You have a simple pendulum that oscillates with a period of 2 s as you stand on the surface of Earth. Your friend, an astronaut standing on the surface of the Moon, has a pendulum of the same length. What would be the period of oscillation of your friend’s pendulum?

a. Less than 2 s
b. The answer depends on whether the amplitudes are the same
c. More than 2 s
d. Exactly 2 s

Answers

Answer 1

Answer:

c. More than 2 s

Explanation:

First, we will find the length of the pendulum:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\2\ s = 2\pi \sqrt{\frac{l}{9.81\ m/s^2}}\\\\4\ s^2 = 4\pi^2 (\frac{l}{9.81\ m/s^2})\\\\l = \frac{(4\ s^2)(9.81\ m/s^2)}{4\pi^2} \\\\l = 0.99\ m[/tex]

Now, the value of g becomes 1.625 m/s² on the surface of the moon. So the time period will be:

[tex]T = 2\pi \sqrt{\frac{l}{g}}\\\\T = 2\pi \sqrt{\frac{0.99\ m}{1.625\ m/s^2}}\\\\[/tex]

T = 4.9 s

Therefore, the correct option is:

c. More than 2 s


Related Questions

A car has a mass of 900 kg is accelerated from rest at a rate of 1.2 m/s calculate the time taken to reach 30/s​

Answers

Answer:

12+2=24+30+2=66

Explanation:

A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and the sound of the whistle is then 290 Hz. What is the speed of the train before and after slowing down? Assume the speed of sound is 343 m/s.

Answers

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

[tex] f = f_{0}\frac{v + v_{o}}{v - v_{s}} [/tex]        

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer  

v: is the speed of the sound = 343 m/s

[tex] v_{o}[/tex]: is the speed of the observer = 0 (it is heard in the town)

[tex] v_{s}[/tex]: is the speed of the source =?

The frequency of the train before slowing down is given by:

[tex] f_{b} = f_{0}\frac{v}{v - v_{s_{b}}} [/tex]  (1)                  

Now, the frequency of the train after slowing down is:

[tex] f_{a} = f_{0}\frac{v}{v - v_{s_{a}}} [/tex]   (2)  

Dividing equation (1) by (2) we have:

[tex] \frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}} [/tex]

[tex] \frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}} [/tex]   (3)  

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

[tex] v_{s_{b}} = 2v_{s_{a}} [/tex]     (4)

Now, by entering equation (4) into (3) we have:

[tex] \frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}} [/tex]  

[tex] \frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}} [/tex]

By solving the above equation for [tex]v_{s_{a}}[/tex] we can find the speed of the train after slowing down:

[tex] v_{s_{a}} = 11.06 m/s [/tex]

Finally, the speed of the train before slowing down is:

[tex] v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s [/tex]

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.                        

I hope it helps you!                                                        

A boy pushes his little brother on a sled. The sled accelerates from rest to (4 m/s). If the combined mass of his brother and the sled is (40.0 kg) and (20 W) of power is developéd, how long time does boy push the sled?


16s

300s

15s

23s​

Answers

300 because the mass and weight

The boy pushed the sled for 16 seconds.

We have a boy who pushes his little brother on a sled.

We have to determine for how long time does boy push the sled.

State Work - Energy Theorem.

The Work - Energy theorem states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

According to the question -

The sled is initially at rest → initial velocity (u) = 0.

Final velocity (v) = 4 m/s

Mass of boy and sled (M) = 40 kg

Power developed (P) = 20 W = 20 Joules/sec

According to work - energy theorem -

Work done (W) = Δ E(K) = E(f) - E(i)

Therefore -

W = ([tex]\frac{1}{2} \times 40 \times 4 \times 4 - \frac{1}{2}[/tex] x 40 x 0) = 320 Joule

Now, Power is defined as the rate of doing work -

P = [tex]\frac{dW}{dt}[/tex] = [tex]\frac{W}{t}[/tex]

20 = [tex]\frac{320}{t}[/tex]

t = 16 seconds

Hence, the boy pushed the sled for 16 seconds.

To solve more questions on Work, Energy and Power, visit the link below -

https://brainly.com/question/208670

#SPJ2

Rahul sits in a chair reading a book. Which force is equal to the force Rahul exerts on Earth?

Answers

In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.

