A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below.
B) What equilibrant force is required to keep the block at rest once it does?
C) If you were to rearrange the three forces as you like, what maximum force could be applied to slow the block?
D) How much time would it take for the block to stop under maximum force conditions?
Answers
Newton's second law and the kinematic relations allow to find the results for the questions about forces and the movement of the block are:
B) the force applied to maintain the system is equilibrium is: F = 0.39 N with an angle of tea = 180º
C) The maximum force is: F = 24 N
D) The time to stop the block is: t = 25 s
Newton's second law establishes a relationship between the net force, the mass, and the acceleration of the body. In the special case that the acceleration is zero it is called the equilibrium condition.
B) They indicate a diagram of forces on the block, let's look for the components of the force that the block maintains with zero acceleration, in the attached we have a free-body diagram including the force applied to keep the system in equilibrium.
x-axis
-10 + 12 sin 60 + Fₓ = 0
Fₓ = 10- 12 sin 60 = -0.39 N
y-axis
12 cos 60 - 6 + F_y = 0
F_y = 6 - 12 cos 60 = 0 N
We can give the result of the force in two ways:
Form of coordinates F = -0.39 i ^ N Form of module and angle.
Let's use Pythagoras' theorem to find the modulus.
[tex]F = \sqrt{F_x^2 + F_y^2 } \\F = \sqrt{0.39^2 +0^2}[/tex]
F = 0.39N
We use trigonometry for the angle.
[tex]tan \theta = \frac{F_y}{F_x}[/tex]
tan θ= 0º
The component of the force is negative therefore this angle is in the second quadrant, to measure the angle from the positive side of the x axis in a counterclockwise direction.
θ = 180 + θ'
θ = 180 + 0
θ = 180º
C) if the three forces can be moved and the maximum force occurs when they are all linear.
10+ 6 + 6 + F = 0
F = -24 N
D) if we maintain this force and eliminate the other three, the block stops, let's look for its acceleration.
[tex]a = \frac{F}{m}[/tex]
a = [tex]\frac{24}{6}[/tex]
a = 4 m / s²
The acceleration is in the opposite direction of the initial velocity of the block v₀ = -100 m / s
If we use kinematic relations.
v = v₀ - a t
Final velocity when stopped is zero
t = [tex]\frac{0-v_o}{a}[/tex]
t = 100/4
t = 25 s
In conclusion using Newton's second law and the kinematics relations we can find the results for the questions about the forces and the motion of the block are:
B) the force applied to maintain the system is equilibrium is: F = 0.39 N with an angle of tea = 180º
C) The maximum force is: F = 24 N
D) The time to stop the block is: t = 25 s
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Related Questions
1. Which of these is not a spherical mirror?
a) Concave mirror
b) Convex mirror
c) Plane mirror
d) None of these
Answers
Answer:
C.Plane mirror this is the answer of this question.
None of the above. That is option D.
A spherical mirror is defined as a mirror that has a surface that reflects curved rays. It is also called a curved mirror.
Types of spherical mirror include:
Concave mirror: This has a reflective surface that is curved inward and away from the light source. It reflects light inward to one focal point.Example of concave mirror are Torch lights and automobile headlights.
Convex mirror: These are the spherical mirror that reflects light outwards and towards the light source.Example of convex mirror is the magnifying glasses and telescopes.
Plane mirrors: This is a type of spherical mirror with a flat surface. Reflection of light occurs in plane mirror but it's center of curvature is infinite because it's flat.Therefore, concave, convex and plane mirrors are all examples of a spherical mirror.
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ignoring air resistance, an object falling toward the surface of the earth has a velocity that is
Answers
2. A nutty professor leaves a history classroom and walks 10. meters north to a drinking fountain. Then, in a daze, she turns and walks 30. meters south to an art classroom. (draw vectors to scale to show your work)
(a) What is the professor’s total displacement from the classroom to the art classroom?
(b) What was the total distance she traveled?
