a 0.8 ,^3 insulated rigid tank contains 1.54 kg of carbon dioxide at 100 kPa. Now paddle wheel work is done on the system until pressure in the tank rises to 135 kpa assuming the ideal gas model and negligible kinetic and potential energy effects determine the paddle wheel work dine during the process and the energychange during this process

Answers

Answer 1

Answer:

The answer is "[tex]W= 100.44 \ KJ\ \ \ \W_{win}=7.23 \ KJ[/tex]"

Explanation:

Please find the complete question in the attached file.

From of the ideal gas relation that initial and the last temperatures were determined:  

[tex]T_1 = \frac{P_1 V}{m R}[/tex]

    [tex]= \frac{100 \times 0.8}{1.54 \times 0.1889} \\\\ = 275 \ K[/tex]

[tex]T_2 = \frac{P_2 V}{m R}[/tex]

    [tex]= \frac{135 \times 0.8}{1.54 \times 0.1889} \\\\ = 317 \ K[/tex]

In the initial and final states, the internal energies for given temperatures are described from A-20 by means of intelmpolation and divided by the carlxon molar mass.  

[tex]u_1 = 141.56 \frac{KJ}{kg}\\\\u_2 = 206.78 \frac{KJ}{kg}[/tex]

The real job is just the difference between internal energies:  

[tex]W = m(u_2 - u_1) \\\\[/tex]

    [tex]= 1.54(206.78 -141.56) \ kJ \\\\ =100.44 \ kJ[/tex]

In the initial and final states, the zero entries are as determined as internal energies:

[tex]S_1^{\circ} =4.788 \frac{KJ}{kg K}\\\\S_2^{\circ} =5.0478 \frac{KJ}{kg K}[/tex]

From its energy increase, the minimum work required is determined:

[tex]W_{min} = m(u_2-u_1 - T_0(s_2 -S_1))\\\\=W-mT_0(S_2^{\circ}- S_1^{\circ} -R \In \frac{P_2}{P_1})\\\\= 100.44kJ -1.54 \times 298( 5.0478-4.788-0.1889 \In \frac{135}{100})\\\\=7.23\ KJ\\[/tex]

A 0.8 ,^3 Insulated Rigid Tank Contains 1.54 Kg Of Carbon Dioxide At 100 KPa. Now Paddle Wheel Work Is

Related Questions

How are clouds formed? What are the three major
Types of clouds and what do they look like?
O

Answers

Answer:

clouds are created when water vapor and invisible gas turns into water droplets and these water droplets form tiny particles like dust and float in the air.

you have cumulus

cirrus

cirrostraus  

Explanation:

A car accidently roll of a cliff. As it leaves the cliff it has horzontal velocity of 13 m/s it hits the ground 60m from the shoreline. Calculate the hight of the cliff

Answers

Answer: The height of the cliff is 104.59 m

Explanation:

The horizontal speed of the car when it leaves the cliff is 13 m/s, and it hits the ground 60m from the shoreline.

Here we can use the relationship:

Time*Speed = Distance.

To find the time that the car is in the air, we know that:

speed = 13m/s

distance = 60m

time = T

13m/s*T = 60m

T = (60m)/13m/s = 4.62 s

This means that the car is falling for 4.62 seconds.

Now let's analyze the vertical problem.

As the car leaves the cliff, it only has horizontal velocity, this means that the vertical initial velocity will be zero

The only force acting in the vertical axis is the gravitational force, this means that the acceleration will be equal to the gravitational acceleration, which is:

g = 9.8m/s^2

then:

a = -9.8m/s^2

Where the negative sign is because the acceleration is pulling the car downwards.

To get the vertical velocity, we could integrate over time to get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the constant of integration and the initial vertical velocity, that we already know that is equal to zero, then the vertical velocity as a function of time can be written as:

v(t) = (-9.8m/s^2)*t

To get the vertical position equation, we need to integrate again over the time:

P(t) = (1/2)*(-9.8m/s^2)*t^2 + H

Where H is the constant of integration and the initial vertical position, then H will be the height of the cliff.

