1. A force of 30N is applied to a screwdriver to pry the lid off of a can of paint. The
screwdriver applies 90N of force to the lid. What is the MA of the screwdriver?

Answers

Answer 1

Answer:

I would guess that the MA of the screwdriver is 120N.

Explanation:

I think this because you are adding 30 and 90, since there are two forces being acted on the same place in the same direction.

#teamtrees #WAP (Water And Plant)


Related Questions

Because any natural element used in the cathode produced negative particles that bent to a positive charge, scientists concluded that:
A) all atoms contained negative electrons
B) all atoms are actually negative
C) atoms were indivisible and had no sub-particles
D) metals contained positrons

Answers

A, hope that helps!!

Because any natural element used in the cathode produced negative particles that bent to a positive charge, scientists concluded that ll atoms contained negative electrons.

What is cathode ?

A polarized electrical device's cathode is the electrode from which a regular current exits. The abbreviation CCD, which stands for Cathode Current Departs, might be used to remember this definition. Positive charges move in the direction described by a conventional current.

A cathode is a drawback. As an electron donor, it functions. It serves as an acceptor of electrons. The anode of an electrolytic cell is where the oxidation reaction occurs.

The negatively charged ions are drawn to the cathode, which is the negative electrode. Lead ions travel through the metal use negatively charged terminal of the battery and onto the lead ions because metal ions are usually positive. There must be a way to remember cathodes and anodes, cations and anions.

Thus, option A is correct.

To learn more about cathode, follow the link;

https://brainly.com/question/11920555

#SPJ6

component of fuel for engines is organic compound or hydrocarbons​

Answers

CnHm is the general closed chemical formula of liquid hydrocarbons used as a fuel in the internal combustion engines. However, hydrocarbons consist of hydrogen and carbon and also small amounts of O2, H2, S, H2O, and some metals containing crude oil derivatives .

a weather balloon is inflated to a volume 2.2 10square3 L with 374g of helium. what is the density of helium in grams per liter

Answers

Answer:

Density = 0.17 g/L

Explanation:

It is given that,

Volume of the inflated balloon filled with Helium, [tex]V=2.2\times 10^3\ L[/tex]

Mass, m = 374 g

We need to find the density of helium. It is equal to its mass per unit volume. It can be given by :

d =m/V

[tex]d=\dfrac{374\ g}{2.2\times 10^3\ L}\\\\=0.17\ g/L[/tex]

So, the density of helium in the balloon is 0.17 g/L.

Gold has a density of 17.3 g/cm", what is the volume of 285g piece of gold?
(Show all work)

Answers

9514 1404 393

Answer:

  about 16.5 cm³

Explanation:

Volume, mass, and density are related by ...

  volume = mass/density

  volume = (285 g)/(17.3 g/cm³) ≈ 16.5 cm³

By studying the distribution of different types of fossils, geologists have determined that some plates have traveled great distances. Evidence to support this comes from the fact that –
A.fossils of organisms that lived in warm climates have been found in arctic environments.
B. Species of organisms in the fossil record have changed over geologic time.
C. Some fossilized organisms have only been found on one continent.
D. The oldest known fossils, found in the deepest rock layers, represent ocean organisms.

Answers

Answer:

A. Fossils of organisms that lived in warm climates have been found in arctic environments.

Explanation:

One of the logic used by Geologists to justify plate movement over a region of space is that the fossils of organisms that lived in warm climates have been found in arctic environments.

this is as a result of plate tectonics. organisms that are well adapted to warm climates in times past have their relics preserved as fossils. their fossils are no found today around the arctic environment which are coldthis suggests that the plate must have drifted or moved

iii. A sound wave can be modelled by using a slinky spring. A wavelength in this model is...
a. the distance between a rarefaction and a compression.
b. the length of one compression.
c. the length of one rarefaction.
d. the distance between two rarefactions,

Answers

Answer: d. the distance between two rarefactions,

Explanation:

Wavelength is the distance between two identical adjacent points in a wave. This means that it is the distance between two adjacent compressions or two adjacent rarefactions.

Wavelengths are inversely related to frequency because the longer the wavelength, the less the number of wave cycles per second.

The total number of oxygen atoms in Al2(SO4)3 is

Answers

Answer : 12

Steps :

Al2(SO4)3 =

Al2 S3 O12

Total atom :

Al = 2

S = 3

O = 12

Which properties are examples of chemical properties? Check all that apply.

reactivity
color
hardness
boiling point
combustibility
shape

Answers

Answer:

1.Reactivity

2.combustibility

3.Shape

Hope this helps,

If you think I am right please give brainliest

Happy Holidays!

Explanation:

Reactivity, combustibility, shape.

Need help on 8,9, and 10. ONLY if you know them please.