Answers
Total displacement:-
[tex]\\ \sf\Rrightarrow 10-30=20m[/tex]
Total distance
[tex]\\ \sf\Rrightarrow 10+30=40m[/tex]
plssss helppppppppppp i need it
Answers
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
haun wants to enter the science fair at his school. he has a list of ideas for his project. which questions could be answered through scientific investigations. check all that apply
Answers
Correct Answer:
- Does pressure have an effect on the volume of a gas?
- Which brand of soap is the best for cleaning grease off dishes?
why can you predict how the moon will change appearance from day to day
Answers
As the Moon orbits our planet, its varying position means that the Sun lights up different regions, creating the illusion that the Moon is changing shape over time. This is because it rotates once on its axis in exactly the same time it takes to orbit Earth – 27 days and seven hours
1. An 80 kg skydiver uses a parachute to produce an applied force of 700 N while falling with an initial
velocity of 40 m/s
Answers
Time taken by the skydiver to land on the ground is 4.57 seconds
The applied force, F = 700 N
The mass of the skydiver, m = 80 kg
The velocity, v = 40 m/s
To calculate the time taken by the skydiver to fall to the ground will be calculated using the formula
[tex]F=\frac{mv}{t}[/tex]
Substitute F = 700, m = 80, and v = 40 to solve for t
[tex]700=\frac{80(40)}{t}\\\\700t=3200\\\\t=\frac{3200}{700}\\\\t=4.57 s[/tex]
Time taken by the skydiver to land on the ground is 4.57 seconds
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when do magnets have the most potential energy
Answers
Answer:
Explanation:
Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.
a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.
Answers
The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C
Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car
i.e. | Fg |car < | Fg | truck
also : | Fₙ | car < | Fₙ | truck
Since the gravitational force on the car is less than the gravitational force on the truck
| Ff | car < | Ff | truck
where : Ff = frictional force
Fg = force due to gravity
Fn normal force
Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is : Diagram C.
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Attached below is the missing data related to your question
hi i need some help with this.....
Answers
Answer: D
Explanation: moogle helps lol.
Explanation:
In a plant cell, chloroplast makes sugar during the process of photosynthesis converting light energy into chemical energy stored in glucose. In mitochondria, through the process of cellular respiration breaks down sugar into energy that plant cells can use to live and grow.
You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?
Answers
Answer:
Explanation:
Centrifugal force Fc = m x v2 / r
Weight = mg
As required by the question
Fc = W
v2 /r = g
given radius r = 22 m
v2 /22 = 9.8
Solve for v
required speed v = √(22 * 9.8)
= 14.35 m/s
v=15 m/s
this may help you
The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.
What is centrifugal force?The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.
The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:
[tex]{\displaystyle F=m\omega ^{2}r}[/tex]
Given, the radius of the curve, r = 22m
The acceleration, a = v²/r
The weight of the box, W = mg
We know that, F = ma
mg = m(v²/r)
v = √gr
[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]
v = 14.68 m/s
Therefore, you should drive at a speed of 14.68 m/s
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*
as the mass of an object increases, the force of attraction...
Answers
Answer:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
Answer:
thanks
Explanation:
for answer byebye
what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answers
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
A wave completes one vibration as it moves a distance of 2 meters at a speed of 20 meters per second. What is the frequency of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answers
Answer:
I put the answer
Explanation:
Can you see it
10Hz is the frequency of the wave.
How to find the frequency of the wave?
To calculate the frequency of a wave, divide the velocity of the wave by the wavelength. Write your answer in Hertz or Hz
Given,
F = 2
λ=2m
v=20m/s
By applying the formula, we get
V = Fλ
F = V / λ
F = 20 / 2
=10Hz
Wave frequency is the number of waves that pass a fixed point in a given amount of time.
