A chocolatier makes chocolate bon-bons in the shape of a sphere with a radius of 2cm. The chocolate used in the bon-bons has a density of 1.31 g/cm^3. If the chocolate
used costs $0.06 per gram, how much would the chocolate for 140 bon-bons cost, to
the nearest cent?

Answers

Answer 1

We will get the mass of each chocolate sphere, and the cost of 140 of these is $368.56

How much would it cost?

A sphere of radius R has a volume:

V = (4/3)*3.14*R^3

The mass of a sphere of chocolate will be given by the volume times the density, then one ball of chocolate has a mass:

M = (4/3)*3.14*(2cm)^3*(1.31 g/cm^3) = 43.88 g

And we know that the cost is of $0.06 per gram, the cost for 140 of these spheres is:

cost = 140*(44.88 g)*$0.06 = $368.56

If you want to learn more about density, you can read:

https://brainly.com/question/1354972


Related Questions

Jim earns a regular hourly rate of five dollars and a premium hourly rate of six dollars he worked 45 hours last week what is his gross pay

Answers

Answer:

The premium is the overtime.

Total time = 45 hours.

40 hours of regular time at $5, and 5 hours of overtime.

Total = 40*5 + 5 * 6 = 200 + 30 = $230

[tex]\rm \lim \limits_{n \to \infty } {n}^{ - \frac{1}{2} ( \frac{n + 1}{n} )} (1 \times {2}^{2} \times {3}^{2} \times \dots \times {n}^{n} {)}^{ \frac{1}{ {n}^{2} } } [/tex]​

[tex]\rule{200pt}{2pt}[/tex]
[tex] \rm I= \sum \limits_{k = 1}^{98} \int_{k}^{k + 1} \frac{k + 1}{x (x+ 1)} \: dx, then \\ [/tex] [tex] \rm[A] \phantom{gg}I>log_e99 \\ \\ \rm [B] \phantom{gg}I < log_e99 \\ \\ \rm[C] \phantom{hffgg} I < \frac{49}{50} \\ \\ \rm[D] \phantom{gfffg} I > \frac{49}{50} \\ [/tex]​

Answers

Using the exp-log technique,

[tex]\displaystyle \lim_{n\to\infty} \frac{\left(1 \times 2^2 \times 3^3 \times \cdots \times n^n\right)^{\frac1{n^2}}}{n^{\frac{n+1}{2n}}}[/tex]

[tex]\displaystyle = \exp\left(\lim_{n\to\infty} \frac{\ln\left(\prod\limits_{k=1}^n k^k\right)}{n^2} - \frac{n+1}{2n} \ln(n)\right)\right)[/tex]

[tex]\displaystyle = \exp\left(\lim_{n\to\infty} \frac{\sum\limits_{k=1}^n k\ln(k)}{n^2} - \frac{n+1}{2n} \ln(n)\right)\right)[/tex]

We have ln(k) = ln(k/n) + ln(n), and so we can rewrite the limand as

[tex]\displaystyle = \exp\left(\lim_{n\to\infty} \left(\frac1n \sum\limits_{k=1}^n \frac kn \ln\left(\frac kn\right) + \frac{\ln(n)}{n^2} \sum_{k=1}^n 1 - \frac{n+1}{2n} \ln(n)\right)\right)[/tex]

Then the first sum converges to a definite integral,

[tex]\displaystyle \lim_{n\to\infty} \frac1n \sum_{k=1}^n \frac kn \ln\left(\frac kn\right) = \int_0^1 x \ln(x) \, dx = -\frac14[/tex]

while the remaining terms vanish since

[tex]\displaystyle \frac{\ln(n)}{n^2} \sum_{k=1}^n 1 = \frac{\ln(n)}{n^2} \times \frac{n(n+1)}2 = \frac{n+1}{2n}\ln(n)[/tex]

So the limit is [tex]\boxed{e^{-1/4}}[/tex].

Since

[tex]\dfrac1{x(x+1)} = \dfrac1x - \dfrac1{x+1}[/tex]

it's easy to show that the integral reduces to

[tex]\displaystyle \int_k^{k+1} \frac{k+1}{x(x+1)} \, dx = (k+1) \ln\left(\dfrac{(k+1)^2}{k(k+2)}\right)[/tex]

so we can write the sum as

[tex]I = \displaystyle \sum_{k=1}^{98} \int_k^{k+1} \frac{k+1}{x(x+1)} \, dx = \sum_{k=2}^{99} k \ln\left(\frac{k^2}{k^2-1}\right)[/tex]

We have k²/(k² - 1) > 1 for all k, so that ln(k²/(k² - 1)) > ln(1) = 0. We can see the first 3 terms of the sum already exceed 1 > 49/50, so (D) is true.

Numerical computation of the sum suggests I < ln(99), but I have yet to come up with an analytical solution for this bound...

