Answer:
A magnesium atom must lose two electrons to have the same number electrons as an atom of the previous noble gas, neon. Thus, a magnesium atom will form a cation with two fewer electrons than protons and a charge of 2+. The symbol for the ion is Mg2+, and it is called a magnesium ion.
Acetylene C2H2 gas is often used in welding torches because of the very high heat produced when it reacts with oxygen O2 gas, producing carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 1.60mol of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to 3 significant digits.
Answer:
3.20 moles of carbon dioxide
Explanation:
The reaction of C₂H₂ with O₂ is:
C₂H₂ + 5/2O₂ → 2CO₂ + H₂O
Where 1 mole of acetylene produce 2 moles of carbon dioxide.
Based on the chemical equation of this reaction, there are produced twice the moles of acetylene in moles of carbon dioxide assuming a compete reaction.
If 1.60 moles of acetylene reacts there are produced:
1.60 moles * 2 =
3.20 moles of carbon dioxidebalance by oxidation number method<br />KMnO4 + Na2O₂ + H2 so4 ko2so4 +<br />Mosou4 + Na2so<br />4 + O2 + H₂O
Answer:
8H2SO4 + 2KMnO4 + 5Na2O2 => 8H2O + 2MnSO4 + 5Na2SO4 + 5O2 + K2SO4
have:
Explanation:
Calculate the mole fraction of each solute and solvent in the solution of 46.85 g of codeine, C 18 H 21 NO 3 , in 125.5 g of ethanol, C 2 H 5 OH.
mol fraction Codein : 0.054
mol fraction Ethanol : 0.946
Further explanationGiven
46.85 g of codeine
125.5 g of ethanol
Required
mol fraction
Solution
The mole fraction : the mole ratio of a substance to the mole of solution /mixture
mol Codeine, C₁₈H₂₁NO₃(MW=299.4 g/mol) :
[tex]\tt mol=\dfrac{46.85}{299.4 g/mol}\\\\mol=0.1565[/tex]
mol Ethanol, C₂H₅OH(MW=46.07 g/mol)
[tex]\tt mol=\dfrac{125.5}{46.07}=2.7241[/tex]
mol of solution :
[tex]\tt mol~codein+mol~ethanol=0.1565+2.7241=2.8806[/tex]
mol fraction Codein :[tex]\tt \dfrac{0.1565}{2.8806}=0.054[/tex]
mol fraction Ethanol :
[tex]\tt \dfrac{2.7241}{2.8806}=0.946[/tex]
A perfectly spherical balloon occupied 35°C of neon gas under a pressure of 2 atm.
The radius of the balloon is 15 cm. The balloon is then released up in the air until it
reached the temperature of -20°C under 0.3 atm. Determine its volume at that instant.
Answer:
V₂ = 116126.75 cm³
Explanation:
Given data:
Radius of balloon = 15 cm
Initial pressure = 2 atm
Initial temperature = 35 °C (35 +273 = 308K)
Final temperature = -20°C (-20+273 = 253 K)
Final pressure = 0.3 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
Initial volume of balloon:
V = 4/3πr³
V = 4/3×22/7×(15cm)³
V = 14137.17 cm³
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 2 atm × 14137.17 cm³ × 253 K / 308 K × 0.3 atm
V₂ = 7153408.02 atm .cm³. K / 61.6 K.atm
V₂ = 116126.75 cm³
I want a Huge conversation about planets (kid friendly)
Answer:
Plants are made of gas and mass
Answer:
hello again :-)))))))
What kind of solution would you have if it contained 50 grams of sodium chloride in 100 mL of water at 30˚C?
Answer:
Supersaturated solution.
Explanation:
Hello!
In this case, according to the types of solution in terms of the relative amounts of solute and solvent, we can define a point called solubility at which the amount of solute is no longer dissolved in the solvent; thus, a value of solute/solvent less than the solubility is related to unsaturated solutions, equal to the solubility is related to the saturated solutions and more than the solubility to supersaturated solutions.
Thus, since solubility is temperature-dependent, at 30 °C the solubility of sodium chloride is 36.09 g per 100 mL of water; which means that, since the solution has 50 g of sodium chloride, more than 36.09 g, we infer this is a supersaturated solution.
Best regards!
What is the molarity of a HCl solution that
contains 6.27 g of HCl in 163 mL of solution?
Answer in units of M.
Answer:
M = 1.04 M
Explanation:
Given data:
Molarity of solution = ?
