a neutral atom of the element given by the symbol ca will to become an ion with a complete outer shell. True or False?

No, The formula CuO2 is for copper super peroxide

The formula of copper peroxide is Cu2H2O2

Losing s electron: None of the above, Losing 2 s electrons: Red, Losing 2 s and 1 p electron: Orange, Adding 1 p electron: Green and Adding electrons to 2 p orbitals: Blue.

Part 1: The correct answer would be (f) None of the above since not all elements form monatomic ions by losing an s electron. Some elements may require losing electrons from other orbitals or may not form monatomic ions at all.

Part 2: The correct answer would be (d) Red. Elements in Group 2A of the periodic table can lose two s electrons to form doubly positive ions, and the element highlighted in red belongs to this group.

Part 3: The correct answer would be (c) Orange. Elements in Group 3A of the periodic table can lose two s electrons and one p electron to form triply positive ions, and the element highlighted in orange belongs to this group.

Part 4: The correct answer would be (b) Green. Elements in Group 5A of the periodic table can add one electron to a p orbital to form singly negative ions, and the element highlighted in green belongs to this group.

Part 5: The correct answer would be (a) Blue. Elements in Group 6A of the periodic table can add electrons to two p orbitals to form doubly negative ions, and the element highlighted in blue belongs to this group.

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The complete question is :

each part below, determine which highlighted element forms a monatomic ion by losing electons from or addling electrons to the below-mentione orbitals  

Part(1) by losing an s electron: Choose one:

(a)Blue

(b) Green

(c) Orange

(d) Red

(e)Brown/Black

(f) None of the above

Part 2 (1 point) by losing two s electrons: Choose one:

(a)Blue

(b) Green

(c) Orange

(d) Red

(e)Brown/Black

(f) None of the above

Part 3 (1 point) by losing two s electrons and one p electron Choose one: (a)Blue

(b) Green

(c) Orange

(d) Red

(e)Brown/Black

(f) None of the above

Part 4 (1 point) by adding one electron to a p orbital Choose one:

(a)Blue

(b) Green

(c) Orange

(d) Red

(e)Brown/Black

(f) None of the above

Part 5 (1 point) by adding electrons to two p orbitals Choose one:

(a)Blue

(b) Green

(c) Orange

(d) Red

(e)Brown/Black

(f) None of the above

The choice of fabric for a lab coat will depend on the specific hazards present in the laboratory and the level of protection required for the lab workers. It is important to consult with safety guidelines and regulations to ensure that the lab coat selected meets the necessary safety standards. Select a fabric that will provide adequate protection.

Of the options listed, a 100% cotton lab coat would not be ideal for all laboratory settings as it can be easily penetrated by chemicals and biological agents. A 60% cotton, 40% polyester blend may offer some added protection due to the presence of polyester, but it still may not be sufficient for all lab environments.

A 100% polyester lab coat would offer better protection against chemical and biological exposure than the cotton options, but it may not be as comfortable to wear as cotton. A 60% polyester, 40% cotton blend may provide a balance of protection and comfort, but the level of protection provided may still depend on the specific type of fabric and construction of the lab coat.

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The rate becomes:  0.0225 m/sec which symbolically in terms of k, [A], and [B]. Consider the reaction A + 2B → C whose rate at 25° C.

The rate constant is the quantity that expresses the connection between the molar concentration of the reactants and the rate of the chemical reaction. The rate constant rises as the reactant concentrations fall. Even if the reactant concentrations fluctuate, the rate constant remains constant. Depending on the kind of reaction and which reactants' concentrations vary, the rate constant will change. The proportionality constant (k) that links the pace of the reaction to reactant concentrations is known as the specific rate constant.

now calculate the rate constant using first equation

rate = k[A]²[B]

take the first row from table it not necessary you can take any

6.0×10⁻⁴ = K[0.1]²[0.05]

K = (6.0 × 10⁻⁴) / (5 × 10⁻⁴)

K = 1.2 mol⁻² lit² sec⁻¹

now use the same equation

substitute the given concentration and use the same K value find the rate constant

rate = k[A]²[B]

rate = 1.2 [0.5]²[0.075]

rate = 0.0225 m/sec

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"antifreeze proteins" or "ice-binding proteins", lower the freezing temperature of water, similarly to the antifreeze used in automobiles, and allow certain fish to remain active in very cold water.

