You weigh 710 N. What would you weigh if the Earth were three times as massive as it is and its radius were five times its present value? Answer in units of N

Answer:  When you cannot stop safely at a yellow traffic light before entering an intersection, enter the intersection carefully and continue across.

Explanation: To find the correct answer, we need to know more about the traffic signal rules.

Thus, we can conclude that, the option C is correct.

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The acceleration of the person is 4.108 m/s^2.

What is acceleration?

The acceleration is the rate of change in the velocity in a unit of time.

Angular velocity: The change in angular displacement in a unit of time is called angular velocity.

Tangential velocity: The tangential velocity can be defined as the velocity of an object which is perpendicular to the radius in the rotational motion.

The relation between angular velocity ω, tangential velocity v, and radius r from the axis when the radius is perpendicular to the tangential velocity is,

v=ω*r

Given r=15 m, and ω=5 turns/minutes, substitute these values in the above formula.

Note: 1 turn/minute = 2π/60 rad/s.

v=(5 turns/minutes)*15 m

v=(5*2π/60 rad/s)* 15 m

v=7.85 m/s

Since the motion is circular, and the person is at the lowest point of the wheel, so the acceleration due to gravity will have no effect as it is perpendicular to tangential velocity here. The acceleration a for rotational motion is given by,

a=v^2/r

Substitute v=7.85 m/s, and r=15 m in this equation and solve it.

a=(2.094)^2/(15)

a=4.108 m/s^2

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The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².

Given:

The flow of water through the hose initially, v₁ = 2.05 m/s

The flow of water through the hose initially, v₂ = 31.4 m/s

Calculation:

From Bernoulli's equation we have:

P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂

where P₁ is atmospheric pressure

           P₂ is the pressure in the hose

           ρ is the density of the fluid

           h₁ is the initial height

           h₂ is the final height

           v₁ is the initial velocity of the fluid

           v₂ is the final velocity of the fluid  and

           g is the acceleration due to gravity

Re-arranging the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)

Applying values in the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]

    = (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)

    = 5.92 × 10⁵ Pa

    = 5.92 × 10⁵ N/m²

Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².

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The reading of the scale after 3.6 seconds is 23.79 N.

v = √2gh

v = √(2 x 9.8 x 2.2)

v = 6.57 m/s

mv/t = F = 0.4 x 6.57 = 2.628 N

Wb = 0.72 x 9.8

Wb = 7.056 N

Wa = (RT)g

Wa = (0.4 x 3.6) x 9.8

Wa = 14.11 N

R = Wa + Wb + F

R = 14.11 N  +  7.056 N  +  2.628 N

R = 23.79 N

Thus, the reading of the scale after 3.6 seconds is 23.79 N.

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when they meet the 40-kg boy will have moved a distance of 6 m.

Friction is the force that resists motion when the surface of one object comes in contact with the surface of another.

It is the average position of all the parts of the system, weighted according to their masses.

here,

masses of the boys

M=40 kg,

m=60 kg

x1 = 10 m

The displacement of the 40 kg boy is calculated from the principle of center mass.

XM = ( mx1 + Mx2) / ( m + M )

X(40) = (60 x 10 +  40 x 0) / (40 kg + 60 kg)

X(40) = (600)/(100)

X(40) = 6 m

X(60) = (60 x 0 + 40 x 10 m) / (40 kg + 60 kg)

X(60) = (400)/(100)

X(60) = 4 m

Thus,

when they meet the 40-kg boy will have moved a distance of 6 m.

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Answer: A small mailbag is released from a helicopter that is descending steadily at 1.53 m/s. Then,

a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.

b)78.4m downwards.

c) v=37.67m/s downward. and d=78.4m downward.

Explanation: To find the answer, we need to know more about the equations of uniformly accelerated motion.