We know that the car needs 4.62 seconds to hit the ground, this means that:

P(4.6s) = 0m

Then:

P(t) = (1/2)*(-9.8m/s^2)*(4.62s)^2 + H = 0

            (-4.9m/s^2)*(4.62s)^2 + H = 0

          H =  (4.9m/s^2)*(4.62s)^2 = 104.59 m

This means that the cliff is 104.59 meters high

12. A 20-newton cart is lifted up 0.40 meters to the top of a ramp.
What is the amount of potential energy gained by the cart? A

Please show your work and I need it fassst

Answers

Answer:

8 joules

Explanation:

Just did it

Answer:

8 J

Explanation:

Potential energy = mass x gravitational field strength x height

Gravitational field strength is accelerations due to gravity which is 9.8m/s² ( you can round it up and take 10 as well)

Mass = Force ÷ Acceleration

20 ÷ 9.8 = 2.04

Potential energy = 2.04 x 9.8 x 0.40

= 7.99 = 8 J

____energy is from the movement of electrons.

A. gravitational
B. chemical
C. electrical
D. nuclear​

Answers

Answer:

C. electrial

Explanation:

I hope l helped you. Please follow me. ❤❤❤❤

When the plutonium bomb was tested in New Mexico in 1945, approximately 1 gram of matter was converted into energy. Suppose another bomb is tested, and 1.5 grams of matter are converted into energy. How many joules of energy are released by the explosion?

Answers

Answer:

The value is [tex]E = 1.35 *10^{14} \ J[/tex]

Explanation:

From the question we are told that

    The mass of matter converted to energy on first test is  [tex]m = 1 \ g = 0.001 \ kg[/tex]

    The mass of matter converted to energy on second test [tex]m_1 = 1.5 \ g = 1.5 *10^{-3} \ kg[/tex]

    Generally the amount of energy that was released by  the explosion is  mathematically  represented as  

         [tex]E = m * c^2[/tex]

=>       [tex]E = 1.5 *10^{-3} * [ 3.0 *10^{8}]^2[/tex]

=>       [tex]E = 1.35 *10^{14} \ J[/tex]

A(n) 70.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 41.4 m away from the shuttle and moving with zero speed relative to the shuttle. She has a(n) 0.916 kg camera in her hand and decides to get back to the shuttle by throwing the camera at a speed of 12 m/s in the direction away from the shuttle. How long will it take for her to reach the shuttle

Answers

Answer:

4.4 min

Explanation:

To solve this, we use the law of conservation of momentum

0 = -m(a).v(a) + m(c).v(c), where

m(a) = mass of the astronaut

m(c) = mass of the camera

v(a) = velocity of the astronaut

v(c) = velocity of the camera

Making v(a) subject of the formula, we have

v(a) = m(c).v(c)/m(a)

Now, we make one last assumption, that the astronaut is moving at constant speed and time, thus the time needed will be

t = s/v -> since s = vt

Now, we already have our v from above, so we substitute

t = s/[m(c).v(c)/m(a)]

t = s.m(a)/m(c).v(c)

Applying the values, we have

t = (41.4 * 70.1) / (0.916 * 12)

t = 2902.14 / 10.992

t = 264 seconds or 4.4 minutes

How much is a ball that is tethered to a post accelerating if its linear speed is 3.5 m/s and the ball is 0.91 meters away from the pole? a = v^2 / r

Answers

Answer:

[tex]a_{c} = 13.46\ m/s^2[/tex]

Explanation:

The motion of the tethered ball around the pole can be modeled as uniform circular motion. The acceleration of the objects executing uniform circular motion is due to the change in direction of their velocity. This is called centripetal acceleration. It is given by the following formula:

[tex]a_{c} = \frac{v^2}{r}[/tex]

where,

ac = centripetal acceleration = ?

v = speed of ball = 3.5 m/s

r = distance of ball from center of rotation = 0.91 m

Using these values in equation, we get:

[tex]a_{c} = \frac{(3.5\ m/s)^2}{0.91\ m}\\\\a_{c} = 13.46\ m/s^2[/tex]

An Airplane moves 70 m/s as it travels around a vertical circular loop which has a 3 km radius. What is the magnitude of the net force on the 95 kg pilot at the bottom of this loop?

