60 PTS!! We often use functions to model or represent situations and relationships. These
representations can be as equations, graphs, tables, or even verbal descriptions.
What does it mean to "represent" something? In what other situations have you heard that term used, and how was its meaning in those situations similar to its usage in
algebra?

Answer:

43°

Step-by-step explanation:

supplementary angles sum to 180° , then

second angle + 137° = 180° ( subtract 137° from both sides )

second angle = 43°

Answer:

?

Step-by-step explanation:

Blurry picture can't give right description. :(

Answer:

Step-by-step explanation:

0     0

7

14     14

Answer: 5 to 8

Step-by-step explanation:

Since there are 5 grey balls and 3 white balls, you add the number of white and grey balls to get the total balls which is 8, then put the number of grey balls over the 8 which comes to [tex]\frac{5}{8}[/tex] or 5 to 8 probability of getting a grey ball.

This also does not reduce so 5 to 8 is the final answer.

Answer:

398,000

Step-by-step explanation:

400,000-2,000=398,000

In word form the answer is three hundred ninety-eight thousand

I hope that has helped :)

Answer:

Step-by-step explanation:

x + x + 2x + 3 + 2x + 3 = 360

6x + 6 = 360

Divide by 6

x + 1 = 60

x = 60 - 1 = 59

Answer:

Step-by-step explanation:

a) 0.6406; b) 1.000; c) C. The probability from part​ (a) is more relevant because it shows the proportion of male passengers that will not need to bend; d) B. Since men are generally taller than​ women, a design that accommodates a suitable proportion of men will necessarily accommodate a greater proportion of women.

Answer: C. 3 to 9

You simply add 1 to each given value (8 and 2)

The ratio 9 to 3 represents the ratio of water to salt, so 3 to 9 is the ratio of salt to water.

Edit: Realized I had the parts mixed up, but the solution has been fixed

Answer:

question 1 : That symbol in question 1 represents 10 houses because 20/2 = 10 I.e it half (1/2) of the first one

question 2 : They built more than 100 houses In the following months:

January 2009

August 2009

December 2009

Answer:

Step 1) Rotate 90 degrees counterclockwise around the origin

Step 2) Shift 5 units down

=======================================================

Explanation:

Focus on one of the corner points of figure S.

I'll focus on (9,1)

Apply a 90 degree counterclockwise rotation on this point, and rotate it around the origin.

The rotation rule is [tex](x,y) \to (-y,x)[/tex]

This means [tex](9,1) \to (-1,9)[/tex] meaning (9,1) rotates to (-1,9)

Notice that (9,1) on figure S corresponds to (-1,4) on figure T.

This means after arriving to (-1,9), we need to somehow apply a shifting translation to get to (-1,4)

To get from (-1,9) to (-1,4) we shift the point down 5 units.

-----------------------

To recap:

If you apply that rotation and shifting rule to each of the four corner points of figure S, then you'll end up with figure T.

Figure S is known as the preimage while figure T is the image.

Answer:

A

...................

Answer:

241 units² (nearest whole number)

Step-by-step explanation:

**Assuming the clock is a circular shape**

Area of a circle = [tex]\pi r^2[/tex]

Given:

⇒ area = [tex]\pi[/tex] × 8.75²

            = 240.5281875...

            = 241 units² (nearest whole number)

Answer:241

Step-by-step explanation:

In Ascending order=22,39,50,61,77,88,89

The Product Rule: If there are n(A) ways to do A and n(B) ways to do B, then the number of ways to do A and B is n(A) × n(B). This is true if the number of ways of doing A and B are independent; the number of choices for doing B is the same regardless of which choice you made for A.

9514 1404 393

Answer:

  $8833

Step-by-step explanation:

The account balance will be given by the formula ...

  A = P(1 +rt)

where P is the amount invested, r is the annual rate, and t is the number of years.

  A =- $7300(1 +0.07·3) = $7300·1.21 = $8833

The ending balance is $8833.