Mass of HCl = 6.27 g
Volume of solution = 163 mL (163 mL× 1L /1000 mL = 0.163 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 6.27 g / 36.5 g/mol
Number of moles = 0.17 mol
Molarity:
M = 0.17 mol/ 0.163 L
M = 1.04 M
Answer:
4.6 M HCI
Explanation:
on edge
Calcium Carbonate reacts with dilute hydrochloric acid. The equation for the reaction is shown. CaCo3 + 2Hcl = Cacl2 + H2O + Co2 1 g of calcium Carbonate is added to 50cm3 of 0.05mol/dm3 hydrochloric acid. Which volume of carbon dioxide is made in this reaction?
Answer:
Approximately [tex]0.224\;\rm L[/tex], assuming that this reaction took place under standard temperature and pressure, and that [tex]\rm CO_2[/tex] behaves like an ideal gas. Also assume that the reaction went to completion.
Explanation:
The first step is to find out: which species is the limiting reactant?
Assume that [tex]\rm CaCO_3[/tex] is the limiting reactant. How many moles of [tex]\rm CO_2[/tex] would be produced?
Look up the relative atomic mass of [tex]\rm Ca[/tex], [tex]\rm C[/tex], and [tex]\rm O[/tex] on a modern periodic table:
[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm C[/tex]: [tex]12.011[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Calculate the formula mass of [tex]\rm CaCO_3[/tex]:
[tex]\begin{aligned} & M(\rm CaCO_3) \\ &= 40.078 + 12.011 + 3 \times 15.999 \\&= 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Calculate the number of moles of formula units in [tex]1\; \rm g[/tex] of [tex]\rm CaCO_3[/tex] using its formula mass:
[tex]\begin{aligned}& n(\mathrm{CaCO_3})\\&= \frac{m(\mathrm{CaCO_3})}{M(\mathrm{CaCO_3})} \\ &= \frac{1\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \approx 1.00\times 10^{-2}\; \rm mol\end{aligned}[/tex].
In the balanced chemical equation, the ratio between the coefficient of [tex]\rm CaCO_3[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{CaCO_3})} = 1[/tex].
In other words, for each mole of [tex]\rm CaCO_3[/tex] formula units consumed, one mole of [tex]\rm CO_2[/tex] would be produced.
If [tex]\rm CaCO_3[/tex] is indeed the limiting reactant, all that approximately [tex]1.00\times 10^{-2}\; \rm mol[/tex] of [tex]\rm CaCO_3\![/tex] formula would be consumed. That would produce approximately [tex]1.00\times 10^{-2}\; \rm mol\![/tex] of [tex]\rm CO_2[/tex].
On the other hand, assume that [tex]\rm HCl[/tex] is the limiting reactant.
Convert the volume of [tex]\rm HCl[/tex] to [tex]\rm dm^{3}[/tex] (so as to match the unit of concentration.)
[tex]\begin{aligned}&V(\mathrm{HCl})\\ &= 50\; \rm cm^{3} \\ &= 50\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{10^{3}\; \rm cm^{3}} \\ &= 5.00\times 10^{-2}\; \rm dm^{3} \end{aligned}[/tex].
Calculate the number of moles of [tex]\rm HCl[/tex] molecules in that [tex]5.00\times 10^{-2}\; \rm dm^{3}[/tex] of this [tex]\rm 0.05\; \rm mol \cdot dm^{-3}[/tex]
[tex]\begin{aligned}& n(\mathrm{HCl}) \\ &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.05\; \rm mol \cdot dm^{-3}\\ &\quad\quad \times 5.00\times 10^{-2}\;\rm dm^{3} \\ &= 2.50 \times 10^{-3}\; \rm mol\end{aligned}[/tex].
Notice that in the balanced chemical reaction, the ratio between the coefficient of [tex]\rm HCl[/tex] and that of [tex]\rm CO_2[/tex] is [tex]\displaystyle \frac{n(\mathrm{CO_2})}{n(\mathrm{HCl})} = \frac{1}{2}[/tex].
In other words, each mole of [tex]\rm HCl[/tex] molecules consumed would produce only [tex]0.5\;\rm mol[/tex] of [tex]\rm CO_2[/tex] molecules.
Therefore, if [tex]\rm HCl[/tex] is the limiting reactant, that [tex]2.50 \times 10^{-3}\; \rm mol[/tex] of [tex]\rm HCl\![/tex] molecules would produce only one-half as many (that is, [tex]1.25\times 10^{-3}\; \rm mol[/tex]) of [tex]\rm CO_2[/tex] molecules.
