Answer:
The energy used by the iron is 0.2083 KWH.
Explanation:
Electric Energy
The energy consumed by an electrical appliance is given by:
E = P.t
Where:
P = Power consumed
t = Time the appliance is connected to the power supply
The power can be calculated as a function of the voltage V and the current I:
P = V.I
Therefore, the energy is:
E = V.I.t
The electric iron draws a current of I=5 A when connected to a V=250 V supply for t=10 minutes. The time must be expressed in hours, thus t=10/60=0.167 hours.
Thus, the energy is:
E = 250 V * 5 A * 0.167 H
E = 208.33 WH
Converting to KWH:
E = 208.33/1000 = 0.2083 KWH
The energy used by the iron is 0.2083 KWH
Two locomotives approach each other on parallel track. Each has speed of 95 km/h with respect to the ground.If they are initially 8.5 km apart. How long will it take before they reach each other?
Answer:
It will take 2.68 minutes for them to reach each other.
Explanation:
We use the two following kinematic equations, making the final position the same (for the moment they meet each other):
locomotive 1 --> [tex]x_f=v*t[/tex]
locomotive 2 --> [tex]x_f=8.5\,-\,v*t[/tex]
we make the two xf equal, and solve for the time (t) using v = 95 km/h:
[tex]95*t=8.5-95*t\\2*95*t=8.5\\t=8.5/(190)\\t = 0.0447\,\,hours[/tex]
converting the hours into minutes by multiplying this value times 60;
t = 2.68 minutes
CUP 6. A wire has a diameter of 0.032 inches. The AWG rating of this wire is most likely to be O A. 20 O B. 14. O C. 12. O D. 18.
Answer:
A. 20
Explanation:
The AWG rating of the wire can be determined by applying the formula;
[tex]d_{i}[/tex] = 0.005 x [tex]92^{\frac{(36 - s)}{39}} }[/tex]
where [tex]d_{i}[/tex] is the diameter of wire in inches, and s is the diameter of wire in AWG.
Given that [tex]d_{i}[/tex] = 0.032 inches, then;
0.032 = 0.005 x [tex]92^{\frac{(36 - s)}{39}} }[/tex]
[tex]\frac{0.032}{0.005}[/tex] = [tex]92^{\frac{(36 - s)}{39}} }[/tex]
6.4 = [tex]92^{\frac{(36 - s)}{39}} }[/tex]
Find the log of both sides to have,
log 6.4 = log [tex]92^{\frac{(36 - s)}{39}} }[/tex]
log 6.4 = [tex](\frac{36 -s}{39})[/tex] log 92
[tex]\frac{log 6.4}{log92}[/tex] = [tex](\frac{36 -s}{39})[/tex]
0.410523 = [tex](\frac{36 -s}{39})[/tex]
36 - s = 0.410523 x 39
= 16.0104
⇒ s = 36 - 16.0104
= 19.9896
s = 20
Therefore, the AWG of the wire is 20.
Mark all the units for speed
Answer:
Speed. I am speed.
Explanation:
The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.
What is net force?
A. The sum of all the forces acting on an object
B. The difference between the largest and smallest forces acting on
an object
C. The largest force acting on an object
D. The smallest force acting on an object
Answer:
A. The sum of all the forces acting on an object.
Of these electromagnetic waves, which has the A Over a unit distance, wave A has three crests and two troughs. The wave begins and ends at the rest position. B Over a unit distance, wave B has two crests and one trough. The wave begins at the rest position and ends at the top of a crest. C Over a unit distance, wave C has four crests and four troughs. The wave begins and ends at the rest position. longest wavelength?
Answer:
Wave B has the longest wavelength
Explanation:
The wavelength of a wave is the distance between two consecutive points that are in phase.
The wavelength of a wave is also defined as the distance between successive crests or troughs along the z-axis.
A crest is the point of maximum upward displacement whereas a trough is a point of maximum downward displacement.
Comparing the three waves A, B and C over a unit distance.
