A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass

Answers

Answer 1
Force= mass x acceleration

79=mass(3)

m=79/3

m=26.3 kg

Related Questions

If you are soaking wet and the water on your clothes evaporates, you will feel cold. Explain the cooling effect in the terms of kinetic theory.​

Answers

What is Evaporation?

Evaporation is a type of vaporization which usually occurs in liquid when molecules of that liquid transform into the gaseous phase.

 Evaporation causes cooling. This is because, when a molecule wants to evaporate, it requires heat to do so.

    This heat is derived from the surface from which the molecule is about to evaporate. The emission of heat from this surface results in the cooling of the surface left behind.

Kinetic Theory and Evaporation.

Liquid molecules are in constant random motion while possessing different velocities.

  Molecules which are near the surface possess higher velocities and kinetic energy escape from the surface.

  Since the average kinetic energy is a measure of temperature, it implies that the  temperature is lowered and hence a person who is soaking wet feels cold when evaporation  occurs.

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please help me !! i’ll give you brainliest if you get the answer right!

Answers

Answer: 25N to the right

Explanation: 35N - 10N = 25N

"PLS HELP ME WITH THIS QUESTION!" Two factors that affect climate patterns on Earth are the tilt of Earth on its axis and the topography of Earth. Describe how these two factors affect the climate patterns of Earth.

Answers

Answer:

The tilt of the Earth causes some places to be hit more by the sun's rays, while the topography affects wind travel.

Explanation:

Because of the way the Earth is tilted on its axis, some parts receive more heat due to being hit more directly by the sun's rays. This is the reason why the North pole is very cold since it doesn't get directly hit by the sun's rays. As for the topography, the way the wind travels is affected by mountains, and the temperature of winds are affected by the places the wind originated from. Also, high altitude places such as mountain summits are colder, while low altitude places are warmer. So, when an area is under direct sunlight, it causes warm climate, and when an area receives warm air because of its topography, it causes further heat.




Which of the following devices can be red to produce both transverse and
longitudinal waves?
1o) a string
(b) a ripple tank
(c) a helical spring (Slinky (d) a tuning fork

Answers

Answer:

Slinky is the correct answer.

Slinky is the correct answer

What is the change in velocity of a 1068 kg truck that experiences an impulse of 440 N ⋅ s? Include 2 decimal places in your answer.

Answers

Answer:

try 2.4136 as an answer/ good luck

What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp for water is 4186 J/kgC

Answers

The final temperature of water is equal to 50.9999°C

Given the following data:

Mass = [tex]2.38892 \times 10^{-2}\;kg[/tex]Quantity of heat = 5000 J Specific heat capacity of water = 4186 J/kg°C

To determine the final temperature of water:

Mathematically, quantity of heat is given by the formula;

[tex]Q=mc\theta[/tex]

Where:

Q represents the quantity of heat.m represents the mass of an object.c represents the specific heat capacity.∅ represents the change in temperature.

Substituting the given parameters into the formula, we have;

[tex]5000=2.38892 \times 10^{-2}\times 4186 \times \theta\\\\5000=100.0001912 \theta\\\\ \theta=\frac{5000}{100.0001912} \\\\ \theta=49.9999^{\circ}C[/tex]

For the final temperature:

[tex]\theta = T_2 - T_1\\\\T_2 = \theta+T_1\\\\T_2 = 49.9999 + 50[/tex]

Final temperature = 50.9999°C

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Halpinium metal (Jh(s)) can lose electrons via the photoelectric effect. The binding energy for Jh is 2.25x10-19 J. If a photon having an energy of 4.52x10-19 J strikes the surface of halpinium, calculate the de Broglie wavelength (in nm) of the electron that is ejected.

Answers

The relationship of the photoelectric effect and the de Broglie expression allows us to find the result for the wavelength of the ejected electrons is:

Wavelength of de Broglie is λ= 1.03 10⁻⁹m

The photoelectric effect was explained by Einstein assuming that the light rays behave like particles called photons, therefore the

                 [tex]E_{photon} = K + \Phi[/tex]  

where [tex]E_{photon}[/tex] is the energy of the photon given by the Planck relation, K is the kinetic energy of the ejected electrons and Ф the work function of the material.

The Planck relationship states that the energy of the photons is proportional to the frequency.

            [tex]E_{photon} = h f[/tex]

Where h is Planck's constant and f is the frequency of the photons.

They indicate The work function is Ф= 2.25 10⁻¹⁹ J, the energy of the photon [tex]E_{photon}[/tex] = 4.52 10⁻¹⁹ J, let's find the kinetic energy of the ejected electrons.

            [tex]K = E_{photon} - \Phi[/tex]  

Let's calculate.