Answers

Answer:

D, D, A

Explanation:

If you have 10 grams of Aluminum and a 500 gram Aluminum bottle with different volumes. Explain why the density will be the same.

Answers

E density will be same as the material will be same however if they were of same volume one would be denser than other hope this helps sry if not

Please help this is a big grade please

Answers

Answer:

the answer Is d

Explanation:

or the last option is the answer if u need an explanation I may help u and tell me if u are from India

Answer:

dvis you're answer please like me

A solution of a concentration of H+ (10-4 M) has a pH of​

Answers

Answer:

pH = 4

Explanation:

Step 1: Given data

Concentration of H⁺ ions in the solution ([H⁺]): 10⁻⁴ M

Step 2: Calculate the pH of the solution

We will use the definition of pH.

pH = -log [H⁺]

pH = -log 10⁻⁴ M

pH = 4

The pH of the solution is 4. Considering the pH scale, given the pH is lower than 7, the solution is acidic.

help I. have until 11:59 to hand it in ​

Answers

This chemical reaction can also be written as

2C2H6+7O2-->4CO2+6H2O

This is a chemical reaction because reactants are converted into products. This is the combustion of ethane where ethane and oxygen have been converted into carbon dioxide and water

Atomic number of a member of halogens

Answers

Bromine 35

Chlorine 17

Flourine 9

Iodine 53

Astatine 85

Define heating effect?​

Answers

Explanation:

when the current passes through a conductor the electrons have to face the resistance of the conductor which results in the loss of energy and this loss of energy gets converted into heat energy and it is called heating effect.good night.hope it will help uh.

Which of the following represents a compound made of five molecules co5 c2o5 c50 5co2

Answers

Answer:

The answer is: 5co2

How can a galvanic cell become an electrolytic cell?

A. The cathode is oxidized.
B. The salt bridge is removed.
C. The electrolytes are swapped.
D. The redox reaction is reversed.

(The answer is D.)

Answers

D. The redox reaction is reversed lol..............

During laparoscopic surgery , carbon dioxide gas is used to expand the abdomen to help create a larger working space. If 4.80 L of CO 2 gas at 18 °C at 785 mmHg is used, what is the final volume , in liters, of the gas at 37 degrees * C and a pressure of 745 mmHg if the amount of CO 2 does not change ?

Answers

Answer:

5.37 L

Explanation:

To solve this problem we need to use the PV=nRT equation.

First we calculate the amount of CO₂, using the initial given conditions for P, V and T:

P = 785 mmHg ⇒ 785/760 = 1.03 atmV = 4.80 LT = 18 °C ⇒ 18 + 273.16 = 291.16 K

1.03 atm * 4.80 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 291.16 K

We solve for n:

n = 0.207 mol

Then we use that value of n for another PV=nRT equation, where T=37 °C (310.16K) and P = 745 mmHg (0.98 atm).

0.98 atm * V = 0.207 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 310.16 K

And we solve for V:

V = 5.37 L

What is the mass of Na2CO3∙10H2O that is needed to make 100 ml of sodium carbonate solution with the mass percentage of Na2CO3∙ equal to 2%? The density of the final solution is equal to 1 g/ml.

Answers

first we find the mass of the final solution

we know that

density=mass/volume

we know the density and volume

1=m/100

m=100g

now we calculate the mass ofNa2CO3

2% of 100 is equal with 2g of Na2CO3

(a) Some sodium chloride was found to be contaminated with Copper (ii) oxide. Describe
how a sample of sodium chloride can be separated from the mixture.

Answers

Answer:

A mixture of sodium chloride and sand in water can be separated by the process of filtration and then by the process of distillation.

Answer:

Explanation:

As this oxide is insoluble in water you would dissolved the sample of sodium chloride in water and filter off the oxide.

Then concentrate the liquid by boiling and cooling, to get crystals of pure sodium chloride.

how many grams of water can be produced the combination of 10 grams of oxygen and 8 grams of hydrogen

Answers

Answer:

Mass =  11.16 g

Explanation:

Given data:

Mass of hydrogen = 8 g

Mass of oxygen = 10 g

Mass of water produced = ?

Solution:

Chemical equation:

2H₂ + O₂         →      2H₂O

Number of moles of hydrogen:

Number of moles = mass / molar mass

Number of moles = 8 g/ 2 g/mol

Number of moles = 4 mol

Number of moles of oxygen:

Number of moles = mass / molar mass

Number of moles = 10 g/ 32 g/mol

Number of moles = 0.31 mol

now we will compare the moles of hydrogen and oxygen with water.

                   O₂          :           H₂O

                    1            :             2

                  0.31         :            2/1×0.31 = 0.62

                  H₂           :            H₂O

                    2            :              2

                     4            :              4

Number of moles of water formed by oxygen are less this it will act as limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 0.62 mol × 18 g/mol

Mass =  11.16 g

Which trait can a plant acquire during its lifetime?
O A. A damaged stem
OB. A blue flower color
O C. A long, narrow leaf shape
O D. A smooth seed texture

Answers

Answer:

OB

Explanation:

wat does aquire mean

Answer:

a

Explanation:

a damaged stem

How many moles of atoms are in 8.1 × 10^5
g
Pb?
Answer in units of mol.

Answers

Answer:

3900 mol Pb

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic TableUsing Dimensional Analysis

Explanation:

Step 1: Define

8.1 × 10⁵ g Pb

Step 2: Identify Conversions

Molar Mass of Pb - 207.2 g/mol

Step 3: Convert

[tex]8.1 \cdot 10^5 \ g \ Pb(\frac{1 \ mol \ Pb}{207.2 \ g \ Pb} )[/tex] = 3909.27 mol Pb

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

3909.27 mol Pb ≈ 3900 mol Pb

When 2.00 g of silver nitrate and 2.50 g of sodium sulfide in different solutions combine to react, 1.25 g of precipitate are collected. * The text box will not allow you to use subscript. If you want to type the chemical formula for iron(III) sulfate, Fe2(SO4)3, it will need to be typed as Fe2(SO4)3. Remember that the symbol for iron, Fe, is not "fe" or "FE." Do not include the state of matter for each formula. • What is the chemical formula* for the product? Remember that spectator ions do not form a product in solutions. • What is the theoretical yield, in gram(s) for the solid product? • What is the chemical formula for the limiting reagent? • What is the chemical formula for the excess reagent? • What is the percent yield for the reaction? • How many gram(s) of the excess reagent is/are left over?

Answers

Answer:

See Explanation ...

Explanation:

        2AgNO₃(aq)    +    Na₂S(aq) => 2NaNO₃(aq) + Ag₂S(s)

given  2.0g                        2.5g          Spec Ions       Driving Force ppt

= 2.0g/169.8g·mol⁻¹        =2.5g/78g·mol⁻¹

= 0.012mol                      =0.032mol

0.012/2=>0.006*              0.032/1=>0.032*

Limiting Reactant => *Dividing moles by respective coefficient => Limiting Reactant is the smaller resulting value. Therefore AgNO₃ is the Limiting Reagent

Theoretical Yield of ppt Ag₂S(s) = 1/2(0.012 mol) = 0.006 mol Ag₂S(s) = 0.006mol(246g·mol⁻¹ ) = 1.48g Ag₂S(s)

%Yield = (Lab Yield/Theoretical Yield) x 100% = (1.25g/1.48g)100% = 84%

Reagent in Excess => Na₂S(aq) => 0.032mol is given but only 0.016mol is consumed in the reaction. That is, (0.032 - 0.016)mol = 0.016mol  Na₂S(aq) remains in excess = (0.016mol)(78g·mol⁻¹) = 1.25g Na₂S(aq) in excess.

What is the formula for Na+ F-

Answers

answer
NaF
Sodium fluoride

Plz help me
What is a challenge in wild animal photography?


A. They are easy to close to


B. They don’t move much


C. You can’t position them


D. All of the above

Answers

all of the above would be the answer


mark me brainliest

Answer:

c

Explanation:

Because they are in the wild and they move a lot because they freedom. They are easy to close but you can not position so it is c. Pls tell if I am wrong.

which object is a good conductor of heat and electricity?



A. rubber tires


B. rubber boots


C. metal gate


D. wooden sign

Answers

Answer:

C

Explanation:

Metals are good conductors of heat

Please help I need this done

Answers

Answer:

they arent alcohols.

Explanation:

They aren’t alcohols

g The energy associated with the lowest n = 1 state in a hydrogen atom is – 13.6 eV. The wavelength of the emission line corresponding to the transition from n = 4 to n = 3 is

Answers

Answer:

10.9 * 10^-7 m

Explanation:

We know that the Rydberg constant (R) is – 13.6 eV = -2.18 * 10^-18 J

ΔE= -R(1/nf - 1/ni)

Where;

nf = final state

ni= initial state

ΔE=  -2.18 * 10^-18(1/3 - 1/4)

ΔE= -2.18 * 10^-18(1/12)

ΔE= -1.81 * 10^-19 J

From;

ΔE=hc/λ

h = plank's constant = 6.6 * 10^-34 Js

c = 3 * 10^8 ms-1

λ = ?

λ = hc/ΔE

λ = 6.6 * 10^-34 * 3 * 10^8/ 1.81 * 10^-19

λ = 10.9 * 10^-7 m

what is a molecule? PLEASE DONT LOOK THIS UP I WILL GET IN TROUBLE!

Answers

Answer:

A molecule is a group of two or more atoms that form the smallest recognizable unit into which the structure and chemical properties of that substance can be divided and preserved by a pure substance.

Explanation:

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