wavelength of the radiation changes according to the refractive index of the material.

       λₙ = λ₀ / n

when we introduce these aspects in the expression of contributory interference, it remains

        2 d sin θ = (m + ½) λ₀ / n

In general, reflection phenomena are measured at an almost normal angle, whereby θ = π/2  and sin θ = 1

        2 d = (m +1/2) λ₀/ n

         2n d = (m + ½) λ₀

Let's apply this expression to our case

         d = (m + ½) λ₀ / 2n

Suppose we measure on the first interference, this is m = 0

         d = ½ λ₀ / 2n

let's calculate

         d = ½ 496 10⁻⁹ / (2 2.30)

         d = 53.9 10-9 m  

This is the thickness of the glass, the next wavelength that gives constructive interference is

          λ₀ = 2 n d / (m + ½)

let's calculate

          λ₀ = 2 2.3 5.39 10-8 / (1 + ½)

          λ₀= 4.9588 10-7 m

          λ₀= 495.88 nm

Answer:

11,000 kg

(a) 11.2 m/s

(b) 1.6 m/s

Explanation:

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(2200 kg) (60.0 km/h) + m (0 km/h) = (2200 kg) (10 km/h) + m (10 km/h)

132,000 kg km/h = 22,000 kg km/h + m (10 km/h)

110,000 kg km/h = m (10 km/h)

m = 11,000 kg

Momentum is conserved.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(m) (-v) + (2m) (5v) = (m) (v₁) + (2m) (v₂)

-mv + 10mv = m v₁ + 2m v₂

9mv = m (v₁ + 2 v₂)

9v = v₁ + 2 v₂

Since the collision is elastic, kinetic energy is also conserved.

½ m₁u₁² + ½ m₂u₂² = ½ m₁v₁² + ½ m₂v₂²

m₁u₁² + m₂u₂² = m₁v₁² + m₂v₂²

(m) (-v)² + (2m) (5v)² = m v₁² + (2m) v₂²

mv² + 50mv² = m v₁² + 2m v₂²

51mv² = m (v₁² + 2 v₂²)

51v² = v₁² + 2 v₂²

We know v = 1.60 m/s.  So the two equations are:

14.4 = v₁ + 2 v₂

130.56 = v₁² + 2 v₂²

Solve the system of equations using substitution.

130.56 = (14.4 − 2 v₂)² + 2 v₂²

130.56 = 207.36 − 57.6 v₂ + 4 v₂² + 2 v₂²

0 = 6 v₂² − 57.6 v₂ + 76.8

0 = v₂² − 9.6 v₂ + 12.8

v₂ = [ 9.6 ± √(9.6² − 4(1)(12.8)) ] / 2(1)

v₂ = 1.6 or 8

If v₂ = 1.6 m/s, then v₁ = 14.4 − 2 v₂ = 11.2 m/s.

If v₂ = 8 m/s, then v₁ = 14.4 − 2 v₂ = -1.6 m/s.

We know v₁ can't be -1.6 m/s, since that would mean puck A didn't change speeds after the collision.  Therefore, v₁ = 11.2 m/s and v₂ = 1.6 m/s.

Answer:

P = 180 [w]

Explanation:

To solve this problem we must use ohm's law, which is defined by the following formula.

V = I*R & P = V*I

where:

V = voltage = 200[volts]

I = current [amp]

R = resistance [ohm]

P = power [watts]

Since the bulbs are connected in series, the powers should be summed

P = 60 + 60 + 60

P = 180 [watts]

Now we can calculate the current

I = 180/200

I = 0.9[amp]

Attached is an image where we see the three bulbs connected in series, in the circuit we see that the current is the same for all the elements connected to the circuit.