Answer:

Rahul's weight

Explanation:

In fact, the force Rahul exerts on Earth corresponds to the force of gravity. But Rahul's weight is, in fact, the force of gravity exerted by the Earth on Rahul, and these two forces correspond to the action-reaction pair of Newton's third law, which states that the two forces are equal.

Using formulas, Rahul's weight is equal to

W=mg

where m is Rahul mass and g is the gravitational acceleration (g=9.81 m/s^2).

You are helping to design a new electron microscope to investigate the structure of the HIV virus. A new device to position the electron beam consists of a charged circle of conductor. This circle is divided into two half circles separated by a thin insulator so that half of the circle can be charged positively and the other half can be charged negatively. The electron beam will go through the center of the circle. To complete the design your job is to calculate the electric field in the center of the circle as a function of the amount of positive charge on the half circle, the amount of negative charge on the other half circle, and the radius of the circle.

Answers

Answer:

The electric field in the center is  [tex]\frac{2k}{\pi R^{2}}\left ( Q_{2}-Q_{1 } \right )[/tex].

Explanation:

Determine the minimum horizontal force P required to hold the crate from sliding down the plane. The crate has a mass of 50 kg and the coefficient of static friction between the crate and the plane is . ms

Answers

Answer: hello some data related to your question is missing attached below is the missing data and diagram related to the solution

answer:

P = 141.21 N

Explanation:

Given data:

Mass of crate = 50 kg

coefficient  of static friction ( μ ) = 0.25

Calculate minimum horizontal force ( P ) that holds the crate from sliding

∑fx = 0

     = P + Fcos θ - N*sinθ = 0

     = P + 0.25N cos 30° - Nsin30°  = 0

∴ P = 0.2835 N = 0

P - 0.2853 N = 0 ------- ( 1 )

∑fy = 0

     - 50g + Ncosθ + Fsinθ

     - 50*9.81 + Ncos30° + 0.25Nsin30°

∴ N = 494.942 N ----- ( 2 )

input 2 into 1

P - 0.2853 ( 494.942 ) = 0

P = 141.21 N

Now imagine that you are a Haitian taptap driver and want a more comfortable ride. You decide to replace the springs with new springs that can handle the typical heavy load on your vehicle. What spring constant do you want your new spring system to have?
The new springs should have a spring constant that is (slighty larger, substantially larger, slightly smaller, substantially smaller) substantially larger slightly larger slightly smaller substantially smaller than the spring constant of the old springs.

Answers

Answer:

We use a spring of large spring constant.

Explanation:

The spring constant is defined as the force applied on the spring per unit extension or compression in length.

F = k x

where, F is the force, x is the extension, k is the spring constant.

Its unit is N/m.

To get the comfortable ride, we use the spring of large spring constant, so that the spring gets stiffer and we get comfort.

A string of length 3m and total mass of 12g is under a tension of 160N. A transverse harmonic wave with wavelength 25cm and amplitude 2cm travels to the right along the string. It is observed that the displacement at x=0 at t=0 is 0.87cm.
a) What is the wave?
b) Wrote the wave function, y(x,t)
c) Find the particle velocity at position x=0 at time t=10s. What is the maximum particle velocity?​

Answers

Answer:

Explanation:wave=wavelength×frequency,

A 75.0 kg diver falls from rest into a swimming pool from a height of 5.10 m. It takes 1.34 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

Answers

Answer:

559.5 N

Explanation:

Applying,

v² = u²+2gs............. Equation 1

Where v = final velocity,

From the question,

Given: s = 5.10 m, u = 0 m/s ( from rest)

Constant: 9.8 m/s²

Therefore,

v² = 0²+2×9.8×5.1

v² = 99.96

v = √(99.96)

v = 9.99 m/s

As the diver eneters the water,

u = 9.99 m/s, v = 0 m/s

Given: t = 1.34 s

Apply

a = (v-u)/t

a = 9.99/1.34

a = -7.46 m/s²

F = ma.............. Equation 2

Where F = force, m = mass

Given: m = 75 kg, a = -7.46 m/s²,

F = 75(-7.46)

F = -559.5 N

Hence the average force exerted on the diver is 559.5 N

Identifying the factors contributing to and acting as determinant factors of health disparities during the program theory and development process is a means of culturally tailoring the program.
a) true
b) false

Answers

Answer:

a) True

Explanation:

A program-specific message provided to an individual or group with the intention of raising awareness of a health condition, motivating behavior change, removing perceived barriers to participating in a health habit, or something else relating to the program's aims and objectives. The most effective intervention messages are usually theory-based and culturally adapted.

