1. Based on the score you got in our previous activity, do you consider yourself physically fit? Explain your answer.
2. Why is it important to be physically fit? 3. What do you think are the implications of having a physically fit body?
4. What can you do to become physically fit?​

Answer:

Ek = 192000 [J]

Explanation:

Originally missing speed data to solve this problem, we must assume that the original speed is 20 [m/s]. In this way, we can calculate the mass of the object.

48000 = (1/2)*m*(20)^2

m = 240 [kg]

The mass is conserved since it does not change only changes the speed of the body so we can calculate a new kinetic energy.

Ek = (1/2)*240*(40)^2

Ek = 192000 [J]

Answer:

Micrometers provide very accurate measurements

The micrometer is one of the most accurate types of measuring device.

Most micrometers can measure up to 0.001mm or 0.0001 inches.

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Ratchet speeder helps to provide reliable measurements

The ratchet speeder/stop mechanism ensures that uniform pressure is applied to the thimble so that measurements are reliable and repeatable.

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Explanation:

The positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.

Opposite charges have the ability to attract each other while, similar charges repel each other.

The given charge of object A is negative, and it will be strongly attracted to a positive charge.

The greater the positive charge, the greater the force of attraction of object A.

From the given options, the positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.

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Answer:

I = 0.25  AND  T= 4 HOURS, Q = ??  

 multiply  both min  and sec , 240 and 60

we get 1400 sec  

the formula for current is   I = Q/T

substitute the given data in the formula  and simplify it

so , Q = 3600C  

Answer:

25 m/s

Explanation:

First we should define the variables

T=4

Dx = 100

ay=-9.8

ax=0

We can use formula 1 from the BIG 5

x=(v+v0)t/2

By plugging in our variables we can get 100=4(v+v0)/2

Which is 50=v+v0

v=v0 since horizontal acceleration always equals zero

so 2v0 = 50

v0 = 25

Answer:

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

Explanation:

Answer:

Explanation:

Area of the room = Length × Width

Given

Length = 12.71m

Width = 5.46m

Area of the room = 12.71m×5.46m

Area of the room = 69.3966m²

To get the area of the error, we will use the relationship;

∆A/A = {∆L/L + ∆W/W}

∆A/A = {0.01/12.71 + 0.01/5.46}

∆A/A = {0.0007868+ 0.001832}

∆A/A = 0.0026182

∆A = 0.0026182A

Since Area A = 69.3966m²

∆A = 0.0026182(69.3966)

∆A ≈ 0.1817m²

Hence error in the area of the room is 0.1817m²

Answer:

[tex]P=3.61\times 10^{-3}\ Pa[/tex]

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

[tex]P=\dfrac{F}{A}[/tex]

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

[tex]P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa[/tex]

So, the maximum pressure created by brick is [tex]3.61\times 10^{-3}\ Pa[/tex].

Answer: An S reaction has one product and two or more reactants and a D reaction has one reactant and two or more products.

Explanation:

In a synthesis reaction, two or more simple molecules or substances interact to form a more sophisticated product. (General equation: A + B → AB)

When one reactant decomposes into two or more products, this is known to as a decomposition reaction. (General equation: AB → A + B)

Answer:

a precision instrument for taking extremely precise measurements. It's the newest advancement in caliper technology.

Explanation:

Answer:

Infilteration

Answer:

-42 kJ

Explanation:

Q = ΔE + W

W = -63.0 kJ

Q = -105 J

so -105 = ΔE + (-63)

ΔE = 63 - 105 = -42 kJ

A system does the work of 63 kJ and releases 105 kJ of heat, then the change in internal energy will be -42 kJ.

When a thermodynamic system's boundary is crossed by a form of energy due to a temperature differential, that form of energy is referred to as heat. Heat is not present in thermodynamic systems.

In the right-hand image, a metal bar is "conducting heat" from its hot end to its cold end. However, if the metal bar is thought of as a thermodynamic system, then the energy moving within the metal bar is what is being described as "conducting heat" instead is called internal energy.

Q = Δ E + W

W = -63.0 kJ

Q = -105 J

Then,

-105 = Δ E + (-63)

ΔE = 63 - 105 = -42 kJ

Therefore, the change in internal energy will be -42 kJ.

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Answer:

The less energy a wave has, the smaller the amplitude

Explanation:

Hope this helps!!!

Answer: Topsoil

Explanation:

Bio

Answer:

topsoil

Explanation:

Explanation:

A 620 kg satellite above the earth's surface experiences a gravitational field strength of 4.5 N/kg.

Knowing the gravitational field strength at Earth’s sur-

face and Earth’s radius, how far above Earth’s surface

is the satellite? (Use ratio and proportion.)

