Answer:
2.51 kg * m/s
Explanation:
In order to find momentum, use the equation below:
momentum = mass * velocity.
Since neither mass nor velocity was given, you must solve for both variables.
In order to solve for mass, use the force equation for its weight / gravitational force.
Fg (gravitational force) = 3.2 N = ma = 9.8m
mass = 3.2 N / 9.8 m/s^2 = 0.326531 kg
In order to solve for velocity, use the equation:
velocity = displacement / time
velocity = 10m / 1.3 s = 7.69231 m/s
Momentum = mass * velocity = 0.326531 kg * 7.69231 m/s = 2.51177 kg * m/s = 2.51 kg * m/s
A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
А. The frequency increases and the wavelength decreases.
B. The frequency decreases and the wavelength increases.
C. The frequency stays the same and the wavelength increases.
D.The frequency stays the same and the wavelength decreases.
E. Neither the frequency nor the wavelength is affected.
Answer:
The frequency stays the same and the wavelength decreases.
Explanation:
When sound wave enters a new medium where sound travels faster, its frequency will remain same because it depends only on the source.
The relation between wavelength and speed is inverse, it means when the speed of sound increases, its wavelength will decrease.
So, the frequency stays the same and the wavelength decreases. Hence, the correct option is (d).
Pitch refers to A. how high or low a note is. B. the loudness of a note. C. the length of the note. D. the range of notes in the composition.
This is music by the way.
Answer:
A
Explanation:
OKAY REAL QUICK A NOTE REPRESENTS THE 12 TONES ON THE CHROMATIC SCALE WHICH IN TURN REPRESENTS THE WHOLE OF SOUND IN ALL MUSIC- EACH NOTE HAS A PITCH THAT REPEATS IN EVERY OCTAVE.
The moment of inertial of the hoop yo-yo when it is: (a) rotating about its center of mass, and (b) rotating about the point where the tension force is applied
mass=332g
diamater=35.9cm
thickness.95cm
Answer:
a) The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].
b) The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].
Explanation:
a) The hoop yo-yo can be modelled as a tours with a minor radius [tex]a[/tex], related with the thickness, and with a major radius [tex]b[/tex], related with the diameter, and with an uniform mass. The momentum of inertia about its center of mass ([tex]I_{g}[/tex]), measured in kilogram-square meters, which is located at the geometrical center of the element, is determined by the following formula:
[tex]I_{g} = \frac{1}{4}\cdot m \cdot (4\cdot b^{2}+3\cdot a^{2})[/tex] (1)
[tex]b = 0.5\cdot D[/tex] (2)
[tex]a = 0.5\cdot t[/tex] (3)
Where:
[tex]D[/tex] - Diameter, measured in meters.
[tex]t[/tex] - Thickness, measured in meters.
[tex]m[/tex] - Mass, measured in kilograms.
If we know that [tex]m = 0.332\,kg[/tex], [tex]D = 0.359\,m[/tex] and [tex]t = 9.5\times 10^{-3}\,m[/tex], then the moment of inertia of the hoop yo-yo is:
[tex]a = 0.5\cdot (9.5\times 10^{-3}\,m)[/tex]
[tex]a = 4.75\times 10^{-3}\,m[/tex]
[tex]b = 0.5\cdot (0.359\,m)[/tex]
[tex]b = 0.180\,m[/tex]
[tex]I_{g} = \frac{1}{4}\cdot (0.332\,kg)\cdot [4\cdot (0.180\,m)^{2}+3\cdot (4.75\times 10^{-3}\,m)^{2}][/tex]
[tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex]
The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].
b) The hoop yo-yo rotate at a point located at a distance of half diameter from the center of mass of the element, whose moment of inertia is determined by the Theorem of Parallel Axes:
[tex]I_{O} = I_{g} +m\cdot r^{2}[/tex] (4)
Where:
[tex]r[/tex] - Distance between parallel axes, measured in meters.
If we know that [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex], [tex]m = 0.332\,kg[/tex] and [tex]r = 0.180\,m[/tex], then the moment of inertial of the hoop yo-yo rotating about the point where the tension force is applied is:
[tex]I_{O} = 0.0108\,kg\cdot m^{2}+(0.332\,kg)\cdot (0.180\,m)^{2}[/tex]
[tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex]
The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].