If [tex]\rm CaCO_3[/tex] is the limiting reactant, [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. However, if [tex]\rm HCl[/tex] is the limiting reactant, [tex]1.25\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be produced.
In reality, no more than [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2[/tex] molecules would be produced. The reason is that all [tex]\rm CaCO_3[/tex] would have been consumed before [tex]\rm HCl[/tex] was.
After finding the limiting reactant, approximate the volume of the [tex]\rm CO_2\![/tex] produced.
Assume that this reaction took place under standard temperature and pressure (STP.) Under STP, the volume of one mole of ideal gas molecules would be approximately [tex]22.4\; \rm L[/tex].
If [tex]\rm CO_2[/tex] behaves like an ideal gas, the volume of that [tex]\rm 1.00\times 10^{-3}\; \rm mol[/tex] of [tex]\rm CO_2\![/tex] molecules would be approximately [tex]\rm 1.00\times 10^{-3}\; \rm mol \times 22.4\; \rm L = 0.224\; \rm L[/tex].
What is the rate constant of a reaction if rate = 1 x 10-2 (mol/L)/s, [A] is 2 M,
[B] is 3 M, m = 2, and n = 1?
k=
rate/[A]" [B]"
The rate constant of a reaction : 8.3 x 10⁻⁴
Further explanationGiven
rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M, [B] is 3 M, m = 2, and n = 1
Required
the rate constant
Solution
For aA + bB ⇒ C + D
Reaction rate can be formulated:
[tex]\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}[/tex]
the rate constant : k =
[tex]\tt k=\dfrac{rate}{[A]^m[B]^n}\\\\k=\dfrac{1.10^{-2}}{2^2\times 3^1}\\\\k=8.3\times 10^{-4}[/tex]
Answer:
8.3x10^10-4
Explanation:
a p e x
How many moles are in 347 grams of HBr
Answer:
4.289 mol
Explanation:
Given that the molar mass of HBr (known as Hydrobromic Acid or Hydrogen Bromide) has a molar mass of 80.91 g/mol.
To find the number of moles, we have the formula
(Grams of the substance ÷ moles of the substance) * (molar mass of the substance in grams ÷ one mol)
Here the Grams of the substance = 347grams,
Moles of the substance =?
Molar mass of the substance = 80.91 g/mol
By cross multiplying, we have
347 grams * 1 mol = Z * (80.91)
Z = 347 grams ÷ 80.91g/mol
Z = 4.289 mol
Valence electrons are determined by the...
a. highest occupied energy level and Group Number. I
b. highest occupied energy level and Group Number - 8.
Explanation:
A) Highest occupied energy level and Group Number.
Show Work
1. If you were to combine hydrogen with 80.0 g of oxygen, how much hydrogen would
you need to completely react with all of the oxygen?
2. Suppose sodium and chlorine form a compound in the ratio of 1.54 g chlorine to
1.0 g sodium. How much sodium would be needed to completely react with 45.0
of chlorine?
Answer:
Mass of hydrogen needed = 10 g
29.22 gram of sodium are required
Explanation:
1 )Given data:
Mass of oxygen = 80.0 g
Mass of hydrogen needed = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/molar mass
Number of moles = 80 g/ 32 g/mol
Number of moles = 2.5 mol
now we will compare the moles of oxygen and hydrogen.
O₂ : H₂
1 : 2
2.5 : 2× 2.5 = 5 mol
Mass of hydrogen:
Mass = number of moles × molar mass
Mass = 5 mol × 2 g/mol
Mass = 10 g
2 : Given data:
initial mass ration of chlorine and sodium react with each other = 1.54 g : 1.0 g
Mass of sodium required for 45 g of chlorine = ?
Solution:
Cl₂ : Na
1.54 : 1.0
45 : 1.0/1.54× 45 = 29.22 g
Thus, 29.22 gram of sodium are required.
Which pair of dispersed phases and dispersing media can never form a colloid?
