Ahmad said that the volume of cone A is half the volume of cone B? Do you agree? Explain

Answer:

total amount of sweets=230

Step-by-step explanation:

ratio=8:5:10

total ratio=8+5+10

=23

Adrian=x

Charlie= x+20

Ben=1/2×(x+20)

Charlie's share

10/23×(x+20+x+(1/2×x+20))=x+20

10/23×(x+20+x+(x+20/2))=x+20

10/23×(x+20+x+x+20/2)=x+20

10/23×(2(x+20)+(2×x)+(x+20/2)/2=x+20

10/23×(2x+40+2x+x+20)/2=x+20

10/23×(2x+2x+x+40+20)/2=x+20

10/23×(5x+60)/2=x+20

50x+600/46=x+20

50x+600=46(x+20)

50x+600=46x+920

50x-46x=920-600

4x=320

4x/4=320/4

x=80

Total amount of sweet

x+x+20+1/2(x+20)

80+80+20+1/2(80+20)

180+1/2(100)

180+50

230

Answer:

line n

Step-by-step explanation:

Line n goes through points A and G on the diagram.

Answer:

B. 6

Step-by-step explanation:

3³ x 3³ = 3⁶

The answer is 6

Answer:

B) 6

Step-by-step explanation:

The reason for this is really awesome and is clearly seen when you expand it.

x^3= x times x times x

x^3= x times x times x

x^3 times x^3= x times x times x times x times x times x= x^6

Answer:

3420 minutes 205,200 second.

Answer:

9

Step-by-step explanation:

sqrt(27*3)

sqrt(81)

sqrt(9*9)

9

Answer:

9

Step-by-step explanation:

27 * 3 = 81

√81 = 9

Answer:

See Explanation

Step-by-step explanation:

You posted an incomplete question with little and unclear details.

I will answer this question with a more complete version (see attachment)

Given that:

[tex]Scores: 100\ 95\ 88\ 62\ 76\ 90\ 100\ 58\ 72\ 60\ 85\ 90\ 70\ 72\ 54\ 100\ 60\ 80\ 75\ 51[/tex]

Required

The fraction that passed the test

Rearrange the score in ascending order:

[tex]Scores: 51\ 54\ 58\ 60\ 60\ 62\ 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

The total number of students is:

[tex]n =20[/tex]

Extract the students that passed (scored 70 and above)

[tex]Passed: 70\ 72\ 72\ 75\ 76\ 80\ 85\ 88\ 90\ 90\ 95\ 100\ 100\ 100[/tex]

Their numbers are:

[tex]Passed: 14[/tex]

So, the fraction of those that passed is:

[tex]Fraction = \frac{Passed}{n}[/tex]

[tex]Fraction = \frac{14}{20}[/tex]

Reduce fraction

[tex]Fraction = \frac{7}{10}[/tex]

Answer:

25

Step-by-step explanation:

First number      = 1

Second number = 2

Third number     = 5

Fourth number   = 10

Fifth number      = 25

Sixth number     = 50

Seventh number = 100

Again 14th number will be = 100

Again 21st number will be = 100

Continuing 70 th number will be = 100

71st number= 1

72nd number = 2

73rd number = 5

74th number = 10

75th number = 25

OR

[tex]\frac{75}{7} = 10 \times 7 + 5\\[/tex]

So, after repeating 10 times up to 100, then the 5 number will be the 75th number , which is 25

Answer:

Step-by-step explanation:

length = Pi.radius.15degree/180degree

= Pi.2.15/180 = about 0,5 feet

The length of the arc that is subtended by 15° is: 0.5 ft.

Formula for the arc length in a circle with a radius of r and a central angle of ∅ is, ∅/360 × 2πr.

Given the following:

Arc length = 15/360 × 2π(2)

Arc length = 0.5 ft.

Thus, the length of the arc that is subtended by 15° is: 0.5 ft.

Learn more about the arc length on:

https://brainly.com/question/17329757

Answer:

C. 54

Step-by-step explanation:

1. Drop down the 1

2. Multiply 1 by 3, put that answer, 3, underneath the 5

3. Add 3+5, then put that answer, 8, below.

4. Multiply 8 by 3, put the answer, 24, under the -8

5. Add 24 and -8 to get 16, drop 16 underneath

6. Multiply 16 by 3, put the answer, 48, under the 6

7. Add 48 and 6 to get 54. Drop 54 below.

Now there are no more coefficients to add the 54 to, so 54 is the remainder!

I hope this helped, the explanation without writing it down is kind of confusing. :))

Given:

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

To find:

The quadrant in which [tex]\theta[/tex] lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.

In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.

In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.

