Answer:
1218.75
Explanation: If he makes a 25% profit, he needs to sell it for 125% of the computer price. 1.25*975 is 1218.75
3. What type of thinking are you
engaging in when you ask about the
pay and benefits of a job you are
considering?
a) constructive
b) associative
c) critical
d) creative
The type of thinking are you engaging in when you ask about the pay and benefits of a job you are considering is known as constructive. Thus, the correct option for this question is A.
What are the different types of thinking?The different types of thinking may include convergent or analytical thinking, divergent thinking, critical thinking, and creative thinking. Each of these types has specific attributes and a set of functions in order to make a specific criterion for individuals.
Constructive Thinking refers to a set of cognitive productive and counterproductive automatic habitual thoughts that affects one's ability to think in a manner that solves problems. It basically includes the ability to solve problems in everyday life with minimal stress.
Therefore, constructive thinking is the type of thinking that are you engaging in when you ask about the pay and benefits of a job you are considering. Thus, the correct option for this question is A.
To learn more about Thinking skills, refer to the link:
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Explain how to properly engage the safety latches on the Stan Design Pit Jack.
The way to properly engage the safety latches on the Stan Design Pit Jack is:
Connect the hydraulic jack.Make sure it is properly lubricated.Ensure that the rolling bridge jack is well fused together.Use the machine.What is the Stan Design Pit Jack?This refers to the machination which makes use of pit jacks to execute tire rotation in a fast lube pit.
We can note that based on the design, this machine is put in the pit of a car and then rolls back and forth and perform their operations on both the front and real axles.
Hence, it is important to note that the safety latches are designed to prevent work accidents and it is important to properly lubricate the parts to prevent damage.
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a. An 80-percent efficient pump with a power input of 20 hp is pumping water from a lake to a nearby pool at ar ate of 1.5 ft3 /s through a constant-diameter pipe. The free surface of the pool is 80 ft above that of the lake. Determine the mechanical power used to overcome frictional effects in piping.
b. Water is pumped from a lake to a storage tank 15 m above at a rate of 70 L/s while consuming 15.4 kW of electric power. Disregarding any frictional losses in the pipes and any changes in kinetic energy. Determine:
1. The overall efficiency of the pump–motor unit.
b. The pressure difference between the inlet and the exit of the pump.
Answer:
A) mechanical power used to overcome frictional effects in piping = 2.373 HP
B) efficiency = 66.82%
Pressure difference = 147 KPa
Explanation:
We are given;
efficiency of pump; η = 80% = 0.8
power input of pump;P_pump,in = 20 hp
rate being pumped; Q = 1.5 ft³/s = 0.04248 m³/s
free surface of pool; Δz = 80 ft = 24.384 m
mechanical pumping power used to deliver water is;
W_u = η × P_pump,in
W_u = 0.8 × 20
W_u = 16 Hp
Now, change in total mechanical energy of water will be equal to the change in potential energy.
Thus, it is expressed as;
ΔE_mech = ρ × Q × g × Δz
Where ρ is density of water = 1000 kg/m³
Thus;
ΔE_mech = 1000 × 0.04248 × 9.81 × 24.384 = 10,161.5150592 J/s
Converting to HP gives;
ΔE_mech = 13.627 HP
Now, mechanical power used to overcome frictional effects is given by;
W_frict = W_u - ΔE_mech
W_frict = 16 - 13.627
W_frict = 2.373 HP
B) We are now given;
W_elect,in = 15.4 KW
Volumetric flow rate; q = 70 l/s = 0.07 m³/s
Height; h = 15 m
Mass flow rate; m' = qρ
Where ρ is density of water = 1000 kg/m³.
m' = 0.07 × 1000
m' = 70 kg/s
Now,
ΔE_mech = workdone through height of 15m
Thus;
ΔE_mech = m'gh
ΔE_mech = 70 × 9.8 × 15
ΔE_mech = 10,290 W = 10.29 Kw
efficiency of the pump–motor unit = ΔE_mech/(W_elect,in) = 10.29/15.4 = 0.6682 or 66.82%
Pressure difference = ρgh = 1000 × 9.8 × 15 = 147,000 Pa = 147 KPa
Please give me the answers
Answer:
Water ferries
Consider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.
Required:
a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?
b. Find the average rate of CO emissions during this two-hour period.
c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pm
Consider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.