Find the slope of the line that passes between the points (4,3/8) and (6,7/8)

Answers

Answer:

1

Step-by-step explanation:

1. Plug the points into the slope formula:

[tex]\frac{\frac{7}{8} - \frac{3}{8}}{6 - 4}[/tex]

2. Simplify.

[tex]\frac{4}{8}[/tex] ÷ [tex]\frac{2}{1}[/tex] = 1

PLEASE HELP I WILL GIVE BRAINLIEST

Answers

Answer:

V=72

Step-by-step explanation:

4x6=24

24x3=72

WxBxH=V

B=6

W=3

H=4

1ST ONE TO ANSWER THIS QUESTION GETS BRAINLIEST
Find the area of this polygon

Answers

Answer:

162 units^2

Explanation:

Separate the polygon into a rectangle and triangle, and then use the equations of area for those shapes to find the area.

Suppose a cubic polynomial, f, has two rational roots c and d and one irrational
root which is a conjugate pair a + vb, where a and b are rational numbers.
Does f have rational coefficients? Explain.

Answers

Answer:

what is force ? write its S.I unit

Pls help me
Question 2 Part C (5 points): Mrs. Hinson is replacing her rectangular driveway with pavers. The area of her driveway is 64m² - 9n² square units. Mrs. Hinson needs to find the dimensions of her driveway so she knows how many pavers to buy.


Help Mrs. Hinson by factoring the area completely. To receive full credit, you must show all work.


WORK:
ANSWER: The dimensions are...

Answers

Let's factor out

[tex]\\ \rm\Rrightarrow 64m^2-9n^2[/tex]

[tex]\\ \rm\Rrightarrow (8m)^2-(3n)^2[/tex]

Use the identity

(a+b)(a-b)=a^2-b^2

[tex]\\ \rm\Rrightarrow (8m-3n)(8m+3n)[/tex]

Done

Can someone help me with my homework need to divide fractions

Answers

Answer:

yeah sure

Step-by-step explanation:

How do you do these two questions?

Answers

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

write an equation that you can use to determine the number of hours for which it would cost $270 to hire brian then solve the equation

Answers

Answer:

How do you write an equation for problem solving?Here are some steps to follow:Understand the problem. Understand all the words used in stating the problem. Understand what you are asked to find. ... Translate the problem to an equation. Assign a variable (or variables) to represent the unknown. ... Carry out the plan and solve the problem.

Step-by-step explanation:

x^4y^2 - 6xyz + 9z^2=​

Answers

Answer:

(xy+3z) 2 (The two is small just saying)

Step-by-step explanation:

Step 1:

(((x2) • (y2)) +  6xyz) +  32z2

Step 2:

2.1    Factoring    x2y2 + 6xyz + 9z2

Try to factor this multi-variable trinomial using trial and error

Found a factorization  :  (xy + 3z)•(xy + 3z)

Step 3:

2.2    x2y2  +6xyz  +9z2  is a perfect square

It factors into  (xy+3z)•(xy+3z)

which is another way of writing  (xy+3z)2

PLEASE PLEASE HELP ASAP!!​

Answers

Answer: B

Step-by-step explanation:

Group the variables together: 3i + 2i -3i = -4i

Then for the fractions: 3/4 - 9/3 = -9/4

Answer:

B. (-9/4 -4i)

Step-by-step explanation:

Help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

B

Step-by-step explanation:

You have listed a property. The seller told you that he must net at least $14,000 after all the fees and expenses are paid. You estimate the seller's closing cost to be $3,500, and he must payoff an existing loan of $108,750. In addition, you are going to charge 7 percent commission on the sale. What is the LEAST amount that the property can sell for to return the seller's desired net?

Answers

Answer:

wow

Step-by-step explanation:

Answer with step-by-step explanation:

Step 1: $14,00 - $3,500 + $108,570 = $10,500 + $108,750 = $119,250

Step 2: 7% of $119,250 = $8,347.50

Step 3: $119,250 + $8,347.5 = $127.597.50

Hope this was helpful! (brainliest please)

Two consecutive odd integers have a sum of 92

Answers

you can just set 92=n+(n+2). this means 92=2n+2, and that 90=2n. finally, that means n=45 and n+2=47, so 45 and 47

Find the distance between the points (-7,-6) and (4,-6)?

Answers

Answer:

Step-by-step explanation:

the distance between the two points are 11.

the slope is m=0

Answer:

11 units

Step-by-step explanation:

[tex]Solution,\\\\Let,\\\\(x_1,y_1)=(-7,-6)\\\\(x_2,y_2)=(4,-6)\\\\Now,\\\\Using\:distance\:formula,\\\\\hookrightarrow d=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2} } \\\\\hookrightarrow d=\sqrt{(4-(-7))^{2} +(-6-(-6))^{2} } \\\\\hookrightarrow d=\sqrt{(11)^{2} +(0)^{2} }\\\\\hookrightarrow d=\sqrt{121} \\\\\hookrightarrow d=11\: units[/tex]

I need really good support in this!

