Answer:
The mass of the truck is 11,000 Kg.
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
It's given a truck travels at a constant acceleration of [tex]a=3.6~m/s^2[/tex] when a net force of F=39,600 N is applied.
To find the mass of the truck, solve the equation for m:
[tex]\displaystyle m=\frac{F}{a}[/tex]
[tex]\displaystyle m=\frac{39,600}{3.6}[/tex]
Operating:
m = 11,000 Kg
The mass of the truck is 11,000 Kg.
what is not a raquet sport
Answer:
what
Explanation:
Racket sports include tennis, badminton, squash or any other sport where you use rackets to hit a ball or shuttlecock to play. They can be played competitively or just for fun and are a great form of physical activity.
PLS HEP WILL GIVE BRAINLIEST TO FIRST ANSWER SCIENCEE!!
Answer:
Claim: The heart pumps more blood throughout the body when one exercises because exercise takes a lot of energy from the body.
Evidence: Heart rate went from 80 bpm to 120 bpm
Reasoning: Doing exercise takes a lot of energy to do, causing the circulatory system to have to work harder and pump more blood throughout the body in order to allow someone to be able to do a task that involves so much movement and energy.
Explanation:
NEED AWNSER NOW! WILL MARK BRAINLY! Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through?
index of reflection
index of refraction
angle of reflection
angle of incidence
Answer:
Index of refraction.
Answer:
index of refraction
Explanation:
I just took the k12 quiz.
Joe and Jim start at rest at the starting line of a race track. Both runners accelerate at the same rate, but Joe accelerates for twice as long as Jim. Describe the final speed of Joe compared to Jim.
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy
Answer:
42.69J
Explanation:
The question is not complete, here the complete one
A 2.3 kg mass oscillates back and forth from the end of a spring of spring constant 120 N/m. Depending on that x max =0.7 calculate the total energy
and it velocity vx= -3.4m/s
Step one:
given
mass m= 2.3kg
spring constant k= 120 N/m
x= 0.7m
vx=-3.4m/s
Step two:
The expression for the total energy is
[tex]Energy= 1/2mv^2 + 1/2Kx^2[/tex]
substituting we have
[tex]Energy= 1/2*2.3*3.4^2+1/2*120*0.7^2[/tex]
[tex]Energy= 13.29+29.4\\\\Energy=42.69J[/tex]
A plastic ball is tied to 1 end of a long string and is swung in a horizontal circle. If it takes to complete 1 circle, what is the acceleration of the ball
Explanation:
Assuming the ball is swung with a constant velocity V and radius of circle R. Therefore, The tangential acceleration of the ball would be zero.
Considering the centripetal acceleration to be a_c . we get,
[tex]a_c= \frac{V^2}{R}[/tex]
help me, please
Amino Acid Sequence: Create the amino acid sequence from protein synthesis using 3 letter abbreviation for amino acids (#5).
Question
3.2
Calculate the value of critical angle for light passing from glass to air (given that refractive index of
glass - 1.5)
Answer:
42°
Explanation:
From the question given above, the following data were obtained:
Refractive index (n) = 1.5
Critical angle (C) =?
The refractive index and the critical angle are related according to the following reaction:
n = 1 / Sine C
Thus, with the above formula, we can obtain the critical angle as follow:
Refractive index (n) = 1.5
Critical angle (C) =?
n = 1 / Sine C
1.5 = 1 / Sine C
Cross multiply
1.5 × Sine C = 1
Divide both side by 1.5
Sine C = 1 / 1.5
Sine C = 0.6667
Take the inverse of sine
C = Sine¯¹ (0.6667)
C = 41.8 ≈ 42°
Thus, the critical angle is approximately
42°.
The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m and it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.
Solution:
The magnitude of A vector is 84.9 m in the positive y-axis direction.
So the X component of A =0
the Y component of A = 84.9 m
Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.
So the X component of B = B cos 41°
= 195 x cos 41°
= 195 x 0.75 = 146.25 m
the Y component of B = B sin 41°
= 195 x sin 41°
= 195 x 0.65 = 126.75 m
Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.