Answer:

Rectangular prism X

Step-by-step explanation:

For rectangular prism X:

7*3*6=126 cm³
For rectangular prism Y:
5*2*11=110 cm³
Rectangular prism X holds more because 126 is greater than 110
Hope this helps :)

Answer:

f(x) = -5/3 x +44/3

Step-by-step explanation:

helo :   let  f(x)= ax+b

f(4) = 8   means : a(4)+b=8 and f(7) = 3   means : a(7)+b=3

you have this system :  4a +b = 8....(*)

                                      7a+b = 3 ....(**)

solve this system  use (*) : b = 8 -4a   and use (**) : b = 3-7a

so : 8-4a = 3-7a

-4a+7a = 3-8

3a = -5   so a = -5/3

but b =8-4a     so : b= 8-4(-5/3) =8+20/3  =44/3

f(x) = -5/3 x +44/3

Answer:

1)23/20

2)14/5

3)47

4)27/56

5)10/7

6)23/14

7)73/35

8)7/4

Step-by-step explanation:

1)multiply both fractions to get 20 as a common denominator

15/20+8/20=23/20

2)make 1 be 5/5

5/5+9/5=14/5

3)multiply both fractions to get 14 as a common denominator

26/14+21/14=47

4) multiply both sides to get 56 as a common denominator

35/56-8/56=27/56

5)make one 7/7

7/7+3/7=10/7

6)make 14 as the common denominator

2/14+21/14=23/14

7)make 35 the common denominator

28/35+45/35=73/35

8)make 1/2 be 2/4

5/4+2/4=7/4

Answer:

1.[tex]1\frac{3}{20}[/tex]
2.[tex]2\frac{4}{5}[/tex]
3.[tex]3\frac{5}{14}[/tex]
4.[tex]\frac{27}{56}[/tex]
5.[tex]1\frac{3}{7}[/tex]
6.[tex]1\frac{9}{14}[/tex]
7.[tex]2\frac{3}{35}[/tex]
8.[tex]1\frac{3}{4}[/tex]

Step-by-step explanation:

Given the following questions:

In order to add or subtract fractions we must find the common denominator, and then add the numerators. To subtract we complete the same steps but subtract the numerators instead of adding them. Of course, converting the improper fraction into a mixed number if needed.

Question one:

[tex]\frac{3}{4} +\frac{2}{5}[/tex]
[tex]CD=20[/tex]
[tex]\frac{3}{4} \times5=\frac{15}{20}[/tex]
[tex]\frac{2}{5} \times4=\frac{8}{20}[/tex]
[tex]\frac{15}{20} +\frac{8}{20}[/tex]
[tex]15+8=23[/tex]
[tex]=\frac{23}{20}[/tex]

Convert into mixed number:
[tex]\frac{23}{20}[/tex]
[tex]=\frac{23}{20}=23\div20=1\frac{3}{20}[/tex]
[tex]=1\frac{3}{20}[/tex]

Your first answer is indeed "1 3/20."

Question two:

[tex]1+\frac{9}{5}[/tex]
[tex]1=\frac{1}{1}[/tex]
[tex]\frac{1}{1} +\frac{9}{5}[/tex]
[tex]CD=5[/tex]
[tex]\frac{1}{1} \times5=\frac{5}{5}[/tex]
[tex]\frac{9}{5} \times1=\frac{9}{5}[/tex]
[tex]\frac{5}{5} +\frac{9}{5}[/tex]
[tex]5+9=14[/tex]
[tex]=\frac{14}{5}[/tex]

Convert into mixed number:
[tex]\frac{14}{5}[/tex]
[tex]\frac{14}{5}\di=14\div5=2\frac{4}{5}[/tex]
[tex]=2\frac{4}{5}[/tex]

Your second answer is indeed "2 4/5."

Question three:

[tex]\frac{13}{7} +\frac{3}{2}[/tex]
[tex]CD=14[/tex]
[tex]\frac{13}{7} \times2=\frac{26}{14}[/tex]
[tex]\frac{3}{2}\times7=\frac{21}{14}[/tex]
[tex]\frac{26}{14} +\frac{21}{14}[/tex]
[tex]26+21=47=\frac{47}{14}[/tex]
[tex]=\frac{47}{14}[/tex]

Convert into mixed number:
[tex]\frac{47}{14}[/tex]
[tex]\frac{47}{14}=47\div14=3\frac{5}{14}[/tex]
[tex]=3\frac{5}{14}[/tex]

Your third answer is indeed "3 5/14."