23 POINTS!! will get brainiest
What is the relationship between temperature range and proximity to the coast?
Answer:I think it’s because both can provide heat and cold
Explanation:
A 430.0 g mass is being pushed by a 1.1 N net force. What is the acceleration?
Answer:
[tex]a = 2.56\ m/s^2[/tex]
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
The object has a mass of m=430 g = 0.43 Kg and is pushed by a net force of F=1.1 N. To calculate the acceleration, we solve for a:
[tex]\displaystyle a=\frac{F}{m}[/tex]
[tex]\displaystyle a=\frac{1.1}{0.43}[/tex]
[tex]\mathbf{a = 2.56\ m/s^2}[/tex]
True or False: Solids always have a higher density than liquids and gases.
Answer:
TRUE THE ANSWER IS TRUE
_________ is the distance an object travels per unit of time.
(5 Points)
speed
displacement
velocity
rate
Explanation:
Speed is the distance an object travel per unit of time
A block of wood of length L = 21.0 cm, width w = 9.53 cm, and height h = 5.92 cm is just barely immersed in water by placing a mass m on the top of the block. The density of the wood is rho = 0.390 g/cm^3. The value of m is:______
a. 0.72 kg
b. 1.2 kg
c. 1.6 kg
d. 7.1 kg
e. 0.36 kg
Answer:
0.462kg
Explanation:
Density = Mass/Volume
Given
Density of the wood = 0.390 g/cm^3
Volume of the wood = Length * Width * Height
Volume = 21 * 9.53 * 5.92
Volume = 1,184.7696cm³
Get the mass m;
mass = density * volume
mass = 0.390 * 1,184.7696
mass = 462.060144g
The mass in kg is 0.462kg
A ball of clay is thrown at a wall at a velocity of 28.0 m/s. After it hits the wall, it
takes 0.020 s to stop. What is the acceleration of the clay when it hits the wall?
Answer:
Explanation:
1400 m/s2
The acceleration of the ball when it hits the vertical wall is -1,400 m/s²
The given expression:
velocity of the ball, v = 28 m/s
time of motion of the ball, t = 0.02 s
To find:
the acceleration of the ball when it hits the vertical wall.The acceleration of the ball is calculated as follows:
[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]
Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²
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Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (568 nm) on a double slit with a separation of 0.107 mm. The diffraction pattern shines on the classroom wall 3.5 m away. Calculate the fringe separation between the third order and central fringe.
Answer:
18.58 mm
Explanation:
Formula for the fringe width is;
β = λL/d
We are given;
λ = 568 nm = 568 × 10^(-9) m
L = 3.5 m
d = 0.107 mm = 0.107 × 10^(-3) mm
β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))
β = 0.01858 m = 18.58 mm
When two objects collide is the momentum before equal to the momentum after the collision? What happens to the individual carts momentum in terms of momentum before and after collision?
Answer:
a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.
thank you.
a 6.5 kg box is pulled across a floor by a horizontal 12.0 N tension force. If there is a 5 N friction exerted on the box, what is its acceleration
Explanation:
Fnet = 12.0N - 5.0N = 7.0N
a = Fnet/m = 7.0N/6.5kg = 1.07m/s².
The spiral spring showed are identical. Each spring has a spring constant K =100N/m determine the total extension caused by the 150N weight
1 spring k=100
2 springs k =200
f=kx
then k=f/x
200=150/x
x=200/150
x=4/3
Explanation:
need thanks ..................
The total extension caused by the 150N weight is 1.5 m
Data obtained from the question Spring constant (K) = 100 N/mForce (F) = 150 NExtention (e) =? How to determine the extensionFrom Hooke's law,
Force (F) = spring constant (K) × extention (e)
F = Ke
150 = 100 × e
Divide both side by 100
e = 150 / 100
e = 1.5 m
Therefore, the total extention caused by the weight is 1.5 m
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Car A travelled 300k in 5 hours, what was its average speed?
