You randomly choose one of the morales.Without replacing the first marble, you choose a second marble. What is the probability of choosing red and then green?
P(Red and green)=1/4*1/4=1/16

(I really need help) ​

You Randomly Choose One Of The Morales.Without Replacing The First Marble, You Choose A Second Marble.

Answers

Answer 1
Let’s say, hypothetically speaking, you chose the second marble without replacing the first marble so, events are hypothetically dependent. Events are dependent if the occurrence of one hypothetical event hypothetically does affect the likelihood that the other events occur. The probably of two or more dependent events A and B is the probability of A times the probability of B after A hypothetically occurs

P(A and B) = P(A) x P(B after A)

Choose the first marble

The total number of hypothetical marbles are, hypothetically speaking, 4 on a hypothetical basis, and there is one red marble.

P(red)=1/4

Choose the second marble

Without hypothetically replacing the hypothetical first marble, you choose the hypothetical marble, hypothetically speaking. So, the total hypothetical number of marbles are, hypothetically, 3, and there is, hypothetically, one green marble.

P(green) = 1/3

The probability of choosing red and then, hypothetically, green is:

P(red and green) = P(red) x P(green)
=1/4 x 1/3

= 1/12

P(red and green) is hypothetically equal to 1/12 on a hypothetical account.

Final hypothetical answer: 1/12

Related Questions

Robin got home from school
at 3:45. She spent 2 hours
working on her homework, a
half an hour walking the dog,
and forty-five minutes eating
dinner with her family. Then
she began reading her book.
At what time was she finished
eating dinner?

Answers

Answer:

She was finished with dinner at 6:50

Step-by-step explanation:

3:45 + 2 = 5:45

5:45 + 30 = 6:05

6:05 + 45 = 6:50

3:45 + 2 = 5:45
5:45+ 30= 6:15
6:15 + 45 = 7:00
Hope this helped

Find the measures of the interior angles that maximize the area of an isosceles trapezoid
where the length of the non-parallel sides are each 4 inches and the length the shorter of
the two bases is 6 inches.

Answers

The measure of the angle that would maximize the area of this isosceles trapezoid is equal to 0.4395 rad.

Given the following data:

Base length = 6 inches.Sides length = 4 inches.

How to calculate the area of a trapezium.

Mathematically, the area of a trapezium is given by this formula:

A = ½ × (a + b) × h

A = ½ × (12 + 2l) × h

A = h(6 + l)

Next, we would derive a mathematical expression for A in terms of h as follows;

Let l = 4sinθ Let h = 4cosθ

A = (6 + 4sin(θ)) × 4cosθ

In order to determine the value of θ for which the area of this isosceles trapezoid is maximized, we would differentiate the area (A) with respect to angle (θ):

Note: sin²θ + cos²θ = 1   ⇒ cos²θ = 1 - sin²θ.

[tex]\frac{dA}{d\theta} =16 cos^{2} \theta - 4sin \theta(6+4sin \theta)\\\\\frac{dA}{d\theta} = 16 cos^{2} \theta - 16 sin^{2} \theta - 24sin\theta\\\\\frac{dA}{d\theta} =16(1-sin^{2} \theta)- 16 sin^{2} \theta - 24sin\theta\\\\\frac{dA}{d\theta} = - 32 sin^{2} \theta - 24sin\theta+16\\\\32 sin^{2} \theta + 24sin\theta-16=0[/tex]

Next, we would use the quadratic formula to solve for the value of sinθ.

Mathematically, the quadratic formula is given by this equation:

[tex]sin\theta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}[/tex]

Where:

a = 32.b = 24.c = -16.

Substituting the parameters into the formula, we have;

[tex]sin\theta = \frac{-24\; \pm\; \sqrt{24^2 - 4(32)(-16)}}{2(32)}\\\\sin\theta = \frac{-24\; \pm\; \sqrt{2624}}{64}\\\\sin\theta = \frac{-24\; \pm\; 51.23}{64}\\\\sin\theta = \frac{-24\;+\; 51.23}{64}\\\\sin\theta = \frac{27.23}{64}\\\\sin\theta = 0.4255\\\\\theta = sin^{-1}(0.4255)[/tex]

θ = 0.4395 rad.

Note: We would only consider the positive value of the quadratic root.