Answer:

t = 0, p = 12.0, v = 6.00

t = 20, p = 112, v = 56.0

t = 25, p = 62.0, v = 31.0

Explanation:

Impulse = change in momentum

J = Δp

FΔt = mΔv

The impulse equals the area under the F vs t graph.

At t = 0 s, the initial velocity is 6.00 m/s, so the momentum is:

p = (2.00 kg) (6.00 m/s)

p = 12.0 kg m/s

From t=0 s to t=20 s, the impulse is:

J = (20 N) (5 s) + ½ (20 N) (5 s) + ½ (-10 N) (10 s)

J = 100 Ns

So the new momentum is:

p = 12.0 kg m/s + 100 kg m/s

p = 112 kg m/s

And the new velocity is:

v = (112 kg m/s) / (2.00 kg)

v = 56.0 m/s

From t=20 s to t=25 s, the impulse is:

J = (-10 N) (5 s)

J = -50 Ns

So the new momentum is:

p = 112 kg m/s − 50 kg m/s

p = 62.0 kg m/s

And the new velocity is:

v = (62.0 kg m/s) / (2.00 kg)

v = 31.0 m/s

Answer:

Explanation:

M3U1 Pre-Assessment

Reflection Journal - Thursday

Answer:

9.8m/s

Explanation:

Wherever you're on the earth's surface, gravitational force remains the same and it does not matter either its a rock that's being tossed or a sheet of paper, the acceleration remains 9.8m/s only. *Condition applied=air resistance neglected

Answer:

Approximately [tex]75.3\; \rm m \cdot s^{-2}[/tex]. (Approximately [tex]7.69\, g[/tex], where [tex]g[/tex] denotes the acceleration due to gravity on the surface of the earth.)

Explanation:

The weight of an object is the size of the overall gravitational pull on that object. If the mass of this person is [tex]m[/tex], the weight of this person at a point with gravitational acceleration [tex]g[/tex] would be [tex]m \cdot g[/tex].

Let [tex]g_{0}[/tex] denote the gravitational acceleration on the surface of the earth. The weight of this person on the surface of the earth would be [tex]m \cdot g_0[/tex].

Let [tex]g_1[/tex] denote the gravitational acceleration on the surface of that "nearby planet". The weight of this person on the surface of that planet would be [tex]m \cdot g_1[/tex].

According to the question:

Take the quotient of these two equations:

[tex]\displaystyle \frac{m\cdot g_1}{m \cdot g_0} = \frac{5320 \; \rm N}{692\; \rm N}[/tex].

[tex]\displaystyle \frac{g_1}{g_0} \approx 7.6879[/tex].

[tex]g_1 \approx 7.6879 \, g_0[/tex].

In other words, the gravitational acceleration on the surface of that nearby planet is approximately [tex]7.6879[/tex] times the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth is approximately [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex]. Therefore, the gravitational acceleration on the surface of that planet would be approximately [tex]7.6879\, g \approx 7.8679 \times 9.8\; \rm m \cdot s^{-2} \approx 75.3\; \rm m \cdot s^{-2}[/tex].

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

Explanation:

and Thais

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

Answer:

it is the white rhinoceros because it weighs more then the bullet all though the bullet travels faster once the rhino gets running it is hard to stop because it weighs so much

Answer:

5

Explanation:

when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because

a number line also has negative numbers.Then if you move 6 units your object is at 5

Answer:

Explanation:

0m x96 would put as an mass of 900 into 0 so there for your answer would be 0

The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field. Option A is correct.

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The electric field formula is as follows:

E = F /Q

Where,

The electric field is denoted by the letter E.

F is the electric force

The charge is Q.

The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field.

Hence option A is correct.

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Answer:

3rd sentence

Explanation:

Answer:

the moon showing up at same time as what

Explanation:

???

Based on the acceleration-time graph, the segments of the motion in which the object experience a net force are both 1 and 3.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

[tex]F=ma =\frac{m(v\;-\;u)}{t}[/tex]

Where:

Note: Mass represents the conversion factor between net force and acceleration on an acceleration-time graph.

Based on the acceleration-time graph, the segments of the motion in which there is a net force acting on the object are both 1 and 3 while it experienced constant acceleration at segment 2 and 4.

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For a  pulley in the form of a uniform disk with a mass of 63 kg and a radius of 20 cm, the magnitude of the tension T is mathematically given as

T1=292.4N

For 20kg

T1=196+20a

For

33kg

T2=323.4-33a

Generally, the simultaneous equation is mathematically given as

T2-T1=(323.4-33a)-(196+20a)

Hence

127.4-53.a

a=1.67m/s^2

T1=196+20(1.67)

T1=292.4N

In conclusion, the magnitude of the tension T

T1=292.4N

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