The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.From the question,
⇒ Given:
M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)⇒ Solve for V
0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/sHence the final speed of the combined masses is 0.21 m/s
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how do you think the liquid density affects the buoyancy of objects placed in the liquid?
Answer:
density can be written as:
d = F / V (weight density) or M / V (mass density)
Since F in the first equation can be written as
B = d V where B is the buoyant force and is proportional to the
weight of the liquid displaced
For a given volume the weight of the liquid displaced is proportional to the density and hence the buoyant force
Given that the mass of a liquid is 0.01kg and the volume of the liquid is 0.05m^3 . Calculate the density of the liquid
A) 2kg/m^3
B)0.2kg/m^3
C) 5kg/m^3
D) 0.5kg/m^3
Answer:
B.
Explanation:
Density = mass / volume
= 0.01/0.05
= 0.2 kg/m^3.
place any object (textbook, pen, or eraser) on a floor what happens then
Answer:
The force of gravity on earth, no matter the object is approximately 9.8 m/ s2 . The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.
( the answer only for points will be reported ) A crane lifts a load of 36000N to a height of 50 metre in 1 minute . What is the power of the crane ?
Answer:
- 30 kW
Explanation:
IDEA:
Power of an object that does work(source) is given by:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
where work done is mostly shown as the Force applied on an object to Displace it through some distance in the same direction as the Force.
[tex] \boxed{ \mathsf{ work = force \times displacement}}[/tex]
___________________
INFORMATION:
In the question,
The source of power is the crane, while the object is a load of 36000N.
Note, what's given is the force, not the mass. Since, the SI unit of mass is kg and that of Force is Newton(N).
[The weight of the load is represented in Newton, since weight of an object is the amount of Force with which the Earth attracts that object]
I) work done
So,
Force = 36000NDisplacement = 50 m=> Work = 36000 × 50
= 1,800,000 J
(The SI unit of work is Joules(J)).
___________________
II) power
After getting the amount of work done, now we have to place it in the formula for power.
That is:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
Note, During calculations, all quantities must be in their SI units.
SI unit for time is Seconds (s)
But the time we have is in minutes.
___________________
Converting time from minutes to Seconds:
1 minute = 60 Seconds.
Hence,
time = 60 s[tex] \implies \mathsf{power = \frac{1800000}{60} } \: [/tex]
=> power = 30,000 W
(SI unit of power is Watts(W))
To write four zeroes with a 3 and W is a lot of effort. So, we can look for simple expressions like kilowatts(kW) that can express bigger quantities in lesser terms.
1000 W = 1 kW
•°• 30,000 W = 30 kW.___________________
Direction and sign:
The crane displaces the load in an upward direction (from the term "lifts")
But, the Force is acting downwards, as the weight of the body is always towards the Earth.
Since, the directions of Force and displacement are opposite, a minus takes its place in front of both Work and power.
___________________
Therefore, the final answer will be:
Power of the crane = - 30 kWPhysics Practice Help just need an explanation really not looking for an answer
What variables would be required for a computational model that predicts change in the energy of a falling object?(1 point)
A.)Momentum, speed, mass
B.)Height, speed, mass
C.)Acceleration, speed, mass
D,) x, y, z
This question involves the concepts of the law of conservation of energy and kinetic energy.
The variables required for a computational model that predicts change in the energy of a falling object are "B.)Height, speed, mass".
According to the law of conservation of energy the change in energy can be given in the following form for a falling object:
Loss in Potential Energy = Gain in Kinetic Energy
[tex]mgh = \frac{1}{2}mv^2[/tex]
It is clear from the formula that the variables involved in the computational model are mass, height, and velocity.
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Answer:
b) height, speed, mass
Explanation:
just took the test
19) Suppose a ball is thrown straight up and experiences no appreciable air resistance. What is its acceleration just before it reaches its highest point? A) zero B) slightly less than g C) exactly g D) slightly greater than g
Answer:
C)
Explanation: In freefall motion object always has gravity as its acceleration.
what is the magnitude of the force exerted on the bottom of the bottle?
A calculator of mass 0.11 kg is lowered from a bookshelf that is 1.6m above the floor to a desk that is 0.85m above the floor. What's the change in GPE?
Answer:
I think it would be 0.1496 but I'm not really sure sorry
A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.
Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.
S = I(fsd) / V(fsd).
S = 4.0 / 25
S = 0.16 mA/Ω
Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)
(S(new)) = 50 mA / V(fsd)
(S(new)) = 50 / 0.16
(S(new)) = 312.5 Ω
Add External Resistor:
Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter
(R(internal) = 25 Ω:
R(ext) = R(new) - R(internal)
R(ext) = 312.5 Ω - 25 Ω
R(ext) = 287.5 Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.
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#SPJ3
whats 10x10 PLEASE I NEED THIS
Answer:
100
Explanation:
the system shown above is released from rest. if friction is negligible, the acceleration of the 4.0 kg block sliding on the table shown above is most nearly
The acceleration of the first block (4 kg) is -9.8 m/s².
The given parameters:
Mass of the first block, m₁ = 4.0 kgMass of the second block, m₂ = 2.0 kgThe net force on the system of the two blocks is calculated as follows;
[tex]m_2 g - T = m_1 a[/tex]
where;
T is the tension in the connecting string due weight of the first block[tex]m_2 g - m_1 g = m_1 a\\\\a = \frac{m_2 g - m_1g}{m_1} \\\\a = \frac{g(m_2 - m_1)}{m_1} \\\\a = \frac{9.8(2-4)}{2} \\\\a = -9.8 \ m/s^2[/tex]
Thus, the acceleration of the first block (4 kg) is -9.8 m/s².
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why is water soaked cloth used on forehead during fever?please can you tell me answer
This is because the cloth soaked in water can absorb and evaporate the heat from your forehead.