Wave A:
Wave A has three crests and two troughs. The wave begins and ends at the rest position. There are 2½ successive points in phase in wave A
Therefore, the wavelength = 1/2.5 = 0.4
Wave B:
Over a unit distance, wave B has two crests and one trough. The wave begins at the rest position and ends at the top of a crest. There are 1¼ successive points in phase in wave B
Therefore, the wavelength = 1/1¼ = 0.8
Wave C:
Over a unit distance, wave C has four crests and four troughs. The wave begins and ends at the rest position.
There are 4 successive points in phase in wave B
Therefore, the wavelength = 1/4 = 0.25
Therefore, wave B has longest wavelength
What’s the answer to this
Wavelength is a measurement of ___________ , while period is a measurement of ___________ . *
Speed; time
Time; speed
Distance; time
Time; distance
Distance; speed
Speed; distance
distance ; time
Explanation:
wavelength is in metres [m]
period is in seconds [s]
What power does a toaster with 15 A of current and 20 Ωof resistance consume?
Answer:
4500W
Explanation:
[tex]P = {I}^{2} R[/tex]
where P = Power consumed , I = Current & R = Resistance.
In the question it's given that
I = 15A ; R = 20Ω
So ,
[tex]P = {15}^{2}\times 20 = 225 \times 20 = 4500W[/tex]
what is the current definition of intelligence?
Answer:
the ability to learn, emotional knowledge, creativity, and adaptation to meet the demands of the environment effectively
For a scene in a movie, a stunt driver drives a 1700 kg pickup truck with a length of 4.45 m around a circular curve with a radius 0f 0.355 km. The truck is to complete a semicircle, jump across a gully, and land on the other side 3.00 m below and 10.5 m away. What is the minimum centripetal acceleration the truck must have going around the circular curve so that the entire truck will clear the gully and land on the other side
Answer:
[tex]0.51\ \text{m/s}^2[/tex]
Explanation:
t = Time taken
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
r = Radius of track = 0.355 km
Displacement in [tex]y[/tex] direction is 3 m
[tex]y=ut+\dfrac{1}{2}gt^2\\\Rightarrow 3=0+\dfrac{1}{2}\times 9.81 t^2\\\Rightarrow t=\sqrt{\dfrac{3\times 2}{9.81}}\\\Rightarrow t=0.782\ \text{s}[/tex]
Displacement in [tex]x[/tex] direction
[tex]x=10.5\ \text{m}[/tex]
[tex]v=\dfrac{x}{t}\\\Rightarrow v=\dfrac{10.5}{0.782}\\\Rightarrow v=13.43\ \text{m/s}[/tex]
Centripetal acceleration is given by
[tex]a_c=\dfrac{v^2}{r}\\\Rightarrow a_c=\dfrac{13.43^2}{355}\\\Rightarrow a_c=0.51\ \text{m/s}^2[/tex]
The minimum centripetal acceleration the truck must have is [tex]0.51\ \text{m/s}^2[/tex]
The two images show side views of ocean waves. How are the two sets of waves different?
A piece of copper wire with thin insulation, 200 m long and 1.00 mm in diameter, is wound onto a plastic tube to form a long solenoid. This coil has a circular cross section and consists of tightly wound turns in one layer. If the current in the solenoid drops linearly from 1.60 A to zero in 0.120 seconds, an emf of 80.0 mV is induced in the coil. What is the length of the solenoid, measured along its axis
Answer:
N= 3
Explanation:
For this exercise we must use Faraday's law
E = - dФ / dt
Ф = B . A = B Acos θ
tje bold indicate vectors. As it indicates that the variation of the field is linear, we can approximate the derivatives
E = - A cos θ (B - B₀) / t
The angle enters the magnetic field and the normal to the area is zero
cos 0 = 1
A = π r²
In the length of the wire there are N turns each with a length L₀ = 2π r
L = N (2π r)
r = L / 2π N
we substitute
A = L² / (4π N²)
The magnetic field produced by a solenoid is
B = μ₀ N/L I
for which
B₀ = μ₀ N/L I
The final field is zero, because the current is zero
B = 0
We substitute
E = - (L² / 4π N²) (0 - μ₀ N/L I) / t
E = μ₀ L I / (4π N t)
N = μ₀ L I / (4π t E)
The electromotive force is E = 0.80 mV = 0.8 10⁻³ V
let's calculate
N = 4π 10⁻⁷ 200 1.60 / (4π 0.120 0.8 10⁻³)]
N = 320 10⁻⁷ / 9.6 10⁻⁶
N = 33.3 10⁻¹
N= 3
in which part of the circulatory system can the exchange of gases and nutrients take place?
