6. Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
A(n)
12 + (n-1)(3)
3,24, 27
0,9,27
12,24, 42
12, 21, 39
Answers
Answer:
[tex] A_1 = 12[/tex]
[tex] A_4=21[/tex]
[tex] A_{10}= 39[/tex]
Step-by-step explanation:
[tex]A_n = 12+(n-1)(3) \\ \\ plug \: n = 1 \\ A_1 = 12+(1-1)(3) \\ = 12 + 0(3) \\ = 12 + 0 \\ \red{ A_1= 12} \\ \\ plug \: n = 4\\ A_4 = 12+(4-1)(3) \\ = 12 + 3(3) \\ = 12 + 9 \\ \purple{ A_4= 21} \\ \\ plug \: n = 10\\ A_{10} = 12+(10-1)(3) \\ = 12 + 9(3) \\ = 12 + 27 \\ \orange{ A_{10}= 39} \\ \\ [/tex]
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