Speed =distance/time
Speed=300/5=60 km/h
mark brainliest please
Light of intensity So and polarized horizontally passes through three polarizes. The first and third are horizontal, but the second is oriented 0.3927 rad to the horizontal. In terms of So , what is the intensity of the light that passes through the set of polarizers
Answer: the intensity of the light that passes through the set of polarizers is 0.7285 S₀
Explanation:
based on the data in the question;
As the first polarizer lets all the light through because its plane of polarization is not different from light.
The second polarizer has 2 effects;
firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355
Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.
Hence;
after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.
Therefore
the Overall reduction is by a factor of 0.85355 × 0.85355 S₀
= 0.7285 S₀
Therefore the intensity of the light that passes through the set of polarizers is 0.7285 S₀
A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle of 30 degrees above the horizontal. Find the work done on the box.
Answer: 67 how much candy does nick have
Explanation:
PLEASE HELP ME
1) If a bus travelling at 20 m/s is subject to a steady deceleration of 5 m/s2, how long will it
take to come to rest?
Answer:
Bus will take 4 seconds before it comes to rest.
Explanation:
Initial Velocity of bus = u = 20 ms⁻¹
Final Velocity of bus = v = 0 ms⁻¹
Deceleration of bus = a = -5 ms⁻²
Time taken by bus before it comes to rest = t = ?
Using the equation formula
a = (v - u)/t
-5 = (0 - 20) / (t)
t = -20/-5
t = 4 sec
Therefore, Bus will take 4 seconds before it comes to rest.
What could you do to decrease the rate at which salt dissolves in water?
Add more salt.
Stir the mixture.
Use cold water.
Use hot water.
Answer:
use hot water
Explanation:
hot water helps dissolve things faster
A horse pulls a wagon with 2000N of at constant velocity. What is the friction acting on the wagon?
0N
1000N
1500N
2000N
Answer:
f = 0 N
Explanation:
It is given that,
A horse pulls a wagon with 2000N of at constant velocity.
We need to find the friction acting on the wagon.
As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.
Hence, the correct option is (a).
which nervous system includes the spinal cord
A. Sympathetic
B. autonomic
C. Central
D. Somatic
Answer:
the central nervous system
Answer: C. central
Explanation:
An arrow is shot straight up in the air at an initial speed of 15 m/s. After how much time is the arrow heading downward at a speed of 8 m/s?
Answer:
2.35 seconds
Explanation:
Remark
This is a question where direction matters. Let us call down + and up minus. It won't matter. The answer will be the same.
Formula
a = (vf - vi)/t
Givens
a = 9.8 m/s^2
vi = - 15 m/s
vf = 8m/s
Solution
9.8 = (8 - - 15)/t Multiply both sides by t
t * 9.8 = 23 Divide by 9.8
t = 23/9.8
t = 2.35 s
when an object (like a ball) falls, some of its _____ energy changes to _____ energy, due to the law of conservation of energy
a.) kinetic, potential
b.) kinetic, motion
c.) potential, kinetic
d.) motion, potential
Answer:
c ) potential your welcome heheFind the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s
Answer:
10
Explanation:
Given that :
Initial Velocity (u) = 25 m/s
Range can be obtained using the relation :
Range = (u² * sin2θ) / g
g = 10m/s ; θ = 45
Range = [10² * sin2(45)] / 10
Range = [100 * 1] ÷ 10
Range = 10
write the characteristic of aluminum
Answer:
see below
Explanation:
alluminium is,
1.lustrous
2.highly malleable
3.reactive metal
4.some times acts as non metal
5.good conductor
6.obtained from bauxite
7.Atomic number 13 so electrons and protons are 13
8.neurons are 14
9.ductile
10.melting point is very high approximately 660 degree celsius.
Answer:
It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.
Explanation:
An insulating rod is bent into the shape of a quarter-circle having total charge Q distributed uniformly over its length. At the origin, the magnitude of the total electric field due to this charge configuration is E0 and the potential is V0. A second insulating rod is added to the fourth quadrant to complete a semi-circle. This second quarter-circle has charge -Q uniformly distributed. In terms of E0 and V0, determine the total electric field vector and the total potential at the origin due to the semi-circle of charge.