A student heated 50mL of water from zero degree Celsius to 60 degree Celsius. How much energy did she use to heat the water? Remember cal = m x delta T
Answer:
Q = 12.5 kJ
Explanation:
Given that,
Mass of water, m = 50 mL = 0.05 kg
The temperature changes from 0 degree Celsius to 60 degree Celsius.
We need to find how much energy she use to heat the water. The energy required to heat the water is given by :
[tex]Q=mc\Delta T[/tex]
Where c is specific heat of water, c = 4186 J/kgºC
[tex]Q=0.05\times 4186 \times (60-0)\\\\=12558\ J[/tex]
or
Q = 12.5 kJ
So, the energy used to heat th water is 12.5 kJ.
help please Derive an equation
Ta=1.44T1/2
Answer:
To derive an equation you must indicate the variable you want to solve for.Here we have tension of an object A and Tension 1.Two variables or unknown are given hence we cannot derive any other equations.if gravity on the earth increased, what affect would it have on the moon
Answer:
If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.
To get up on the roof, a person (mass 85 kg) places a 6.82 m aluminum ladder (mass 12.6 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. At the top ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2.0 m from the bottom. The person is standing 3.0 m from the bottom of ladder. What are the magnitudes of the forces on the ladder at the top and at the bottom
Answer:
Fₓ = 123.8 N and F_{y} = 0
Explanation:
This is a static balance exercise, to see the forces, see the attachment. In this W is the weight of the ladder and W1 the weight of the man.
locate a reference system at the bottom of the ladder with the horizontal x axis, it will assume that the counterclockwise turns are positive
Σ τ = 0
x + Fₓ y - W₁ d₁ -W d₂ + N 0 + fr 0 = 0
use trigonometry to find the distances
cos θ = x / L
θ = cos⁻¹ (x / L)
θ = cos⁻¹ (2 / 6.82)
θ = 72.9º
in 72.9 = y / L
y = L sin 72.9
y = 6.82 sin 72.9
y = 6.519 m
Center of mass ladder
cos 72.9 = d₂ / 2
d₂ = 2 cos 72.9 = 0.588 m
x coordinate of man
cos 72.9 = d₁ / 3
d₁ = 3 cos 72.9 = 0.882 m
we substitute
2 + Fₓ 6.519 - W₁ 0.882 -W 0.588 = 0
as they indicate that the plastic basket has no friction
F_{y} = 0
Fₓ 6.519 - W₁ 0.882 -W 0.588 = 0
Fₓ 6.519 = M₁ g 0.882 + m g 0.588
we calculate
Fₓ = 85 9.8 0.882 + 12.6 9.8 0.588) / 6.519
Fₓ = 123.8 N
The technology in the picture produces which energy conversion?
A. Chemical energy to kinetic energy
B. Thermal energy to kinetic energy
C. Light energy to electrical energy
D. Kinetic energy to electrical energy
Answer:
D
Explanation:
because the whole town needs to be powered through some sort of energy and kinetic energy means the movement of something
The technology in the picture represents the conversion of kinetic energy to electrical energy. So, the correct option is D.
What is meant by kinetic energy ?Kinetic energy of a body is defined as the energy acquired by the body due to the virtue of its motion.
Here,
The given picture represents the dam system at a town.
We know, according to conservation of energy, energy can neither be created nor be destroyed, but can be transferred from one form to another.
In the dam system, the application of conservation of energy is implemented.
Dam consists of a water stream and turbines. The water stream is arranged in such a way that, when the water is running from a height, the water acquires an energy in the form of kinetic energy.
This kinetic energy of the water is converted to electrical energy with the help of the turbines, which are rotating continuously and thus electricity is produced.
Hence,
The technology in the picture represents the conversion of kinetic energy to electrical energy.