Question four:

[tex]\frac{5}{8} -\frac{1}{7}[/tex]
[tex]CD=56[/tex]
[tex]\frac{5}{8} \times7=\frac{35}{56}[/tex]
[tex]\frac{1}{7} \times8=\frac{8}{56}[/tex]
[tex]\frac{35}{56} -\frac{8}{56}[/tex]
[tex]35-8=27[/tex]
[tex]=\frac{27}{56}[/tex]

Your fourth answer is indeed "27/56."

Question five:

[tex]1+\frac{3}{7}[/tex]
[tex]1=\frac{1}{1}[/tex]
[tex]CD=7[/tex]
[tex]\frac{1}{1}\times7=\frac{7}{7}[/tex]
[tex]\frac{3}{7} \times1=\frac{3}{7}[/tex]
[tex]\frac{7}{7} +\frac{3}{7}[/tex]
[tex]7+3=10[/tex]
[tex]=\frac{10}{7}[/tex]

Convert into mixed number:
[tex]\frac{10}{7}[/tex]
[tex]\frac{10}{7} =10\div7=1\frac{3}{7}[/tex]
[tex]=1\frac{3}{7}[/tex]

Your fifth answer is indeed "1 3/7."

Question six:

[tex]\frac{1}{7} +\frac{3}{2}[/tex]
[tex]CD=14[/tex]
[tex]\frac{1}{7} \times2=\frac{2}{14}[/tex]
[tex]\frac{3}{2} \times7=\frac{21}{14}[/tex]
[tex]\frac{2}{14} +\frac{21}{14}[/tex]
[tex]2+21=23[/tex]
[tex]=\frac{23}{14}[/tex]

Convert into mixed number:
[tex]\frac{23}{14}[/tex]
[tex]\frac{23}{14}=23\div14=1\frac{9}{14}[/tex]
[tex]=1\frac{9}{14}[/tex]

Your sixth answer is indeed "1 9/14."

Question seven:

[tex]\frac{4}{5} +\frac{9}{7}[/tex]
[tex]CD=35[/tex]
[tex]\frac{4}{5} \times7=\frac{28}{35}[/tex]
[tex]\frac{9}{7} \times5=\frac{45}{35}[/tex]
[tex]\frac{28}{35} +\frac{45}{35}[/tex]
[tex]28+45=73[/tex]
[tex]=\frac{73}{35}[/tex]

Convert into mixed number:
[tex]\frac{73}{35}[/tex]
[tex]=\frac{73}{35}=73\div35=2\frac{3}{35}[/tex]
[tex]=2\frac{3}{35}[/tex]

Your seventh answer is indeed "2 3/35."

Question eight:

[tex]\frac{5}{4} +\frac{1}{2}[/tex]
[tex]CD=8[/tex]
[tex]\frac{5}{4}\times2=\frac{10}{8}[/tex]
[tex]\frac{1}{2} \times4=\frac{4}{8}[/tex]
[tex]\frac{10}{8}+\frac{4}{8}[/tex]
[tex]10+4=14[/tex]
[tex]=\frac{14}{8}[/tex]

Simplify by reducing:
[tex]\frac{14}{8}[/tex]
[tex]\frac{14}{8}\div2=\frac{7}{4}[/tex]
[tex]=\frac{7}{4}[/tex]

Convert into mixed number:
[tex]\frac{7}{4}[/tex]
[tex]\frac{7}{4} =7\div4=1\frac{3}{4}[/tex]
[tex]=1\frac{3}{4}[/tex]

Your final answer is indeed "1 3/4."

Hope this helps.

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  C

Step-by-step explanation:

From the question we are told that

    The number of outcome is  3 (rock paper and scissors)

     The number of game you and the first friend played is  a = 400

      The number of times friend A chose scissors is b = 100

      The number of game you and the second friend played is c= 120

       The number of times friend B chose scissors  is  d =  20

        The number of game you and the third friend played is e =  300

        The number of times friend B chose scissors  is f = 65

Generally the probability of success of each outcome is  

        [tex]p = \frac{1}{3} = 0.33[/tex]

Generally the probability of failure of each outcome is  

      [tex]q = 1-p[/tex]

=>   [tex]q = 1-\frac{1}{3}[/tex]