Antifreeze proteins function by binding to ice crystals and preventing them from growing, which in turn prevents the formation of ice within the tissues of the organism. This allows the organism to remain active in very cold water, even when the water temperature is below the freezing point of pure water.

Acetylcholine is not a compound that can lower the freezing temperature of water.It is important to note that antifreeze proteins are a specialized adaptation that has evolved in certain organisms to help them survive in extremely cold environments, and they should not be confused with the antifreeze used in automobiles, which is a mixture of chemicals designed to lower the freezing point of the liquid in a car's cooling system.

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The rate law is the relationship between the rate of a reaction and the rate constant, as well as the concentration of reactants raised to various powers.

In chemical kinetics, the rate law (also known as the rate equation) is a mathematical equation that describes the rate of a chemical reaction as a function of the concentrations of the reactants. The rate law provides a quantitative way of expressing how the rate of a reaction depends on the concentration of each reactant, as well as any other factors that may affect the reaction rate, such as temperature or the presence of a catalyst. The general form of a rate law is:

rate = k[A]^m[B]^n

where "rate" is the rate of the reaction, [A] and [B] are the concentrations of the reactants A and B, respectively, and k is the rate constant. The exponents m and n are the reaction orders with respect to A and B, respectively, and they determine how the rate of the reaction changes with changes in the concentration of each reactant.

0.072 M/min is the correct answer.

r2 = 0.2/5

r1/r2= [A1/A2]m

K=1/25

r= K×1/8= 0.072 M/min

The between relationship the rate of a reaction and the rate constant, as well as the concentration of the reactants raised to various powers for the overall process, is expressed by the rate law.

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The Kp value, at 500 K for the reaction 2NO(g) + Cl2(g) ↔ 2NOCl(g) is Kp=0.01.

2NO(g) + Cl2(g) ↔ 2NOCl(g)

Coefficient of the reaction equation: 2 - 1 – 2

Several moles of gas at equilibrium:

The number of moles of gas = 5 moles

PNO = (mol NO/total moles) x Ptotal

PNO = (2/5) x 500

PNO = 200 K

PCl = (mol Cl/mol total) x Ptotal

PCl = (1/5) x 500

PCl = 100 K

PNOCl = (mol NOCl/mol total) x Ptotal

PNOCl = (2/5) x 500

PNOCl = 200 K

Calculating the value of Kp:

Kp = (right side partial pressure)[tex]^{coefficient}[/tex]/(left side partial pressure)[tex]^{coefficient}[/tex]

Kp = [PNOCl]²/[PNO]²[Cl]

Kp = [200]²/[200]²[100]

Kp = 4 x 10⁴/4 x 10⁶

Kp = 0.01

Answer is Kp = 0.01

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The correct response is (a) Higher boiling point, (b) Higher freezing point, and (c) Lower vapor pressure, all of which are 0.35 M CaCl2.

Boiling point is the temperature where a pure substance transforms from the a liquid to a gas. Now, the pressure being applied to the liquid and its vapour are equal. Boiling at one pressure atmosphere is the standard boiling point. Boiling point and saturation temperature are synonyms.  The standard boiling point was established by the International Union of Pure and Applied Chemistry (IUPAC) in 1982 as the temperature at which water boils at one bar of pressure.

A temperature at which a liquid's vapor pressure equals the surrounding pressure is known as the boiling point. The boiling point falls off as altitude rises. Evaporation is the transformation of a liquid into its vapor when it occurs below the liquid's boiling point. As a result of the water molecules' vibrations caused by heat, some of the water's molecules escape into the atmosphere and turn into water vapor, or even the gaseous state for water. We name it evaporation for this reason. Water turns from a liquid to a gas known called vapor.

This is because urea does not dissociate, but CaCl2 breaks down into three ions in solution—one Ca2+ and two Cl-. CaCl2's higher boiling point, lower vapor pressure, and lower freezing point are all caused by the presence of more particles in the solution (since the solute ions disrupt the crystal lattice formation of the solvent molecules).

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Water containing carbonic acid can react with minerals like calcite (CaCO₃) and dolomite (CaMg(CO₃)₂) to dissolve them, resulting in the formation of bicarbonate (HCO₃⁻) and calcium or magnesium ions in solution.