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A spring with a mass attached to it is stretched from the rest position of 20 cm to the position of 87 cm. If the spring constant of this spring is 1729 N/m, what is the potential energy stored in this spring?
561.29 J
120.97 J
388.07 J
254.79 J
Answer:
388.07 J
Explanation:
Answer:
C) 388.07
Explanation:
It is a spring therefore, there must be Elastic potential energy. Now what is the formula for elastic potential energy? It is 1/2 *k *x^2
K=spring constant
x= displacement
1/2=.5 (hate fractions)
Now, Displacement simply means (how much was it moved?) So, that means subtract.
87-20= 67 x=67
Next, do x^2 (so you don't make a mistake by squaring everything :) )
67*67=4,489
NOW, do....
.5*1729*4,489=3,880,740.5
Now convert to Joules, I just did 3,880,740.5 / 10^3 = 3880.745
round to 3880.7 J
~There you go loves !
I NEED BY JAN 4!!!!!!
Research what is known about Earth’s magnetic field. Begin by looking for images and credible sites on the Internet or refer to some books in a library. Answer the following questions:
What is the approximate size of Earth’s magnetic field?
Where are Earth’s magnetic poles?
Where is the magnet that causes Earth’s magnetic field located? What is this magnet made of?
Does Earth’s magnetic field move?
The earth has a magnetic field. It is much like a bar magnet. Imagine a gigantic bar magnet inside the Earth. But there is no giant magnet inside it.
To have a pretty good idea what earth's magnetic field is shaped like we imagine a bar magnet inside the earth.
The magnetic field is made by the motion of molten iron in earth's outer core. The swirling motion of molten iron changes all the time. Therefore, the magnetic fields will also get change. Then, the magnet poles also move.
The North pole and the south pole are two geographic poles of earth. These poles are the places on the earth's surface that earth's imaginary spin axis passes through.
There are two magnetic poles of the earth: North magnetic pole and South magnetic pole.
Earth's magnetic field is tilted a little bit. If we imagine that earth's magnetic field is made by a giant bar magnet. Then, the bar magnet would make an with earth's spin axis.
The geographic poles and the magnetic poles are not in the same place.
If we are standing at one magnetic poles then the magnetic field lines would be straight up and down.
Earth's magnetic field is a complex and dynamic phenomenon that is generated by the motion of molten iron in its outer core. The magnetic field extends far beyond the planet and is responsible for protecting Earth from harmful solar radiation and cosmic rays.
What is the approximate size of Earth's magnetic field?Earth's magnetic field is roughly dipolar in shape, meaning it has two main magnetic poles - north and south - and the field lines emerge from the north and re-enter at the south pole. The magnetic field has a strength of about 25-65 microteslas (μT) at the Earth's surface, and it extends for several tens of thousands of kilometers into space.
2. Where are Earth's magnetic poles?
Earth's magnetic poles are not fixed and are constantly moving due to the complex and dynamic nature of the planet's magnetic field. Currently, the north magnetic pole is located in the Arctic Ocean, close to Canada's Ellesmere Island, and the south magnetic pole is located in the Antarctic Ocean, near the coast of Antarctica.
3. Where is the magnet that causes Earth's magnetic field located? What is this magnet made of?
The magnet that causes Earth's magnetic field is not a physical magnet but rather a result of the motion of molten iron in the Earth's outer core. The outer core is a layer of liquid iron and nickel that surrounds the solid inner core. The motion of this molten iron generates electrical currents, which in turn create a magnetic field.
4. Does Earth's magnetic field move?
Yes, Earth's magnetic field is not static and is constantly changing due to the complex nature of the planet's interior. The magnetic poles are constantly moving and the strength of the magnetic field can vary over time. The magnetic field can also be influenced by external factors such as solar storms and changes in the solar wind. Scientists continue to study Earth's magnetic field to better understand its behavior and how it affects the planet.
Therefore, The magnetic field of the Earth is a complex and dynamic phenomenon caused by the movement of molten iron in its outer core. The magnetic field extends far beyond the planet and is in charge of shielding the planet from harmful solar radiation and cosmic rays.