Required:
a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?
b. Find the average rate of CO emissions during this two-hour period.
c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pmConsider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.
Required:
a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?
b. Find the average rate of CO emissions during this two-hour period.
c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pmConsider an area-source box model for air pollution above a peninsula of land. The length of the box is 15 km, its width is 80 km, and a radiation inversion restricts mixing to 15 m. Wind is blowing clean air into the long dimension of the box at 0.5 m/s. On average, there are 250,000 vehicles on the road, each being driven 40 km in 2 hours and each emitting 4 g/km of CO.
Required:
a. Estimate the steady-state concentration of CO in the air. Should the city be designated as "nonattainment" (i.e., steady-state concentration is over the NAAQS standard)?
b. Find the average rate of CO emissions during this two-hour period.
c. If the windspeed is zero, use the formula to derive relationship between CO and time and use it to find the CO over the peninsula at 6pm
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what is this answer Is cereal soup?
Answer:
depend what cereal yeha
Explanation:
no explanation
7)
Given a series silicon diode circuit with the resistor R=2 ko ohms and an applied voltage of 10
V, what is Ipg?
A) 0.5 mA
B) 10 mA
C) 4.65 mA
D) 1.0 mA
Answer:
C) 4.65 mA
Explanation:
The series circuit will have a voltage drop of about 0.7 V across the silicon diode, so the voltage drop across the 2 kΩ resistor is 10 -0.7 = 9.3 V. The current through the resistor is given by Ohm's Law:
I = V/R = 9.3 V/(2 kΩ)
I = 4.65 mA
What make metal ductwork more desirable than flex duct?
Less friction loss
Less chance of restriction
More direct routes to boots
All of the above
explain wet and dry compression tests
A wet compression test is similar to a dry compression test except it has the addition of oil placed in each cylinder. A wet compression test is done for two reasons: One or more cylinders has a reading of less than 100 psi on the dry compression test.
Using the Equilibrium Equation (F1d1 = F2d2), find F1, if d1 = 30ft, and F2 = 1050lb, and d2=22ft. Please state your answer in pounds and round to the nearest whole number.
Answer:
77 lb
Explanation:
Equation: F₁d₁ = F₂d₂
Knowns:
d₁ = 30 ft
F₂ = 105 lb
d₂ = 22 ft
Solving for F₁:
1). F₁•30 = 105•22
2). F₁•30=2,310
3).[tex]\frac{F_1\cdot 30}{30}=\frac{2310}{30}[/tex]
4). F₁ = 77 lb
A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on
the free end of the rope for maintaining equilibrium that is required to just support a 5 kN weight. The
coefficient of friction between the rope and the cylinder is 0.2
The range of force exerted at the end of the rope is; 285.7 N to 1,000 N.
What is the Net horizontal force?The net horizontal force of the cylinder when it is at equilibrium position can be found by applying Newton's second law of motion. Thus;
∑F = 0
F - μF_n = 0
We are given;
F_n = 5 kN = 5000 N
μ = 0.2
Thus;
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force will be increasing as the number of turns of the rope increases. Thus;
Minimum force = Total force/number of turns of rope
Since rope is wrapped three and half times, then;
number of turns = 3.5
Thus;
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Read more about net horizontal force at; https://brainly.com/question/26957287
Most schools use a learning management system (LMS) in order to make daily tasks easier, like taking attendance, entering grades, and: communicating with students and parents. Changing data into a different form, in order to prevent unauthorized access. Ensuring that regulations and standards are being met. Sorting through large amounts of data.
Answer:
like taking attendance, entering grades, and: communicating with students and parents.
Explanation:
Indeed, the learning management system (LMS) is a multipurpose software application that allows an organization to record, analyze, and distribute information at flexibility. For example, a school can use this software to take attendance, enter student grades, and can facilitate communication with students and parents.
whats your answer Where is the strangest place you’ve urinated or defecated?
Answer:At the train station
Explanation:
Answer:
in those camping portal pottys
A completely reversible heat engine operates with a source at 1500 R and a sink at 560 R. At what rate must heat be supplied to this engine, in Btu/h, for it to produce 5 hp of power?
Answer: iy had around 5000 R
Explanation:
The gas velocity decrease from 480 m/s to 160 m/s through a stationary normal shock. If the pressure and density upstream of the shock are 62 kPa and 1.5 kg/m^3 , respectively, find the pressure and density down stream of the shock and the specific heat ratio of the gas.