                                [tex]v=u+at\\S=ut+\frac{1}{2}at^2\\ v^2-u^2=2aS\\S=\frac{v+u}{2}t[/tex]

            [tex]v=u+gt=-1.53-(9.8*4)=-40.73 m/s^2[/tex]

           [tex]d_1=ut+\frac{1}{2}gt^2=(-1.53*4)+\frac{-9.8*16}{2} =-84.52 m\\d_2=vt=-40.73*4=-162.92 m\\d=-162,92+84.52=-78.4m[/tex]

                 [tex]v=u+gt=1.53-(9.8*4)=-37.67 m/s[/tex]

                 [tex]d_1=ut+\frac{1}{2}gt^2=(1.53*4)+\frac{-9.8*16}{2} =-72.28 m\\ d_2=vt=-37.67*4=-150.68 m\\d=-150.68+72.28=-78.4 m[/tex]

Thus, we can conclude that, the answers to the question are, a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.

b)78.4m downwards.

c) v=37.67m/s downward. and d=78.4m downward.

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The most accurate place to conduct a weight check is at safety-stop death, at the end of the dive.

Why is a weight check important in diving?

A weight check before diving helps an individual decide on the right amount of weight needed for each scuba dive.

To do a weight check one must float upright on the surface, head placed above water. The individual then needs to ­release some air from their Buoyancy compensator as they take a deep breath from their regulator.

Now if the individual sinks rapidly below the ­surface, they are overweight and if their head stays above the water surface, then they are underweight. Thus, when an individual sinks up to the mask ­level, then the weight is just right.

Therefore, the most accurate place to conduct a weight check is at safety-stop depth, at the end of the dive.

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The basic elements for every contract include

1) an offer,

2) acceptance,

3) Awareness

4) with legal capacity, for a legal purpose

A contract is an agreement between two or more parties, to perform a specific job or duty. A contract is usually temporary or of fixed duration and usually governed by a written agreement.

The basic elements every contract should contain are as follows:

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The velocity of the money at the given price, and amount of money in the time frame is 6.75.

The velocity of money is a measurement of the rate at which money is exchanged in an economy.

It is the number of times that money moves from one entity to another.

It also refers to how much a unit of currency is used in a given period of time.

MV = PY

V = PY/M

where;

Substitute the given parameters and solve for velocity;

V = (2.25 x 6000) / 2000

V = 6.75

Thus, the velocity of the money at the given price, and amount of money in the time frame is 6.75.

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The form of precipitation which may occur from this type of clouds is cumulus clouds.

Precipitation cloud is the cloud from which rain falls or looks likely to fall.

Below are some types of precipitation:

Precipitation refers to any or all of the forms of water particles, whether liquid or solid, that fall from the atmosphere such as; rain, hail, snow or sleet).

It is a major class of hydrometeor, but it is distinguished from cloud, fog, dew, rime, frost, etc., in that it must fall. It is distinguished from cloud and virga in that it must reach the ground.

Cloud refers to visible mass of water droplets suspended in the air.

In conclusion, the form of precipitation which may occur from this type of clouds is cumulus clouds

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Answer:

Error

Explanation:

Speed= Distance / Time

Speed = 0.1

Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

The joining of tail of the first vector with the head of the second vector represents the resultant vector whereas the direction of the resultant vector is from the tail of the first vector towards the head of the second.

So we can conclude that Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

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It would take 531 minutes for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long.

What is electric current?

A rate of electric charge flowing past a place or region is called an electric current. A net passage of electric charge through a region creates an electric current.

Here,

ρ is the density of electrons = 8.4×10²⁸ kg/m³

i is the electric current =9.08×10¹⁸ electrons/sec

d is the diameter of the wire =3.6 mm = 0.0036 m

r is radius, r = d/2, r = 1.8 mm = 0.0018 m

l is the length of wire = 34 cm = 0.34 m

v is The volume of the wire

We know that Volume:

V = π r^2* l

V = (3.14* 0.0018^2) 0.34

V = 3.45* 10^-6 m³

Now,

no of electrons= ρ × V

n =  8.4×10²⁸ * 3.45* 10^-6

n = 2.898 * 10^ 23

The time required for the drifting electron is equal to the ratio of the number of electrons to the electric current flows.

T = n/i

T = 2.898 * 10^ 23 / 9.08×10¹⁸

T = 0.3191 * 10^5 s

T = 531 minutes

Hence,

It would take 531 minutes for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long.