For the obtuse interior angles of the trapezoid, we have [tex](\frac{\pi}{2} +0.4395)[/tex]

Similarly, the measure of the acute interior angles of the trapezoid is [tex](\frac{\pi}{2} -0.4395)[/tex]

Read more on isosceles trapezoid here: https://brainly.com/question/4758162

PLEASE ANSWER THIS ASAP IT'S DUE IN 5 MINUTES!!!!

1. The rule for an arithmetic sequence is: __________?
2. The rule for a geometric sequence is: __________?

Answers

Answer:

an = a1 + d (n - 1)

aⁿ = a₁ˣ⁻1

Palil used 6 pieces of ribbon that were each 9 inches long on a project.

How many inches of ribbon did he use?

Use the bar diagram to show how many inches of ribbon Palil used.

Drag the numbers to the bar diagram. Numbers may be used once, more than once, or not at all.

Answers

Answer:

54

Step-by-step explanation:

9x6=54

Since you are using 6 pieces of ribbon that are each 9 inches long, you are just multiplying the 2 numbers to get your amount. The answer is 54!

2) Jose bought a magazine for $10 and some erasers for $2 per eraser. He spent a total of $26. How many erasers
he buy?

I can solve it i just need to know the equation with X

Answers

I think it’s 13 bc of you spent 26 in total you could do 26 divided by 2 and that will give you 13. I hope this helps
The eq is
1 magazine for 10$ + x times eraser for 2$= $26

Solve | x + 6| - 7 = 8

A: x= -9 and x = -21

B: x = 9 and x = -9

C: x = -9 and x = 21

D: x = 9 and x = -21

Answers

Answer:

x = 9,-21

Step-by-step explanation:

Given:

[tex]\displaystyle \large{|x+6|-7=8}[/tex]

Transport -7 to add 8:

[tex]\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}[/tex]

Cancel absolute sign and add plus-minus to 15:

[tex]\displaystyle \large{x+6=\pm 15}[/tex]

Transport 6 to subtract ±15:

[tex]\displaystyle \large{x=\pm 15-6}[/tex]

Consider:

[tex]\displaystyle \large{x= 15-6}[/tex] or [tex]\displaystyle \large{x = -15-6}[/tex]

[tex]\displaystyle \large{x=9}[/tex] or [tex]\displaystyle \large{x=-21}[/tex]

Solution:

[tex]\displaystyle \large{x = 9}[/tex] or [tex]\displaystyle \large{x=-21}[/tex]

__________________________________________________________

Second Method

Given:

[tex]\displaystyle \large{|x+6|-7=8}[/tex]

Transport -7 to add 8:

[tex]\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}[/tex]

Absolute Function Property:

[tex]\displaystyle \large{|x-a| = \begin{cases} x-a \ \ (x \geq a) \\ -x+a \ \ (x < a) \end{cases}}[/tex]

Consider both intervals:

When x ≥ a then:

[tex]\displaystyle \large{|x+6|=15}\\\displaystyle \large{x+6=15}[/tex]

Transport 6 to subtract 15:

[tex]\displaystyle \large{x=15-6}\\\displaystyle \large{x=9}[/tex]

When x < a then:

[tex]\displaystyle \large{|x+6|=15}\\\displaystyle \large{-(x+6)=15}\\\displaystyle \large{-x-6=15}[/tex]

Transport -6 to add 15:

[tex]\displaystyle \large{-x=15+6}\\\displaystyle \large{-x=21}[/tex]

Transport negative sign to 21:

[tex]\displaystyle \large{x=-21}[/tex]

Solution:

[tex]\displaystyle \large{x=9}[/tex] or [tex]\displaystyle \large{x=-21}[/tex]

__________________________________________________________

Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!

how many positive integers are between 28/3 and 83/5

Answers

Answer: ur dad

Step-by-step explanation:

lol

There are 7 positive integers in between 28/3 and 83/5.

What is an integer?

An integer is a whole number (not a fractional number) that can be positive, negative or zero.

Given that;

Two fractions are;

28/3 and 83/5.

Now, Write fraction into decimal form as;

28/3 = 9.33

83/5 = 16.6

So, All Integers in between 9.33 and 16.6 are;

⇒ 10, 11, 12, 13, 14, 15, 16

Thus, There are 7 positive integers in between 28/3 and 83/5.