Answer:
E = - 2*E₀*sinθ*i
V = V = 2*E₀*sinθ /r
Explanation:
First situation: a quarter-circle rod produces at the origin
E₀ and V₀
We know that E = K * Q/r and
E = E₀ Q = L*λ Q = 1/4 * 2*π*r*λ Q = (1/2)*π*r*λ
where:
r is the radius of the circle which at the same time is the distance between the rod quarter of the circle and the origin.
λ is the longitudinal density of charge, and
k = 1/4*π*ε₀
Then E₀ = (1/2)* k*π*λ and V₀ = - E₀/Q V₀ = - E₀/r
E₀ = E₀ₓ + E₀y E₀ₓ = E₀*cosθ E₀y = - E₀*sinθ
θ the angle between E₀ and the x-axis
Second situation half of a circle ( first quarter +Q and fourth -Q )
In that configuration, the components in the x-axis cancel each other ( by symmetry) and the y-axis components of +Q and -Q are to be added then
E = Eₓ + Ey but by inspection we find Eₓ = 0 ( the components of the
the electric field produced of the two quarters canceled each other)
and we have to add the two identical y-axis components of the two quarters therefore
E = 2*E₀y
each component of E₀y = - E₀*sinθ
Then the new electric field becomes
E = - 2*E₀*sinθ*i
The new V = - (- 2*E₀*sinθ /r)
V = 2*E₀*sinθ /r
(Note remember that V is a scalar )
Describe the energy transfers and transformations for a javelin, starting from the point at which an athlete picks up the javelin and ending when the javelin is stuck into the ground after being thrown.
Explanation:
When the Javelin is at rest on the ground, Potential Energy and Kinetic Energy are zero. immediately the Athlete picks the javelin up from the ground, there is an increase in the Kinetic Energy this increase continues until the javelin comes to a halt. Potential Energy also increases.
As the Athlete throws javelin, there is a decrease in the Potential Energy, the Kinetic Energy increases simultaneously until the javelin hits the ground.
after which Potential Energy and Kinetic Energy becomes zero.
When landing from a jump, a basketball player of mass 82 kg has a velocity of 1.2 m/s right before they hit the ground. The player then lands on the floor with their feet and is quickly brought to a stop. If the the floor deforms by 0.025 m while the player lands on it, what was the average force under the player's feet during the landing
Answer:
2361.6N
Explanation:
Mass of player = 82kg
Velocity = 1.2m/s
Kinetic energy of player:
= 1/2mv²
= 1/2*82*1.2²
= 41x1.44
= 59.04J
Final kinetic energy = 0
Change in kinetic energy
|∆k| = |0-59.04|
= 59.04
Workdone by the feet = fd
d = 0.025
Fd = 59.04
F = 59.04/0.025
= 2361.6N
This is his average force.
A space probe is sent to an alien planet and conducts an experiment in order to determine the acceleration due to gravity on the planet. It produces the following table
Object Rock Grain of sand Metal bolt
Mass 20 grams 0.8 grams 79 grams
Recorded force of gravity :0.1224 N 0.00501 N 0.4871 N
Given this data, which of the following the closest approximation of the acceleration due to gravity on this planet
a
3.8 m/s^2
b
4.0 m/s^2
c
9.9 m/s^2
d
6.1 m/s^2
Answer: D. 6.1 m/s^2
Explanation:
These steps are involved in the production of work by a four-stroke heat engine. Place the steps in the correct order. Piston moves up, compressing gas and causing gas to increase its temperature: Piston moves up, pushing burned gases through exhaust valve: 1 Spark plug fires, causing combustion as gas is still compressed; increase in energy from combustion pushes piston down: Piston moves down, allowing fuel-air mixture to enter intake valve:
Answer:
correct order 2,4,3,1
Explanation: correct on edge
Aner shopping. It took Jacob 18 seconds to push his shopping cart to his car. He was moving at 2 meters per second. His daughter walked beside the cart for one-third of the time it took Jacob to reach his car. How far did Jacob's cart move while his daughter was walking beside Write your answer as a whole number meters
Answer:
I am going to answer you just wait a little bit.