Answers

Answer:

155.17N.

Explanation:

The magnitude of the net force is expressed as;

F = mv²/r where;

m is the mass

v is the velocity of the airplane

r is the radius of the loop

Given

m = 95kg

v = 70m/s

r = 3km = 3000m

Required

Magnitude of the net force

F = 95*70²/3000

F = 95*4900/3000

F = 95*49/30

F = 4655/30

F = 155.17N

Hence the magnitude of the net force on the 95 kg pilot at the bottom of this loop is 155.17N.

The net force on the pilot is 1551.67 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the net force at the bottom of the loop, we use the formula below.

Formula:

F = mv²/r............. Equation 1

Where:

m = mass of the pilotv = velocity of the Airplaner = radius of the loopF = net force on the pilot.

From the question,

Given:

m = 95 kgr = 3 km = 3000 mv = 70 m/s

Substitute these values into equation 1

F = 95(70²)/300F = 465500/300F = 1551.67 N

Hence, the net force on the pilot is 1551.67 N.

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Given a force of 100N and an acceleration of 5 m/s2 , what is the mass?

Answers

Answer:

20kg

Explanation:

Given parameters:

Force  = 100N

Acceleration  = 5m/s²

Unknown:

Mass  = ?

Solution:

According to Newton's second law of motion:

 Force  = mass x acceleration;

 So;

          Mass  = [tex]\frac{force }{acceleration}[/tex]  

          Mass  = [tex]\frac{100}{5}[/tex]   = 20kg

X- rays with a wavelgnth of 0.0700 nm diffract from a crystal. Two adjacne angels of x-ray diffraciton are 45.6 and 21.0 degrees. What is the distance in nm between the atomic planes responsible for the diffraction? (Use 2dcos(θ)=m(λ))

Answers

Answer:

0.15 nm

Explanation:

d = Distance between the atomic planes

m = Order

[tex]\theta_{m}[/tex] = First angle = [tex]45.6^{\circ}[/tex]

[tex]\theta_{m+1}[/tex] = Adjacent angle = [tex]21^{\circ}[/tex]

[tex]\lambda[/tex] = Wavelength = 0.07 nm

From Bragg's relation we know

[tex]2d\cos\theta_{m}=m\lambda[/tex]

[tex]2d\cos45.6^{\circ}=m0.07[/tex]

[tex]2d\cos\theta_{m+1}=(m+1)\lambda[/tex]

[tex]2d\cos21^{\circ}=(m+1)0.07\\\Rightarrow 2d\cos21^{\circ}=m(0.07)+0.07[/tex]

So

[tex]2d\cos21^{\circ}=2d\cos45.6^{\circ}+0.07\\\Rightarrow 2d(\cos21^{\circ}-\cos45.6^{\circ})=0.07\\\Rightarrow d=\dfrac{0.07}{2(\cos21^{\circ}-\cos45.6^{\circ})}\\\Rightarrow d=0.14962\ \text{nm}[/tex]

The distance between the atomic planes is 0.15 nm.

A car slows down uniformly from a speed of 21.0m/s to rest in 6.00s. How far did it travel in that time?

Answers

(sorry something wrong w my keyboard so write each line for the explnation!)

63.0 m

Explanation:

Acceleration of car

=

v

u

t

=

0 ms

1

21.0 ms

1

6.00 s

=

3.50 ms

2

S

=

v

2

u

2

2a

S

=

(

0 ms

1

)

2

(

21.0 ms

1

)

2

2

×

3.50 ms

2

S

=

63.0

m

HELP ME NOW PLZ
What is the speed of a boy moving around a circular park of
radius 6 m if he goes once around the park in 20 s?
A-1.88m/s
B-3.76m/s
C-5.65m/s
D-None of the above

Answers

Answer: 1.88 m/s

Explanation:

The speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.

What is speed?

Speed is a measurement of how quickly an object's distance traveled changes. Speed is a scalar, which implies it has magnitude but no direction as a unit of measurement.

A thing that moves quickly and with great speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time.