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3. If a net horizontal force of 49 N is applied to a box whose mass is 5 kg what acceleration
is produced?
Answer:
9.8 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{49}{5} \\ [/tex]
We have the final answer as
9.8 m/s²Hope this helps you
An axe used to split wood is driven into a piece of wood for an input distance of 0.05m. If the mechanical
advantage of the axe is 0.85, how far apart (output distance) is the wood split?
Two sacks contain the same number of identical apples and are separated by a distance r. The two
sacks exert a gravitational orce on each other that is opposite in direction but with the same
F. Half the apples are removed from one sack and placed in the second sack. What is the magnitude
the gravitational force between the two sacks in terms of the original force, F?
Answer:
The appropriate response will be "[tex]F_2=\frac{3}{4}F[/tex]". A further explanation is given below.
Explanation:
According to the question,
⇒ [tex]F_1=\frac{G(m_1 m_2)}{r^2}[/tex] ....(equation 1)
and,
⇒ [tex]F_2=\frac{G(m_1 m_2)}{r^2}[/tex] ....(equation 2)
Now,
On dividing both the equations, we get
⇒ [tex]\frac{F_1}{F_2}=\frac{\frac{G(2)(2)}{(1)^2}}{\frac{G(1)(3)}{(1)^2}}[/tex]
⇒ [tex]\frac{F_1}{F_2}= \frac{4}{3}[/tex]
⇒ [tex]F_2=\frac{3}{4}F[/tex]
The magnitude of gravitational force is different due to difference in masses of two sacks.
The magnitude of gravitational force between the two sacks in terms of the original force is different because the mass of the two objects are different from each other. There is direct relationship between gravitational force and mass of an object. Higher the mass of an object higher will be the gravitational force of attraction and vice versa.
So that sack which gains more weight have more force of gravitation as compared to the other sack which has less weight so we can conclude that the magnitude of gravitational force is different due to difference in masses of two sacks.
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How large a net force is required to accelerate a 1,586-kg SUV from rest to a speed of 10.4 m/s in a distance of 212 m?
Answer:
F = 404.6 N
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
On the other hand, the equations of the Kinematics describe the motion of the object by the equation:
[tex]v_f=v_o+a.t[/tex]
Where:
vf is the final speed
vo is the initial speed
a is the acceleration
t is the time
Another useful equation for speeds and distance X is:
[tex]V_f^2=V_o^2+2aX[/tex]
To calculate the acceleration, we solve for a:
[tex]\displaystyle a=\frac{V_f^2-V_o^2}{2X}[/tex]
The SUV starts from rest (vo=0) to vf=10.4 m/s traveling a distance of X=211 m, thus the acceleration is:
[tex]\displaystyle a=\frac{10.4^2-0^2}{2(212)}[/tex]
[tex]\displaystyle a=\frac{108.16}{424}[/tex]
[tex]a=0.26 \ m/s^2[/tex]
The force needed to accelerate the SUV of mass m=1,586 Kg is:
F = 1,586*0.26
F = 404.6 N
SOMEBODY ONCE TOLD ME THE WORLD WAS GONNA ROLL ME
I AIN'T THE SHARPEST TOOL IN THE SHED~
SHE WAS LOOKING KINDA DUM WITH HER FINGER AND HER THUMB
IN THE SHAPE OF AN "L" ON HER FOREHEAD~
WELL THE YEARS START COMING AND THEY DON'T STOP COMING
FED TO THE RULES AND I HIT THE GROUND RUNNING
DIDN'T MAKE SENSE NOT TO LIVE FOR FUN
YOUR BRAIN GETS SMART BUT YOUR HEAD GETS DUM
SO MUCH TO DO, SO MUCH TO SEE--
SO WHATS WRONG WITH TAKING THE BACKSTREETS?
YOU'LL NEVER KNOW IF YOU DON'T GO
YOU'LL NEVER SHINE IF YOU DON'T GLOW.