Select one:
O a. solid and gas
O b. liquid and gas
O c. solid and solid
O d. liquid and liquid
O e. gas and gas
Answer:
Option B Liquid and Gas
Rank the following in terms of increasing boiling point:_______. CH3CH2OCH2CH3 CH3CH2OCH3 CH3CH2CH2CH3 CH3CH2CH2CH2NH2 a. CH3CH2CH2CH2NH2 < CH3CH2CH2CH3 < CH3CH2OCH3 < CH3CH2OCH2CH3 b. CH3CH2CH2CH3 < CH3CH2OCH2CH3 < CH3CH2OCH3 < CH3CH2CH2CH2NH2 c. CH3CH2OCH3 < CH3CH2CH2CH3 < CH3CH2OCH2CH3 < CH3CH2CH2CH2NH2 d. CH3CH2CH2CH2NH2 < CH3CH2OCH2CH3 < CH3CH2OCH3 < CH3CH2CH2CH3 e. CH3CH2CH2CH3< CH3CH2OCH3< CH3CH2OCH2CH3< CH3CH2CH2CH2NH2
Answer:
CH3CH2CH2CH3 <CH3CH2OCH3<CH3CH2OCH2CH3< CH3CH2CH2CH2NH2
Explanation:
Some important factors affect the boiling point of aliphatic compounds. Prominent among them are;
1) relative molecular mass
2) nature of intermolecular
3) surface area of compound.
In this case, the nature of intermolecular forces and the molecular mass of the compounds are worthy of mention.
The degree of dipole interaction in CH3CH2CH2CH2NH2 is far greater than that in the ethers hence the amine has the highest boiling point followed by the ether of higher molecular mass then the ether of lower molecular mass and finally the alkane has the lowest boiling point because only dispersion forces are involved.
The correct ranking of the given organic compounds from highest to lowest boiling points is given by;
Option D; CH3CH2CH2CH2NH2 < CH3CH2OCH2CH3 < CH3CH2OCH3 < CH3CH2CH2CH3
We are given the organic compounds;
CH3CH2OCH2CH3
CH3CH2OCH3
CH3CH2CH2CH3
CH3CH2CH2CH2NH2
The family names of the given organic compounds are;
CH3CH2OCH2CH3 is an ether
CH3CH2OCH3 is an ether
CH3CH2CH2CH3 is an alkane
CH3CH2CH2CH2NH2 is an amine
The boiling points are given in the order from highest to lowest as;
Alkanes < Ethers < Amines
This is because Amines have higher possibility of hydrogen bonding than the others.
Lastly, a longer chain ether will have a higher boiling point than the shorter chain one because it can have more Vander walls force interactions.
Thus, the correct order of arrangement of the given organic compounds from highest to lowest boiling point is;
CH3CH2CH2CH2NH2 > CH3CH2OCH2CH3 > CH3CH2OCH3 > CH3CH2CH2CH3
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In the Lewis structure of BF3, how many lone pairs surround the boron atom?
NEED ASAP
Select one:
a. 0
b. 1
c. 2
d. 3
We can see here that the number of lone pairs surround the boron atom is A. 0.
What is a boron atom?A boron atom is an atom of the chemical element boron, which is represented by the symbol B in the periodic table. Boron is a metalloid with atomic number 5, meaning it has five protons in its nucleus. It belongs to Group 13 (formerly known as Group IIIA) of the periodic table and is located in period 2.
The Lewis structure of [tex]BF_{3}[/tex] indicates that boron (B) forms three single bonds with three fluorine (F) atoms. Each bond consists of a pair of electrons shared between boron and fluorine. Since there are no unshared electron pairs around the boron atom, the answer is option a. 0.
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describe the effect of subjecting hydrogen to pressure
Answer:
When hydrogen is subjected to large enough pressure, it solidifies according to theory.
Explanation:
According to theory, when hydrogen molecules are subjected to enormous degree of pressure the molecules will solidify.
What happens here is that the hydrogen–hydrogen bonds in the hydrogen molecule will break apart and the molecules collapses into hydrogen atoms.
Hence, when hydrogen is subjected to large enough pressure, it solidifies according to theory.
describe manganese as oxidizing agent
Answer:
See explanation
Explanation:
A reducing agent in chemistry is any substance that accepts electrons and its oxidation number is decreased in a redox reaction.
Manganese occurs in a variety of oxidation states; +7, +6, +5, +4, +3, +2. This makes it an exceptionally good reducing agent since it can accept different number of electrons and change from one oxidation state to another.
The commonest compound of manganese used as a strong oxidizing agent is KMnO4 in which manganese has an oxidation number of +7.
Ren runs a hamburger stand and needs to clean up a season’s worth of grease buildup on the range hood over his griddle. Explain what he should look for in a cleaning product that can handle a layer of grease.