What happens to the water when you throw rock into a pond

Answers

Answer:

The water usually rushes back too enthusiastically, causing a splash – and the bigger the rock, the bigger the splash. The splash then creates even more ripples that tend to move away from where the rock went into the water.

Mark Brsinliest please

Answer :

When a stone is thrown into a pond transverse waves are produced.

A balloon is filled with 80 liters of gas on a day where the temperature was 34 degrees at sea level which is 101.3 kPa and released. As the balloon rises to a certain altitude, the temperature drops to 0 degrees celsius and the balloon doubles in volume. What is the atmospheric pressure at that altitude?

Answers

Answer:

0.444atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (

P2 = final pressure (

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question,

P1 = 101.3 kPa = 101.3 × 0.00987 = 0.999atm

P2 = ?

V1 = 80L

V2 = 160L (double of V1)

T1 = 34°C = 34 + 273 = 307K

T2 = 0°C = 0 + 273 = 273K

Using P1V1/T1 = P2V2/T2

0.999 × 80/307 = P2 × 160/273

79.92/307 = 160P2/273

Cross multiply

307 × 160P2 = 79.92 × 273

49120P2 = 21818.16

P2 = 21818.16 ÷ 49120

P2 = 0.444

P2 = 0.444atm

It is said that a gas fills all the space available to it. Why then doesn't the atmosphere go off into space?

Answers

Earth has its own atmosphere. That is one reason all the water that has been on Earth has been recycled through the water cycle. It never leaves Earth’s atmosphere.

Kirchhoff's junction rule is a statement of: Group of answer choices the law of conservation of momentum the law of conservation of charge the law of conservation of energy. the law of conservation of angular momentum. Newton's second law

Answers

Answer:

the law of conservation of energy.

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

In Physics, a point where at least three circuit paths (wires) meet is referred to as a junction.

The Kirchhoff’s circuit laws are two(2) equations first published by Gustav Kirchhoff in 1845.

Fundamentally, they address the conservation of energy and charge in the context of electrical circuits.

One of the laws known as Kirchoff's Current Law (KCL) deals with the principle of application of conserved energy in electrical circuits.

Kirchoff's Current Law (KCL) states that the sum of all currents entering a junction must equal the sum of all currents leaving the junction.

This simply means that the algebraic sum of currents in a network of conductors(wires) meeting at a point is equal to zero.

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

This ultimately implies that, Kirchhoff's junction rule is a statement of the law of conservation of energy.

Assignment: 06.05 Infections and Health

Answers

Is there a certain question u have?


The engine in the car from question 1 uses a force of 1200 N to cause the car to accelerate at 3.5 m/s2. What is the car's mass?​

Answers

Answer:

Mass of car's engine = 342.85 kg (Approx.)

Explanation:

Given values:

Force applied by car = 1,200 N

Acceleration of car' engine = 3.5 m/s²

Find:

Mass of car's engine

Computation:

⇒ Mass = Force / Acceleration

⇒ Mass of car's engine = Force applied by car / Acceleration of car

⇒ Mass of car's engine = 1,200 / 3.5

⇒ Mass of car's engine = 342.85 kg (Approx.)


What is a reasonable measurement for the distance to Neptune?
30 light years
30 kilometers
30 parsecs
30 Astronomical Units

Answers

Answer:

30 kilometers is a reasonable measurement

State two (2) examples of osmosis occurring in everyday life

Answers

when you keep raisin in water and the raisin gets puffed.
Movement of salt-water in animal cell across our cell membrane.

A man standing on a frictionless ice throws a 1.00kg mass at 20m/s at an angle elevation of 40.0 degrees. What was the magnitude of the mans momentum immediately after the the throl

Answers

Answer:

Explanation:

1.00kg×20m/s×cos40=15.3

A skateboarder is inside of a half pipe, shown here. Explain her energy transformations as she jumps off at point A, slides to point B, and finally reaches point C.