So the X component of C =126.2 m
the Y component of C = 0
Comparing all these, we get
1. B vector has the largest X component
2. B vector has the largest Y component
9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
Hiaaa I need help pwease" concerning the planetary orbits why was Copernicus somewhat inaccurate?"
Work is a _______ acting upon an object for a given ______. The amount of work done is equal to the change in ________ of the object.
Answer:
Work is a FORCE acting upon an object for a give DISTANCE. The amount of work done is equal to the change in KINETIC ENERGY of the object.
Explanation:
The answer is from the definition and equations for work:
Work = force*distance = change in kinetic energy
Answer:
energy
Explanation:
i took the quiz
1) If a projectile launched at a speed of 20m/s above the horizontal axis of an angle 53 ;(usin g=10mls sin 53=0.8 cos 53=0.6)
find
a the displacement at 2sec
b) the velocity of 2sec
c) total time
d) maximum time
e) Range
f) maximum height
Answer:
(a) 26.83 m
(b) 12.65 m/s
(c) 3.2 seconds
(d) 3.2 seconds
(e) 38.4 m
(f) 12.8 m
Explanation:
Given that a projectile launched at a speed of 20m/s above the horizontal axis at an angle of 53 degrees.
The vertical component of the velocity in the upward direction,
u= 20 sin 53= 20 x 0.8 = 16 m/s.
The horizontal component of the initial velocity,
s=20 cos53 = 20x0.6=12 m/s.
As the gravitational force acts in the vertical direction, so it will only change the vertical component of the initial velocity while the horizontal component of the initial velocity remains unchanged.
(a) The displacement at 2 seconds:
The horizontal distance covered in 2 seconds = 12x2= 24 m
By using the equation of motion, s= ut +1/2 at²
Here, a= -10 m/s² (as g=10m/s² acts in the downward direction)
the vertical displacement s= 16x2- 1/2 x 10 x 2²=12 m
Hence, the displacement after 2 seconds = [tex]\sqrt{24^2+12^2}[/tex]=26.83 m
(b) The velocity at 2 seconds:
As the horizontal component of the velocity is not changing, so the horizontal component of the velocity = 12 m/s
By using the equation of motion, v=u+at
The vertical component of the velocity, v= 16 - 10x2=-4m/s
The negative sign shows that the vertical component of the velocity is in the downward direction.
So, the the velocity at 2 seconds = 12 i - 4 j m/s
The magnitude of the velocity = [tex]\sqrt{12^2+(-40^2}[/tex]=12.65 m/s
(c) Total time of flight:
Total time of flight = 2 x (time to reach the maximum height)
At maximum height, the vertical component of the velocity = 0
So, by using the equation of motion, v=u+at
0= 16-10 t
t= 16/10=1.6 seconds
Hence, the total time of flight= 2 x 1.6 = 3.2 seconds.
(d) Maximum time:
This is the same as the total time of flight, so the maximum time = 3.2 seconds.
(e) Range:
Range = Horizontal component of the velocity x total time of flight
= 12 x 3.2 = 38.4 m
(f) Maximum height:
As the time to reach the highest point = 1.6 seconds
So, by using the equation of motion s = ut + 1/2 at²
The maximum height, s = 16 x 1.6 + 1/2 (-10)1.6² =12.8 m
Hence, the maximum height is 12.8 m.
Question 8 of 15
Which of the following distinguishes electromagnetic waves from mechanical
waves?
A. They carry energy.
B. They have frequencies.
C. They have wavelengths.
D. They don't require a medium to travel through.
Answer:
D. They don't require a medium to travel through.
Explanation:
Electromagnetic waves and mechanical waves are both types of waves. Electromagnetic waves are waves that arise from the combination of electric and magnetic fields while mechanical waves are waves that arise as a result of transfer of energy via matter.
One major difference between these two types of waves is that electromagnetic waves such as light waves, radiowaves etc. do not need a medium to travel i.e. they can travel through a vacuum, while on the other hand, mechanical waves such as sound waves need a medium to travel.
Answer:
They don't require a medium to travel through
Explanation: hope this helps
As you travel downhill, your vehicle needs less power to reach the bottom and your stopping _________ increases.
Answer: Distance
Explanation:
When driving, it is important for one to always use safety belt and obey traffic rules.