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Three forces acting on an object are given by F1 = (−2.00 i + 2.00 j) N,F2 = (5.00 i − 3.00 j) N, and F3 = (−45.0 i) N. The object experiences an acceleration of magnitude 3.75 m/s2.
i. What is the direction of the acceleration?
ii. What is the mass of the object?
iii. If the object is initially at rest, what is its speed after 10.0 s?
iv. What are the velocity components of the object after 10.0 s?
Answers
From summation and resultant of forces, the four answers are:
i. ∅ = 34 degrees
ii. M = 0.48 kg
iii. V = 37.5 m/s
iv. V = 37.5i + 0j + 0k
Given that Three forces acting on an object are
F1 = (−2.00 i + 2.00 j) N
F2 = (5.00 i − 3.00 j) N
F3 = (−45.0 i) N.
If the object experiences an acceleration of magnitude 3.75 m/s2.
i. The direction of the force will be the direction of the acceleration.
Sum of the forces = (-2 + 5 - 4.5)i + (2 - 3 + 0)j
Sum of the forces = -1.5i -j
The acceleration direction will be
tan∅ = [tex]\frac{y}{x}[/tex]
tan∅ = [tex]\frac{1}{1.5}[/tex]
∅ = [tex]tan^{-1}[/tex] (0.67)
∅ = 34 degrees (approximately)
ii. The mass of the object can be calculated from Newton's law.
Resultant force = mass x acceleration.
Resultant force = [tex]\sqrt{1.5^{2} + 1^{2} }[/tex]
Resultant force = [tex]\sqrt{3.25}[/tex]
Resultant force = 1.8N
Then,
1.8 = 3.75M
M = 1.8 / 3.75
M = 0.48 kg
iii. If the object is initially at rest, the speed of the object after 10.0 will be calculated by using first equation of motion.
V = U + at
Where U = 0
V = 0 + 3.75 x 10
V = 37.5 m/s
Therefore, the speed of the object after 10.0 is 37.5 m/s
iv. The velocity components of the object after 10.0 are
V = 37.5i + 0j + 0k
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the only two forces acting on a body have magnitudes of 20 n and 35 n and directions that differ by 80. the resulting acceleration has a magnitude of 20 m/s2. what is the mass of the body?
Answers
Answer:
the mass of the body is 2.75 kg
how can I make a square fit in a triangle hole
Answers
cut the square and make it a triangle
how to prove the first linear motion
Answers
Answer:
Then solve for v as a function of t. This is the first equation of motion . It's written like a polynomial — a constant term (v0) followed by a first order term (at). Since the highest order is 1, it's more correct to call it a linear function.
Explanation:
A hockey player hits a rubber puck from one side of the rink to the other. It has a mass of .170 kg, and is hit at an initial speed of 6 m/s. If the rink is 61 meters long, how fast is the puck moving when it hits the far wall?
Answers
By using third law of equation of motion, the final velocity V of the rubber puck is 8.5 m/s
Given that a hockey player hits a rubber puck from one side of the rink to the other. The parameters given are:
mass m = 0.170 kg
initial speed u = 6 m/s.
Distance covered s = 61 m
To calculate how fast the puck is moving when it hits the far wall means we are to calculate final speed V
To do this, let us first calculate the kinetic energy at which the ball move.
K.E = 1/2m[tex]U^{2}[/tex]
K.E = 1/2 x 0.17 x [tex]6^{2}[/tex]
K.E = 3.06 J
The work done on the ball is equal to the kinetic energy. That is,
W = K.E
But work done = Force x distance
F x S = K.E
F x 61 = 3.06
F = 3.06/61
F = 0.05 N
From here, we can calculate the acceleration of the ball from Newton second law
F = ma
0.05 = 0.17a
a = 0.05/0.17
a = 0.3 m/[tex]s^{2}[/tex]
To calculate the final velocity, let us use third equation of motion.
[tex]V^{2}[/tex] = [tex]U^{2}[/tex] + 2as
[tex]V^{2}[/tex] = [tex]6^{2}[/tex] + 2 x 0.3 x 61
[tex]V^{2}[/tex] = 36 + 36
[tex]V^{2}[/tex] = 72
V = [tex]\sqrt{72}[/tex]
V = 8.485 m/s
Therefore, the puck is moving at the rate of 8.5 m/s (approximately) when it hits the far wall.