Learn more about the integers visit:

https://brainly.com/question/24653557

#SPJ2

PLEASE HELP WILL GIVE BRANLIEST

Answers

3.75 is the answer I think it is

Work out the length of x.
Give your answer rounded to 3 significant figures.
х
16.5 mm
6.6 mm

Answers

Answer:

x=17.771mm

Step-by-step explanation:

given a right triangle

to find vslue of x

solution (perpendicular) ² + (base) ² =(hypotenus) ²

using pythagorus theorem

(16.5)²+(6.6)²=(x)²

272.25+43.56=(x)²

315.81=(x)²

√315.81=x

x=17.771mm

Answer:

By Pythagoras theorem

H^2=P^2+B^2

x^2=(6.6)^2+(16.5)^2

x^2=43.56+272.25

x^2=315.81

x=√315.81

x=17.771mm

Carly needs $149 to buy a skateboard. She already has $52. She earns money washing cars for $20 a car.
Carly says that if she washes 5 cars she will have enough money to buy the skateboard.

Use the drop-down menus to explain how to solve this problem.

First multiply
Choose...
× $20 to find how much money Carly will earn washing cars. Then add this amount to
Choose...
to find how much money Carly has in all. Finally,
Choose...
the total to the cost of the skateboard.

Answers

Answer:

$149 - skateboard price

$52 - carly's money

$20 × 5 cars = $100

$100 + $52 = $152

$152 - $149 = $3 left

Determine the type of symmetry of r=-7+ 2cos3ø from the equation, if any. Make sure to confirm graphically. Symmetric with respect to the:
A) pole
B) none of these
C)line /2
D) polar axis

Answers

well, hmmm to check for polar symmetry, hmmm say we simply replace the value for either "r" or "θ" or both in the original equation, if the equation rendered is the same as the original, there you have it, symmetry, so let's do that.

[tex]\underline{\textit{testing for symmetry to the }\frac{\pi }{2}~line\qquad \qquad r=-r~~,~~\theta =-\theta } \\\\\\ r=-7+2cos(3\theta )\implies (-r)=-7+2cos[3(-\theta )]\implies -r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{-r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\implies r=7-2cos(3\theta )\impliedby \textit{woopsie, no dice} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\underline{\textit{testing for symmetry to the polar axis}\qquad \qquad \theta =-\theta} \\\\\\ r=-7+2cos(3\theta )\implies r=-7+2cos[3(-\theta )]\implies r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\impliedby \textit{low and behold\qquad \Large \checkmark}[/tex]

now, we could run a test for "the pole" or namely the origin by simply changin r = -r, however we already know where the symmetry is, so no need.

Check the picture below.

What is the answer for this question?

Answers

Answer:

is this from flvs?

Step-by-step explanation:

A square pyramid has a base with a side length of 7.5 feet and lateral faces with heights of 16 feet. Write an expression that can be used to find the surface area, in square feet, of the square pyramid.

Please provide an expression, not just the surface area please :)

Answers

Check the picture below.

so the surface area of the pyramid will be the sum of the areas of the base and the four triangular faces.

[tex]\stackrel{\textit{\Large Areas}}{\stackrel{\textit{4 triangular faces}}{4\left[ \cfrac{1}{2}(7.5)(16) \right]}~~ + ~~\stackrel{\textit{rectangular base}}{(7.5)(7.5)}}\implies 240~~ + ~~56.25\implies 296.25~ft^2[/tex]

Factor completely 4a^2-b^2-2a+b GUYS HELP THERE ARENT ANY CORRECT ANSWERS ON BRAINLY URGENT

Answers

Answer:

(2a-b)(2a+b-1)

Step-by-step explanation:

NO LINKS!!!

Part 3: Figure A is a dilated image of Figure B. Find the scale factor. #5 and 6

Answers

Answer:

Step-by-step explanation:

Scale:- 1box=1units

So

Take one side of each

B=6unitsA=10units

Scale factor(A to B)

[tex]\\ \rm\rightarrowtail \dfrac{6}{10}=\dfrac{3}{5}[/tex]

Scale factor (B to A) is 5/3

#6

B=12A=6

Scale factor (A to B)

[tex]\\ \rm\rightarrowtail \dfrac{12}{6}=2[/tex]

Scale factor (B to A)

[tex]\\ \rm\rightarrowtail \dfrac{6}{12}=0.5[/tex]

l need help with this pls

Answers

Answer:

50°

Step-by-step explanation:

In a parallelogram opposite angles have the same measure. Angle ABC has then the same measure of angle ADC, which is 38°+12°=50°

50 i did it and got a 100

can someone please help me with this

Answers

Answer:

"4 or less, let it rest. 5 or more, raise the score."