When carbonic acid is present in water, it can react with minerals such as calcite (CaCO₃) and dolomite (CaMg(CO₃)₂) to dissolve them, forming bicarbonate (HCO₃⁻) and calcium or magnesium ions in solution. This process is known as chemical weathering and can result in the formation of underground caves and sinkholes.

On the other hand, when the concentration of carbonic acid decreases, the reverse reaction can occur, and minerals such as calcium carbonate can precipitate out of solution, forming deposits such as stalactites and stalagmites in caves.

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The speed of light in kilometers per second is 300 kps.

According to the information on light speed from the Sun to the Earth:

Known:

Distance light travels in 10 seconds from Sun to Earth = 3,000,000 km

Average distance between Earth and Sun = 150,000,000 km

Formula:

Speed = Distance / Time

Unknown:

Speed of light in kps

Substitutions:

Distance = 3,000,000 km

Time = 10 seconds

Speed = Distance / Time

Speed = 3,000,000 km / 10 seconds

Speed = 300,000 km/s

Answer:

The speed of light in kps is 300 kps (kilometers per second).

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The rate constant at 445 K is 0.0122 m/s.

The rate constant at 445 K for the reaction with an activation energy of 37.8 kJ/mol can be calculated using the Arrhenius equation:

k = A*e^{(-Ea/RT)}

Where k is the rate constant at 445 K, A is the pre-exponential factor, Ea is the activation energy, R is the ideal gas constant (8.314 J/molK) and T is the temperature in Kelvin. Substituting the values given we get:


k = 0.178 * e^{(-37.8*10^3/(8.314*445)}


Therefore, the rate constant at 445 K is 0.0122 m/s.

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The concentration of the solution in molarity can be calculated as follows:

Molarity (M) = moles of solute/liters of solution

In this case, the number of moles of glucose is 5 moles and the volume of the solution is 10 liters. So,

M = 5 moles / 10 liters = 0.5 M

Therefore, the concentration of the glucose solution is 0.5 M.

Considering the Dalton's partial pressure, the pressure of O₂ in the mixture is 319 mmHg.

Dalton's law states that the total pressure of a gas mixture is equal to the sum of the partial pressures of the gas:

[tex]P_{T}[/tex]= P₁ + P₂ + ... + Pₙ

where:

This relationship is due to the assumption that there are no attractive forces between the gases.

In this case, you know:

If the total pressure of the mixture is:

Total pressure= Pressure of O₂ + Pressure of N₂ + Pressure of H₂

the pressure of O₂ can be calculated as:

902 mmHg= Pressure of O₂ + 355 mmHg + 228 mmHg

Solving:

902 mmHg= Pressure of O₂ + 355 mmHg + 228 mmHg

902 mmHg= Pressure of O₂ + 583 mmHg

902 mmHg - 583 mmHg= Pressure of O₂

319 mmHg= Pressure of O₂

Finally, the pressure of O₂ is 319 mmHg.

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The three solutions with different volumes, all being 3M in glucose, fructose, and ethanol must contain the same total number of moles of solute.

This is because the concentration of each solution is the same, and the number of moles of a substance is directly proportional to its concentration and volume. Therefore, if the concentration is the same for each solution, the total number of moles of solute must also be the same. However, the solutions may not necessarily have the same density, mass of solute, or boiling points. The density of a solution is affected by factors such as temperature and pressure, and the mass of solute depends on the molar mass of each solute. The boiling point of a solution is influenced by the concentration and identity of the solutes, as well as external factors such as pressure.

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Nitrogen is a chemical element with the symbol N and atomic number 7. It is a nonmetal and makes up about 78% of the Earth's atmosphere. Nitrogen is essential for all forms of life on Earth as it is a critical component of DNA, RNA, and proteins.

Uses:

Nitrogen has many uses in industry, agriculture, and medicine. In the industrial sector, nitrogen is used in the production of ammonia, which is used to make fertilizers, explosives, and other chemicals. Nitrogen gas is also used to create a controlled atmosphere in food storage and packaging, to prevent spoilage and preserve freshness. In the medical field, nitrogen is used to preserve blood, tissues, and other biological samples.

Process:

Nitrogen gas is produced through a process called fractional distillation, which separates the gases in the air based on their boiling points. Nitrogen gas is obtained by cooling air until it becomes a liquid, and then slowly warming it up again. Nitrogen gas boils at a lower temperature than oxygen gas, so it is collected as a gas as the temperature rises.