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if a big person and a small person run up the stairs at the same time who has more force
Answers
Answer:
a big person
Explanation:
because the big person exerts more force over the same distance
Answer:
the big person exerts the largest force on the stairs because he weighs more
Explanation:
this question answer is ☝️☝️
A bullet having mass of 120 g is fired. It its velocity is 40 m/s, calculate its kinetic energy
Answers
Happy Holidays!
Recall the equation for kinetic energy:
[tex]\large\boxed{KE = \frac{1}{2}mv^2}}[/tex]
KE = kinetic energy (J)
m = mass (kg)
v = velocity (m/s)
Begin by converting 120 g to kg:
1000g = 1 kg
120 g = .120 kg
Plug in the given values:
[tex]KE = \frac{1}{2}(.120)(40^2) = \boxed{96J}[/tex]
Answer:
96 Joules
Explanation:
[tex]E_k=1/2* mass*velocity^2\\E_k=1/2 * 0.12 kg * (40m/s)^2 = 96 J[/tex]
what are the main component of network
Answers
Answer:
A network has 5 basic components viz. clients, servers, channels, interface devices and operating systems.
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A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.
Part A
How much work is done during this part of its motion by the cable that lowering the elevator? Neglect any friction or air resistance.
Answers
Answer:
11115 J
Hope you could get an idea from here.
Doubt clarification - use comment section.
When Magnesium and Fluorine react what type of bond is formed
A) Metallic
B) Ionic
C) Covalent
D) Diatomic
Answers
Answer:
hi your answer should be B
Explanation:
Hope this helps!
Answer:
ionic
Explanation:
two metals that bond are considered ionic bonds
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to the cup or surroundings. What is the final temperature of the mixture? answer in celsius
Answers
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
Kepler’s laws of planetary motion describe each of the three laws
Answers
Kepler's laws laid the foundation for the early study of astronomy.
Kepler was one of the earliest astronomers that contributed immensely to the study of the planets. The Kepler's laws of planetary motion are as follows;
The planets each travel along an ellipse with the sun at one focus.The line joining the sun and the planets sweeps out equal areas in equal time intervals.The square of the period of the revolution of the planets equals the cube of the planet's mean distance from the sun.Learn more about Kepler's laws; https://brainly.com/question/1017661
What does the diagram show about X and Y?
A They have the same mass and the same volume but different weights.
B They have the same mass and the same weight but different volumes.
C They have the same mass, the same volume and the same weight.
D They have the same weight and the same volume but different masses.
Answers
Answer: answer is c rest of explanation is in the comments
Starting with only the Balmer series light (visible light), how could we ensure that the solar panels generate a current that Mark can use for his power station? (It may help to look at the electromagnetic spectrum from week 3):.
Answers
We can ensure that the solar panels generate a current that Mark can use for his power station is by gradually increasing the brightness (amount) of light that we reflect on it.
Solar panel are photo-voltaic module or cells which means they uses sunlight as a source of energy to generate current.
when the sun rays hit a silicon crystal of the solar panel then the electron inside of the solar panel start to charge and travel rapidly. when such charged electron flow through the circuit then the solar panel generate electricity.
So, to optimize the electricity generation, the energy of light is to be maximized which is determined by the frequency of the source.
Hence, To ensure that the solar panels generate a current that Mark can use for his power station we need to gradually increase the brightness (amount) of light that we reflect on it.
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Why does gravity on Earth have a stronger attraction with you than the sun has with you? Plsssssss help I really need this rn
Answers
Answer:
Although the Earth has a lesser mass than the Sun, it is far closer to you, allowing for a stronger pull.
Explanation:
A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?
Answers
Answer:it was lifted
Explanation:
by me lifting it because i can life it very high