Given information:

The radius of the circular park, r = 6 m,

The time is taken to cover one round, t = 20s,

The total distance covered by the boy is equal to the circumference of the park, so

d = 2[tex]\pi[/tex]r,

[tex]d = 2*3.14*6\\d = 37.68 m[/tex]

Now,

the speed of the boy, s = [tex]37.68/20[/tex] ,

s = 1.88 m/s

Therefore, the speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.

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Question 1 of 25
Two asteroids with masses 3.71 x 10 kg and 1.88 x 104 kg are separated by
a distance of 1,300 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity
Gm, 2 The gravitational
constant Gis 6.67 x 10-11 Nm²/kg?
A. 275 x 10"N
B. 4.13 x 10°N
C. 2.04 x 10°N
O D. 3.58 x 10-N
SUBMIT

Answers

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

As the fragment falls through the atmosphere it is heated and some of the material is vaporized. Explain how you could determine the composition of this hot vaporized material from the light it emits.

Answers

Answer:

by determining the wavelength of the light emitted

Explanation:

The composition of the hot vaporized materials of an asteroid can be find out by the wavelength of the light emitted when the fragment material is burnt out.

Some of the asteroids that are very large do not burn completely in the atmosphere and they fall on the surface of the earth. Thus there is a possibility of radioactivity. An atom is radioactive or unstable when the forces that constitutes the nucleus are not balanced and then the nucleus have excess of energy. Thus these unstable and highly energetic nucleus will try to attain stability by ejecting protons and neutrons, or by releasing gamma rays, beta particles or positrons, etc. Thus they will radiate energy and will cause radioactivity.

If a paratroopers legs have enough strength to support five times her weight, and they can do so over a travel distance of 0.5 m as they flex, from what height can she free fall to a solid surface without injury

Answers

Answer: the required height is 2.5 m

Explanation:

given the given data in question

Lime to come in rest;

using S = ((U1 + U2)/2) t

⇒ 0.5 = ((√(2gh) + 0)/2) t

t = (0.5 × 2) / √(2gh)

now fat = impulse = change in momentum dp

F = 5mg = dp/dt = [(m√(2gh))/(0.5 × 2)] × √(2gh)

5mg = 2mgh/(0.5 × 2)

5 = h / 0.5

h = 5 × 0.5

h = 2.5 m

Therefore the required height is 2.5 m

Which type of bond has elements with the greatest difference in electronegativity?

Covalent
Ionic
Metallic
Polar

Plz Help

Answers

Answer:

inonic bond has greatest difference in electronegativiru

The type of bond that has elements with the greatest difference in electronegativity ionic bond. The correct option is is B.

What is electronegativity?

Electronegativity is a chemical property that describes an atom's or functional group's tendency to attract electrons toward itself.

An atom's electronegativity is affected by both its atomic number and the distance between its valence electrons and the charged nuclei.

Electronegativity is a measurement of an atom's proclivity to attract electrons (or electron density) towards itself.

It governs the distribution of shared electrons between two atoms in a bond. The greater an atom's electronegativity, the more strongly it attracts electrons in its bonds.

Ionic bonds are formed by elements with large differences in electronegativity. Covalent bonds are formed between atoms of elements with similar electronegativity.

Thus, the correct option is B.

For more details regarding electronegativity, visit:

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Which one of the following is insoluble in water?

Food coloring
Lemon slices
Rock salt
White vinegar

Answers

Answer:

Lemon slices is the correct answer

Answer:

food coloring

Explanation:

i think food coloring is because it's just water with food coloring and that's it

A 1500 kg car sits on a 3.5° inclined hill. Find the force of friction required to keep it from
sliding down the hill. The coefficient of static friction is μ=0.45

Answers

Answer:

The force of friction required to keep the car from sliding down the hill is 898.054 newtons and since [tex]f<f_{max}[/tex], the car will not slide down the hill.

Explanation:

The free body diagram is included below and now we prepare each equation of equilibrium for respective orthogonal axis:

[tex]\Sigma F_{x'} = f-m\cdot g \cdot \sin \theta = 0[/tex] (1)

[tex]\Sigma F_{y'} = N-m\cdot g \cdot \cos \theta = 0[/tex] (2)

Where:

[tex]f[/tex] - Static friction force, measured in newtons.