Step-by-step explanation:

1) 5.57, 5.62, 5.59

2) 2.349, 2.352, 2.346, 2.354

3)

0.7

0.3

1.5

3.4

4)

3.74

0.93

0.33

1.56

I hope this helps! Have a lovely day!! :)

(I would appreciate brainliest!!)

the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width

Answers

Answer:

Step-by-step explanation:

Let the width of the rectangle = x

As length is 5 inches longer than width, we have to add 5 to width

Length = x + 5

Perimeter of ractangle = 56 in

2* (length + width) = 56

2*( x + 5 + x) = 56

2* (2x + 5)    = 56

Use distributive property: a*(b +c) =(a*b) + (a * c)

2*2x + 2*5   = 56

4x  + 10 = 56

Subtract 10 from both sides

4x = 56- 10

4x = 46

Divide both sides by 4

x = 46/4

x = 11.5

Width = 11.5 in

length = 11.5 + 5

            = 16.5 in

Find the value of each variable in the parallelogram.

Answers

Answer:

h=9

g=61

Step-by-step explanation:

16-h=7

g+4=65

&

Opposite angles and sides are equal in a paralleogram

g+4=65g=65-4g=61

Amd

16-h=7h=16-7h=9

What is a Semicircle?

Answers

Answer:

half a circle

A semicircle is half a Circle! :)

For each of the following, draw a diagram or use words to explain your answer.

A. How many 2/3 are in 2?


B. How many 1/10 are in 3?

Answers

Answer:

A. 3.    B. 20

Step-by-step explanation:

2 divided by 2/3 is 2/ 2/3 or  6/2   which is 3.

3 divided by 1/10 is  3/ 1/10 or 30.

What is the least common multiple of 324 and 245?

Answers

the lcm would be 79380

Step-by-step explanation:

5×7×7

2×2

×3×3×3×3

muliply all the 3 numbers and then you get 79380

In two or more complete sentences, compare the number of x-intercepts in the graph of f(x)=x2 to the number of x-intercepts in the graph of g(x)= (x+2)2 -7

Answers

Because f(x)=x^2 is the parent function of a quadratic, it has one x-intercept at (0,0), no shifts up or down. But because g(x)=(x+2)^2-7 is a quadratic being shifted 2 units to the left and most importantly 7 units down, the function will cross the x-intercept 2 times.

I hope this is the answer you were looking for!

Pls help pls pls help me pls pls help pls

Answers

Answer:

D should be the answer because the rate of Mason and Evan is 3 pages per a minute because three goes into both like so 30÷10=3 and 12÷4=3. Which is why D is your answer.


What is the area in polynomial form

Answers

Answer:

[tex] \orange{ \boxed{ \sf{ ( \: {x}^{2} + 11x + 18 \: ) \: sq. \: units}}}[/tex]

Solution :

Area = lenght x width

Lenght = x + 9

Width = x + 2

[tex] \sf \green{area \: = \: (x + 9)(x + 2)} \\ \sf \green{ = \: { {x}^{2} + 11x + 18}} [/tex]

Answer:

[tex]x^2+11x+18\: \sf(square\:units)[/tex]

Step-by-step explanation:

To use the area model of solving multiplication and division problems, calculate the area of each of the colored rectangles and add them together.

Area of a rectangle = Length × Width

Area of blue rectangle:  [tex]x \times x = x^2[/tex]

Area of pink rectangle:  [tex]x \times 9 = 9x[/tex]

Area of green rectangle:  [tex]2 \times x=2x[/tex]

Area of orange rectangle:  [tex]2 \times 9=18[/tex]

Area of entire rectangle = blue + pink + green + orange

                                        = [tex]x^2+9x+2x+18[/tex]

                                        = [tex]x^2+11x+18\: \sf(square\:units)[/tex]

A student was asked to simplify the expression 2(x+3)+(4x−8)−7x.
Identify the line which contains the initial error.
1: 2(x+3)+(4x−8)−7x
2: 2x+6+4x+8−7x
3: (2x+4x−7x)+(6+8)
4: −x+14

Answers

Answer:

Line 2

Step-by-step explanation:

When factoring the second bracket, 1 x -8 is -8.

