Which wave has a greater frequency

Answer:

B

Explanation:

I'm learning it in science.

Answer:

its not b i just took the test and b was wrong

Explanation:

Answer:

jjjjj

Explanation:

dkcdzjc

Answer:

ight bet

Explanation:

Answer:

C. Some of the mass of the four hydrogen nuclei was converted into

energy

Explanation:

a p e x , just took the quiz

Some of the mass of the four hydrogen nuclei was converted into energy.

When four hydrogen nuclei fuse to form one helium nuclei, mass defect, some mass is converted into energy, that is the reason of energy of the sun.

"When two nuclei form a big nuclei, the phenomenon is known as fusion."

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Question is whether the statement made is true or false.

Answer:

False

Explanation:

The statement is false.

Thus is because even though we are told that the spaceship is running at 1000 miles per hour and an enters an area free of gravitational forces, there is no rule or law that says the engine must run at some maximum level to maintain the velocity.

So, that's why it is false as there is no proof of the statement from every law of physics.

Answer:

resonance frequency is the frequency when capacitive reactance and inductive reactance become equal and opposite to each other and all impedence is given by resistance.

Explanation:

              f=1/2[tex]\pi[/tex][tex]\sqrt{LC}[/tex]

Answer:

The value is [tex]u_x = 597 \ m/s[/tex]

Explanation:

From the question we are told that

    The distance of the target from the riffle is  [tex]d = 40 \ m[/tex]

    The height at which the bullet hit the target is  [tex]y = 2.2 \ cm = 0.022 \ m[/tex]

Considering the vertical motion  

Generally from kinematic equations we have that

        [tex]y = u_y t + \frac{1}{2} * gt^2[/tex]

At the initial stage the velocity is  zero  i.e [tex]u_y = 0 \ m/s[/tex]

=>     [tex]0.022 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]

=>    [tex]t = 0.067 \ s[/tex]

Generally the velocity of the bullet when it leaves the riffle is mathematically represented as

         [tex]u_x = \frac{ d}{t}[/tex]

=>     [tex]u_x = \frac{40 }{ 0.067 }[/tex]

=>     [tex]u_x = 597 \ m/s[/tex]

Answer:

v0 = 24.42 m/s (Approx)

Explanation:

Given:

Increase in frequency = 7.1% =

Computation:

Assume n = 100%

n1 = [(v+v0)/(v+v1)]n

[100 + 7.1] =  [(344+v0)/(344+0)]100

107.1 =   [(344+v0)/(344)]100

v0 = 24.42 m/s (Approx)

Answer: Kinetic Energy to Electrical.

Explanation: The magnet is rotated as a result of the spinning wheels, and this results in a powerful stream of electrons, therefore converting kinetic to electrical.

Answer:

Explanation:

From the question we are told that

Constant speed =48mile/hr

Diameter of a wheel = 22inch therefore [tex]r=\frac{22}{2} =>11[/tex]

Generally Convert from mile/hr to inches/sec

The length in inches is equal to the miles multiplied by 63,360.

an hour is 3600seconds

[tex]\frac{48*63360}{3600}[/tex]

48miles/h = 849.8 inch/sec

[tex]V_a =844.8 inch/sec[/tex]

therefore

[tex]\omega= \frac{v}{r}[/tex]

[tex]\omega= \frac{844,8}{11}[/tex] =>[tex]76.8 sec ^-^1[/tex]

a)Considering the velocity of Vb  in inches per seconds

Generally the formula is stated as

[tex]V_b= V_a + V_b_/_a[/tex]

[tex]V_b = 844.8 + \omega r[/tex]

[tex]V_b= 1639.6in/s[/tex]

b)Considering the velocity of Vc  in inches per seconds

Since the tire doesn't slip as earlier stated in the question

Therefore [tex]V_c = 844.8 -w(r) =0[/tex]

c)Considering the velocity of Ve  in inches per seconds

Generally the formula is stated as

[tex]V_e=V_a + V_e_/_a[/tex]

[tex]V_e = 844.8 \uparrow \theta -844.8 \uparrow = 844.8\sqrt{2}[/tex]