[tex]N[/tex] - Normal force from the inclined hill to the car, measured in newtons.

[tex]m[/tex] - Mass of the car, measured in newtons.

[tex]g[/tex] - Gravitational constant, measured in meters per square second.

[tex]\theta[/tex] - Angle of inclination of the hill, measured in sexagesimal degrees.

If we know that [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 3.5^{\circ}[/tex], then the friction force required to keep the car from sliding down the hill is:

[tex]f = m\cdot g \cdot \sin \theta[/tex]

[tex]f = (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \sin 3.5^{\circ}[/tex]

[tex]f = 898.054\,N[/tex]

The force of friction required to keep the car from sliding down the hill is 898.054 newtons.

If the car does not slide down the hill, then the following condition must be observed:

[tex]f\le \mu_{s}\cdot m\cdot g \cdot \cos \theta[/tex] (2)

Where [tex]\mu_{s}[/tex] is the static coefficient of friction, dimensionless.

If we know that [tex]\mu_{s} = 0.45[/tex], [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 3.5^{\circ}[/tex], then the maximum allowable static friction force is:

[tex]f_{max} = \mu_{s}\cdot m \cdot g \cdot \cos \theta[/tex]

[tex]f_{max} = (0.45)\cdot (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \cos 3.5^{\circ}[/tex]

[tex]f_{max} = 6607.378\,N[/tex]

Since [tex]f<f_{max}[/tex], the car will not slide down the hill.

To understand the meaning of the variables that appear in the equations for rotational kinematics with constant angular acceleration. Rotational motion with a constant nonzero acceleration is not uncommon in the world around us. For instance, many machines have spinning parts. When the machine is turned on or off, the spinning parts tend to change the rate of their rotation with virtually constant angular acceleration. Many introductory problems in rotational kinematics involve motion of a particle with constant, nonzero angular acceleration. The kinematic equations for such motion can be written as

Answers

Answer:

   ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

Explanation:

Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is

     x → θ

     v → ω

     a → α

with these changes the three linear kinematics relations change to

      ω = ω₀ + α t

      ω² = ω₀² + 2 α  θ

      θ = θ₀ + ω₀ t + ½ α t²

where it should be clarified that to use these equations the angles must be measured in radians

A lens is designed to work in the visible, near-infrared, and near-ultraviolet. The best resolution of this lens from a diffraction standpoint is A) The same for all wavelengths B) In the near-ultraviolet C) In the visible D) In the near-infrared E) Indeterminate

Answers

Answer:

B) In the near-ultraviolet

Explanation:

The best option to this problem is : In the near-ultraviolet

did sans from Undertale really die or was he just trolling

Answers

he did sadly can’t believe it T-T

Answer:

I think he was just trolling.

Explanation:

They don't give out any good reasons or evidence about him dying. I think they are just pretending. You tell me tho.... Many people think he did die, while others think that he didnt.

What do you think?!

How long is a simple pendulum with a period of 1 second?​

Answers

Answer:

the second pendulum ( also called the royal pendulum) o.994m (39.1 in) long, in which each swing takes one second, became widely used in quality clocks.

A tissue is a group of similar cells that perform a specific function in an organism true or false

Answers

Answer:

true

Explanation:

Answer:

This is true

A large pendulum with a 200-lb gold-plated bob 12 inches in diameter is on display in the lobby of the United Nations building. The pendulum has a length of 75 ft. It is used to show the rotation of the Earth-for this reason it is referred to as a Foucault pendulum. What is the least amount of time it takes for the bob to swing from a position of maximum displacement to the equilibrium position of the pendulum?

Answers

Answer:

2.4s

Explanation:

The length of the pendulum = 75ft

Diameter d = 12 inches

The time period of the pendulum is given as

T = 2pi(L/g)^1/2

Then the time it takes to move from displacement to equilibrium is given as:

t = T/4

= (Pi/2)*(L/g)^1/2

= pi/2 x [(75x0.3048)/9.81]^0.5

= 1.57x[22.86/9.81)^0.5

= 2.4s

2.4 seconds is the least amount of time that it would take.