Answer:
52m/s
12 kpa
0.1 kg/m
Explanation:
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What is rainfall intensity
Answer:
Rainfall intensity is defined as the ratio of the total amount of rain (rainfall depth) falling during a given period to the duration of the period It is expressed in depth units per unit time, usually as mm per hour (mm/h).
Answer:
the ratio of the total amount of rain (rainfall depth) falling during a given period to the duration of the period
Calculate the current in the coiled heating element of a 240-V stove. The resistance of the element is 60 ohms at its operating temperature.
Answer:
4 A
Explanation:
Current is found using Ohm's law.
I = V/R
I = (240 volts)/(60 ohms) = 4 A
The heating element current is 4 amperes.
A liquid of specific heat 3000J/kgk rise from 15°c to 65°c in 1 min when an electric heater is used. If the heater generate 63000J, calculate the mass of the water
Answer:
0.42 kg
Explanation:
Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.
[tex]\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}[/tex]
The mass of the liquid is about 0.42 kg.
Refrigerant-134a at 1 MPa and 100 C is to be cooled to 1 MPa and 28 C in a condenser by air. The air enters at 125 kPa and 25 C with a mass flow rate of 697 kg/min and leaves at 97 kPa and 58 C. Determine the mass flow rate of the refrigerant. Assume air has a constant heat capacity determined at room temperature. Report the mass flow rate of the refrigerant in kg/min with one decimal digit, for example 95.3 or 105.6.
if you play roblox leave user down bellow
Answer:
why dont you make friends on roblox lol might be safer
Explanation:
Answer:
yes i play roblox
Explanation:
But why are you asking this type of Question
At time t the resultant force on a particle, of mass 250kg is (300ti-400tj)N. Initially, the particle is at the origin and is moving
with the velocity (2i-3j)m
−1
Answer:
i
Explanation:
An experimental arrangement for measuring the thermal conductivity of solid materials involves the use of two long rods that are equivalent in every respect, except that one is fabricated from a standard material of known thermal conductivity kA while the other is fabricated from the material whose thermal conductivity kB is desired. Both rods are attached at one end to a heat source of fixed temperature Tb, are exposed to a fluid of temperature [infinity] T[infinity], and are instrumented with thermocouples to measure the temperature at a fixed distance x1 from the heat source. If the standard material is aluminum, with kA= 200 W/m·K, and measurements reveal values of TA= 75°C and TB= 70°C at x1 for Tb= 100°C and [infinity] T[infinity]= 25°C, what is the thermal conductivity kB of the test material?
Answer: the thermal conductivity of the second material is 125.9 W/m.k
Explanation:
Given that;
The two rods could be approximated as a fins of infinite length.
TA = 75°C, θA = (TA - T∞) = 75 - 25 = 50°C
TB = 70°C θB = (TB - T∞) = 70 - 25 = 45°C
Tb = 100°C θb = (Tb - T∞) = (100 - 25) = 75°C
T∞ = 25°C
KA = 200 W/m · K , KB = ?
Now
The temperature distribution for the infinite fins are given by
θ/θb = e^(-mx)
θA/θb= e^-√(hp/A.kA) x 1 --------------1
θB/θb = e^-√(hp/A.kB) x 1---------------2
next we take the natural logof both sides,
ln(θA/θb) = -√(hp/A.kA) x 1 ------------3
In(θB/θb) = -√(hp/A.kB) x 1 ------------4
now we divide 3 by 4
[ ln(θA/θb) /in(θB/θb)] = √(KB/KA)
we substitute
[ In(50/75) /In(45/75)] = √(KB/200)
In(0.6666) / In(0.6) = √KB / √200
-0.4055/-0.5108 = √KB / √200
0.7938 = √KB / 14.14
√KB = 11.22
KB = 125.9 W/m.k
So the thermal conductivity of the second material is 125.9 W/m.k
Lynx eat snowshoe hares, and snowshoes hears eat plants. Which term can be applied to the lynx in this food chain example? Primary consumer predator secondary consumer
Answer:
primary consumer because YES
Answer:predator and secondary consumer
Explanation:
How can you tell whether a trash container is for regular or biohazardous waste?.
How long would a piece of wood need to be to make a diagonal brace for a rectangle that measures 4 inches by 3 inches? Use the Pythagorean theorem, a² + b² = c², to determine the answer. 5 inches 7 inches 12 inches 25 inches Select the correct answer.