During a collision, it is vital to always adhere to safety belts and also use occupant protection systems in order to help reduce the impact that an be felt during a collision. As you travel downhill, your vehicle needs less power to reach the bottom and your stopping distance increase.
Your family is going to drive to your grandma's house for Christmas dinner. You set the car's odometer to 0 before you leave. When you arrive, the odometer reads 42.6 miles. Looking at a map, you see the direct, straight-line distance is 30 miles due east. When you return home, what will be your distance and displacement for the round trip, in that order?
Answer:
Distance = 85.3 miles
displacement = 0
Explanation:
The total distance covered to grandma's house is 42.6 miles as recorded by the odometer. The same distance would be covered when returning to the base. Hence;
Total distance for the round trip = 42.6 + 42.6 = 85.2 miles
Since the trip was a round trip, the displacement is zero because the family returned to their initial location.
A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?
Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.
Which best defines gravity?
A. The tendency of objects to fall from trees
B. An attractive force between two objects due to their mass
C. The amount of matter in an object
D. The rate at which objects fall to earth
Answer:
B. An attractive force between two objects due to their mass
Explanation:
Answer:
B
Explanation:
Gravity is a force that pulls 2 objects towards each other and varies depending on mass. The earth for example is large enough to have a gravitational force that keeps us down. The sun has a gravitational force that keeps the Earth in orbit.
Waves are often caused by
a
vibrating objects.
b
colliding objects.
c
potential energy.
d
mechanical energy.
Answer:
vibrating objects.
I think
Waves are often caused by vibrating objects. Based on the type of vibrational motion, there are different types of waves. Hence, option a is correct.
What are waves ?Waves are disturbances in air or the passage of energy through vacuum or through a medium. Waves are caused by vibration of objects. Three are two types of waves broadly, mechanical waves and electromagnetic waves.
Electromagnetic waves are those associated with combined electric and magnetic field. They can pass through both vacuum and mediums. Mechanical waves need a medium to pass and does not transfer through vacuum.
Based on the vibrational motion, there are two types of waves longitudinal waves and transverse waves. In transverse waves, the vibrational motion of particles is perpendicular to the wave propagation.
In the case of transverse waves, the particle vibration is along the wave propagation. Hence, option A is correct.
Find more on waves:
https://brainly.com/question/3639648
#SPJ2
the ocean contains many plants and protists that can make their own food through photosynthesis. Which need do these organisms get by living near the surface that they cannot get in deep water?
shelter
oxygen
sunlight
Answer:
sunlight
Explanation:
Photosynthesis is made possible by energy from the sun.
Gradually increasing resistance, increasing repetition, increasing sets are examples of which principle?
Answer:
Resistance training.
Explanation:
Resistance training is based on the principle of gradually increasing resistance, increasing repetition and increasing sets to acquire resistance. Resistance training refers to those physical exercises which are designed and done to improve strength and endurance of the body. Resistance training uses the principle of repetition of a particular exercise in order to attain strength as well as resistance against diseases.
According to Kepler's second law of planetary motion,
O a. planets maintain constant speed around the Sun.
Ob. the area swept out by the orbit per time unit keeps changing.
O c. the speed of a planet is greatest when it is closest to the Sun.
O d. planets maintain constant acceleration around the Sun.
Answer:
c. the speed of a planet is greatest when it is closest to the Sun.
Explanation:
Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).
The three (3) laws published by Kepler include;
I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.
II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.
Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.
III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.
Answer:
A planet moves faster when it is closer to the Sun.
Explanation:
Kepler law!
What is the height of a horizontal projectile if it takes 3 seconds to hit the ground?
a
29.4 m
b
3.0 m
C
44.1 m
d
88.3 m
Answer:
B
Explanation:
What is thermodynamics?
a) the way energy changes
b) the classification of energy
c) the movement of energy
d) the movement of heat
Answer:
I think it is D
Explanation:
Answer:
D :D lol
Explanation:
a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.
Answer:
What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true
what is one standard kilogramun si system
Answer:
The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.
What equation would you use to solve for voltage?