Answer:
so true though
Explanation:
A 1500 kg car is moving on a flat, horizontal flat road. If the radius of the curve is 35 m and
the coefficient of static friction between tires and dry road, Ms = 0.5. Calculate the maximum
speed the car can have and still make the turn successfully
The net force on the car is the friction that keeps it on the road, which points toward the center of the circle of the curve. Then by Newton's second law, we have
• net vertical force:
∑ F = N - W = 0
• net horizontal force:
∑ F = Fs = m a
where
N = magnitude of normal force
W = car's weight
Fs = mag. of static friction
m = car's mass
a = v ²/R = mag. of the centripetal acceleration
v = car's speed
R = radius of curve
Now,
• compute the car's weight:
W = m g = (1500 kg) (9.8 m/s²) = 14,700 N
• solve for the mag. of the normal force:
N = 14,700 N
• solve for the mag. of the friction force, using the given friction coefficient:
Fs = 0.5 N = 7350 N
• solve for the (maximum) acceleration:
7350 N = (1500 kg) a → a = 4.9 m/s²
• solve for the (maximum) speed:
4.9 m/s² = v ²/ (35 m) → v ≈ 13 m/s
A truck is traveling at 27 m/s down the interstate highway where you are changing a flat tire. frequency of 185 Hz.
A) What frequency do you hear?
B) Suppose after fixing the flat you were driving your car at 22 m/s the truck drives blows his horn again. What frequency do you hear? (Speed of sound in air is 340 mis).
Answer:
(a) the observed frequency is 200 Hz
(b) the observed frequency is 188 Hz.
Explanation:
speed of the truck, Vs = 27 m/s
frequency of the truck as it approaches, Fs = 185 Hz
(a) Apply Doppler effect to determine the frequency you will hear.
As the truck approaches you, the observed frequency will be higher than the source frequency because of decrease in distance.
[tex]F_s = F_o [\frac{V}{V_S + V} ][/tex]
Where;
Fo is the observed frequency which is the frequency you will hear.
V is speed of sound in air
[tex]F_s = F_o [\frac{V}{V_S + V} ]\\\\185 = F_o [\frac{340}{27 + 340} ]\\\\185 = F_o (0.926)\\\\F_o = \frac{185}{0.926}\\\\F_o = 199.78 \ Hz[/tex]
[tex]F_o = 200 \ Hz[/tex]
(b) Apply the following formula for a moving observer and a moving source;
[tex]F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )[/tex]
The observed frequency is negative since you are driving away from the truck and the source frequency is also negative since it is driving towards you.
[tex]F_o = F_s[\frac{V-V_o}{V} ](\frac{V}{V-V_S} )\\\\F_o = 185[\frac{340-22}{340} ](\frac{340}{340-27} )\\\\F_o = 185(0.9353)(1.0863)\\\\F_o = 188 \ Hz[/tex]
What is the correct order of the layers' density from lowest density to highest?
A. crust, core, mantle
B. core, mantle, crust
C. crust, mantle, core
D. mantle, crust, core
Answer:
C. crust, mantle, core
Explanation:
density increases as you travel from the crust to the inner core
the crust is on top
next is the mantle
and then the core
Answer:
C. Crust, mantle, core
Explanation:
If you travel further into the earth's core, the density and pressure increases, along with temperature.
what is a atomic nuclues
You hit a hockey puck and it slides across the ice at nearly a constant speed.Is a force keeping it in motion?Explain.
Answer:
Explanation:
When the puck is sliding on the ice, there is no force being exerted on the puck to keep it moving forward. Instead, inertia keeps the puck moving forward. Friction between the puck and the ice gradually slows the puck down. You hit a hockey puck and it slides across the ice at nearly a constant speed
At constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.
According to Newton's second law of motion, the force applied to a an object is directly proportional to the product of mass and acceleration of the object.
F = ma
Acceleration is the change in the velocity of an object per change in time of motion.
At constant velocity, the acceleration of an object is zero.When acceleration of an object is zero, the force on the object is zero.A constant speed (magnitude only) and change in the direction of the object, implies a change in velocity of the object.at changing velocity, the acceleration on an object is positive, and hence net force acts on the object.Thus, we can conclude that at constant speed and varying position of the hockey puck, implies a change in the velocity of the hockey puck and net force is acting on it to keep it in motion.
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