If you take a given pendulum to the Moon, where the acceleration of gravity is less than on Earth, the resonant frequency of the pendulum will
As the acceleration of gravity is less on the moon than on the Earth, thus the resonant frequency of the pendulum will be less on the moon.
Explanation:
The acceleration due to gravity is less on the moon than the gravitational acceleration on the earth. It is required to examine how the resonant frequency of a pendulum is changed on the moon compared to the earth.
We know that the resonant frequency is dependent on the acceleration of gravity.
[tex]$f=\frac{1}{2 \pi} \sqrt{\frac{g}{l}}$[/tex] where g is the acceleration due to gravity and l is the length of the string.
From the above equation, it is clear that the resonant frequency is directly proportional to the square root of the acceleration due to gravity.
The gravitational acceleration on the moon is less than that on the earth.
Therefore the resonant frequency of the pendulum on the moon is less than that on the earth.
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The evolutionary cutoff between low- and high-mass stars occurs at approximately:
The evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
What are high-mass stars?The high-mass stars are celestial bodies that exhibit a high level of luminosity and lived for short periods of time.
Conversely, low-mass stars are small and cool stars that lived for a long period of time.
In conclusion, the evolutionary cutoff between low- and high-mass stars occurs at eight (8) M.
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Even with the best and largest telescopes, we can’t see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. Why is that?
Because starlight cannot pass through black space, we are unable to view all of the stars in the Milky Way galaxy, even with the best and largest telescopes.
In the Milky Way galaxy, the Earth is situated. Part of it can be seen as a broad, opaque ring of stars and dust on a clear night (from sufficiently dark areas). We can see thousands of these stars with our unaided eyes, and a telescope can reveal many more.
However, a large number of the Milky Way's stars are obscured. The supermassive black hole at the centre of the galaxy and the bulge, which is made up of stars, gas, and dust, are to blame for this. The substance in this is opaque to all but the most powerful telescopes.
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= Sem 2 CR-SS159VGSZE
nating a my ponnesis. I art
Since the investigative question has two variables, you
need to focus on each one separately. Thinking only
about the first part of the question, mass, what might be
a hypothesis that would illustrate the relationship
between mass and kinetic energy? Use the format of
"if...then...because..." when writing your hypothesis.
The relationship between mass and kinetic energy is K.E ∝ m and K.E ∝ v².
What is the relationship between mass and kinetic energy?The kinetic energy of an object exists as the energy that it maintains due to its motion. It is defined as the work required to accelerate a body of a disseminated mass from rest to its stated velocity. Having acquired this energy during its acceleration, the body preserves this kinetic energy unless its speed changes.
The kinetic energy is directly proportional to the mass and also directly proportional to the square of the velocity.If we increase the mass, then kinetic energy will also increase.But if we increase the velocity by n times , then the kinetic energy will increase by [tex]n^{2}[/tex] times.To know more about kinetic energy, refer:
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51. After conducting a search directly above the floor of a fire in a high rise building what is your next priority
After conducting a search directly above the floor of a fire in a high rise building what is your next priority is that their own safety is the first priority.
Life safety is the top consideration at any fire incident. Firefighters practice frequently to be ready to free trapped persons from a burning structure. On some occasions, though, it's the firefighters who require assistance.What are the three incident priorities?
Reviewing the three main responsibilities on the fireground—life safety, incident stabilization, and property preservation—is a good idea. These three concerns must be taken care of at every fire scene to which we react. The circumstances will determine which ones are addressed in what order.Learn more about firebrigade safty rules
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The following is regarding Momentum Change and Force. help is needed please!
1. A force of 50 N acts on an object of mass 250 kg which is initially at rest, for 10 s. find the distance travelled and the velocity gained at the end of this time.
The distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
Velocity of the object at the end of the timeF = mv/t
where;
m is mass of the objectv is velocity of the objectt is timeFt = mv
v = Ft/m
v = (50 x 10)/250
v = 2 m/s
Distance traveled by the objectv² = u² + 2as
where;
u is initial velocity = 0
a is acceleration
a = F/m
a = 50 N/ 250 kg
a = 0.2 m/s²
v² = 0 + 2as
s = v²/2a
s = (2²)/(2 x 0.2)
s = 10 m
Thus, the distance travelled is 10 m and the velocity gained at the end of this time is 2 m/s.
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Jan is holding an ice cube. What causes the ice to melt?
Thermal energy from the ice is transferred to the air.
Thermal energy from Jan’s hand is transferred to the ice.
The air absorbs thermal energy from Jan’s hand.
Jan’s hand absorbs thermal energy from the ice.
The ice melts because Thermal energy from Jan’s hand is transferred to the ice.
What is thermal energy?Thermal energy is the energy due to temperature difference.
Thermal energy flows from hotter to colder bodies.
The ice Jan is holding melts because heat is transferred from his hands t the ice.
In conclusion, thermal energy flow causes melting.
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Answer:
its b
Explanation:
because the heat from your hand makes the ice melt!
4. Which is the best season for shearing? Why?
Answer:
During dry season /Spring
Explanation:
Shearing is the removal of wool from a sheep. When you remove wool from sheep, you subject the sheep to cold since nothing is covering the entire body. Therefore, the most suitable season is during dry periods/ Spring since you won't subjects the sheep to cold but warm environment. Thus important to consider that.
PLSLPSLLPSLPSLPS HELP I ONLY HAVE 5 MINS PLEASE
a bus slows down from 50.0 km/h to 36.5/h in the school zone. determine the magnitude of the vehicle's acceleration if it took 19.5 seconds to slow down.
Answer:
0.19m/s²
Explanation:
Initial velocity(u) = 50×1000/60×60
=13.88 m/s
Final velocity(v) = 36.5×1000/60×60
=10.13 m/s
Acceleration(a) = v-u/t
=10.13-13.88/19.5
a= -0.19m/s²
-a = 0.19m/s²
The magnitude of retar dation is 0.19m/s²
Answer:
[tex]\sf 0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]
Explanation:
Given:
initial velocity (u) = 50.0 km/hfinal velocity (v) = 36.5 km/htime (t) = 19.6 secondsFirst, convert the velocities into meters per second by dividing by 3.6:
[tex]\implies \sf 50.0\: km h^{-1}=\dfrac{50.0}{3.6}\:ms^{-1}= \dfrac{125}{9}\:ms^{-1}[/tex]
[tex]\implies \sf 36.5\: km h^{-1}=\dfrac{36.5}{3.6}\:ms^{-1}= \dfrac{365}{36}\:ms^{-1}[/tex]
To find the vehicle's acceleration, use one of the constant acceleration equations with the given values:
[tex]\implies \sf v=u+at[/tex]
[tex]\implies \sf \dfrac{365}{36}=\dfrac{125}{9}+19.5a[/tex]
[tex]\implies \sf \dfrac{365}{36}-\dfrac{125}{9}=19.5a[/tex]
[tex]\implies \sf 19.5a=-3.75[/tex]
[tex]\implies \sf a=-\dfrac{3.75}{19.5}[/tex]
[tex]\implies \sf a=-0.1923076923...\:ms^{-2}[/tex]
Therefore, the magnitude of acceleration is:
[tex]\implies \sf |a|=|-0.19230...|=0.192\:ms^{-2}\:\:(3\:s.f.)[/tex]
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He wavelengths of the sounds produced by two horns are 6.0 m and 7.0 m, respectively. what beat frequency is heard when the horns are sounded on a day when the speed of sound is 340 m/s?
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
frequency = speed / wavelength
f1 = 340 / 6 = 56.67 Hz
f2 = 340 / 7 = 48.57 Hz
Beat frequency = fb = | f2 - f1 |
= | 48.57 - 56.67 |
= 8.1 Hz
The beat frequency will be 8.1 Hz when the horns are sounded on a day when the speed of sound is 340 m/s
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Define mass .Also write the table showing the relation of 'kg' with it's sub- multiples and multiples.
Answer:
the quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Answer:
The quantity of matter contained in a body is called mass .si unit of mass is kilogram.weight is effected by gravity but mass is not effected by gravity.
Explanation:
Calculate the force needed to give a car of mass 800 kg an acceleration of 2.0 ms−2. plss quick
The force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.
How to calculate force?The force needed to push an object can be calculated by multiplying the mass of the object by its acceleration as follows:
Force = mass × acceleration
According to this question, a car of mass 800 kg has an acceleration of 2.0 ms−². The force is calculated as follows:
Force = 800kg × 2m/s²
Force = 1600N
Therefore, the force needed to give a car of mass 800 kg an acceleration of 2.0 ms-² is 1600N.
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Consider a two-dimensional projectile motion problem involving a ball starting and ending at the same height. the projectile leaves the ground with an initial velocity of 10 m/s at some angle theta with the horizontal, (a) what value of the angle theta (in degrees) makes the range of the projectile maximum? explain, (b) what is the range at this angle? (c) how long does it take for the ball to reach maximum height? (d) what is the maximum height?
The range of the projectile is maximum at angle 45°, the range is 10.2m, the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m
What is a Projectile ?The stone, or object or anything projected in a trajectory path is known as a projectile.
In the given two-dimensional projectile motion problem involving a ball starting and ending at the same height. the projectile leaves the ground with an initial velocity of 10 m/s at some angle Ф with the horizontal,
(a) The value of the angle Ф (in degrees) which will makes the range of the projectile maximum is angle 45° because Range = u²sin2Ф ÷ g
At Ф = 45
Range = u²sin90° ÷ g
where sin 90 = 1
So, Range = u² / g which is the maximum range.
(b) The range at this angle will be
Range = 10² ÷ 9.8
Range = 100 / 9.8
Range = 10.2 m
(c) To calculate how long it takes the ball to reach maximum height, we will use the formula
t = usinФ ÷ g
t = 10 sin 45 ÷ 9.8
t = 0.72s
(d) The maximum height will be
H = u²sin²Ф ÷ 2g
H = 10²(sin45)² ÷ 2 × 9.8
H = 100 × 0.5 ÷ 19.6
H = 50 ÷ 19.6
H = 2.55 m
Therefore, the range of the projectile is maximum at angle 45°, the range is 10.2m, the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m
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The work-energy principle states that the work done by all the __________ forces acting on an object (or system of objects) causes a change in total __________ of the object or system.
The work-energy principle states that the work done by all the non-conservative forces acting on an object (or system of objects) causes a change in the total mechanical energy of the object or system.
What is the work-energy principle?
The work-energy principle states that the total work done on a system is equal to the change in kinetic energy of the system. It is given as:
W.D = ΔK.E
= K.E₁ - K.E₂
where K.E₁ is the initial kinetic energy of the system
K.E₂ is the final kinetic energy of the system
What is meant by non-conservative forces?
Non-conservative forces as the name suggests are not conserved i.e. these forces cause a loss of mechanical energy from the system. A prime example of non-conservative forces is friction.
The total mechanical energy of the system is the sum of the potential energy and kinetic energy that the system contains. This energy is conserved and follows the work-energy theorem.
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Please give detailed explanation
Answer:
» (a)
Explanation:
Velocity is the rate of change in displacement.
[tex]{ \rm{velocity = \frac{ \triangle displacement}{time} }} \\ [/tex]
The change from one position to another is displacement or distance between the points.
[tex] = { \rm{ \frac{22000}{200} }} \\ \\ = { \tt{110 \: m {s}^{ - 1} }}[/tex]
How should you plan to excercise if you want to remain healthy past the age of 65
Explanation:
by taking a brisk walking about 150 minutes
2 days a week exercise that strengths muscles
drinking water
A molecular cloud fragments as it collapses because Choose one: A. the interstellar wind is stronger in some places than others. B. the density increases fastest in the center of the cloud. C. the rotation of the cloud throws some mass to the outer regions. D. density variations from place to place grow larger as the cloud collapses.
The cause for a molecular cloud forming fragments when it collapses is indicated correctly by option D. density variations from place to place grow larger as the cloud collapses.
Molecular cloud:
A molecular cloud, also known as a stellar nursery, is a specific kind of interstellar cloud, whose density and size allow the development of molecules, absorption nebulae, and H II regions. In contrast, some regions of the interstellar medium mostly consist of ionized gas.
Molecular clouds are cold, dense areas of space where stars form. The cloud collapses into a proto-star when the gravitational force pulling it in outweighs the internal pressure pushing it in.
When a molecular cloud collapses, it is observed that the density varies from place to place with the variation increasing with collapse. As a result, the collapse is characterized by fragmentation of the cloud.
Thus the correct option is: D. density variations from place to place grow larger as the cloud collapses.
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What is a stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second?
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
Discharge rate = velocity * area
= velocity * depth * width
= 2 * 2 * 10 = 40 [tex]m^{3}[/tex]/sec
A stream’s discharge rate if it has a width of 10 meters, a depth of 2 meters, and a velocity of 2 meters per second will be 40 [tex]m^{3}[/tex]/sec .
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The mississippi river delta is one in which the primary source of local current energy is ____.
Answer:potential energy
Explanation:
PLS GIVE RIGHT ANSWER
I GIVE UP
YOU WILL GET 100 PTS or MORE
Answer:
it is in explanation part
Explanation:
9
7
3
2
5
8
1
11
14
12
13
Answer:
Explanation:
what is the number of moles in 12.04×10²³ particles of NH3?
Answer:
[tex]\huge\boxed{\sf m = 2 \ moles}[/tex]
Explanation:
Given data:No. of particles = 12.04 × 10²³ particles
Avogadro's number = 6.02 × 10²³
Required:No. of moles = n = ?
Formula:[tex]\displaystyle No. \ of\ moles\ = \frac{no.\ of \ particles}{Avogadro's \ number}[/tex]
Solution:Put the given in the above formula
[tex]\displaystyle n =\frac{12.04 \times 10^{23}}{6.02 \times 10^{23}} \\\\n = 2 \times 1 \ moles\\\\m = 2 \ moles\\\\\rule[225]{225}{2}[/tex]
To correct myopia (nearsightedness) requires ___________ lenses; to correct hyperopia (farsightedness) requires _____________ lenses to correct.
By using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
To find the answer, we need to know about Myopia and Hyperopia.
What is Myopia and Hyperopia?Myopia is an optical defect, in which a person can see nearby objects clearly and cannot see far off objects clearly.Here the eyeball becomes too longer, and the focal length of eye lens become too short.It can be corrected by using concave lens.For Hyperopia, the person can see far off objects clearly and cannot see nearby objects clearly.This can be corrected by using convex lens.Thus, we can conclude that, by using concave lens, we can correct Myopia and Hyperopia can be corrected by convex lenses.
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Myopia can be corrected using concave lenses, while the Hyperopia is corrected by convex lenses.
We need to be aware of myopia and hyperopia in order to locate the solution.
Myopia and hyperopia: what are they?Myopia is an optical defect in which a person can see clearly up close but not clearly far away.Here, the eyeball lengthens excessively and the eye lens focal length contracts.Concave lenses can be used to rectify it.A person with hyperopia can clearly see distant objects but cannot see nearby objects clearly.Convex lenses can be used to fix this.Thus, we can deduce that myopia and hyperopia can be corrected using concave lenses and convex lenses, respectively.
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What does the length of a vector arrow represent?
O A. angle
OB. magnitude
C. direction
OD. force
A computer uses 3.5 A at 110 V. What is its resistance in ohms?
Answer:
31.43 Ω
Explanation:
Using Ohm's Law:
[tex]\displaystyle{V=IR}[/tex]
Where V = voltage (V) , I = electric current (A) and R = resistance (ohm)
We know that a computer uses 3.5 ampere at 110 volt, we want to know the resistance. Therefore substitute V = 110 and A = 3.5
[tex]\displaystyle{110=3.5R}\\\\\displaystyle{\dfrac{110}{3.5}=R}\\\\\displaystyle{R=31.43}[/tex]
Therefore, the resistance will be around 31.43 Ohm
If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, what is the Earth's Mass
Answer: If the Moon takes 27.3 days to complete its orbital path around the Earth, and the orbit has a radius of 3.8 x 108 meters, then, the Earth's Mass is [tex]6*10^{24}kg[/tex].
Explanation: To find the answer, we have to know more about the Law of periods or the harmonic law.
What is the law of periods or harmonic law?The law of periods states that, the square of the period of revolution of a planet is proportional to the cube of the semi major axis of the elliptical path.We can express it as,[tex]T^2[/tex]∝ [tex]r^3[/tex]
[tex]T^2=\frac{4\pi ^2r^3}{GM}[/tex]
How to solve the problem?From the above given equation, we can reduce mass of earth as,[tex]M=\frac{4\pi ^2r^3}{GT^2}[/tex]
Substituting the values given in the question, we get,[tex]M=\frac{4\pi ^2(3.8*10^8)^3}{6.67*10^-11*(27.3*24*60*60s)^2} =\frac{2.164*10^{27} }{371.08} =5.831*10^{24}=6*10^{24}kg[/tex]
Thus, we can conclude that, the mass of earth is [tex]6*10^{24}kg[/tex] .
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Astronomers have realized that the surface of ida is older than the surface of gaspra. How do they measure this?
From counting craters on each asteroids , astronomers have realized that the surface of ida is older than the surface of gaspra.
Ida, and Gaspra are three objects located in the asteroid belt between Mars and Jupiter.
Crater counting is a method for estimating the age of a planet's surface based upon the assumptions that when a piece of planetary surface is new, then it has no impact craters; impact craters accumulate after that at a rate that is assumed known.
Counting how many craters of various sizes there are in a given area allows determining how long they have accumulated and consequently, how long ago the surface has formed. Hence , from counting craters on each asteroids ,astronomers have realized that the surface of ida is older than the surface of gaspra.
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A 50.0 g stone is attached to the bottom of a vertical spring and set vibrating. If the maximum speed of the stone is 15.0 cm/s and the period is 0.500 s, find the (a) spring constant of the spring, (b) amplitude of the motion, and (c) frequency of oscillation.
Spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
To find the answer, we need to know about angular frequency, frequency, amplitude of spring mass system.
What's the angular frequency of the spring mass system, if its time period is 0.5 second?Mathematically, w=2π/Tw= 2π/0.5= 12.6 rad/sWhat's the relation between angular frequency and spring constant?Mathematically, w =√(k/m)k= w²mHere, w= 12.6 rad/s, m= 50gm = 0.05kg k= 12.6²× 0.05 = 8 N/mWhat's the relation between amplitude, angular frequency and velocity of mass of a spring mass system?Mathematically, Amplitude= velocity/angular frequencyHere, velocity= 15 cm/s = 0.15m/s, angular frequency= 12.6 rad/sAmplitude= 0.15/12.6= 0.012m = 1.2 cmWhat's the expression of frequency in term of time period?Frequency= 1/time periodHere time period= 0.5 sFrequency= 1/0.5 = 2 HzThus, we can conclude that spring constant of the spring, amplitude of the motion, and frequency of oscillation are respectively 8N/m, 1.2 cm and 2Hz.
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What was Kobe’s attitude toward life and competition?
Answer: Positive
Explanation: Kobe has had an positive attitude on situations and life itself. No matter the competition he still kept a positive attitude regardless. He still wished the best for others even if his enemies thought otherwise. So Kobe was a positive person on the outlook of life and competition.
A hypothetical metal has the bcc crystal structure, a density of 7. 24 g/cm3, and an atomic weight of 48. 9 g/mol. The atomic radius of this metal is.
Atomic radius of this metal is 0.85 x 10^23
Given:
density of metal = 7. 24 g/cm3
metal has the bcc crystal structure
atomic weight = 48. 9 g/mol
To Find:
atomic radius of this metal
Solution: Atomic radius is defined as half the distance between the centers of two neighboring atoms. the atomic radius of a simple cube and hcp is a/2 respectively, whereas it is a√2/4 and a√3/4 for fcc and bcc respectively.
density = Z x M/N• x a^3
a = edge length
Z = 2 atoms = numeber of atoms per unit cell
N• = 6.023 x 10^23 atoms/mol = Avogadro's number
a^3 = density x N•/Z x M
a^3 = 7.24 x 6.023 x 10^23/ 2 x 48. 9
a = 3√0.44 x 10^23
a = 1.98 x 10^23
4R = √3a
R = √3 x 1.98 x 10^23/4
R = 0.85 x 10^23
Atomic radius of this metal is 0.85 x 10^23
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A 350-g mass is attached to a spring whose spring constant is 64 N/m. Its maximum acceleration is 5.3 m/s2. What is the frequency of its oscillations?
The frequency of oscillation is 2.153 Hz
What is the frequency of spring?
Spring Frequency is the natural frequency of spring with a weight at the lower end. Spring is fixed from the upper end and the lower end is free.
For the mass-spring system in this problem,
The Frequency of spring is calculated with the equation:
[tex]f = \frac{1}{2\pi } \sqrt{\frac{k}{m} }[/tex]
Where,
f = frequency of spring
k = spring constant = 64 N/m
m = mass attached to spring = 350g = 0.350 kg
a = maximum acceleration = 5.3 m/s^2
Substituting the values in the equation,
[tex]f = \frac{1}{2\pi } \sqrt{\frac{64}{0.350} }[/tex]
[tex]f = \frac{1}{2\pi } ( 13.522)[/tex]
[tex]f = 2.1535 Hz[/tex]
Hence,
The frequency of oscillation is 2.153 Hz
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