In which reaction are the atoms of elements rearranged?
A. A neutron fuses with hydrogen-1 to form hydrogen-2.
B. Uranium-235 breaks apart into cesium, rubidium, and two
neutrons.
C. A neutron fuses with uranium-238 to form uranium-239.
D. Hydrogen combines with oxygen to form water.

Answers

Answer:

D. Hydrogen combines with oxygen to form water.

Explanation:

Hydrogen combining with oxygen to form water is a typical example of chemical reaction.

During a chemical reaction, atoms of elements are rearranged. Most chemical reactions obey the law of conservation of mass which states that "matter is neither created nor destroyed in a chemical reaction but atoms are simply rearranged".

The other choices given are nuclear reactions. In such reactions, atoms are not rearranged but are simply destroyed and made in the process.

Answer:

D.) Hydrogen combines

Explanation:

BE HAPPY

What is the force required to stretch a spring whose constant value is 35 N/m by an amount of 0.25 m?

Answers

Answer:

or whatever then look it up it

Explanation:

Characteristics of good home insulation :

Answers

Answer:

Explanation:

all

An object that is initially traveling at 17.6 m/s has
1,743 J of work performed on it. If the mass of the
object is 283 kg, its final kinetic energy will be
J.

Answers

CnnsmamfmdmmaldlMnvnnakwkkfkfosksmnfnfnek

The pendulum consists of two slender rods AB and OC which each have a mass of 3 kg/m. The thin plate has a mass of 10 kg/m2. Determine the location of the center of mass G of the pendulum, then calculate the moment of inertia of the pendulum about an axis perpendicular to the page and passing through G.

Answers

Answer:

the answer is below

Explanation:

The diagram of the problem is given in the image attached.

Mass of rod AB = (0.4 m + 0.4 m) * 3 kg/m = 2.4 kg

Mass of rod OC = (1.5 m) * 3 kg/m = 4.5 kg

Mass of plate = 10 kg/m²[ (π* 0.3²) - (π* 0.1²)] = 2.513 kg

The center of mass is:

[tex]\hat{y}[2.4+2.513+4.5]=(0.75*4.5)+(2.513*0.5)\\\\\hat{y}=0.839\\\\I_{AB}=\frac{1}{12}*2.4*(0.4+0.4)^2= 0.128\ kg/m^2\\\\I_{OC}=\frac{1}{12}*4.5*(1.5)^2= 3.375\ kg/m^2\\\\I_{Gplate}=\frac{1}{2}*(\pi*0.3^2*10)*(0.3)^2-\frac{1}{2}*(\pi*0.1^2*10)*(0.1)^2= 0.126\ kg/m^2\\\\I_{plate}=I_{Gplate}+md^2=0.126+2.513(1.8^2)=8.27\ kg/m^2\\\\I_o=I_{plate}+I_{AB}+I_{OC}\\\\I_{o}=0.128+3.375+8.27=11.773\ kg/m^2 \\\\I_G=I_o-m_{tot}\hat{y}^2\\\\I_G=11.773-(9.413*0.839^2)\\\\I_G=5.147\ kg/m^2[/tex]

What do your observations show you about the forces exerted on objects in a collision?
Scroll for more