Nitrogen Cycle:

The nitrogen cycle is the process by which nitrogen is converted between its various chemical forms in the environment. The nitrogen cycle is important because it allows nitrogen to be used by living organisms, and it helps to regulate the levels of nitrogen in the atmosphere and in the soil.

The nitrogen cycle consists of four main stages: nitrogen fixation, nitrification, denitrification, and ammonification. Nitrogen fixation is the process by which nitrogen gas from the atmosphere is converted into a form that can be used by living organisms, such as ammonia or nitrate. This process is carried out by certain types of bacteria that live in the soil or in the roots of plants.

Nitrification is the process by which ammonia is converted into nitrate by other types of bacteria. This nitrate can then be absorbed by plants and used to make proteins and other essential molecules.

Denitrification is the process by which nitrate is converted back into nitrogen gas, which is released back into the atmosphere. This process is carried out by certain types of bacteria that live in oxygen-poor environments, such as wetlands or soils that are waterlogged.

Ammonification is the process by which organic nitrogen compounds, such as proteins or amino acids, are broken down into ammonia by bacteria and fungi. This ammonia can then be used by other organisms in the nitrogen cycle.

Testing:

The most common test for the presence of nitrogen is the Kjeldahl method, which is used to determine the amount of nitrogen in organic compounds. The Kjeldahl method involves heating a sample of the organic compound with sulfuric acid, which converts the nitrogen into ammonia. The ammonia is then distilled off and collected in a solution of boric acid, which forms a compound called ammonium borate. The amount of nitrogen in the original sample can then be determined by measuring the amount of ammonium borate that is produced.

The statement X +1 is formed is not true.

Ionic substances are formed through the process of ionization, which occurs when atoms or molecules gain or lose electrons. This results in the formation of ions, which are charged particles. When ions of opposite charge come together and form a crystal lattice structure, an ionic substance is formed.

For example, when a metal atom reacts with a non-metal atom, the metal atom can lose electrons to the non-metal atom, forming positively charged ions (called cations) and negatively charged ions (called anions). These ions are held together in a repeating pattern by ionic bonds, which are strong electrostatic forces. The resulting substance is an ionic compound.

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The yield is 108.2% in percentage. As this result is higher than 100%, it is possible that the experimental process or the measurements had errors.

In mild conditions, magnesium oxide works well as a catalyst for the cycloaddition of carbon dioxide to epoxides; when carbon dioxide reacts with (R)-styrene oxide in the presence of magnesium oxide, (R)-phenyl carbonate is produced in 97% of the time with stereochemistry retained.

We must first estimate the theoretical yield of the compound generated in order to calculate the percent yield.

molar mass of MgO = 24.31 g/mol (for Mg) + 15.99 g/mol (for O) = 40.30 g/mol

moles of MgO = 8.41 g / 40.30 g/mol = 0.2087 mol MgO

moles of compound formed = 0.2087 mol MgO = 0.2087 mol compound

mass of compound = (28.83% Mg / 100%) x 14.45 g = 4.16 g Mg

(14.24% C / 100%) x 14.45 g = 2.06 g C

(56.93% O / 100%) x 14.45 g = 8.23 g O

= 14.45 g of the compound formed

percent yield = (actual yield / theoretical yield) x 100%

actual yield = 14.45 g

theoretical yield = 0.2087 mol x (24.31 g/mol + 15.99 g/mol + 3(16.00 g/mol)) = 13.36 g

percent yield = (14.45 g / 13.36 g) x 100% = 108.2%.

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Approximately 1.24 × 10^-9 miles of nylon could be formed in this experiment, assuming 10,000 dimers are linked together.

One angstrom is equal to 1 × 10^-10 meters, and there are 3.281 feet in one meter, so:

20 angstroms × (1 × 10^-10 m/angstrom) × (3.281 ft/m) = 6.5628 × 10^-10 ft

Let's assume that in this experiment, 10,000 dimers are formed.

length = 6.5628 × 10^-10 ft/dimer × 10,000 dimers = 6.5628 × 10^-6 ft

This is the total length of nylon that could be formed in this experiment, assuming 10,000 dimers are linked together.