Answer:
It depends upon what you have given in the question but according to Ohm's law,
[tex]\boxed{V\:= I × R}[/tex]
where, V = voltage (v)
I = current (amperes)
R = resistance (Ω)
Other formulas are:
V = P/IV = √P × RHope it helps!<3
Determine the energy lost, due to friction, as an 8000 N car that skids to a stop, if its initial velocity was 12 m/s.
Answer:
58,800Joules
Explanation:
The energy lost is equal to the workdone by the car as it skids.
Workdone = Force * Distance
Given
Force = 8000N
Get the distance using the equation of motion
v² = u² - 2gS
0² = 12² - 2(9.8)S
-12² = - 2(9.8)S
-144 = -19.6S
S = 144/19.6
S = 7.35m
Calculate the required energy
Workdone = 8000 * 7.35
Workdone = 58,800Joules
Hence the energy lost due to friction is 58,800Joules
While delivering 125 kg blocks of ice to a local village, Kristoff and his family (and Sven too) come upon a cliff that is 5.7 m above them. To solve their problem, they build a catapult that will launch their blocks of ice with an initial velocity of 15 m/s and at an angle of 45 degrees above the ground.
Prove that the catapult will successfully launch the ice blocks up to the top of the cliff. Quantities you will need to solve for will be initial vertical velocity, horizontal velocity, the distance the catapult is from the cliff, and the amount of time it takes the ice to reach the cliff. Assume that they are experts and have arranged everything so that the ice blocks just barely reach the top of their parabolic path when they land at the top of the cliff and make a smooth landing. Draw a picture of the scene to help you visualize what is happening.
After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.
What is the rate of acceleration while the blocks slow to a stop?
How long do the blocks take to slow to a stop?
What is the amount of friction between the ice and the snowy ground?
How long do the blocks take to slow to a stop?
What is the amount of friction between the ice and the snowy ground?
Answer:
a. Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.
b. -2.81 m/s²
c. 3.78 s
d. -351.25 N
Explanation:
a. After landing on the flat land above, each block of ice travels 20 meters while slowing to a stop.
For the block of ice to reach the top of the cliff, its maximum height, h should be greater than or equal to 5.7 m. That is, h ≥ 5.7 m.
The maximum height of a projection h, projected with an initial velocity v at an angle Ф is h = v²sin²Ф/2g where g = acceleration due to gravity = 9.8 m/s².
For the block of ice, v = 15 m/s and Ф = 45°. So,
h = v²sin²Ф/2g
= (15 m/s)²sin²45/(2 × 9.8 m/s²)
= 225 (m/s)²(1/√2)²/19.6 m/s²
= 225 (m/s)²(1/2)/19.6 m/s²
= 112.5 (m/s)²/19.6 m/s²
= 5.74 m
Since h = 5.74 m > 5.7 m, the height of the cliff, the block of ice will successfully launch to the top of the cliff.
The graph is in the attachment.
b. What is the rate of acceleration while the blocks slow to a stop?
Using v² = u² + 2as where u = initial horizontal velocity of block = 15m/scos45° = 10.61 m/s, v = final velocity of block = 0 m/s since it stops, a = acceleration and s = distance block moves = 20 m
So, a = (v² - u²)/2s
substituting the variables into the equation, we have
a = ((0 m/s)² - (10.61 m/s)²)/2(20 m)
= - 112.57 (m/s)²)/40 m
= -2.81 m/s²
c. How long do the blocks take to slow to a stop?
Using v = u + at where u = initial horizontal velocity of block = 10.61 m/s v = final velocity of block = 0 m/s since it stops, a = acceleration = -2.81 m/s² and t = time it takes block of ice to stop
So, making t subject of the formula,
t = (v - u)/a
substituting the values of the variables, we have
t = ( 0 m/s - 10.61 m/s)/-2.81 m/s²
= -10.61 m/s/-2.81 m/s²
= 3.78 s
d. What is the amount of friction between the ice and the snowy ground?
The frictional force, f = net force on block of ice
f = ma where m = mass of bock = 125 kg and a = acceleration of block = -2.81 m/s²
f = ma
= 125 kg(2.81 m/s²)
= -351.25 N
Why must the rockets use great force to get into outer space?