=>    [tex]q = \frac{2}{3} = 0.67[/tex]

Generally the proportion of  scissors chosen by friend A is  mathematically represented as

        [tex]p_1 =  \frac{b}{a}[/tex]

=>       [tex]p_1 =  \frac{100}{400}[/tex]

=>       [tex]p_1 = 0.25[/tex]

Generally the proportion of  scissors chosen by friend B is  mathematically represented as

        [tex]p_2 =  \frac{d}{c}[/tex]

=>       [tex]p_2 =  \frac{20}{120}[/tex]

=>       [tex]p_2 = 0.167[/tex]

Generally the proportion of  scissors chosen by friend B is  mathematically represented as

        [tex]p_3 =  \frac{f}{e}[/tex]

=>       [tex]p_3 =  \frac{65}{300}[/tex]

=>       [tex]p_3 = 0.2167[/tex]

Generally the standardized value  for  friend A is mathematically represented as

          [tex]z_1 =  \frac{p_1 - p}{\sqrt{\frac{p* q}{a} } }[/tex]

     => [tex]z_1 =  \frac{0.25- 0.33}{\sqrt{\frac{0.33* 0.67}{400} } }[/tex]

      =>  [tex]z_1 = -3.4[/tex]      

Generally the standardized value  for  friend B is mathematically represented as

          [tex]z_2 =  \frac{p_2 - p}{\sqrt{\frac{p* q}{c} } }[/tex]

     => [tex]z_2 =  \frac{0.167- 0.33}{\sqrt{\frac{0.33* 0.67}{120} } }[/tex]

      => [tex]z_2 =  -3.8 [/tex]      

Generally the standardized value  for  friend C is mathematically represented as

          [tex]z_3 =  \frac{p_3 - p}{\sqrt{\frac{p* q}{e} } }[/tex]

     => [tex]z_3 =  \frac{0.2167- 0.33}{\sqrt{\frac{0.33* 0.67}{300} } }[/tex]

      => [tex]z_3 =  -4.17 [/tex]            

Answer: C

reason: There are special rules to follow when an expression is raised to the power of 0 or 1. Remember these rules when using numerical expressions involving the exponents 0 and 1:

Any number raised to the power 0 is equal to 1. For example, 120 is equal to 1 and 300 is equal to 1. However, this rule does not apply when 0 is the base: 0 raised to any power other than 0 is equal to 0, and 00 is not defined.

Any number raised to the power 1 is equal to the number itself. For example, 121 is equal to 12, 301 is equal to 30, and 01 is equal to 0

A numerical expression contains numbers and operations but not the equality symbol (=). Here are some examples of numerical expressions:

15 + 4 − 2

56 ÷ 7 + 5 × 5 × 5

32 × 5 + 7

Numerical expressions can also be written in words, such as "nine times six minus seven" and "five divided by ten plus two."

Look at the expression 56 ÷ 7 + 5 × 5 × 5. Instead of writing 5 three times in the expression, we can replace it with a whole-number exponent. For that, we write 5 × 5 × 5 as 53:

56 ÷ 7 + 5 × 5 × 5

56 ÷ 7 + 53.

Let's write 2 × 3 × 3 × 3 × 3 × 3 × 3 with a whole-number exponent. Here, 3 is multiplied by itself and occurs 6 times in the expression. Instead of writing 3 six times, we can write 3 × 3 × 3 × 3 × 3 × 3 as 36. So, 2 × 3 × 3 × 3 × 3 × 3 × 3 is the same as 2 × 36.

Answer:

250 km/h

Step-by-step explanation:

5x50=250

Hope it helps!

brainliest, ty!

Answer:

4

Step-by-step explanation:

6 - (-12) / (-6)

6 + 12 / (-6) (because subtracting a negative is the same as adding)

6 + (-2)

4

I hope this helps! Have a lovely day! :)

(Give brainliest to the other person bc they got it right first)

Answer:

Evaluate 6-(-12) / (-6)

6+12 / -6(The minus change to plus because when 2 minuses meet they make +(plus))

6-2(This is 6-2 because 12 /-6 is -2 because the negative takes over it like dividing 12  by 6 but with not negative)

4

The answer is 4

Answer:

I'm not sure of the exact term in the blank, but a^3 and a^7 are both exponents with the same base meaning you can add the exponents to create one.