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The difference in the power required by the motor at start up and at operating speed is 9778.57

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = voltage (V) × current (I)

P = IV

Power = square voltage (V²) / resistance ®

P = V² / R

P = V² / R

P₁ = 62² / 0.14

P₁ = 27457.14 watts

P = V² / R

P₂ = 37² / 0.14

P₂ = 9778.57 watts

Difference = P₁ - P₂

Difference in power = 27457.14 - 9778.57

Difference in power = 17678.57 watts

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The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

According to the question

The frequency of a photon of electromagnetic radiation = 151.7 Mhz

By using the Formula of wavelength and frequency

λ = C/f

Where,

λ (Lambda) = Wavelength in meters

C = Speed of Light (c = 3x10⁸ m/s)

f = Frequency

Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is  

1 Mhz = 1000000 Hz

151.7 Mhz = 151.7 * 10⁶ Hz

λ = C/f  

Substituting the value of C and f  

  λ =  [tex]\frac{3*10^{8} }{151.7 * 10^{6} }[/tex]

  λ = 1.978 meter

Hence,  the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

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Answer:

false

Explanation:

Answer:

Approximately [tex]\$ 3.02[/tex].

Explanation:

Note that the electric rate in this question is in the unit dollar-per-[tex]{\rm kWh}[/tex], where [tex]1\; {\rm kWh}[/tex] is the energy to run an appliance of power [tex]1\; {\rm kW}[/tex] for an hour.

Number of minutes for which the air conditioner is running in that day: [tex]15 \times 24 = 360\; \text{minute}[/tex]. Apply unit conversion and ensure that this time is measured in hours (same as the unit of the electric rate.)

[tex]\begin{aligned} \text{time} &= 360\; \text{minute} \times \frac{1\; \text{hour}}{60\; \text{minute}} = 6\; \text{hour} \end{aligned}[/tex].

The power of this air conditioner is:

[tex]\begin{aligned} \text{power} &= \text{voltage} \times \text{current} \\ &= 240\; {\rm V} \times 21\; {\rm A} \\ &= 5040\; {\rm W} \\ &= 5.04\; {\rm kW} \end{aligned}[/tex].

Thus, the energy that this air conditioner would consume would be:

[tex]\begin{aligned}\text{energy} &= \text{power} \times \text{time} \\ &= 5.04\; {\rm kW} \times 6\; \text{hour} \\ &= 30.24\; {\rm kWh} \end{aligned}[/tex].

At a rate of [tex]0.1[/tex] dollar-per-[tex]{\rm kWh}[/tex], the cost of that much energy would be approximately [tex]3.02[/tex] dollars (rounded to the nearest cent.)

Work done in compressing spring =  40.833

It simply needs a three-inch compression by applying a compressive force to a 15-inch long spring. we know that  F(x)=kx. To act in displacement X and the poles' values cannot be substituted. Consequently, there will be 4. The spring constant K is therefore equal to 5, so. Three fit within this slot. We consequently derive the compressing spring constant K from this. , which is 5, 3. Now change this formula to include the value of the compressing spring constant. Four f will therefore equal 5.3 x and vice versa. Integration of four factors equals W.

In order to ensure the limit and further all of this, we currently have the range 0–7. Thus, this compressing spring task is completed. W is equal to  40.833

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In addition to ozone, the four other greenhouse gases or groups of greenhouse gases are included in nearly all the climate models are Carbon dioxide, water vapor, and methane, nitrous oxide.

Carbon dioxide, absorbs energy at a variety of wavelengths, a range that overlaps with that of infrared energy. As CO2 soaks up this infrared energy, it vibrates and re-emits the infrared energy back in all directions. About half of that energy goes out into space, and about half of it returns to Earth as heat, contributing to the ‘greenhouse effect.’

As methane is emitted into the air, it reacts in several ways. It reacts and  after oxidization methane forms water vapor and carbon dioxide. So, not only does methane contribute to global warming directly but also, indirectly through the release of carbon dioxide.

Nitrous oxide enhances the greenhouse effect by capturing reradiated infrared radiation from the Earth’s surface and subsequently warming the troposphere . It is chemically inert in the troposphere and stays in the troposphere for about 120 years before moving into the stratosphere where it ultimately leads to destruction of stratospheric ozone.