Answer:

4

Step-by-step explanation:

2{x+3}+{4x_8}_7x is same2x+6+4x+8_7x the first bracket was multiply by 2 {2x+4x_7x}+{6+8} the like term was collected and grouped with brackets

The number 9 is a common factor of _________.
A) 6 and 9
B) 9 and 36
C) 16 and 27

Answers

Answer:

Step-by-step explanation:

B) 9 and 36

hello!

================================================

9 is a common factor of

9 and 36.

Here's why:

6 is not evenly divisible by 9

16 is not divisible evenly by 9 (it is divisible by 8)

All the other numbers are divisible by 9.

=============================================

note:-

Hope everything is clear; if you need any more explanation/clarification, kindly let me know, and I will comment and/or edit my answer. :)

Pam’s monthly food budget is equal to 40% of her monthly rent payment. If her food budget is $200 a month, how much is her rent payment each month?

Answers

so we know that 40% for the rent payment is for food, and we also know that those 40% are really 200 bucks, so what would it be for the 100%?

[tex]\begin{array}{ccll} \%&amount\\ \cline{1-2} 40 & 200\\ 100& x \end{array} \implies \cfrac{40}{100}=\cfrac{200}{x}\implies \cfrac{2}{5}=\cfrac{200}{x} \\\\\\ 2x=1000\implies x=\cfrac{1000}{2}\implies x=500[/tex]

please help I'm so stuck on this​

Answers

Answer:

divide the anser in the pasage

Step-by-step explanation:

divide the two numbers

Please help solve by elimination I hope its not blurry Have a nice day and Goodnight

Answers

Answer:

[tex]\displaystyle \textcolor{black}{4.}\:[-3, -5][/tex]

[tex]\displaystyle \textcolor{black}{3.}\:[8, -1][/tex]

[tex]\displaystyle \textcolor{black}{2.}\:[4, -7][/tex]

[tex]\displaystyle \textcolor{black}{1.}\:[3, -2][/tex]

Step-by-step explanation:

When using the Elimination method, you eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

[tex]\displaystyle \left \{ {{2x - 3y = 9} \atop {-5x - 3y = 30}} \right.[/tex]

{2x - 3y = 9

{[−5x - 3y = 30]

[tex]\displaystyle \left \{ {{2x - 3y = 9} \atop {-2x - 1\frac{1}{5}y = 12}} \right. \\ \\ \frac{-4\frac{1}{5}y}{-4\frac{1}{5}} = \frac{21}{-4\frac{1}{5}} \\ \\ \boxed{y = -5, x = -3}[/tex]

------------------------------------------------------------------------------------------

[tex]\displaystyle \left \{ {{x - 2y = 10} \atop {x + 3y = 5}} \right.[/tex]

{x - 2y = 10

{[x + 3y = 5]

[tex]\displaystyle \left \{ {{x - 2y = 10} \atop {\frac{2}{3}x + 2y = 3\frac{1}{3}}} \right. \\ \\ \frac{1\frac{2}{3}x}{1\frac{2}{3}} = \frac{13\frac{1}{3}}{1\frac{2}{3}} \\ \\ \boxed{x = 8, y = -1}[/tex]

_______________________________________________

[tex]\displaystyle \left \{ {{y = -3x + 5} \atop {y = -8x + 25}} \right.[/tex]

{y = −3x + 5

{−⅜[y = −8x + 25]

[tex]\displaystyle \left \{ {{y = -3x + 5} \atop {-\frac{3}{8}y = 3x - 9\frac{3}{8}}} \right. \\ \\ \frac{\frac{5}{8}y}{\frac{5}{8}} = \frac{-4\frac{3}{8}}{\frac{5}{8}} \\ \\ \boxed{y = -7, x = 4}[/tex]

------------------------------------------------------------------------------------------

[tex]\displaystyle \left \{ {{y = -x + 1} \atop {y = 4x - 14}} \right.[/tex]

{y = −x + 1

{¼[y = 4x - 14]

[tex]\displaystyle \left \{ {{y = -x + 1} \atop {\frac{1}{4}y = x - 3\frac{1}{2}}} \right. \\ \\ \frac{1\frac{1}{4}y}{1\frac{1}{4}} = \frac{-2\frac{1}{2}}{1\frac{1}{4}} \\ \\ \boxed{y = -2, x = 3}[/tex]

_______________________________________________

I am joyous to assist you at any time.

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