Expressing result with vector

[tex]V_e =844.54 + 20.85j[/tex]

d)Considering the velocity of Vd  in inches per seconds

Generally the formula is stated as

[tex]V_d= V_a + V_d_/_a[/tex]

Mathematically

[tex]V_d =844.8 \uparrow +( 844.8\frac{\sqrt{3} }{2} \uparrow + \frac{844.8}{2} \uparrow)[/tex]

[tex]V_d= (1576.4 \uparrow + 422.4\uparrow)[/tex]

[tex]V_d= 1632.028in/s[/tex]

Answer:

√3 * Gm²/d²

Explanation:

m1 = m, m2= m, distance = d. hence:

F = Gm²/d²

Let the origin be A, the point x = d be B and the point above the first two is C.

The net force acting on the third mass (point C) [tex]F_{net}[/tex] = [tex]F_A+F_B[/tex]

Let j represent the vertical component and i the horizontal component. Hence:

[tex]F_B=-F_j\\\\F_A=-F(icos\frac{\pi}{6}+jsin\frac{\pi}{6} )=-F(i\frac{\sqrt{3} }{2}+j\frac{1}{2} )\\\\F_{net} =F_A+F_B\\\\F_{net} =-F_j+{-F(i\frac{\sqrt{3} }{2}+j\frac{1}{2} )}\\\\F_{net} =-\frac{F}{2} \sqrt{3}(i+j\sqrt{3} )\\\\The\ magnitude\ of\ the\ net\ force\ is:\\\\|F_{net}|=\frac{F}{2}\sqrt{3}(\sqrt{1^2+\sqrt{3}^2 })=\frac{F}{2} \sqrt{3}(\sqrt{4})\\\\|F_{net}|=\frac{F}{2} \sqrt{3}*2=F*\sqrt{3}\\\\|F_{net}|=\sqrt{3}*\frac{Gm^2}{d^2}[/tex]

Answer:

Explanation:

For equilateral triangle,

[tex]\theta = 30^o[/tex]

Force between masses,

[tex]F_1 = \frac{G*m*m}{d^2}\\\\F_! = \frac{Gm^2}{d^2}[/tex]

Therefore,

[tex]F_net = 2F_1cos\theta\\\\F_net = 2 * \frac{Gm^2}{d^2} * cos30\\\\F_net = 3^{0.5} * \frac{Gm^2}{d^2}[/tex]

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Answer: 300m

1 minute = 60s

the unladen swallow can fly: 60.5 = 300 (m)

Explanation:

Explanation:

m means mass and v means velocity.

now, you can calculate

The change in potential energy in moving a 10kg box from the floor to a table 1 m high is 98 Joules.

To find the potential energy, the given values are,

Mass of the box = 10Kg

Height h = 1 m

The potential energy can be defined as the energy that is stored and that can be determined through various parts in a particular system.

Also, the energy will gets stored when the object is not moving.

For example: Spring. Even when the spring is not stretched or contracted it stores energy.

The formula for Potential energy PE= mgh joules.

m is the Mass,

g is the acceleration due to gravity = 9.8 m/s²,

h is the height.

Substituting all the given values,

Potential Energy= 10 (9.8)(1)

PE= 98 J

Thus the potential energy of the box= 98 J.

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Answer:

v = 0.33 [m/s]

Explanation:

We must remember that speed is defined as the relationship between the displacement in a given time. In this way, we can propose the following equation.

[tex]v=d/t[/tex]

where:

v = velocity [m/s]

d = displacement = 40 [m]

t = 2 [min] = 120 [s]

Now replacing we have:

[tex]v=40/120\\v=0.33[m/s][/tex]

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

Answer:

the velocity is 210 - hq squared which equals to 14

Answer:

Impulse = 0.1 Kgm/s

Explanation:

Given the following data;

Force, F = 10N

Time, t = 0.01 seconds

To find impulse

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

Impulse = force * time

Substituting into the equation, we have;

Impulse = 10 * 0.01

Impulse = 0.1 kgm/s

Therefore, the impulse of the hammer is 0.1 kilogram meter per seconds.

The impulse of the hammer is 0.1 Ns.

To solve the given problem we need to use the formula for calculating impulse.

Impulse: This can be defined as the product of force and time on a body.

The formula of impulse is given below.