We have,

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.

Therefore, the correct option is D.

Answer:

Step-by-step explanation:

volume of reqd. figure=10×5×1+3×3×1=50+9=59 cm³

Answer:

[tex]{ \bf{perimeter = 2(length + width}} \\ \\ { \tt{28 = 2((x + 2) + (x + 6))}} \\ \\ 14 = 2x + 8 \\ 2x = 6 \\ { \tt{x = 3}}[/tex]

x = 3

Perimeter of rectangle = 2 ( l + b )

Where, we have

substitute the values

28 cm = 2 ( ( x + 2) + ( x + 6 ))

combine like terms

distributing 2 through parantheses

subtract 16 from both side

divide both side by 4

Answer:

9

Step-by-step explanation:

Answer:

250

Step-by-step explanation:

4/16 = 1/4 = .25

When dividing exponents, subtract the bottom from the top, so [tex]10^{5}[/tex]÷[tex]10^{2}[/tex] = [tex]10^{3}[/tex]

So, .25 * [tex]10^{3}[/tex] = 250

Answer:

[tex] \large{ 16.}[/tex]

[tex] \: \large{\tt{❃ \: m \: \angle \: 1 + m \: \angle \: 2 = 180 \degree \: ( \: SUM \: OF \: ANGLE \: IN \: LINEAR \: PAIR)}}[/tex]

[tex] \large{ \tt{⟶ \: 47 \degree + m \angle \: 2 = 180 \degree}}[/tex]

[tex] \large{ \tt{⟶ \: m \angle \: 2 \: = 180 \degree - 47 \degree}}[/tex]

[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: 2 = 133 \degree}}}[/tex]

–––––––––––––

[tex] \large{17}.[/tex]

[tex] \large{ \tt{↝ \: m \angle \: 6 = m \angle5 = \boxed{ 99.5\degree }\: ( \: BEING \: VOA)}}[/tex]

–––––––––––––

[tex] \large{18.}[/tex]

[tex] \large{ \tt{✻ \: m \angle \: JHL = m \angle \: JHK + m \: \angle \: KHL\: }}[/tex]

[tex] \large{ \tt{⤏ \: m \angle \: JHL= 60 \degree + 46 \degree}}[/tex]

[tex] \large{ \boxed{\tt{⤏ \: m \angle \: JHL = 106 \degree}}}[/tex]

–––––––––––––––

[tex] \large{ {19.}}[/tex]

[tex] \large{ \tt{❁ \: m \: \angle \: JHK + m \: \angle JHP+ m \: \angle PHN= 180 \degree \: ( \: sum \: of \: angle \: in \: straight \: line)}}[/tex]

[tex] \large{ \tt{↣ \: 60 \degree + m \angle \: JHP+ 46 \degree = 180 \degree}}[/tex]

[tex] \large{ \tt{↣ \: m \angle \: JHP = 74 \degree}}[/tex]

[tex] \large{ \tt{☂ \: m \angle \: JHN = m \angle \: JHP + m \angle \: PHN}}[/tex]

[tex] \large{ \tt{↦m \angle \: JHN = 74 \degree + 46 \degree}}[/tex]

[tex] \large{ \boxed{ \tt{ ↦m \angle \: JHN = 120 \degree}}}[/tex]

––––––––––––––––

[tex] \large{ 20.}[/tex]

[tex] \large{ \tt{✺ \: m \angle \: KHP = m \angle \: KHJ + m \angle \: JHP}}[/tex]

[tex] \large{ \tt{ ↬ \: \: m \angle \: KHP = 74 \degree + 60 \degree}}[/tex]

[tex] \large{ \boxed{\tt{↬ \: m \angle \: KHP = 134 \degree}}}[/tex]

––––––––––––––––

[tex] \large{ \tt{ \# \: StayInAndExplore \: !}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

True

Step-by-step explanation:

A system of equations can be solved by Translating the system of equations into a matrix by following theses steps

write out the resulting answer in form of equations.

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]

7.) Detemine the value of [tex] \sf{ {3a}^{2} -b.}[/tex]

[tex] \huge\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]

[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]

[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{3a}^{2} - b}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶{(3)( 2)}^{2} -( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶3(4)-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12-( - 1)}[/tex]

[tex]\quad \quad \quad \quad \sf{⟶12 + 1 }[/tex]

[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ 13}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{7.)\:13}}}}[/tex]

8.) Find the value of [tex] \sf{ {a}^{3} {b}^{3} - abc.}[/tex]

[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶ {a}^{3} {b}^{3} - abc}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(2)}^{3} {( - 1)}^{3} - (2)( - 1)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{(8)}{( - 1)} - ( - 2)( - 3)}[/tex]

[tex]\quad\quad\quad\quad\sf{⟶{( - 8)} - ( 6)}[/tex]

[tex]\quad\quad\quad\quad ⟶\boxed{\sf{ - 14}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{8.)-14}}}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]

Answer:

a

Step-by-step explanation:

Answer:

The answer would be D.