Answers

Point A would be the build up and leverage to slide down the half pipe to point b she would be bending her knees to increase speed to go up the other side and meet point c

a system absorbs 500J of heat and at the same time 400J of work is done on the system what is change in internal energy​

Answers

This is the solution of the problem. The problem is calculated from a closed system energy balance equation

The first charged object is exerting a force on the second charged object. Is the second charged object necessarily exerting a forcer on the first?

Answers

Answer:

Explanation:

Of course because it's Newton's Law that if body A exerts force on body B, then body B will exert equal but opposite force on body A.

HAPPY LEARNING:)

The first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first is correct.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Newton's third law states that for every action (force) in nature there is an equal and opposite reaction, from that we can understand when force is exerted on first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first.

The first charged object is exerting a force on the second charged object. The second charged object necessarily exerting a force on the first is correct.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

What is the potential energy of a 7kg object 4m off the ground ?

please show your work

Answers

Answer:

Gravitational potential energy is mass of the object times the gravitational constant times the height of the object:

U = mgh (I will use 10 for the gravitational constant but you can use 9.8 or 9.81 or something even more accurate)

U = 280

The gravitational potential of the object is 280 joules

When an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt). Determine the following quantities. (a) maximum voltage V (b) rms voltage V (c) rms current A (d) peak current A (e) Find the current when t = 0.0045 s.

Answers

Explanation:

the answer is in the above image

(a) The maximum voltage V is  190 Volts.

(b) The rms voltage V is 95√2 Volts.

(c) The rms current in Amperes is  7.9 A.

(d) The peak current Amperes is  11.18 A.

(e)The current when t = 0.0045 s is 7.26 A.

What is current?

The current is the stream of charges which flow inside the conductors when connected across the end of voltage.

Given is an AC source is connected across a 17.0 Ω resistor, the output voltage is given by Δv = (190 V)sin(50πt).

(a) From the given voltage equation, maximum voltage V is 190 Volts.

(b) rms voltage =Vmax/√2

Put the values, we get

Vrms = 190/√2 = 95√2 Volts

(c) rms current = Vrms/Resistance

Put the values, we get

Irms =  95√2 /17

Irms = 7.9 Amperes.

(d) peak current  =√2 Irms

Substitute the values, we get

Peak current = 7.9 √2 = 11.18 A

(e) The current when t = 0.0045 s is written as

I =  (190 V)sin(50πt)/R

Substitute the values, we have

I =  (190 )sin(50π x0.0045)/17

I = 7.26 A.

Learn more about current.

brainly.com/question/10677063

#SPJ2

Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very few collisions with other molecules. Express your answer using two significant figures.

Answers

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ [tex]v=\frac{502.1}{\sqrt{3} }[/tex]

      [tex]=289.9 \ m/s[/tex]

The time will be:

⇒ [tex]t=\frac{d}{v}[/tex]

      [tex]=\frac{2\times 6}{289.9}[/tex]

      [tex]=\frac{12}{289.9}[/tex]

      [tex]=0.041 \ sec[/tex]

hence,

⇒ [tex]N=\frac{1}{t}[/tex]

        [tex]=\frac{1}{0.041}[/tex]

        [tex]=24.39 \ per \ sec[/tex]

Use a projectile motion kinematic equation for the vertical motion to find the time t that the ball is in the air, from when it leaves the track until it strikes the floor.

Answers

Answer:

The time of flight is [tex]T = \frac{2 u sin A}{g}[/tex].

Explanation:

Let the initial velocity is u and the angle of projection is A.

Use first equation of motion for vertical motion

Let the time to reach the maximum height is t.

[tex]v = u - gt\\\\0 = u sin A - gt \\\\t = \frac{ u sin A}{g}[/tex]

Total time of flight is

T =2  t

[tex]T = \frac{2 u sin A}{g}[/tex]

What is used to represent the magnitude of the force in an FBD?

Answers

Answer:

See explanation below

Explanation:

The length of the arrow represents the magnitude/size of the force. The longer it is, the higher the force's magnitude is.

. A 79 g sample of water at 21oC is heated until it becomes steam with a temperature of 143oC. Find the change in heat content of the system.

Answers

Answer:

40479.6 J

Explanation:

Applying,

q = cm(t₂-t₁).................... Equation 1

Where q = change in heat content of the system, c = specific heat capacity of the system, m = mass of the system, t₁ = initial temperature, t₂ = final temperature.