To convert this to miles, we can divide by the number of feet in a mile:

6.5628 × 10^-6 ft / 5,280 ft/mi = 1.240 × 10^-9 miles

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MnSO4•H2O is the correct chemical formula for the final product after heating MnSO4•H2O.

This compound is known as Manganese (II) sulfate monohydrate. When heated, the water of hydration is lost, leaving MnSO4 as the final product.Manganese (II) sulfate monohydrate is an inorganic compound composed of manganese(II) cations, sulfate anions, and one water molecule of hydration. It is a white crystalline solid with the formula MnSO4•H2O. It is used as an oxidizing agent, a fertilizer, and a micronutrient in agriculture. It may also be used to test for the presence of phosphate and carbonate ions.Manganese (II) sulfate monohydrate is a white crystalline solid that is used as a fertilizer and in the production of a variety of chemical products. It is made up of one manganese atom, four oxygen atoms, one sulfur atom, and four water molecules.

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According to the Bohr effect, an increase in the supply of oxygen (O2) to muscles will result from a drop in carbon dioxide (CO2) levels.

The reason for this is that a decrease in CO2 weakens the T state of haemoglobin, which is the type of haemoglobin that binds oxygen. The P50 level (the partial pressure of oxygen at which haemoglobin is half-saturated with oxygen) decreases and the release of O2 from haemoglobin increases due to the T state's poorer stability. Enhanced O2 supply to muscles is the effect of this increased O2 release. The Bohr effect is a phenomena wherein when the pH of the immediate environment falls, hemoglobin's affinity for oxygen also diminishes.

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Niels Bohr's 1913 model depicts that the atom has a small, positively charged nucleus which surrounded by electrons that travel in circular orbits around the nucleus.

The Bohr model, is a representation of the structure of atoms, especially that of hydrogen, The Bohr Model is a universal model in which the negatively charged electrons orbit a small, positively charged nucleus like the planets.

In the Bohr model, electrons are pictured as traveling in circles at dissimilar shells, depending on which element you have. The Bohr model is a proportional primitive model of the hydrogen atom, in contrast to the valence shell mode

So we can conclude that the Bohr Model is a structural model of an atom that shows electrons and the nucleus of an atom.

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covalent molecular crystals have very low melting points, while covalent network crystals have very high melting points because the forces   in molecular crystals are weaker than the network crystals.

The intermolecular forces that hold the covalent molecules together in the molecular crystals are weaker than that of the intermolecular force that hold the molecules or the atoms together in the network crystals.

The Covalent network are contain the  atoms that are covalently bonded together in the three dimensional network or the `layers of two dimensional networks. Because of the  strength of the covalent bonds, the covalent network solids have the high melting points.

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a) Cl is the atom Atoms are expected to have the most negative (exothermic) electron affinities. 

Electron affinity is the amount of energy produced or released when an atom attracts an electron. Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

Electron affinity can be used as a measure of the ease with which an atom captures electrons. The greater the energy released (electron affinity) indicates that the atom tends to attract electrons to become a negative ion.

The energy of an atom is defined when the atom loses or gains energy through a chemical reaction that causes the loss or gain of electrons. Chemical reactions that release energy are called exothermic reactions and chemical reactions that absorb energy are called endothermic reactions.

The energy of an exothermic reaction is negative, so the energy is given a negative sign; while the energy of the endothermic reaction is positive and the energy is given a positive sign. An example that demonstrates both processes is when someone drops a book. When he lifts the book, he gives the book potential energy (absorbed energy).

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The Transition state  A and D will release energy.

When an electron moves from a higher energy level to a lower energy level, it releases energy. This can be seen in the diagram as the arrows pointing downwards. Therefore, transitions A and D will release energy, while transitions B and C will not.

It is important to remember that energy is always conserved, so when an electron moves from one energy level to another, the energy is not lost, but rather transferred in the form of light or heat.

In summary, the transitions that will release energy are A and D, as they involve an electron moving from a higher energy level to a lower energy level.

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The sample contain the greatest number of molecules is 1.00 grams of carbon dioxide. Therefore, option B is correct.

The term molecule is defined as the smallest component of a material that possesses both its chemical and physical characteristics. One or more atoms make up molecules.

There are three different kinds of molecules: atom-sized molecules, element-sized molecules, and compound-sized molecules.