Step-by-step explanation: Hope this helps and gl :)

Answer:

x=4.34 seconds

Step-by-step explanation:

-16x^2+70x-2=0

[tex]x=\frac{35+\sqrt{1193}}{16}[/tex]

x=4.34

Answer:

0.75

Step-by-step explanation:

Answer:

3/4

Step-by-step explanation:

Use x for the equation: (x - 1/2)*1/2 = 1/8

Just go backwards

1/8 is the result, and to get it, you multiply by 1/2, so instead of that, you divide 1/8 by 1/2 instead (Dividing a number by a fraction is the same as multiplying it by its reciprocal. The reciprocal of 1/2 is 2): (1/8)/(1/2) = 1/8 * 2 = 2/8 = 1/4, now since we subtracted 1/2, we add instead: 1/4 + 1/2 = 1/4 + 2/4 = 3/4

Answer/Step-by-step explanation:

The diagram of the circular track is missing, and so also its dimensions.

However, let's assume the dimensions of the circular track given is diameter (d) = 20 meters or radius (r) = 10 meters.

Since it's a circular track, the circumference of the track would give us the number of meters she runs in 1 lap.

Circumference = πd

d = 20 m (we are assuming the diameter is 20 meters)

π = 3.14

Circumference of circular track = 3.14 × 20 = 62.8 m.

This means that 1 lap = 62.8 m that she would have to run.

Therefore,

6 laps would be = 6 × 62.8 = 376.8 m

Therefore, if she completes 6 laps around the circular track that has a diameter of 20 m, she will have to run about 376.8 m.

Answer:

-24, [tex]\frac{1}{24}[/tex]

Step-by-step explanation:

An opposite number or additive inverse of any number (n) is a number which, if added to n, results in 0. The opposite number for n is written as −n.

For 24, this is -24.

A multiplicative inverse or reciprocal for a number n, is a number which when multiplied by n, their product is 1. To find the multiplicative inverse of a real number, just divide 1 by that number.  The reciprocal for n is written as [tex]\frac{1}{n}[/tex] or [tex]n^{-1}[/tex].

For 24, this is [tex]\frac{1}{24}[/tex].

**This content involves opposite and reciprocal numbers, which you may wish to revise. I'm always happy to help!

Answer:

x = 25

Step-by-step explanation:

Angle 1 and the angle opposite from Angle 1 (the angle that's 68°) are vertical angles.

What are vertical angles, you ask?

According to the Oxford dictionary, vertical angles are each of the pairs of opposite angles made by two intersecting lines.

For example, take the letter X. The letter X has two lines that intersect to form 4 angles. The top and bottom angles are a pair of vertical angles. So are the left and right angles.

Vertical angles are always congruent.

(This is VERY important to know! It will help you solve many types of geometry problems!)

m1 is 3x - 7. Because Angle 1 and the angle that's 68° are vertical angles, that means they are equal to each other.

Therefore: 3x - 7 = 68.

Now, you can solve for x to get x = 25.

Hope this helps!

Answer:

3

Step-by-step explanation:

A'B'C'D' is 3 times bigger than ABCD, so to get back to the original we gotta count the length of B'C' and devide by 3

[tex]9 \div 3 = 3[/tex]

The length of the segment BC or preimage of BC was 3 units.

Two-dimensional figures can be transformed mathematically in order to travel about a plane or coordinate system.

Dilation: The preimage is scaled up or down to create the image.

Reflection: The picture is a preimage that has been reversed.

Rotation: Around a given point, the preimage is rotated to create the final image.

Translation: The image is translated and moved a fixed amount from the preimage.

Given, A Quadrilateral A' B'C'D' is the image of quadrilateral ABCD under a dilation with a scale factor of 3.

From the graph diagram the length of segment B'C' is 9 units.

Therefore, Before the dilation, the length of the segment BC would be

(1/3)×9.

= 3 units.

learn more about transformations here :

https://brainly.com/question/11709244

#SPJ2

Answer:

$1160

Step-by-step explanation:

And yes I agree to this statement

Step-by-step explanation:

the asymptotes of f(x) :

(4x-π) = π/2

4x = 3π/2 => x = 3π/8

(4x-π) = 3π/2

4x=5π/2 => x = 5π/8

the answer is

D. X= 3pi/8, x=5pi/8