Why is an absorption spectrum especially useful for astronomers?.

Answer:

f

Explanation:

Answer:

Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it moving. An example of momentum is how quickly a car is moving down a hill.

Answer:

Air does, in fact, have weight, and here's a simple way you can prove it. You'll need two identical balloons, a string, and a dowel. Attach the uninflated balloons to either end of the dowel. Attach the string to the center of the dowel and then hang it from something.

Explanation:

Answer:

sum of the kinetic and potential energy

Explanation:

Answer:

density = 0.16[gr/cm^3] = 160 [kg/m^3]

Explanation:

To solve this problem we must use the definition of density which tells us that this is equal to the relationship between mass and volume. In this way we have:

Since the body is a cube, its sides are equal we have:

v = 5 * 5 * 5 = 125 [cm^3]

m = 20 [grams]

density = m / v

density = 20/125

density = 0.16 [grams/cm^3]

Now if we convert the units to the international system, we have:

[tex]0.16[\frac{gr}{cm^{3} } ]*\frac{1kg}{1000gr} *\frac{100^{3} cm^{3} }{1^{3} m^{3} } \\= 160 [kg/m^{3} ][/tex]

Answer:

A

Explanation:

the ball pushing on the person

Answer:

Whats up Bmw,

The organisms is caused when both the organisms or species are harmed, which is limited supply of at least one resource from food or even water used by both can be a factor.

Explanation:

Hope I helped you, and let me know if you need help on anything else :p

Answer:

Limited resources lead to competition between organisms

Explanation:

Competition is a negative interaction that occurs among organisms whenever two or more organisms require the same limited resource. All organisms require resources to grow, reproduce, and survive. However, organisms cannot acquire a resource when other organisms consume or defend that resource.

universal gravitation is usually started as the particle extracts every other particle in the universe with the force which is directly proportional to the product of masses and inversely proportional to the square of the distance between their centres.

The compression of 10 cm by a 100 N force on the plane that has a

coefficient of friction of 0.39 give the following values.

Mass of the block, m = 3 kg

[tex]Spring \ constant, K = \dfrac{100 \, N}{0.1 \, m} = \mathbf{ 1000\, N/m}[/tex]

Coefficient of kinetic friction, [tex]\mu_k[/tex] = 0.39

Therefore, we have;

Friction force = [tex]\mathbf{\mu_k}[/tex]·m·g·cos(θ)

Which gives;

Friction force = 0.39 × 3 × 9.81 × cos(48°) ≈ 7.68

Work done by the motion of the block, W ≈ 7.68 × d

The work done = The kinetic energy of the block, which gives;

[tex]\mathbf{\dfrac{1}{2} \times k \cdot x^2 }= 7.68 \cdot d[/tex]

The initial kinetic energy in the spring is found as follows;

K.E. = 0.5 × 1000 N/m × (0.1 m)² = 5 J

The initial velocity of the block is therefore;

5 = 0.5·m·v²

v₁ = √(2 × 5 ÷ 3) ≈ 1.83

Work done by the motion of the block, W ≈ 7.68 N × 0.07 m ≈ 0.5376 J

Chane in kinetic energy, ΔK.E. = Work done

ΔK.E. = 0.5 × 3 × (v₁² - v₂²)

Which gives;

ΔK.E. = 0.5 × 3 × (1.83² - v₂²) = 0.5376

Which gives;

The height at which the block will stop moving, h, is given as follows;

[tex]At \ the \ maximum \ height, \ h, \ we \ have ; \ \dfrac{1}{2} \times 1000 \times 0.1^2 = 7.68 \times x[/tex]

Which gives;

[tex]Length \ of \ the \ incline \ at \ maximum \ height, \ x_{max} =\dfrac{ 7.68 }{ \dfrac{1}{2} \times 1000 \times 0.1^2 } \approx 1.536[/tex]

The distance up the inclined, the block rises, at maximum height is therefore;

[tex]x_{max}[/tex] ≈ 1.536 m

Therefore;

h = 1.536 × sin(48°) ≈ 1.1415

From the above solution for the height, the length of the incline is he

distance along the incline at maximum height which is therefore;

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Answer:

i think that you are right becuase when the line goes down it goes back up and passes 10 and goes down and passes 20 and 20 is 2 10's and 10-10 is 0

Explanation:

i think your right

It is shaped like a pinwheel describing a spiral galaxy. A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.