           K = (4.52-2.25) 10⁻¹⁹

           K = 2.27 10⁻¹⁹ J

Kinetic energy is the energy of motion and is given by the relationship.

          [tex]K = \frac{p^2}{2m}[/tex]  

The wave-particle duality was established by de Broglie with the relation.

         [tex]p = \frac{h}{\lambda }[/tex]  

Let's replace.

         [tex]K = \frac{1}{2m} (\frac{h}{\lambda} )^2 \\\lambda^2 = \frac{h^2}{2m K}[/tex]

       

let's calculate.

        [tex]\lambda^2 = \frac{(6.63 \ 10^{-34})^2 }{2 \ 9.1 \ 10^{-31 } \ 2.27 \ 10^{-19}}[/tex]

        [tex]\lambda = \sqrt{1.06397 \ 10^{-18}}[/tex]

        λ  = 1.03 10⁻⁹m

In conclusion with the relationship of the photoelectric effect and the de Broglie expression we can find the result for the wavelength of the ejected electrons is:

Wavelength of de broglie is:  λ  = 1.03 10⁻⁹m

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What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________

Answers

The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

EQUATION OF MOTION:

The final velocity of a moving object can be calculated by using one of the equations of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)

According to this question,

t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?

v = 0 + 4.3(5)

v = 21.5m/s.

Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

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A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.

After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.

Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.

Answers

Assuming both billiard balls have the same mass, conservation of momentum says

[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]

where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so

[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]

After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so

[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

Then the second ball has final velocity vector

[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

so it moves with speed

[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]

at an angle of

[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]

or about 60.5° above the original line of motion.

What is the speed of an 800 kg automobile if it has a kinetic energy of 9.00 x 10^J?

Answers

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two words complete this sentence?

Answers

Answer:

When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.

Hope that helps.

When an object is balanced about a pivot, the total clockwise moment must be equal to the total anticlockwise moment.

What is balancing?

Clockwise involves turning to the right while going in the direction of a clock's hands. The moment is referred to as a clockwise moment if the force acting on a body rotates the body clockwise with regard to the axis of rotation.

On the other hand, the moment is referred to as an anti-clockwise moment if the force rotates the body in the opposite direction. The clock face rule can be used to determine this magnet's polarity.

The face of the loop will display the North Pole if the current is flowing counterclockwise. On the other hand, if the current is moving counterclockwise, the South Pole is visible on the loop's face.

Therefore, the total clockwise and total counterclockwise moments must match when an object is balanced about a pivot.

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what are two variables that are always in every experiment?

Answers

the independent variable and the dependent variable.

A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

Answers

The final speed of the combined masses is 0.21 m/s

Applying the law of conservation of momentum:

Total momentum before collision = Total momentum after collision.

⇒ Formula:

MU+mu = V(M+m).................. Equation 1

⇒ Where:

M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.

From the question,

⇒ Given:

M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)

⇒ Substitute these values into equation 1

0.24(0.6)+0.26(-0.20) = V(0.24+0.2)

⇒ Solve for V

0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/s

Hence the final speed of the combined masses is 0.21 m/s

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how to tell a girl you like her?

Answers

"Hey, I need to talk to you about something." If she reacts adversely, it means she probably doesn't feel the same way.

How fast would a(n) 75 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 420 m/s ?

Answers

Mass of the bullet (m1) = 8g = 0.008 KgVelocity of the bullet (v1) = 420 m/sWe know, kinetic energy = [tex] \frac{1}{2}m {v}^{2} [/tex]Therefore, the kinetic energy of the bullet

[tex] = \frac{1}{2} \times 0.008 \times 420J \\ = 1.68J[/tex]

So, the kinetic energy of the bullet is 1.68 J. It is said that the man's kinetic energy should be same as that of the bullet.Mass of the man (m2) = 75 KgLet the velocity of the man be v2.Therefore,

[tex]1.68J = \frac{1}{2} \times 75 \: kg \times v2 \\ = > v2 = \frac{1.68 \times 2}{75} m {s}^{ - 1} \\ = 0.0448 \: m \: {s}^{ - 1} [/tex]

Answer:

0.0448 m/s

Hope you could get an idea from here.

Doubt clarification - use comment section.

A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº

Answers

T1=40°C=313KT_2=-10°C=263K

Applying Charles law

[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]

[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]

[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]

A 25 N force acts on a box moving along a plane at a distance of 20 meters. What is the work it does with this force?

Help!!​

Answers

Answer:

500 J.

Explanation:

Work done = force * distance

= 25 * 20

= 500 Joules.

which is the correct relationship among pressure, flow, and resistance?

Answers

Answer:

Flow is proportional to change in pressure and inversely proportional to resistance.

Before Collision:
2,000 kg 4 m/s 4,000kg 0 m/s

After collision: 2,000 kg + 4,000kg Vt = ?