Answers

I need more information
Other Questions
(1) For centuries, art scholars have studied the renowned works of Leonardo da Vinci, the Renaissance artist, pondering how he created three-dimensional figures with such depth on flat canvases. (2) If da Vinci did have exotropia, in which an eye turns outward, he would not have been the only artist in history with that condition.(3) Christopher Tyler, a visual neuroscientist at City University of London, noticed a pattern in da Vincis portraits and in works depicting the great artist. (4) While few self-portraits of da Vinci exist, Tyler argues that many of da Vincis portraits reflect his appearance. (5) As the great artist himself said, the soul guides the painters arm and makes him reproduce himself, since it appears to the soul that this is the best way to represent a human being.(6) To test his theory that da Vinci had exotropia, Tyler studied the eye alignments of the subjects of six pieces of art that purportedly depict the Renaissance artist himself, including da Vincis Vitruvian Man and Salvator Mundi and Andrea del Verrocchios sculpture David. (7) The results confirmed Tylers suspicions: da Vinci likely had exotropia, with one eye turning out at -10.3 degrees.(8) Tylers findings, which he published in JAMA Ophthalmology, created a stir in both the art and science communities. (9) Only about 1 percent of the population has exotropia, yet previous studies have suggested that other famous artistslike Rembrandt, Picasso, and Degashad it as well, which indicates that the eye condition was more common in centuries past than it is now. (10) Tyler believes that da Vincis condition was intermittentthat is, his eye drifted out of alignment when he was relaxed, but when he focused, it would realign. (11) If Tyler is right and da Vinci could control his exotropia, then the artist could switch from 2-D to 3-D vision, enhancing his ability to accurately capture three-dimensional figures on a two-dimensional canvas.The writer is considering changing the passage to argue that Tyler does not have enough evidence to support the assertion that da Vinci had exotropia. The writer drafted the following thesis statement, which is intended to preview the line of reasoning the new passage would have.Though it is true that Tyler studied six separate works of art, including such famous works as Vitruvian Man and Salvator Mundi, there is not enough evidence to prove that da Vinci suffered from exotropia.Should the writer include the underlined portion of the thesis statement? A Yes, because it helps remind readers of some famous da Vinci works.B Yes, because it strengthens the thesis by conceding that the works Tyler studied are important ones.C Yes, since it suggests that the writer is knowledgeable on the subject of da Vinci.D No, because a thesis does not need to provide specifics of an argument or evidence to be a good preview.E No, since it specifies what Tylers study included rather than what it failed to include. Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will jump straight upward.Will the shrimp do any work in this case? please answer I will give 20 and brainiest Find the 12th term in the following arithmetic sequence Of all the major European powers, which was the only one to remain outside of Napoleon's empire? Characters in the play Alice in Wonderland.(You only have to do one if you want :) But pls help! And fast! Describe Alice. What is her personality? Does it affect her relationship with other characters in the play? How does she react to the situation that she finds herself in?Describe the White queen. Explain her relationship with Alice. How does this character contribute to the story? Using the picture below, select the answer that best matces the picture ez pls help i will give extra points URGENT PLEASE ANSWER ASAP How did Benito Mussolini get control over Italy's government?Mussolini purged the Communist Party.Mussolini outlawed political parties.Mussolini imprisoned officers of the Italian Army.Mussolini was elected by majority vote. Maria walks up hill to go to school every day. When she reaches the top of the hill, she is always breathing much faster than when she started. How might this affect how her heart is working? Support your hypothesis with evidence. Drag the tiles to the correct boxes to complete the pairs.Match the instances to the marketing utilities that they satisfy toward value proposition.Cassey has her ice-cream shop just outsidethe school.Casseys ice cream blends with the richestingredients to make it tasty as well as healthy.Cassey also offers credit to school kidsby maintaining a book of accounts.Casey lists the nutritional value of eachflavor on a sign at the bottom of theice cream cartons.formplace Solve the equation, showing each step of the solution.1 (x 10) = -4 Why did Marxist ideology emerged during the industrial revolution? Find the 12th term of the geometric sequence 4,8,16? paragraph. how to choose a true friend Adams tells Jefferson HELP NOW PLS !! If you exert 950 N*s of impulse on a 12 kg frictionless cart over the course of 5 seconds, how far will it travel during those seconds? What is the quotient of 3 /7 + 4/8 using reciprocal express your answer in lowest term Which person would be most threatened by silver carp in a local water source?A waterskier B A chicken farmer C A bungee jumper D A beachgoer Activity #1Normal DNA SequenceDNA:TACCCCGTGCAT ATAT CATATAGCACTmRNA:Protein:Mutated DNA SequenceDNA:TACCCCGTGCACATATCGTATAGCACTmRNA:Protein:Describe the effects of the change(s) in the mutated DNA sequence. Did the protein change? Do you thinkthis protein can perform its normal function?Stephanie ElkowitzHelp please!!!!