Answer:
A simple mix of baking soda, kosher salt, and dish soap
Explanation:
I don't know why you would need to know this but the stuff mentioned above should get rid of the grease
Answer:
Sample Response for Edge2021: Ren should use a cleaning product that contains a base. This is because bases readily react with lipids, the kind of compound that makes up grease. A base would break down the grease, forming soap, which would then easily wash away.
Explanation:
Which of the following aqueous solutions
would conduct electricity?
Electroyte and Vonvlectrolyte Solution
Answer:
H2CO
Explanation:
How do fossils provide evidence that evolution has happened on Earth?
Answer:
i dunno
Explanation:
Answer:
Explanation:
Evidence for early forms of life comes from fossils. By studying fossils, scientists can learn how much (or how little) organisms have changed as life developed on Earth. There are gaps in the fossil record because many early forms of life were soft-bodied, which means that they have left few traces behind.
Which variable increases when potential energy increases?
Answer:
Height and mass
Explanation:
The potential energy of a body is the energy due to the position of a body.
It is mathematically expressed as:
Potential energy = m g h
m is the mass of the body
g is the acceleration due to gravity
h is the height of the body
Acceleration due to gravity on the earth surface is a constant.
As mass and height of a body increases, the acceleration due to gravity will also increase.
please help!!!!!!!
according to the laws of conservation of mass how much zinc was present in the zinc carbonate
a. 40 g
b. 88 g
C. 104 g
d. 256 g
compound
element + element
1:Synthesis
2:Decomposition
3:Single Replacement
4:Double Replacement
5:Combustion
Answer:
4
Explanation:
Because of single replacement the ideal shape comes in form
When paper is burned, the mass of the remaining ash is less than the mass of the original paper. Which statement best explains this result?
A. The ash has less volume than the paper.
B. Some of the matter is destroyed during the reaction.
C. The mass of the ash cannot be accurately determined
D. Some of the products of the reaction were given off as a gas.
Answer:
d
Explanation:
According to law of conservation of mass, mass is conserved during burning of paper although the mass of ash is less than paper as some of the products are given out as gas.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
Law needs to be modified in accordance with laws of quantum mechanics under the principle of mass and energy equivalence.This law was proposed by Antoine Lavoisier in the year 1789.
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CHEMISTRY HELP!
Can anyone help me understand or explain why my answer was wrong and why the correct answer is right? Please help!
Answer:
Li to Zn2+
Explanation:
Because oxidation number of Li changes from 0 to 2+ it means that Li has lost two electrons and oxidation number of Zn2+ changes to Zn which means Zn received two electrons.
what is the mass in grams of 9.3 moles of C2H4
Answer:
18.6 ( had to be 20 letter :/)
Explanation:
Explain in brief how the non-covalent weak interactions play a major role in biomolecular structure.
Answer:
See explanation
Explanation:
Many bimolecuar structures are formed by non-covalent interactions such as hydrogen bonding.
A typical example that comes in handy here is the bimolecular structure of acetic acid. In the structure of acetic acid, we notice that the molecule exists as dimmers. This dimmeric structure accounts for its high boiling point.
The dimmeric structure stems from non-covalent hydrogen bonded interaction between acetic acid molecules as shown in the image attached.
Calculate the [H3O+] of 0.10 M HNO2 at equilibrium. Given: Ka = 4.46 × 10-4.
Answer:
0.0067 mol/dm³Explanation:
The [H3O+] of HNO2 can be found by using the formula
[tex][H_3O^{ + } ] = \sqrt{Kac} [/tex]
Ka is the acid dissociation constant
c is the concentration of the acid
From the question we have
[tex][H3O^{ + } ] = \sqrt{4.46 \times {10}^{ - 4} \times 0.1} \\ = 0.006678...[/tex]
We have the final answer as
0.0067 mol/dm³Hope this helps you
1. How many elements within the periodic table are classified as
nonmetals?
A. 10
B. 15
C. 21
D. 28
Answer:
it is actually 17 but the closest would be 15.
B. 15
please help me i will give brain list
a)CH3-CH2-CH2-CH=CH2
b)CH3-CH2-CH2-CH2-CH2-CH2-CH3
c)CH≡C-CH2-CH2-CH2-CH3
d)CH3-CH2-CH2-CH2-CH2-CH2-CH=CH2
e)CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2-CH3
give me brain list