A simple harmonic transverse wave is propagating along a string towards the left direction as shown in the figure. figure shows a plot of displacement as function of position at time t=0.The string tension is 3.6 Newton and it’s linear density is 25GM/M. Calculate
I) the amplitude
Ii) the wavelength
Iii) wave speed
Iv) the period
V) The maximum particle speed in the String

Answer: Electron

Explanation:A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.

Hope this helps!!Brainlist?

Answer:3.4 miles west

Explanation:

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

Answer:

D. -1.7m/s2

Explanation:

the car starts at 100m/s so this is the initial velocity. It ends at 50m/s so this is the final velocity. it took 30 seconds so the time is 30.

[tex]v_{f}=v_{i}+at[/tex]

[tex]a=\frac{\left(v_{f}-v_{i}\right)}{t}[/tex]

[tex]a=\ \frac{\left(50-100\right)}{30}[/tex]

[tex]a=-1.66666666667[/tex][tex]m/s^{2}[/tex]

Therefore, the answer is D

Answer:

an icicle

Explanation:

and icicle has less air resistance compared to that of a snow flake

Answer:

marks an important milestone. It's the shortest day of the year and the longest night of the year, and signals a powerful transition point between seasons that is impossible to ignore. ... In Pagan times the winter solstice was referred to as Yule and was a celebration of the Goddess (Moon) energy

Explanation:

Answer:

The most correct option is the last option

Explanation:

During radioisotope/nuclear imaging in diagnosis, the radioisotope must emit gamma rays from within the body. However, in the case of radionuclide therapy, most radionuclides emit beta particles while some others also emit gamma rays.

Answer:

D

Explanation:

Answer:

Plane mirrors work because the light rays create a virtual image behind the mirror. Light rays from the object strike the mirror and reflect according to the law of reflection. ... Therefore, our eye and brain track the light rays backward to a position from which they appear to have come.

Answer:

Normal force

Explanation:

Normal force is the force that surfaces employ so that solid objects are disallowed from passing through each other.

Answer:

The cell cycle has four stages: during the first three, the cell is in interphase, and in the last one, the cell is dividing itself. Also, there is a resting stage when the cell is not preparing itself for the division.

G0: the cell is not in the cell cycle. It is resting and not preparing itself for the division.

G1: the cell grows and synthesizes proteins and other elements that the cell will need for the next stage.

S: In this phase, which is called Synthesis, the cell synthesizes the DNA.

G2: the cell continues to grow. It synthesizes more proteins, RNA, and other elements that it will need for mitosis.

Mitosis: the division of the cell takes place, and as a result, there are two daughter cells. This phase has four stages, prophase, metaphase, anaphase, and telophase.

Explanation:

The cell cycle has four stages. Each of them has a role in the division of the cell. The first one is Gap 1 or G1, then the Synthesis or S phase follows, after S, Gap 2 takes place, and finally, Mitosis.

We can divide the cell cycle into two big groups: interphase, which includes G1, S, and G2, and the changes that the cell suffer can not be appreciated. The other group is the One where the cell division happens, and it includes Mitosis.

G0 is not part of the cell cycle. It is a state where the cell doe not prepares itself for the division. It is resting.

We know, Work done by all the forces is equal to change in potential energy :

[tex]W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}[/tex]

Here,

[tex]h_i=0\ m\\\\v_i = 0\ m/s[/tex]

Putting all given values, we get :

[tex]W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J[/tex]

Hence, this is the required solution.

Answer:

huiiiiuuu beautiful...

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is [tex]l = 1.0 \ km = 1000 \ m[/tex]

       The speed of  A is  [tex]v__{A}} = 20 \ m/s[/tex]

       The uniform acceleration of  B is  [tex]a__{B}} = 0.333 \ m/s^2[/tex]

  Generally the time taken by go-cart  A is mathematically represented as

              [tex]t__{A}} = \frac{l}{v__{A}}}[/tex]

=>          [tex]t__{A}} = \frac{1000}{20}[/tex]

=>           [tex]t__{A}} = 50 \ s[/tex]

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             [tex]l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2[/tex]

given that go-cart B starts from rest  u =  0 m/s

So

            [tex]1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2[/tex]

=>         [tex]1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2[/tex]            

=>         [tex]t__{B}} = 77.5 \ seconds[/tex]  

Comparing  [tex]t__{A}} \ and \ t__{B}}[/tex]  we see that [tex]t__{A}}[/tex] is smaller so go-cart A is  faster

Answer:

true

Explanation:

i think it's true because I took a quiz on this

Answer:

 temperature is -10

Explanation:

Answer:

True

Explanation:

The main differences between a physical property and a chemical property are mentioned below:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.

While A chemical property describes the ability of a substance to undergo a specific chemical change.