Answer:
Length of a diagonal = 5 inches
Explanation:
Let [tex]a[/tex] and [tex]b[/tex] the sides of the rectangle and [tex]c[/tex] be the diagonal of the rectangle.
According to the Pythagorean theorem, sum of squares of base and perpendicular is equal to the square of hypotenuse.
As each angle of the rectangle is a right angle,
[tex]a^2+b^2=c^2[/tex]
Put [tex]a=4\,,\,b=3[/tex]
[tex]4^2+3^2=c^2\\16+9=c^2\\25=c^2\\\sqrt{25}=c\\ 5=c[/tex]
So,
Length of a diagonal = 5 inches
(TCO 6) A cable company is running a fiber-optic link between the head end and a neighborhood five miles away. The signal applied to the fiber goes through an optical connector having 3dB LOSS at the head end, the fiber has a LOSS of 1 dB, and the connector at the end of the fiber has a LOSS of 3 dB before being applied to an amplifier used to make up for the losses. The desired signal at the output of the amplifier is 10 dBm, and the signal level applied to the fiber connector at the head end is 10 dBm. What should the gain of the amplifier be to have 10 dBm at the output of the neighborhood amplifier
Answer:
7 dB
Explanation:
The total loss from the headend to the amplifier input is the sum of the losses along the fiber, that we simply add as they are in dBs:Total Loss = 3 dB + 1 dB + 3 dB = 7 dBThe signal at the amplifier input is just +10 dBm- 7 dB = +3 dBmSo as the output level at the Headend and the one at the output of the neighborhood amplifier must be equal each other (compensating all losses in the path), the amplifier gain must be equal to the cumulative loss, i.e. , 7 dB, so that the amplifier output level be + 10 dBm.“We’re late for homeroom,” said Bonnie, surprised to hear herself say “we.” “EARL is a tool, Bonnie’s mother kept reminding her, not a friend or a puppy. ‘Don’t anthropomorphize it, honey,’ Bonnie’s mom said one night after she found Bonnie dancing around her bedroom with the metal contraption. ‘It’s a walking blender. Never forget that.”
QUESTION: What does, "Anthropomorphize" means in the sentences above?
(A) It means to program a robot so that it acts in a robotic or unnatural way?
(B) Or it means to give human characteristics to an object or animal?
(C) To make a human act more like an animal and less of a human?
(D) Or to make a human act more like an animal and less of a human?
Answer correctly
Will give Brainliest, a THX, friend request, and will rate ur answer
Answer:
Hi there
Your answer is:
B.
Explanation:
The "metal contraption", as the text goes on to say, is treated like a friend to Bonnie. Her mom comments on this by contrasting the metal contraption to a puppy.
Hope this helps
Deviations from the engineering drawing can’t be made without the approval of the
Engineer's approvall makes it appropriate to alter from the drawing
What is Engineering drawing?Engineering drawing is a document that contain the design of an engineer represented in a sketch.
deviating fron the drawing is same as deviating from the design. it is therefore necessary to call the engineers attention before altering the drawing.
Read more on Engineering drawing here: https://brainly.com/question/15180981
From the top of a vertical cliff 80m high, the angles of depression of 2 buoys lying due west of the cliff are 23° and 15° respectively. How far are the buoys apart?
Answer:
110 m
Explanation:
The geometry of the problem can be modeled by a right triangle. The height of the cliff forms one leg, and the distance to a buoy forms the other leg. The angle of depression is opposite the height of the cliff. An appropriate trig relation is ...
Tan = Opposite/Adjacent
Solving for the Adjacent side (the distance to the buoy), we find ...
Adjacent = Opposite/Tan
distance to buoy 1 = (80 m)/tan(23°) ≈ 188.468 m
distance to buoy 2 = (80 m)/tan(15°) ≈ 298.564 m
Then the distance between the buoys is ...
298.564 -188.468 m ≈ 110 m
The buoys are about 110 meters apart.
Technician A says that a circuit with continuity reads 0 ohms. Technician B says that an open circuit reads 0 ohms. Who is correct
Answer:
A
Explanation:
An open circuit has infinite resistance, not 0. A circuit with continuity usually measures a few ohms or less, depending on the length and gauge of the wire and the condition of the connections. Often, on a general-purpose ohmmeter, the reading is very near 0 ohms.
Technician A is correct.