Water vapor does absorb longwave radiation and radiates it back to the surface, thus contributing to warming.

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Answer: Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.

Explanation: To find the answer, we need to know more about the methylation of cytosine.

Thus, we can conclude that, Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.

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For the different wires the values given are

For Wire A,  Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B,  Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]

So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]

Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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The net electric field at point D is determined as 3.95 x 10⁷ N/C.

E = kq/r²

where;

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

E = kq/r²

where;

r² = 5²  + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i  N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j  N/C

E = kq/r²

where;

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

Ei = 2.16 x 10⁷ i N/C  + 6.36 x 10⁶ i  N/C

Ei = 2.796 x 10⁷ i N/C

Ej = 2.16 x 10⁷ j N/C  + 6.36 x 10⁶j  N/C

Ej = 2.796 x 10⁷ j N/C

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

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Maximum energy stored at the time t = (L/R) ln 2 after the switch is closed

The magnetic field stops expanding when the current in a practical inductor achieves its steady-state value of Im = E/R. The power p = vi is also 0 because the voltage across the inductor has fallen to zero. As a result, the inductor's ability to store energy grows only as the current approaches its steady-state value.

The magnetic field's maximum stored energy is constant when the current is stable. The inductance of the practical inductor does not store any extra energy, but the inductor's resistance continuously loses energy. The magnetic field must continue to exist. current.
The area under the power curve represents the maximum energy stored by the inductance and is equal to the product of the average power and the elapsed time.

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option (a)i.e, It is magnetic when the atoms in a magnetic material are lined up.

Magnetic fields can be represented visually using magnetic field lines. In each case, they specify the direction of the magnetic force acting on a north monopole. The lines' density reveals how large the field is. For example, the magnetic field is more intense and dense near a magnet's poles.

The spin and orbital momentum of an atom's electrons produce magnetism. The term "magnetic anisotropy" refers to how an atom's magnetic characteristics change depending on how the orbits of its electrons are oriented in relation to the composition of a substance. Additionally, it gives magnetization directionality and stability

Each atom creates a tiny magnetic field because the orbiting electrons are tiny moving charges. The direction or orientation of these magnetic fields is referred to as the atom's magnetic moment. In a nutshell, an object's atoms behave like a number of small magnets.

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Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure: hearing loss

A person is said to have hearing loss if they are not able to hear as well as someone with normal hearing, meaning hearing thresholds of 20 dB or better in both ears. It can be mild, moderate, moderately severe, severe or profound, and can affect one or both ears.

High-pitched tuning fork with frequency of 500 to 1000 hertz (Hz) should be used to estimate hearing loss in range of normal speech (300 to 3000 Hz).

The 512-Hz Rinne tuning fork test could be very effective at detecting conductive hearing losses when performed by an experienced tester and when masking was used . Tuning forks  are used to carry Rinne and Weber tests. These tests provide a quick easy method of determining whether a hearing loss is situated in the middle ear or inner ear

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Answer:

initial velocity is the constant in horizontal projectile

F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is described as Force is equal to the rate of change of momentum. For a constant mass, force equals mass duration acceleration.

Newton's Second Law of Motion F=ma is very significant because it indicates the relationship between forces and motion. It permits you to calculate the acceleration (and therefore velocity and position) of an object with known forces. This is extremely helpful for scientists, engineers, inventors, etc.

Therefore : F is directly proportional to m×a. This relation F is directly proportional to m×a can be turned into an equation by placing in a constant k.

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The period remains the same if the amplitude of the motion is increased to 2a

What is Time period?

The time period is the time taken by a complete cycle of the wave to pass a point.

The equation of the period for spring is:

[tex]T = 2\pi \sqrt{\frac{m}{k} }[/tex]

Where,

Time period = T  

mass of system = M

k is the spring constant

Amplitude of the motion is a

From the equation we can say that,

The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.

Now if we increase the amplitude of the motion to 2a, the period of time remains the same.

Because the time period is not dependent on amplitude, it is independent of a.

Hence,

The period remains the same if the amplitude of the motion is increased to 2a.

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