From the question,

Given: m = 79 g = 0.079 kg, t₁ = 21°C, t₂ = 143°C

Constant: c = 4200 J/kg.°C

Substitute these values into equation 1

q = 4200(0.079)(143-21)

q = 331.8(122)

q = 40479.6 J

Short-term memory is active, while long-term memory is:
A dynamic
B
reflective.
c) passive
D
recessive.

Answers

Answer:

the answer is b. reflective

Match the atmospheric energy transfer process that best fits each of the following scenarios:
Warming of the Earth's surface on a sunny day
[ Choose ] convection conduction radiation advection
On a sunny afternoon, you watch cumulus clouds forming
[ Choose ] convection conduction radiation advection
A very shallow layer of air in contact with the ground is warmed
[ Choose ] convection conduction radiation advection
A south wind carries warm air into the central United States
[ Choose ] convection conduction radiation advection

Answers

Answer:

a) RADIATION, b) CONVECTION, c)  CONDUCTION, d) CONVECTION

Explanation:

In the heating processes there can be three types: conduction, convention and radiation.

The conduction process occurs when the movement of atoms or thermal agitation of molecules creates the transfer of thermal energy.

The convention process occurs when there is a movement of matter creating the transfer of energy

The process of Radiation an electromagnetic wave indexes on a material and is absorbed, creating the process of energy transfer.

Now let's examine each situation>

a)Warming of the Earth's surface on a sunny day

in this case the sunlight heats the earth as it is absorbed, which is why it is a RADIATION process

b) On a sunny afternoon, you watch cumulus clouds forming

in this case the nines rise from the surface, since it is a moving mass, the process is CONVECTION

c) A very shallow layer of air in contact with the ground is warmed

in this case the thermal movement of the layer molecules heat the earth, for which the process of CONDUCTION

d) A south wind carries warm air into the central United States

As we have a movement of a mass of matter, the process is CONVECTION.

Other Questions
I need help with this can someone help me please!!! I will give brainlist, no links!!Leo is visiting New York City to see the Empire State building. He knows that the Empire State building is 1,484 feet tall. When he spots it, he stops and has to look up at an angle of 84.7 degrees to see the top. How far away from the base of the Empire State building is he? es urjenteIdentifica los elementos de una ecuacin 18 3x = 14x + 1 b) y 5y + 16 = 0 c) 6m m + 8 = 9mPrimer MiembroSegundo MiembroIncgnitaCoeficienteTrminos independientes Which statement is true about an early European explorer and the route he took? Which expression is equivalent Which development occurred asthe late 1800s?part of the Second Industrial Revolution in the late 1800s? Q 18. Find the volume of a cylinder of diameter = 4 mm & height = 8 mm. Round to the nearest tenth if necessary. *A. V= 131.1 mm^3B. V= 116.9 mm^3C. V= 100.5 mm^3D. V= 230.0 mm^3 9. The cost for a car is $500 000, a decountered of 5% will be offered if the money is peld within 1 year. What is the trade discount? look photoplz help asap i will give brainliest 3.Didwe go to artclass011tuesday?*a. Web. ArtC. Classd. Tuesday force=1500 N pressure=6000 find the area contac Can someone please help me ASAP!! sketch a graph of f(x) = 2 + x What are substance made of Dexter Company uses the direct write-off method. March 11 Dexter determines that it cannot collect $8,700 of its accounts receivable from Leer Co. 29 Leer Co. unexpectedly pays its account in full to Dexter Company. Dexter records its recovery of this bad debt. Prepare journal entries to record the above transactions. there are 24 students in a class. among them 8 are girl.a.find the ratio of boys and girlsb.find the ratio of girls and boys Mr. Tolman believes that our universe is expanding, but with all of the gravitational force from the celestial bodies of space, the universe will begin to contract. He believes in the _____.A) oscillating universe theoryB) inflation theoryC) steady state theoryD) big bang theory a)Loss is denoted by a negative integer and profit is denoted by a positive integer. Acement company earns a profit of 10 per bag of white cement and a loss of 5 perbag of grey cement. The company sells 325 bags of white cement and 500 bags ofgrey cement. What is its profit or loss? What are the limitations of bohr's model of atom Select the correct answer. What is the hydronium (H3O+) concentration of a solution with a pH of 3.60? write a couple of paragraph writing your plans and intention that you are going to when you will be meet your teachers and friends physically