I = Ft....................... Equation 1

Where :

From the question,

Given:

Substitute these values into equation 1

Hence, The impulse of the hammer is 0.1 Ns.

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Potential energy of a particle is directly proportional its position, thus, potential energy of particle increases with increase in the height of the particle and decreases with a decrease in the height of the particle.

The potential energy of a particle is the energy possessed by the particle by virtue of its position. This potential energy is form of mechanical energy and it is expressed mathematically as the product of the mass of the particle, acceleration due to gravity and the particles displacement or position.

P.E = mgh

where;

P.E is the potential energy of the particle

m is the mass of the particle

g is the acceleration due to gravity

h is the position of the particle.

Potential energy of a particle is directly proportional its position, thus, potential energy of particle increases with increase in the height of the particle and decreases with a decrease in the height of the particle.

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Answer:

Well potential energy is when an object is not moving, kinetic energy is when energy is made when an object is moving. So basically the way you can investigate the transformation of the energy of potential and kinetic is that, for example, a ball is being pushed down a hill. Ar first there is potential energy because the ball is not moving. Then there is kinetic energy because the ball is being pushed.

Explanation:

so basically what i'm saying as that as the energy of a ball moving than that's kinetic energy, Something that doesn't move always has potential energy.

Answer:

The value is  [tex]m = 69.24 \ kg[/tex]

Explanation:

From the question we are told that

   The value of the external force is  [tex]F = 59.0 \ N[/tex]

    The magnitude of the astronaut's acceleration is  [tex]a = 0.852 \ m/s[/tex]

Generally Newton's Second Law of Motion from the mass of the astronauts is mathematically represented as

            [tex]m = \frac{F}{a}[/tex]

=>         [tex]m = \frac{59 }{0.852 }[/tex]

=>         [tex]m = 69.24 \ kg[/tex]  

Answer: ur mom

Explanation:

Answer:

Radient to ElEcTrIcAAl

Explanation:

The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.

Answer:

x = A cos (w \sqrt{2y_{o}/g})

a) maximun  Ф= \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) minimun     Ф = [tex]\frac{\pi }{2}[/tex] - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

Explanation:

For this exercise let's use kinematics to find the time it takes for the mass to reach the floor

         y = y₀ + v₀ t - ½ g t²

as the mass is released from rest, its initial velocity is zero (vo = 0) and its height upon reaching the ground is zero (y = 0)

      0 = y₀ - ½ g t²

      t = [tex]\sqrt{2y_{o}/g}[/tex]

The bucket-spring system has a simple harmonic motion, which is described by

     x = A cos wt

in this expression we assumed that the phase constant (Ф) is zero

let's replace the time

     x = A cos (w \sqrt{2y_{o}/g})

this is the distance where the system must be for the mass to fall into it.

a) The new system has a total mass of m ’= 3.0 kg, so its angular velocity changes

          w = [tex]\sqrt{k/m}[/tex]

In the initial state

         w = \sqrt{k/2}

When the mass changes

         w ’= \sqrt{k/3}

the displacement in each case is

         x = A cos (wt)

for the new case

        x ’= A cos (w’t + Ф)

the phase constant is included to take into account possible changes due to the collision of the mass.

we see that this maximum expressions when the cosine is maximum

        cos (w´t + Ф) = 1

         w’t + Ф = 0

        Ф = -w ’t

        Ф = - [tex]\sqrt{k/3}[/tex] [tex]\sqrt{2y_{o}/g}[/tex]

       \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

b) the function is minimun if

        cos (w’t + fi) = 0

        w’t + Ф = π / 2

        Ф = π / 2 - w ’t

        Ф = [tex]\frac{\pi }{2}[/tex] - \sqrt{\frac{2}{3}  \frac{2 y_{o} }{g}  }

yes

Explanation:

because hindi ko tlaga ala

Answer:

the answer is repel

Explanation:

Answer:

srry i ll get back to with an answer

Explanation:

Answer:

c. because A will land first becuase its heavier :)

Explanation:

Answer:

W = 12 J

Explanation:

Given that,

Force, F = 4 N

The object moves in rightward direction for a distance of 3 m.

Work done on the object is given by :

[tex]W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J[/tex]

So, the work done on the object is 12 J.