I will give Brainliest to the first person. Please show work

Answers

Answer:

  4/3 m/s

Explanation:

Assuming momentum is conserved, the sum of products of mass and speed before the collision is the same as after:

  (2000 kg)(4 m/s) +(4000 kg)(0 m/s) = (2000 +4000 kg)(Vt)

  Vt = (8000 kg·m/s)/(6000 kg) = 4/3 m/s

The speed of the combined objects after the collision is 4/3 m/s.

a water balloon is thrown a target at 18 m/s. if the water balloon has a mass of 0.4 kg, what is the momentum?

Answers

The momentum of the water balloon at the given speed is 7.2 kgm/s.

The given parameters:

Speed of the water balloon, v = 18 m/sMass of the balloon, m = 0.4 kg

The momentum of the water balloon is calculated as follows;

P = mv

Substitute the given values of mass and velocity as follows;

P = 0.4 x 18

P = 7.2 kg m/s.

Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.

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Please help me! I don't understand how to do this!

Part 1: A 6 kg shopping cart goes from a velocity of 0.9 m/s to a velocity of 6 m/s over the course of 2.0 seconds. What is the cart's acceleration?​

Part 2: What is the net force acting on the shopping cart during that time? You will need your answer from the previous part.

Answers

From the information in the question, the acceleration of the cart is 2.55 ms-2.

We can find the acceleration using the following information from the question;

u = 0.9 m/s

v = 6 m/s

a =  2.0 seconds

But;

a = v - u/t

v = final velocity

u = initial velocity

t = time

a = 6 - 0.9/2 = 2.55 ms-2

Force= ma

m = mass

a = acceleration

F = 6 kg × 2.55 ms-2

F = 15.3 N

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I couldn't find one .

Answers

Start from the top and go 7 down then go to the right 9 times and there you should fine the letter "one"

Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?​

Answers

Answer:

Density of the mixture = 855.56kgm-3

Explanation:

Density = Mass / Volume

Volume of Liquid X = 0.5m³

Density of Liquid X = 900kgm-3

Mass of Liquid X = Density × Volume

= 900kgm-3 × 0.5m³ = 450kg

Volume of Liquid Y = 0.4m³

Density of Liquid Y = 800kgm-3

Mass of Liquid Y = Density × Volume

= 800kgm-3 × 0.4m³= 320kg

As X and Y are mixed, we add their masses and volumes together:

Mass = 770kg

Volume = 0.9m³

Now we can find the density of the mixture:

Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)

Determine the kinetic energy of a 1500 kg roller coaster that is moving with a
speed of 35 m/s.
A) 200,000 J
B) 25,000
C) O 918,750
D) 920,000J

Answers

Answer:

918,750 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 1500 kg

v = 35 m/s

We have

[tex]k = \frac{1}{2} \times 1500 \times {35}^{2} \\ = 750 \times 1225 \\ = 918750[/tex]

We have the final answer as

918,750 J

Hope this helps you

A current of 2.0 A flows through a flashlight bulb when it is connected
across the terminals of a 5 V battery. What is the energy dissipated by this
bulb during 1 hour of continuous working?*

Answers

V=5VI=2At=1h

Using Joules law

[tex]\\ \sf\Rrightarrow H=VIt[/tex]

[tex]\\ \sf\Rrightarrow H=5(2)(1)[/tex]

[tex]\\ \sf\Rrightarrow H=10Kwh[/tex]

What are the rest of the blanks?

Answers

Not quite, just wanted the points lol

What type of bond is found in pure gold?
A) Metallic
B) Ionic
C)Covalent
D)Diatomic

Answers

Pure gold is a metallic bond as well as silver, iron and platinum

The type of bond found in pure gold is metallic bonding, indicated by metallic bonds. Therefore option A is correct.

Metallic bonding occurs between metal atoms, such as gold, and is characterized by the sharing of electrons among a sea of delocalized electrons.

In metallic bonds, the valence electrons of metal atoms are not strongly bound to any particular atom but are free to move throughout the metal lattice.

This sharing of electrons gives rise to properties such as high electrical and thermal conductivity, malleability, and ductility, which are characteristic of metals like gold.

Unlike ionic or covalent bonds, metallic bonds do not involve the transfer or sharing of electrons between different elements.

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A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of road per hour. The function f(x) = 300x 1,000 represents this situation. What is f(3), and what does it represent?.

Answers

f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.

Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.

The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.

From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."

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The smallest possible particle of complete matter is the atom. True or false?

true

false

Answers

Answer:

TRUE !!

Explanation:

An atom is the smallest particle of an element

Can someone please give me the (Answers) to this? ... please ...

Answers

Answer:

1. 60 kg m/s

2. 2.4 kg

3. none they both have same momentum

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