Explanation:This technique is used to cool down your fever, and to help you feel better.
What is the weight of sugar if 5% of sugar from 6g of sugar
Student 1 lifts a box with a force of 500 N and sets it on a tabletop 1.2 m high. Student 2 pushes an identical box up a 5 m ramp from the floor to the top of the same table. Which student did the MOST work?
The student who did the most work is student 2 with 2500 Joules.
Given the following data:
Force 1 = 500 NewtonDistance 1 = 1.2 meterForce 2 = 500 NewtonDistance 2 = 5 meterTo determine which of the students did the most work:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = Force \times distance[/tex]
For student 1:
[tex]Work\;done = 500 \times 1.2[/tex]
Work done = 600 Joules
For student 2:
[tex]Work\;done = 500 \times 5[/tex]
Work done = 2500 Joules.
Therefore, the student who did the most work is student 2 with 2500 Joules.
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Answer:student 2 did the most work
Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.
how many asteroids do scientists believe exist in the solar system?
Answer:
Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.
Explanation:
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
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I change every second what am i
Explanation:
Ummm i think a timer or clock?
Answer: Timer or a clock
Explanation:
can someone explain please?
Hi there!
We can begin by solving for the velocity in which the ball was thrown at using the following:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
At the top of the trajectory, the ball's velocity is equal to 0 m/s, so:
[tex]0 = v_i^2 + 2ad\\\\vi^2 = 2ad \\\\[/tex]
'a' = acceleration due to gravity and 'd' is the max height, so:
[tex]v_i^2 = 2(10)(5)\\\\v_i^2 = 10 m/s[/tex]
Now, we can use the same equation to calculate the final speed at 4.5 m. Remember, the acceleration is NEGATIVE in this instance (taking the negative direction to be in the direction of gravity).
[tex]v_f^2 = 10^2 - 2(10)(4.5)[/tex]
[tex]v_f^2 = 10^2 - 2(10)(4.5)\\\\v_f^2 = 100 - 90 \\\\v_f^2 = 10 \\\\v_f = \boxed{3.1 m/s}[/tex]
Hi sweeties.. I want 5 solving questions about (Fluid Pressure and Temperature) and (Archimedes' Principle) may u help me?!
Answer:
1) A 1L bottle, with a height of 30cm, full of water is emptied. The bottle is filled with oil (density = 920 kg/m^3). Calculate the change in pressure of the bottom of the first bottle. If you decide to put potatoes (assume its density is 1,8 kg/m^3), each one of a volume V = 10 cm^3, will they float?
2) The fusion temperature of the Nitrogen is -210°C and its boiling temperature is 77K. Calculate the difference between the fusion temperature and the boiling temperature.
what role does gravity have in the motion of planets around the sun?
Answer:
The gravity helps the planets stay together near the Sun, without it Earth would be floating away with the planet eventually becoming frozen up, thus the role gravity have in the motion of planets around the sun is by keeping them together.
Explanation:
Hope this helps!
How much power is used in question #2 if the power time was 100secs
I really need the Formula, substitute & solve , answer with units.
Answer:
I just put a random number for the work
Explanation:
I hope it is ok.
if 9 joules of energy are expended pushing on one coulomb of charge round a circuit, what is the emf across the circuit?
[tex]\\ \sf\Rrightarrow V=\dfrac{W}{Q}[/tex]
[tex]\\ \sf\Rrightarrow V=\dfrac{9}{1}[/tex]
[tex]\\ \sf\Rrightarrow V=9V[/tex]
How much energy has 4x 1010 m³ of water collected in a reservoir at a 2. 3. height of 100 m from the power house? What kind of energy is that? (Given, mass of 1 m³ of water = 1000 kg)
Explanation:
[tex] \rule{999pt}{66646pt}[/tex]
what are the three elements that can be used to make a magnet?
Answer:
Iron, cobalt, and nickel are the only three naturally occurring elements that are magnetic.
Explanation:
hope it helps
correct me if I'm wrong thank you
brainliest please
Answer:
The three elements that can be used to make a magnet are :
Aluminum, nickel and cobalt
Why doesn't the skater ever regain his potential energy?
Answer:
Friction
Explanation:
As the skateboarder goes down the ramp, potential energy is converted to kinetic energy. Because of friction, some of the energy in the system is converted to heat energy. Once the kinetic energy is converted to heat, the energy cannot be converted back to the potential or kinetic energy in the system.
You want to replace the resistor in your
boiler with a more efficient one during win-
tertime. Would you replace it with another
one double the length or half the length?
To make the boiler more efficient, we would replace the resistor with another double the length.
We know that the resistance of the resistor in the boiler is given by R = ρl/A where
ρ = resistivity, l = length of resistor and,A = cross-sectional area of resistor.Also, the power generated by the resistor is P = i²R where
i = current and R = resistance.If i is constant, we see that P ∝ R.
So, to increase the efficiency, the value of the resistance has to increase.
Also, since R = ρl/A and ρ and A are constant, we see that R ∝ l.
Since P ∝ R and R ∝ l ⇒ P ∝ l.
So, to increase the efficiency, we would double the length of the resistor.
So, to make the boiler more efficient, we would replace the resistor with another double the length.
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a plane mirror forms a virtual image why
What happens to all light bulbs in a series circuit when one burns out? How would the situation change when the lights are hooked up in parallel?
As best you can, describe how we can tell the age of the Earth and rocks found on it.
Answer:
We can determine the age of the Earth and the rocks found on Earth with techniques such as measuring ice cores and digging and analysing fossils.
Explanation:
Hopefully this helped!
How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?
Answer:
180 [J].
Explanation:
1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;
2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;
3) then the required work [W]:
W=mg*(h₂-h₁)=30*6=180 [J].