1.00 grams of carbon monoxide,1.00 grams of carbon dioxide and 1.00 grams of carbonate, atoms present in these molecules are different so 1.00 grams of carbon dioxide  contain the greatest number of molecules.

Thus, option B is correct.

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The rise in temperature during the dissolution of an ionic solid in water is a result of the release of energy, indicating that the process is exothermic.

The enthalpy of solution is the difference between the energy required to separate the ionic solid into its constituent ions, known as the lattice energy, and the energy released during the hydration of these ions by water molecules. Since the dissolution of the solid is exothermic, the enthalpy of solution is negative. Therefore, we can state that the correct answer is "O Enthalpy of solution is negative" . Additionally, since the temperature rises dramatically during the dissolution of the ionic solid, it indicates that the magnitude of the lattice energy is greater than the enthalpy of hydration of the ions in water.

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To create a quadrilateral that is similar but not congruent to another quadrilateral, you can apply a non-uniform dilation transformation.

A non-uniform dilation transformation changes the size of a shape by a different scale factor in different directions. This means that the corresponding sides of the similar figures will have different lengths, and the corresponding angles will have the same measure.

To apply a non-uniform dilation transformation to quadrilateral $QRST$, you would need to specify different scale factors for each direction. For example, you could specify a scale factor of 2 in the x-direction and a scale factor of 3 in the y-direction. The resulting transformed quadrilateral, $Q'R'S'T'$, would have sides that are twice as long as the corresponding sides in the x-direction and three times as long as the corresponding sides in the y-direction. The angles of $Q'R'S'T'$ would be the same as the angles of $QRST$.

It is important to note that a non-uniform dilation transformation will not preserve the ratios of side lengths between similar figures, so $Q'R'S'T'$ will not be congruent to $QRST$.

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Small changes in temperature can have a large effect on reaction rates because the exponential factor in the Arrhenius equation is very sensitive to changes in temperature.

The Arrhenius equation is a mathematical formula that describes the relationship between temperature and the rate of a chemical reaction. It is often written as: k = A × [tex]e^{-Ea/RT}[/tex]

The activation energy (Ea) is the minimum energy required for a reaction to occur. In other words, reactant molecules need to have at least this amount of energy in order to break the bonds that hold them together and form the new products. The activation energy can be thought of as the energy barrier that reactants must overcome to form products.

The frequency factor (A) is a constant that reflects the frequency of successful collisions between reactant molecules. A higher frequency factor means that more successful collisions are occurring, which generally leads to a faster reaction rate.

The exponential factor, [tex]e^{-Ea/RT}[/tex], is a mathematical term that describes how the rate constant changes with temperature. This term incorporates the activation energy and temperature in a way that reflects the probability that a given collision between reactant molecules will lead to a successful reaction. At higher temperatures, the exponential factor is larger, which means that the rate constant (k) is higher and the reaction proceeds more quickly.

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Sure! Here's the complete resonance structure of the carbocation intermediate formed during the chlorination of ethylbenzene in the para position Cl | H--C--C |+ C | C | H.

   Cl

     |

H--C--C

    |+

   C

    |

   C

    |  

   H

In this structure, the positive charge is located on the carbon atom adjacent to the chlorine atom, indicating that this carbon is electron deficient and has a high degree of reactivity. This carbocation intermediate can then go on to react with a chlorine ion to form the final product, para-chloro ethylbenzene.

It's worth noting that the other two resonance structures of this carbocation intermediate involve moving the positive charge to the other two carbon atoms in the ring, but they are less stable due to increased electron density at the adjacent carbon atoms.

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If 12.2 moles of (NH₄)₂SO₄ were produced, then 6.1 moles of NH₃ were used.

Assuming the balanced chemical equation is:

2 NH₃ + H₂SO₄ → (NH₄)₂SO₄

This equation shows that two moles of ammonia are required for every one mole of ammonium sulfate produced. Therefore, to find the number of moles of ammonia used, we can use the following calculation:

moles of NH₃= moles of (NH₄)₂SO₄ / 2

moles of NH₃ = 12.2 moles / 2

moles of NH₃ = 6.1 moles

Therefore, if the balanced chemical equation is 2 NH₃ + H₂SO₄ → (NH₄)₂SO₄ and 12.2 moles of (NH₄)₂SO₄ were produced, then 6.1 moles of NH₃ were used.

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