Given :

Mass of water, m = 2 grams.

The temperature of water drops from 31 °C to 29 °C .

The specific heat of water is 4.184 J/(g • °C).

To Find :

Amount of heat lost in this process.

Solution :

We know, heat lost is given by :

[tex]Heat\ lost,H = ms( T_f - T_i)\\\\H = 2\times 4.184 \times ( 31 - 29 )\ J\\\\H = 16.736\ J[/tex]

Therefore, amount of heat lost in this process is 16.736 J.

Answer:

The velocity of the astronaut is approximately 0.0008571 m/s

Explanation:

The mass of the the wrench, m₁ = 4 grams = 0.004 kg

The velocity of the wrench, v₁ = -15 m/s

The mass of the astronaut, m₂ = 70 kg

The velocity of the astronaut = v₂

Whereby the astronaut and the wrench were initially at rest, we have;

The total initial momentum = 0 kg·m/s

The total final momentum = m₁ × v₁ + m₂ × v₂ = 0.004 kg × (-15 m/s) + 70 kg × v₂

By the conservation of momentum principle, we have;

The total initial momentum = The total final momentum

Therefore, we have;

0 kg·m/s = 0.004 kg × (-15 m/s) + 70 kg × v₂

Which gives;

0.004 kg × (-15 m/s) = 70 kg × v₂

70 kg × -v₂ = 0.004 kg × (-15 m/s)

-v₂ = 0.004 kg × (-15 m/s)/(70 kg) ≈ -0.0008571 m/s

-v₂ ≈ -0.0008571 m/s

v₂ ≈ 0.0008571 m/s

The velocity of the astronaut = v₂ ≈ 0.0008571 m/s

Answer:nuclear membrane

Explanation:

Answer:

Nuclear envelope. Hope this helps.

Answer:

The icicle will be moving at 333.54 m/s

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.81 m/s^2[/tex].

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The icicle falls from rest for 34 seconds. We need to find the speed after that time:

vf = 9.81*34

vf = 333.54 m/s

The icicle will be moving at 333.54 m/s

The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy PE :

PE = m g h

PE = (2.0 kg) (9.8 m/s²) (3.0 m)

PE = 58.8 J

Energy is conserved throughout the block's descent, so that PE at the top of the curve is equal to kinetic energy KE at the bottom. Solve for the velocity v :

PE = KE

58.8 J = 1/2 m v ²

117.6 J = (2.0 kg) v ²

v = √((117.6 J) / (2.0 kg))

v ≈ 7.668 m/s ≈ 7.7 m/s

The velocity of the block at maximum kinetic energy is 7.668 m/s.

From  potential energy formula,

PE = m g h

Where,

m = mass = 2 kg

g -gravitational acceleration = 9.8 m/s²

h - height = 3 m

Put the values in the formula,

PE = (2.0 kg) (9.8 m/s²) (3.0 m)  

PE = 58.8 J

Since,  

PE = KE

Thus,

58.8 J = 1/2 m v ²  

117.6 J = (2.0 kg) v ²  

v = √((117.6 J) / (2.0 kg))  

v = 7.668 m/s

Therefore, the velocity of the block at maximum kinetic energy is 7.668 m/s.

To know more about  potential energy

https://brainly.com/question/21288807

Explanation:

Accordibg to Hooke's law ,

F=-kx

the minus sign indicates that the force exerted by the spring is opposite to that of extension and the relation between force and extension is a linear one so in the graph it wll pass through the origin and x=0 F=0 and the k (spring constant) will be a constant

Answer:18,000 meters

Explanation:3600x5=18,000.

Answer:

.

Explanation:

.

Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of masses is conserved unless an external force is applied. The formula for the momentum of a body with mass m and velocity v is

P=mv

If we have a system of masses, then the total momentum is the sum of them all

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If a collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum takes the form:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball remains at rest v2'=0. It's required to find the final speed v1' after the collision.

The last equation is solved for v1':

[tex]\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}[/tex]

[tex]\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}[/tex]

[tex]\displaystyle v'_1=\frac{0.34}{0.16}[/tex]

[tex]v'_1=2.125\ m/s[/tex]

The speed of the 8-ball is 2.125 m/s after the collision.

Answer:

When point particals are replaced by string like particals

Explanation:

Starting from rest, the wheel accelerates to an angular velocity of

ω = (2.52 rad/s²) (7.03 s) ≈ 17.7 rad/s

then undergoes a new acceleration α until it comes to a rest. It does so in 11.9 revolutions, or with an angular displacement of (11.9 rev) • (2π rad/rev) = 23.8π rad. So α satisfies

0² - ω² = 2 α (23.8π rad)

α = - ω² / (47.6π rad)

α ≈ -2.10 rad/s²