And the power is defined by P = V*I

we know that the voltage is equal to 200[V], therefore

P = 200*0.9

P = 180 [w]

Answer:

28230 joules

Explanation:

becasue yes

Answer:

P=2940 Pa

Explanation:

Given that,

Side of a cube, a = 12 cm

It is submerged to  depth of 30 cm

The density of water, d = 1000 kg/m^3

We need to find the pressure at the bottom surface of the cube. We know that the pressure exerted is given by :

[tex]P=d gh\\\\P=1000\ kg/m^3\times 9.8\ m/s^2\times 0.3\ m\\\\P=2940\ Pa[/tex]

So, 2940 Pa of pressure is exerted at the bottom surface of the cube due to water.​

Answer:

90

Explanation:

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bkfjffy

Recall that

v² - u² = 2 a ∆x

where u and v are initial and final velocities, respectively; a is acceleration; and ∆x is the change in position.

We can use this formula to determine the launch speed of the ball. In the vertical direction, the ball has acceleration g in the downward direction, where g = 32.2 ft/s². At its maximum height, the ball has 0 vertical velocity. So we have

0² - u² = 2 (-32.2 ft/s²) (40 ft)

==>  u ≈ 50.75 ft/s

Now, the ball's height y at time t is given by

y = u t - 1/2 g t²

Find at which time t the ball covers the first 20 ft of its trajectory:

20 ft = (50.75 ft/s) t - 1/2 g t²

==>  t ≈ 0.462 s

(there is a second solution, t ≈ 2.69 s, which corresponds to the time it takes for the ball to return to this height as it's falling back down)

During this first interval, the ball's horizontal position x is

x = (20 mph) t ≈ (29.33 ft/s) t

so that at the moment the ball reaches a height of 20 ft, it will have moved

x = (29.33 ft/s) (0.462 s) ≈ 13.5 ft

to the right. (So we've take the right to be positive and the left to be negative.)

In the upper half of its trajectory, when the wind changes direction, the ball's horizontal position is given by

x = 13.5 ft - (29.33 ft/s) t

Note that t = 0 here means we now take the ball's current position to be the "initial" one. So the time we found earlier for when the ball has a height of 20 ft as it's falling back down is actually t = 2.69 s - 0.462 s ≈ 2.23 s. At this point, the ball's horizontal position is

x = 13.5 ft - (29.33 ft/s) (2.69 s - 0.462 s) ≈ -51.8 ft

or about 51.8 ft to the left of where it started.

The wind changes direction again, so that the ball's position at time t is now

x = -51.8 ft + (29.33 ft/s) t

Solving y = 0 for t gives the time when the ball reaches the ground:

0 = (50.75 ft/s) t - 1/2 g t²

==>  t ≈ 3.15 s

Again, this is the time it takes for the ball to reach the ground since it was launched, while the position function takes t = 0 to refer to the moment the ball is 20 ft above the ground. So once it hits the ground, it will be

x = -51.8 ft + (29.33 ft/s) (3.15 s - 2.69 s) ≈ -38.3 ft

which means the ball lands on the ground about 38.3 ft to the left of where it started.

Explanation:

n=75 kg

v=3m/s

m=n×v

m=75x3

m= 225n

Answer:

Mass

axis

distance

intertia

+500   because North is postiive direction

-300 because if you see it as a graph, left side is negative

-800 because South is downward

500-300-800 = -600

displacement is a vector, meaning it has both DIRECTION and magnitude

(literally the only physics problem i can easily solve lol)

Answer:

[tex]\mid D \mid = 424.26\ m[/tex]

Explanation:

Displacement

Suppose a moving object starts from point A and travels through a determined path to point B. The distance is the sum of all the partial distances traveled, and the displacement is the vector directed from A to B.

The path of the person is shown in the image below. Note the 500 m due north and the 800 m due south produce a distance of 300 m due south. The displacement vector D is the resultant of the whole movement.

To find the magnitude of the displacement, we need to calculate the hypotenuse of a triangle of sides 300 m (already described) and 300 m, marked in red.

The magnitude of D is:

[tex]\mid D \mid = \sqrt{300^2+300^2}[/tex]

[tex]\mid D \mid = \sqrt{90000+90000}[/tex]

[tex]\mid D \mid = \sqrt{180000}[/tex]

[tex]\mid D \mid = 424.26\ m[/tex]