Answers

Answer:

D. [tex]\displaystyle -8, -3, 1, 5[/tex]

Explanation:

The greatest negative quantity will ALWAYS be the least. That is all there is to it. ‍♂️

I am joyous to assist you at any time.

if you answer all i will give you brainliest answer! help asap, school starts in 10​

Answers

Answer:

1. 20% increase

2. 40% decrease

3. 50% increase

4. 75% decrease

5. 54.5% decrease

6. 150% increase

Step-by-step explanation:

Hope this helps!!

What is the range of the following relation? {(2, 3), (-4, 1), (5, -2), (0, 0)}
due in soon hours

Answers

Answer:

range is {-2, 0, 1, 3}

Step-by-step explanation:

Range is all the y's. Those are the second number in each ordered pair. I put them smallest to biggest, but it doesn't have to be. All the y-numbers in the set brackets should work for correct.

The greatest common factor of 2M to the fifth power and 32M to the fourth power

Answers

So 2 is the GCF for the coefficient. The variables are m4 and m5 . 4 is the greatest shared power, and so the GCF for that is m4

brainliest please if correct

Determine the absolute value. Type the numerical answer only. -l12l​

Answers

Answer:

-12

cause l12l is 12 then u add the negative sign.

Step-by-step explanation:

HELP PLEASE ITS DUE TODAY

Answers

Answer:

easy peasyyyyy.

1 17/24

Step-by-step explanation:

Answer:

1 17/24

Step-by-step explanation:

we have to make both denominators of the fractions the same. in order to do this you have to basically increase the fraction and make it 20/24. Do the same thing to 7/8 and get 21/24. Now we can add them together 20/24 + 21/24 = 41/24 = 1 17/24

mark me as brainliest

Jacoby says that they
need to save $293.75
per week.
CARD 10:
The Hudson family is saving for a
family vacation to Disney World.
They determine that the trip will
cost $3,200. Mr. and Mrs.
Hudson have already set aside
$1,500 for the trip. If they leave
in 16 weeks, then how much
will they need to save
each week?
Janelle says that they
need to save $106.25
per week

Answers

$240.72 because of it and it’s a little hard but ya know what how can I dm it is a little hard but y’all can

Which equation is true for x = 1.8?

Answers

Answer:

I found the full question online, the answer is 5.4 = 3.6 + x

what are the 3 linear equations and how they different ​

Answers

point-slope form, standard form, and slope-intercept form.

Name
8.2 Using Parallelograms in Proofs
1. Given: Parallelogram ABCD
DE I AB
BFI DC
с
Prove: DE 2 BF
A
E
B

Answers

Answer:

Step-by-step explanation:

1) Parallelogram ABCD, [tex]\overline{DE} \perp \overline{AB}, \overline{BF} \perp \overline{DC}[/tex] (given)

2) [tex]\angle DAE \cong \angle FCB[/tex] (opposite angles of a parallelogram are congruent)

3) [tex]\angle AED[/tex] and [tex]\angle BFC[/tex] are right angles (perpendicular lines form right angles)

4) [tex]\angle AED \cong \angle BFC[/tex] (all right angles are congruent)

5) [tex]\overline{AD} \cong \overline{BC}[/tex] (opposite sides of a parallelogram are congruent)

6) [tex]\triangle AED \cong \triangle CFB[/tex] (AAS)

7) [tex]\overline{DE} \cong \overline{BF}[/tex] (CPCTC)

Emma spent $60.20 on 5 dozen bagels and a gallon of iced tea. The price of the gallon of iced tea was $5.25. The following equation can be used to find d, the price of each dozen of bagels. 5d + 5.25 = 60.2 What was the price of each dozen of bagels?

Answers

23.23 - 5.25 = 17.98

d = 17.98 ÷ 2

d = 8.99

The answer is B. $8.99

A regular Pyramid is formed from 3 right triangles as shown below use the information given in the figure to find the length of RT.

Answers

Answer:

The length of BD is 65 units.

Step-by-step explanation:

ΔADC is a right angle triangle, we will use the Pythagorus Theorem to find the length CD.

Formula of the Pythagorus Theorem : 

⇒ a² + b² = c²

⇒ AD² + CD² = AC²

The value of AD is 54 and the value of AC is 90:

54² + CD² = 90²

Solve for CD:

54² + CD² = 90²

CD² = 90² - 54²

CD² = 5184

CD = √5184

CD = 72

ΔADC is also a right angle triangle, we will use the Pythagorus Theorem to find the length BD.

Formula of the Pythagorus Theorem : 

⇒ a² + b² = c²

⇒ BD² + CD² = BC²

The value of CD is 72 and the value of BC is 97:

BD² + 72² = 97²

Solve for BD:

BD² = 97² - 72²

BD² = 4225

BD = √4225

BD = 65

Grade 7 lesson 5 terminating and repeating decimals quiz

Answers

Answer:

I need more context.

Step-by-step explanation:

3( x + 2 ) = 2( 2 - x )

Answers

Answer:

x=2

Step-by-step explanation:

3x+6=4-2x

3x+2x=6+4

5x=10

x=10/5

x=2

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