Spiral galaxies are a type of galaxy first described by Edwin Hubble are part of the Hubble sequence.

A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.

Many of these are surrounded by a fainter halo of stars, many of which are found in globular clusters.

The Pinwheel Galaxy is a spiral galaxy located approximately 21 million light-years from Earth. M101 is the name given to this swirling galaxy by scientists.

In the Northern Hemisphere, it can be found in the constellation Ursa Major, also known as the "Big Dipper." Binoculars or a small telescope can be used to see if the sky is clear and dark.

Hence it is shaped like a pinwheel describing a spiral galaxy.

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Answer:

-273.15 celcius

−218.52 Réaumur

Explanation:

273. 15 kelvin = 0 degrees celcius

C + 273.15 =k

08. Degrees celcius = 1 Réaumur

C x 0.8 = rea

Try the suggested option, all the details are in the attachment.

Explanation:

1) to calculate the moles of CCl₄;

2) to calculate the moles of HF;

3) to calculate the mass of CCl₂F₂;

4) to calculate the mass of ureacted HF.

Answer:

Explanation:

4.0/5

10

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Electrical power  =  (voltage) x (current)

Electrical energy  =  (power) x (time)

Combine those definitions:

            Energy  =  (voltage) x (current) x (time)

Divide each side by (voltage x time), and we have

            Current  =  Energy / (voltage x time)

You told us that

            Energy = 1.8 x 10⁷ joules

            Time  =  1 hour  =  3,600 seconds

so we have

            Current  =  (1.8 x 10⁷) / (voltage x 3,600).

If you live in the US, Canada, or Mexico, your voltage is 120 volts.

            Current = (1.8 x 10⁷) / (120 x 3,600)  =  41-2/3 Amperes

If you live practically anywhere else in the world, your voltage is 240 volts.

             Current = (1.8 x 10⁷) / (240 x 3,600)  =  20-5/6 Amperes.

The mass of water increases, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.

Seawater is salty due to a variety of substances. The majority of them arrive via rivers, which bring chemicals dissolved from rock and soil. The most common is sodium chloride, also known as salt.

The most popular approach to quantify salinity is to count the amount of salt in 1,000 g of water, which is referred to as ppt. The majority of the ocean has a salinity of 34 to 36 parts per thousand.

Salinity makes water colder and denser by lowering its temperature. The chilly water sinks to the ocean's depths. Slow currents carry it throughout the marine basins.

Because the items have a lower density, they flow across the water's surface. As a result, the buoyancy of items in water improves.

So the events that may occur when ocean salinity increases will be;

1)The mass of water increases.

2) Freezing point of water decreases.

3) buoyancy of objects in the water increases.

Hence the masses of water increase, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.

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Answer:

independent variable- concentration of reactants

dependent variable- rate of reaction

Explanation:

A dependent variable is a variable that is placed under test and is measured under the process of a scientific experiment.

An independent variable is a variable that undergoes the change in the experiment performed. This change is done with respect to test the efforts that are observed on the dependent variable.

In the given hypothesis, 'concentration of reactants' is the independent variable and 'rate of reaction' is the dependent variable

Answer:

Frictional force increases with the increase in the roughness of the surface.

Explanation:

You will see that the rougher the surface, the greater the wear and tear.

The equation for kinetic energy of shm system is given by;

KE=0.5mw²(A²-x²)

where m is the mass of the object

w² is the angular frequency

A is the amplitude

and x is the positive

The equation for the potential energy is given by;

PE=0.5mw²x²

Solve KE=2PE and you get ur answer

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Given:

Amplitude [tex]\displaystyle\sf A = 10\,\text{cm} = 0.1\,\text{m}[/tex]

We want to find [tex]\displaystyle\sf x[/tex] such that the kinetic energy [tex]\displaystyle\sf KE[/tex] is twice the potential energy [tex]\displaystyle\sf PE[/tex].