Step-by-step explanation:

Answer:

A.

Step-by-step explanation:

The graph was shifted (translated) 2 units upward.

This is because the 2 is being added onto the x. If you were to set x to 0, you result with a y of 2, making it the y-intercept.

Answer:

Tanisha = 14 years

Ana = 7 years

Elicia = 16 years

Step-by-step explanation:

Let T = age of Tanisha

Let A = age of Ana

Let E = age of Elicia

Tanisha is twice as old as Ana:  

T = 2A

⇒ A = (1/2)T

Elicia is 2 years older than Tanisha:

E = 2 + T

Sum of all their ages is 37:

A + E + T = 37

Substitute A = (1/2)T and E = 2 + T into A + E + T = 37 and solve for T:

⇒ (1/2)T + 2 + T + T = 37

⇒ (5/2)T = 35

⇒ T = 14

If T = 14, then

A = (1/2)T = (1/2) 14 = 7

If T = 14, then

E = 2 + T = 2 + 14 = 16

Answer:

Step-by-step explanation:

Directions

You cut a pizza cut into 2 equal slices and eat 1 slice, or 1/2

of the pizza. You cut another pizza of the same size cut into 4

equal slices, but you still only eat 1 slice. This time you've

eaten only 1/4 of the pizza, which is less than 1/2.

As you divide the pizza into more slices, the bottom number

(the denominator) gets bigger, but the size of each slice gets

smaller.

Drag the fractions in order from least to greatest.

1/3

1/4

1/2

1/8

-------------------

1/3 = 0.33

1/4 = 0.25

1/2 = 0.5

1/8 = 0.125

so

1/8

1/4

1/3

1/2

Step-by-step explanation:

IN ORDER OF INCREASING ORDER OR FROM LEAST TO GREATEST =1/8, 1/4, 1/3 ,1/2

Answer:

The width of the fence measures 6 feet

Step-by-step explanation:

Firstly, we assign variables.

Let the width of the fence be represented by w and the length by l

Now let’s get what the length would be. width is 2 less than half length

w = l/2 - 2

or simply l/2 = w + 2

which is same as l = 2(w + 2)

Now the perimeter of the fencing is 44. The perimeter of a rectangle can be calculated using the formula

P = 2(l + w)

Now let’s insert what we have:

P = 44 and l = 2(w + 2)

44 = 2(2(w+2) + w)

44 = 2(2w + 4 + w)

44 = 2(3w + 4)

44 = 6w + 8

6w = 44-8

6w = 36

w = 36/6

w = 6 feet

Step-by-step explanation:

Answer:

The answer is 3/4

Answer:

it's 3/4

Step-by-step explanation:

.075 as a fraction is 75/1000 and 75 ÷ 1000 is 0.75 and 0.75 as a fraction is 3/4

Answer:

ms. perez needs to pays 60$ for the pizzas

Step-by-step explanation:

28÷8=3.5

since you can't buy extra large pizzas by halves, you need to change 3.5 into 4

4x15=60

ms. perez needs to pays 60$ for the pizzas

Using the z-distribution, as we have the standard deviation for the population, to test the hypothesis, it is found that this is evidence that workers in the large city take longer than 28 minutes to get home from work.

At the null hypothesis, it is tested if the mean time is of 28 minutes, that is:

[tex]H_0: \mu = 28[/tex]

At the alternative hypothesis, it is tested if the mean time is greater than 28 minutes, that is:

[tex]H_1: \mu > 28[/tex].

The test statistic is given by:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

The parameters are:

In this problem, the values of the parameters are given by:

[tex]\overline{x} = 32, \mu = 28, \sigma = 5, n = 10[/tex]

Hence:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{32 - 28}{\frac{5}{\sqrt{10}}}[/tex]

[tex]z = 2.53[/tex]

Considering that we have a right-tailed test, as we are testing if the mean is greater than a value, with a standard significance level of 0.05, the critical value is of [tex]z^\ast = 1.645[/tex].

Since the test statistic is greater than the critical value, it is found that this is evidence that workers in the large city take longer than 28 minutes to get home from work.

To learn more about the z-distribution, you can check https://brainly.com/question/26454209