Explanation:
if we convert it into g/cm it'll be
2000 grams
Assessment started: undefined.
Item 1
Select a word from the drop-down menu to correctly complete the statement.
The elements fluorine, chlorine, and iodine are all part of the same on the periodic table.
a.diagonal
b.group
c.piriod
d.row
Answer:
Option B: Group
Explanation:
The elements fluorine, chlorine, and iodine are commonly known as halogens.
They all have 7 valence electrons in their outermost shell and thus they all belong to group 7A in the periodic table.
Correct Answer is: Group
Answer:
Explanation:
Group hope this helps
what is a mitochondria
Answer:
The mitochondria, also known as the mitochondrion, is the organelle that produces energy in living organisms.
Explanation:
This organelle is found in Eukaryotic cells. This organelle converts energy into food molecules through a process known as cellular respiration.
I hope this helps you
:)
is there gravity in water?
Gravity works the same way in water that it works in air or a vacuum -- but you have to consider the force of gravity on the water as well as on the object you put into it
You want to double the radius of a rotating solid sphere while keeping its kinetic energy constant. (The mass does not change.) To do this, the final angular velocity of the sphere must be Group of answer choices
The Final angular velocity of the sphere is : Half of its initial value ( W/2 )
Kinetic energy of a rotating body
Given that The kinetic energy of a rotating body ( K ) = 1/2 IW² --- ( 1 )
where : I = moment of inertia, w = angular velocity
I = [tex]\frac{2}{5} MR^{2}[/tex]
Therefore equation ( 1 ) becomes
K = [tex]\frac{1}{5}MR^2W^2[/tex] ----- ( 2 )
After doubling the radius
R' = 2R
K' = K
Mass = unchanged
therefore :
[tex]\frac{1}{5}MR'^2W'^2 = \frac{1}{5}MR^2W^2[/tex]
= ( 2R )² W'² = R²W²
Resolving equation above
Hence : W' ( new angular velocity ) = W / 2
In conclusion The Final angular velocity of the sphere is : Half of its initial value ( W / 2).
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a 3000 kg car accelerates uniformly from 15 m/s to 60 m/s in 5 seconds. determine the net force on the car during this time
Answer:
F = 2700 N
Explanation:
Given that,
Mass of a car, m = 3000 kg
Initial velocity, u = 15 m/s
Final velocity, v = 60 m/s
Time, t = 5 s
We need to find the net force on the car during this time . The net force on an object is given by the product of mass and acceleration. So,
F = ma
a is acceleration, a = (v-u)/t
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{3000\times (60-15)}{5}\\\\F=27000\ N[/tex]
So, 27000 N is the net force on the car during this time .
Based on the levels of processing memory model, place in order how deeply the following information about dogs will be encoded, from the shallowest to the deepest.
From the question, the order of information processing from the shallowest to the deepest is;
A person glances at a magazine and sees a picture of a dog.A person can remember all the breeds of dogs because she knows a song that lists them.A person dog-sits and spends the weekend walking and playing with a dog A person who grew up with a dog enjoyed walking in the woods with her pet.What is information processing?
The term information processing means the way in which we deal with information. It is the process by which information is encoded into our memory.
The following is the order of information processing from the shallowest to the deepest;
A person glances at a magazine and sees a picture of a dog.A person can remember all the breeds of dogs because she knows a song that lists them.A person dog-sits and spends the weekend walking and playing with a dog A person who grew up with a dog enjoyed walking in the woods with her pet.Learn more about memory processing: https://brainly.com/question/24863946
Hi. If a body with a positive charge touches another with a positive charge, do any of them lose electrons?
The perimeter the sphere is the extreme to which they can go. If ... But what happens if a positively charged object is touched to a neutral object? ... The metal sphere loses electrons.
ILL GIVE BRAINLIEST
The planets move around the center star in different orbits. Which planet has more Vittar is in the same relative position from its star as earth’s orbit isfrom this Sun?
Do you think it’s ethical for tech companies to use your personality type, browsing habit,and online behavior to personalize your experience
Answer:
Yes. Yes. Yes
Explanation:
Answer Is yes
Can someone help me!