Using the formulas for kinetic energy and potential energy in SHM:

[tex]\displaystyle\sf KE = \dfrac{1}{2}mv^{2}[/tex]

[tex]\displaystyle\sf PE = \dfrac{1}{2}kx^{2}[/tex]

Since we are considering the same particle, the mass [tex]\displaystyle\sf m[/tex] cancels out. Therefore, we can compare the expressions for [tex]\displaystyle\sf KE[/tex] and [tex]\displaystyle\sf PE[/tex]:

[tex]\displaystyle\sf \dfrac{1}{2}kx^{2} = 2\left(\dfrac{1}{2}kA^{2}\right)[/tex]

Simplifying this equation:

[tex]\displaystyle\sf kx^{2} = 2kA^{2}[/tex]

Dividing both sides by [tex]\displaystyle\sf k[/tex]:

[tex]\displaystyle\sf x^{2} = 2A^{2}[/tex]

Taking the square root of both sides:

[tex]\displaystyle\sf x = \sqrt{2}A[/tex]

Substituting the value of [tex]\displaystyle\sf A[/tex]:

[tex]\displaystyle\sf x = \sqrt{2} \times 0.1\,\text{m}[/tex]

Calculating the value:

[tex]\displaystyle\sf x = 0.1414\,\text{m}[/tex]

Converting to centimeters:

[tex]\displaystyle\sf x = 0.1414 \times 100\,\text{cm}[/tex]

[tex]\displaystyle\sf x \approx 14.14\,\text{cm}[/tex]

Therefore, the distance from the mean position at which the kinetic energy is twice the potential energy is approximately [tex]\displaystyle\sf 14.14\,\text{cm}[/tex].

[tex]\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}[/tex]

♥️ [tex]\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}[/tex]

Answer:

Gravity, Friction, Air resistance, magnetism, static electricity

Explanation:

Answer:

gravity friction air resistant are a few

The direction of the electrostatic force on the second charge (charge 2) will be away from the first charge (charge 1).

The electrostatic force between the two charges is determined with Coulomb's law;

F = kq²/r²

F = (9 x 10⁹ x 0.0008²)/(2)²

F = 1,440 N

Since the two charges are the same (positive), the direction of the electrostatic force on the second charge (charge 2) will be away from the first charge (charge 1).

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Answer:

45.1 m/s

Explanation:

use the equation v = u + at  substitute the values v = 0 + 9.8×4.6  v = 45.08  round to about 3 s.f v = 45.1 m/s I do apologize if I'm incorrect.

Answer:

The total current in the circuit is the current that travels thru a single conductor that connects to the parallel circuit (current from a electromotive source, etc.)

I = I1 + I2 + I3 ...... In

If n items are in parallel with another, then I is the total current passing thru these items

Answer:

B. 3

Explanation:

Answer:

b

Explanation:

Answer:

its b, the sun is directly over earths north end

Explanation:

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 3.75 g

volume = final volume of water - initial volume of water

volume = 28 - 25 = 3 mL

We have

[tex]density = \frac{3.75}{3} \\ [/tex]

We have the final answer as

Hope this helps you

A) The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg  

B) The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g

To calculate the PBR catalyst weight required to achieve 80% conversion in the absence of pressure drop we will apply the equation below

w = [tex]\frac{V_{o} }{KC_{ao}(1/x - 1 ) }[/tex]  ---- ( 1 )

insert values into equation ( 1 )

w = [tex]\frac{50 kmol}{0.54 * 10 (\frac{1}{0.8}) * 1 }[/tex]

PBR catalyst weight ( w ) = 370 mg

applying the equation below

W = [tex]\frac{Fbwx}{-r'Bu}[/tex]

   = [tex]\frac{50kmol/r * 0.8}{0.042mol/gcat.h}[/tex]

   = 995.025 gcat

Hence we can conclude that The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg  The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g.

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Answer:

helium and hydrogen

Explanation: