Why must the rockets use great force to get into outer space?

Answers

Answer 1
Because of the gravity that is weighing down the rocket

Related Questions

plzzzz help me will mark u brainiest

Answers

Answer:

D

Explanation:

A 10kg box is sliding at 50m/s. Find the momentum

Answers

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

quit my nose so you have a bad guy really good guy​

Answers

Answer:

hmmmmmmmmmmmmmmm

yes.

An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?

Answers

Answer:

You need to put the diagrams. repost and include the diagrams

Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?

Answers

Answer:

30 Watts

Explanation:

 Power = Work/Time

Work = Force*Distance

Power = Force * Distance / Time

Power = 15 N * 20 meters / 10 sec

Power = 30 Watts

A car with a mass of 900 kg is traveling at a
speed of 25 m/s. What is the kinetic energy
from the car's motion?

Answers

Explanation:

Kinetic Energy

= 0.5mv²

= 0.5(900kg)(25m/s)²

= 281,250J.

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?

Answers

Answer:

either its 12 or 0.402

Explanation:

An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.

Answers

Answer:

The final velocity, [tex]v_{f}[/tex], is gd.

Explanation:

The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;

[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs

where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.

Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.

So that;

[tex]v_{f}[/tex] = 0 + 2gd

   = 2gd

[tex]v_{f}[/tex] = 2gd

When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.

Then;

[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]

[tex]v_{f}[/tex] = g x d

When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.

PLZ HELP I DONT GET IT
A sealed can of your favorite soda has a carbon dioxide gas (CO2) volume of 0.05 L. When it is refrigerated, the pressure is 207 kPa. When you open it, the pressure drops to 101 kPa. After opening, what will the new volume of the carbon dioxide gas be?

Answers

Answer:

0.1 L

Explanation:

From the question given above, we obtained the following data:

Initial volume (V₁) = 0.05 L

Initial Pressure (P₁) = 207 KPa

Final pressure (P₂) = 101 KPa

Final volume (V₂) =?

We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

207 × 0.05 = 101 × V₂

10.35 = 101 × V₂

Divide both side by 101

V₂ = 10.35 / 101

V₂ = 0.1 L

Thus, the new volume of the gas is 0.1 L

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

                                   

                                           

A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied​

Answers

Answer:

1) 4000Joules

2) 25%

3) 320N

Explanation:

A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.

Calculate;

1)The work done by the effort

2)The efficiency of the system

3)The effort applied

1) Workdone by the effort is the work input = Load * distance moved by the Load

Workdone by the effort = 400 * 10

Workdone by the effort = 4000Joules

2) Efficiency = Work output/Work input * 100

Work output = work done against friction = 100 Joules

Efficiency = 100/4000 * 100

Efficiency = 10000/4000

Efficiency  = 25%

Hence the Efficiency of the system is 25%

3) Using the efficiency formula:

efficiency = MA/VR * 100

Velocity ratio = 5

MA = Load/Effort

efficiency = (L/E)/5 * 100

25 = 400/E/5 * 100

25/100 = 400/5E

0.25 = 400/5E

0.25 * 5E = 400

1.25E = 400

E = 400/1.25

E = 320N

hence the effort applies is 320N

Cellular respiration occurs in the body 24 hours per day. During exercise, the rate of cellular respiration increases. Why does increased cellular respiration cause people to breathe faster?


More oxygen is needed to produce energy, and more carbon dioxide waste must be removed from the body.


More nutrients are needed to produce more energy, and more oxygen must be removed from the body.


More heat is generated by the body, and breathing cools the body quickly.


More water is lost from the body, and breathing hydrates the body.

Answers

Answer: I think is C

Explanation:

Answer: more oxygen is needed to produce energy

If an arrow is fired from a bow with a perfectly horizontal velocity of 60.0 m/s and the arrow had a vertical velocity of 6m/s just before it hit the ground, how long will it take to strike the ground ?

Answers

Answer:

t  =  1,28 s

Explanation: This problem is a projectile motion problem.

V₀ₓ = V₀ * cosθ

Vₓ  = constant all the way

Vₓ = V₀ₓ

tanθ  = Vyi/Vxi            that means in any point of the trajectory

tanθ  = 6 / 60         ( just before touching the ground )

tanθ  =  0,1       then arctan 0,1  ≈ 6⁰

sin 6⁰  =  0,1045

cos 6⁰ = 0,9945

V₀ₓ = V₀ * cosθ       ⇒  V₀  =  V₀ₓ / cosθ     ⇒  V₀  = 60 / 0,9945

V₀ = 60,33 m/s

V₀y = V₀  *  sin θ   ⇒   V₀y =  60,33 * 0,1045    ⇒  V₀y =  6,30 m/s

Vy = V₀y  - g * t

At  maximum y  Vy = 0    ( the middle of the trajectory)

g*tm = V₀y       ⇒    tm= V₀y / g

tm =  6,30 / 9,8

tm =  0,64 s       ( time to reach maximum y )

Then the time of fligh is twice 0,64 s

t   = 0,64 * 2

t  =  1,28 s

Two soccer players run toward each other. One player has a mass of 85 kg
and runs west with a speed of 8 m/s, while the other has a mass of 105 kg
and runs east with a speed of 7 m/s. What is the total momentum of the
system made up of the two players?

Answers

Answer:

Total momentum, p = 55 kg-m/s

It is given that,

Mass of player 1, m₁ = 85 kg

Mass of player 2, m₂ = 105 kg

Speed of player 1, v₁ = -8 m/s (west)

Speed of player 2, v₂ = 7 m/s (east)

Momentum is equal to the product of mass and velocity. For this system, momentum is given by :

p=m_1v_1+m_2v_2p=m

1

v

1

+m

2

v

2

p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s

p = 55 kg-m/s

The total momentum of the system made up of the two players is 55 kg-m/s.

Answer:

p = 55 kg * m/s east

Explanation:

The answer above explains it neatly, but leaves the direction out of the answer. The player heading east has more momentum, so the net momentum of the system is east.

Queremos un cilindro de simple efecto que utilice en su funcionamiento un volumen de aire a presión atmosférica de 13,122 litros, cuya presión de trabajo sea de 8,5Kgf/ cm2 y cuya longitud sea de 20 cm. -hallar el diámetro de este cilindro. - calcular las fuerzas de este cilindro.

Answers

Answer:

1) El diámetro es de aproximadamente 913,987 cm.

2) La fuerza del cilindro es 5576850 kgf

Explanation:

1) Los parámetros dados son;

El volumen del aire = 13,122 litros = 13122000 cm³

La presión de trabajo = 8.5 kgf / cm²

La longitud del cilindro = 20 cm.

Por lo tanto, tenemos;

El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²

r = √ (656100 / π) ≈ 456,994 cm

El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm

El diámetro ≈ 913,987 cm

2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo

∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf

La fuerza del cilindro = 5576850 kgf

A body moving in a straight line has a uniform motion if it travels ---------- distance in -------- intervals og time

Answers

Answer:

uniform an uniform

please fill it like yhis

liquids that do not mix form into layers when they have_ densities

Answers

Answer:

different

Explanation:

Question 4 of 10
The pendulum below swings in periodic motion between point A and point B.
А
B
C
D

Answers

Answer: C

Explanation:

The pendulum will have the most energy at the bottom of its swing

c. At point C  the pendulum have the most kinetic energy.

What is Kinetic energy?

Kinetic energy is a form of energy that an object or a particle has by reason of its motion.

If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

Kinetic energy is defined as:

⇒E = 1/2mv²

Here, the mass of the pendulum bob won't change, the only way for kinetic energy to change is for the speed of the pendulum to change. Kinetic energy is highest when the velocity is the highest.

This occurs at the bottom of the pendulum. An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.

Therefore,

At point C  the pendulum have the most kinetic energy.

Learn more about Kinetic energy here:

https://brainly.com/question/999862

#SPJ5

Please help me I swear will mark you brainiest

Answers

Answer:

B

Explanation:

I hope this helps!!! <3

Answer:

B.......

Explanation:

Hope this helped

what is the correct answer?

Answers

Answer:

harder daddy

Explanation:

True or false Adding salt to a pot of water will decrease the temperature that water boils at.

Answers

Answer:water gets hot at 212 so incress

Explanation:

Answer:

False

Explanation:

It will increase

here avarose566 you need this

Answers

Answer:

ooooooooooooooooo

Explanation:

*makes holy water*

HAHAHAHAHAHAH NO I NEED A DCIK

State two devices that transfer heat out of a cool environment into a warm environment​

Answers

Answer:

Heat pump

Refrigerators

Explanation:

Some devices like heat pump and refrigerators used transfers of thermal energy in a cool region to warm other region.

These types of devices used for transferring heat energy by thermal conduction method.

Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)

Answers

Answer:

Vf = 9.46 m/s

Explanation:

In order to find the final velocity of the dog we can use third equation of motion:

2gh = Vf² - Vi²

where,

g = acceleration due to gravity = 9.8 m/s²

h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m

Vf = Final Velocity of Dog = ?

Vi = Initial Velocity of Dog = 0 m/s

Therefore,

(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²

Vf = √(89.572 m²/s²)

Vf = 9.46 m/s

A student attaches a block to a force sensor and pulls it across a frictionless table. The sensor measures the block's acceleration What type of mass does the student measure ?
a. gravitational mass
b. inertial mass
c. neither

Answers

Answer:Inertial mass

Explanation:When we measure gravitational mass we find the strength of an object's interaction with a gravitational field.

When we measure inertial mass we find an object's resistance to being accelerated by a force.

An object's gravitational mass and inertial mass are the same.

We apply a force and measure the resulting acceleration, so we can use Newton’s second law to find the inertial mass.

If it requires E joules of energy to raise a mass from the surface of the Earth to an altitude of 6,000 km above the Earth, how much energy is required to raise it from the surface to an altitude of 12,000 km?​

Answers

Answer:

To raise the mass to an altitude of 12,000 Km 2E joules are required.

Explanation:

Gravitational Potential Energy

It's the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where:

m = mass of the object

h  = height with respect to a fixed reference

g  = acceleration of gravity, or [tex]9.8 m/s^2[/tex].

If a mass has a height h1, its potential energy is

[tex]U_1=m.g.h_1[/tex]

If a mass has a height h2, its potential energy is

[tex]U_2=m.g.h_2[/tex]

The ratio of both potential energies is:

[tex]\displaystyle \frac{U_2}{U_1}=\frac{m.g.h_2}{m.g.h_1}[/tex]

Simplifying:

[tex]\displaystyle \frac{U_2}{U_1}=\frac{h_2}{h_1}[/tex]

Solving for U2:

[tex]\displaystyle U_2=U_1.\frac{h_2}{h_1}[/tex]

Since U1=E:

[tex]\displaystyle U_2=E.\frac{12,000~Km}{6,000~Km}[/tex]

[tex]U_2 = 2E[/tex]

To raise the mass to an altitude of 12,000 Km 2E joules are required.

A teacher pushes a cart, while a student pushes a second, heavier cart
with the same amount of force. If the student's cart has three times the
mass as the teacher's, which of the following is true? *

Answers

Answer:

frictional force acting on the cart 450 N.

Given:

mass of cart = 50 kg

acceleration = 3

To find:

Frictional force = ?

Formula used:

F -  = 600 N

F = ma

= frictional force

Solution:

Force on the block is given by,

F -  = 600 N

F = ma

= frictional force

= 600 - m a

= 600 - (50 × 3)

= 600- 150

= 450 N

According to the given data the frictional force acting on the cart 450 N.

solvent that can be used to remove ink from clothes and cleaning greasy
hands​

Answers

Answer:

Rubbing Alcohol

Explanation:

How do bubbles support the atomic theory?
A. The bubbles are lighter than air.
B. There is matter that cannot be seen inside the bubbles.
C. The bubbles will burst before long.
D. The bubbles cannot be broken into smaller pieces.

Answers

Answer:

The answer is probably B or C

Option B supports the atomic theory. Thus, this option is correct.

Atomic theory is the theory which states that matter is composed of particles called atoms. It tells us that all the matters are made of very tiny particles called atoms and all atoms of the same kind have the same size in any object.

Let's look at all the options given,

A-The bubbles are lighter than air- The bubble consists of water and air thus they are not lighter than air. This statement does not tell anything about the atomic theory. Hence this option is not correct.

B. There is a matter that cannot be seen inside the bubbles-The bubble is made up of two kinds of atoms one is oxygen and another is hydrogen. When we feel air into a soap bubble solution molecules want to attract to each other again so they wrap around the burst of air to attach to each other again. These atoms cannot be seen inside the bubbles but this option support the atomic theory. Thus, this option is correct.C. The bubbles will burst before long-In the bubble there is water. When this water loss in some way the bubble pops up. This water can be lost when it comes to contact with dry fingers or objects. It can be burst when the atmosphere is very dry. All the atoms are attracted towards.

D. The bubbles cannot be broken into smaller pieces-This option does not support the atomic theory thus this is not the correct option.

Hence the option B supports the atomic theory. Thus, this option is correct.

For more about the atoms follow the link below-

https://brainly.com/question/13981855

In her lab, Mrs. Smith is pulling a 28 N block across a surface with a constant speed. If
she must pull with a force of 4.0 N, what is the coefficient of sliding friction between the
block and the lab table?

Answers

Answer:

0.14 is the friction coefficient.

Explanation:

The equation for the friction coefficient is friction coefficient = force/normal force. The force is 4N, and the normal force is 28N. 4/28=0.14.

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