Answer:
Explanation:
For example 1, there is no friction, so the acceleration in example 1 is:[tex]\sum F=F=100=ma \rightarrow a=\frac{100}{50}=2 ms^{-2}[/tex]
For example 2, there is a friction, so the acceleration in example 2 is:
[tex]\sum F=F-f=100-40 = 60 = ma\rightarrow a_{2}=\frac{60}{50}=1.2 ms^{-2}[/tex]
Here we can say that "according to Newton's 2nd Law, the box in example 2 has less acceleration than in the example 1". So, the claim is denied.
list down the advantages and disadvantages
of the micrometer
guage
over vernier
Caliper?
Screill
The sphere-rod combination can be pivoted about an axis that is perpendicular to the plane of the page and that passes through one of the five lettered points. Through which point should the axis pass for the moment of inertia of the sphere-rod combination about this axis to be greatest?
The point A with the higher mass of 10kg will have the greatest moment of inertia.
What is Inertia?This can be defined as the resistance of any physical object to a change in its velocity.
Masses which have the highest values and are further away form the axis of rotation have the greatest moment of inertia which was why point A was chosen as the most appropriate choice.
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A buoy is anchored tho the oceanfloor. A large wave approaches the buoy. How will the buoy move as the wave goes by?
Answer:
The buoy will move upwards and downwards and well as left and right
Explanation:
As the wind is storing so had the capability to move the buoy in all directions as it is a light object despite being anchored down
PLEASE GIVE BRAINLIEST AND THANKS :-)
Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial velocity of 11.4 m/s from the Verrazano Narrows bridge in New York City. The roadway of this bridge is 70.0 m above the water. (Enter the magnitudes.)
(a)
0.500 s
displacement
velocity
Answer:
y = 6.92[m]
Vf = 16.305[m/s]
Explanation:
To solve this problem we must use the following kinematics equations, where we must first find the final velocity.
[tex]v_{f}=v_{i}+(g*t)[/tex]
where:
Vi = initial velocity = 11.4[m/s]
Vf = final velocity [m/s]
t = time = 0.5[s]
g = gravity acceleration = 9.81[m/s^2}
Note: the positive sign in the equation above is because the acceleration of gravity goes in the direction of the motion of the rock.
Vf = 11.4 + (9.81*0.5)
Vf = 16.305 [m/s]
Now we can calculate how far the rock goes, using the following equation:
[tex]v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f} ^{2}- v_{i}^{2} = 2*g*y\\y = \frac{v_{f} ^{2}- v_{i}^{2}}{2*g} \\y = \frac{16.305^{2}-11.4^{2} }{2*9.81}\\ y=6.92[m][/tex]
Therefore the Rock will be (70 - 6.92) = 63.07 [m] above the water level
Take another look at line 1. Suppose that you use distance and time between any pair of neighboring dots to calculate speed:
speed = distance ÷ time
Will this speed be the same or different from the average speed you calculated in part F? Why?
Answer:
The time of travel and the distance between neighboring dots is always the same. So, the speed between neighboring dots is constant. This speed will be the same as the average speed in part F. hope it helps!
I need to know what the answer is
Answer:
F = M a fundamental Newton's equation
F = 3 kg * 3 m/s^2 = 9 kg m / s^2 = 9 Newtons
A block-spring system oscillates on a frictionless horizontal surface. The time needed for the block to complete one cycle is 0.1 sec. Determine the time needed for the block to travel from -A/2 to A/2, where A is the amplitude of motion
The time needed for the block to travel from -A/2 to A/2 is mathematically given as
t=0.5sec
What is the time needed for the block to travel from -A/2 to A/2?Generally, when the start point is the mean intial position and it goes from A/2 down through the right goes through and fro back to the mean position, and this is after it must have gone through -A/2. Hence it has finished one cycle (0.1 sec.)
In conclusion, for an -A/2 to A/2 oscillation, then it will finish half-cycle given time period to be
t=1/2
t=0.5sec
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Light travels fast and in a _______________.
straight line
compression wave
wavy line
blue line
{its for my sis shes stu!pd}
Answer:
Straight Line
Light travels in straight lines called rays. Light travels "at the speed of light." This speed is about 186,000 miles per second (670 million miles per hour), or about 300,000 kilometers per second.
Have an amazing day!!
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A, B, and C are three successive points on a straight line. AB = 6.0 m, and BC = 10.0 m.
A small object moving along this line from rest with uniform acceleration, passes B and C, 2.0 s
and 4.0 s, respectively, after passing A. Calculate the
i)
acceleration of the body,
Answer:
1 m/s²
Explanation:
Let velocity at A be v,
Use d = v*t + at²2/2
From A to B,
6 = v(2) + a(2²)/2 = 2v + 2a, so
v + a = 3 (1)
From A to C,
6 + 10 = v(4) + a(4²)/2
16 = 4v + 8a
or, v + 2a = 4 (2)
From (1) (2), get
a = 1 m/s²
A transformer has 10,000 windings on the primary side and 5,000 windings on the
secondary side. 100 volts is applied to the primary side. What is the anticipated voltage
on the secondary side? Is this a step-up or step down transformer?
Answer:
50 V; step-down transformer
Explanation:
10,000 : 5,000 = 100 : V
V = 50 V
From 100 V change to 50 V, so it is a step-down transformer
weather meaning of physics
Answer:
1. The day-to-day conditions of the atmosphere at a place with respect to elements like humidity, temperature, wind speed, rainfall, etc. is called the weather of that place.
2. Weather can be cloudy, sunny, rainy, stormy or clear. It is a part of the natural phenomenon which maintains the equilibrium in the atmosphere.
3. But conditions can be worse sometimes. When the atmospheric conditions are extreme or intense enough to cause property loss or life loss, such weather is termed as severe weather.
4. These also vary according to the altitudes, latitudes, and region and pressure differences. Tornadoes, cyclones, heavy rainfall, fog, winter storms come under this category. They are disastrous and hazardous. Proper disaster management and strategies are required to handle these conditions.
A planar insulating sheet with an infinitesimal thickness has charge per unit area σ and is parallel to the x−z plane, as shown. (The arrows indicate that the object extends for a long distance in the horizontal plane.) By the symmetry of the problem, the electric field may be expressed as E⃗ =Ej^. This problem relates the change in the electric field from the lower side to the upper side of the insulating sheet to the surface charge density.
a) Enter a vector expression, in Cartesian unit-vector notation, for the electric field at points just above the planar insulating sheet.
b)Enter a vector expression, in Cartesian unit-vector notation, for the electric field at points just below the planar insulating sheet.
a. The electric field above the planar insulating sheet is Ej = (σ/ε₀)j
b. The electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j
a. Electric field above planar insulating sheetThe electric field above the planar insulating sheet is Ej = (σ/ε₀)j
Gauss's law
Using Gauss' law ε₀∫E.dA = q where
ε₀ = permittivity of free space, E = electric field vector normal to the surface above the planar insulating sheet = Ej, dA = normal vector to surface above the planar insulating sheet = dAj, q = charge enclosed by Gaussian surface on planar insulating sheet = σA where σ = surface charge density and A = area of surfaceNow, ε₀∫E.dA = q
ε₀∫Ej.dAj = σA
ε₀∫EdA = σA
ε₀E∫dA = σA
ε₀EA = σA
ε₀E = σ
E = σ/ε₀
So, the electric field above the planar insulating sheet is Ej = (σ/ε₀)j
b. Electric field above below insulating sheetThe electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j
Gauss's law
Using Gauss' law ε₀∫E.dA = q where
ε₀ = permittivity of free space, E = electric field vector normal to the surface below the planar insulating sheet = -Ej, dA = normal vector to surface below the planar insulating sheet = -dAj, q = charge enclosed by Gaussian surface on planar insulating sheet = σA where σ = surface charge density and A = area of surfaceNow, ε₀∫E.dA = q
ε₀∫-Ej.-dAj = σA
ε₀∫EdA = σA
ε₀E∫dA = σA
ε₀EA = σA
ε₀E = σ
E = σ/ε₀
So, the electric field below the planar insulating sheet is -Ej = -(σ/ε₀)j
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Explain the disadvantage
of precision
Answer:
The disadvantages are listed below for the defined term.
Explanation:
The initial costs of introducing this method are high, so a long-term solution to agriculture should have been in place. To completely develop a functioning system, it often takes many years to gather data and you'll have to be vigilant about gathering and reviewing data to create a level playing field.Who traveled the farthest after 60 minutes?
Answer:
Is it only me who can't understand your question?
Pls give the full question ...
Hope you have a great day!
A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is the speed of the drone with repeat to the ground? A. 14m/s B. 10m/s C. 2m/s D. 20m/s
Answer:
v=10 m/s
Explanation:
Given that,
Speed of a drone is 8 m/s due East with respects to the wind
Speed of a drone 6 m/s due North with respect to the ground.
We need to find the speed of the drone with respect to the ground. Let v is the speed. It is given by the resultant of two speeds.
[tex]v=\sqrt{8^2+6^2} \\\\v=10\ m/s[/tex]
So, the speed of the drone with respect to the ground is 10 m/s.
The work done in holding a 60 kg object at a height of 2 m above the floor for 20 s is
Answer:
zero
Explanation:
The work done is zero because the object has no displacement
6.When light bends it is called
a - broken
b- benzene
C - reflection
d - refraction
Answer:
D refraction
Explanation:
I had a question like this so and I got it right so I believe this is the correct answer
A spring with a force constant of 5.0×104 N/m is initially at its equilibrium length.
How much work must you do to stretch the spring 0.070 m?
How much work must you do to compress it 0.070 m?
(a) The work done in strecthing the spring is 122.5 N.
(b) The work done in compressing the spring is -122.5 N.
Work done to stretch the spring
The work done in stretching a spring is positive since the applied force acts in the same direction as the displacement.
The work done in strecthing the spring is calculated as follows;
W = ¹/₂kx²
W = ¹/₂ x (5 x 10⁴) x (0.07)²
W = 122.5 N
Work done in compressing the springThe work done in compressing the spring is negative, since the applied force acts in opposite direction to the displacement of the spring.
The work done in compressing the spring is calculated as follows;
W = -¹/₂kx²
W = -¹/₂ x (5 x 10⁴) x (0.07)²
W = -122.5 N
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A gecko crawls vertically up and down a wall. Its motion is shown on the following graph of vertical position yyy vs. time ttt.
Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec
Graph of y (in meters) vs. t (in seconds) that starts at 6 m at 0sec, decreases linearly to 2m at 4 sec, stays constant at 2m from 4 sec to 7 sec, increases linearly to 5 m from 7 sec to 9 sec, then stays constant until 10 sec
What is the average velocity of the gecko between the times t=0\text{ s}t=0 st, equals, 0, start text, space, s, end text and t=7\text{ s}t=7 st, equals, 7, start text, space, s, end text?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
0.57\,\dfrac{\text m}{\text s}0.57
s
m
0, point, 57, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction
(Choice B)
B
-0.57\,\dfrac{\text m}{\text s}−0.57
s
m
minus, 0, point, 57, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction
(Choice C, Checked)
C
-1.0\,\dfrac{\text m}{\text s}−1.0
s
m
minus, 1, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction
(Choice D)
D
1.0\,\dfrac{\text m}{\text s}1.0
s
m
Answer:
gfdvcfffddfgffffdrddgfddddghtscgvfrggxfhxdg
Answer:
-.57
Explanation:
Slope from the points (0,6) and (7,2)
2-6/7-0=-.57
A car travels 100 m in 4 s on a highway going east. What is the velocity of the car?
Answer:
velocity =25Explanation:
Average velocity =total displacement /time e takenso,average velocity =total displacement
total time taken
100m/4 =25
velocity =25