an object is spun around in a circle of radius 2.0m with a period of 10.0s. what’s it’s velocity ?

Answers

Answer 1

Answer:

1.26 m/s

Explanation:

v=(2*pi*r)/T

v=(2*pi*2)/10

Answer 2

The  object is spun around in a circle of radius 2.0m with a period of 10.0s. Its velocity be 1.25 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Radius of the circle = 2.0 m.

Period of spinning of the object = 10.0 s.

So, angular velocity of the object be = 2π/10 radian/second.

So, magnitude of velocity be = radius × angular velocity

= 2.0 × 2π/10 m/s

= 1.25 m/s.

Hence, the magnitude of velocity of the object be 1.25 m/s.

Learn more about velocity here:

https://brainly.com/question/18084516

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Related Questions

Which of these statements best explains why the atmosphere of today was partly due to the interactions of spheres in the past?

Bacteria used nutrients in the soil for volcanic eruptions.
Chemicals released from water formed the atmosphere.
The molten Earth released hydrogen and helium into the atmosphere.
The increase in fertility of soil around the volcano helped produce rain.

Answers

Answer:

The answer is: Plants and animals exchange carbon dioxide and oxygen with the atmosphere.

Explanation:

Got the answer right.

In an elastic collision, ________. A. an individual molecule in the collision never loses energy B. the molecules involved in the collision move in a circular motion C. the total energy of all molecules in the collision remains constant D. the molecules involved in the collision are held to each other by strong intermolecular interactions

Answers

Answer:

Im pretty sure its B im very sorry if its wrong.

Water enter the horizontal, circular cross-sectional, sudden-contraction nozzle sketched below at section (1) with a uniformly distributed velocity of 30 ft/s and a pressure of 80 psi. The water exits from the nozzle into the atmosphere at section (2) where the uniformly distributed velocity is 100 ft/s. Determinethe axial component of the anchoring force required to hold the contraction in place.

Answers

This question is incomplete, the missing image is uploaded along this answer.

Answer:

the axial component of the anchoring force required to hold the contraction in place is 365.6 lb

   

Explanation:

Given the data in the question and as illustrated in the image below;

first we calculate the area at section 1

A₁ = (πD²)/4

we substitute

A₁ = (π(3 in)²)/4

A₁ = 7.06858 in²

we know that; 1 ft = 12 in

A₁ = ( 7.06858 / (12²) ) ft²

A₁ = ( 7.06858 / 144 ) ft²

A₁ = 0.0491 ft²

now, we write the elation for area at section 2

A₂ = πd²/4

here, d is the diameter at section 2

next, we use the conservation of mass equation between the two section;

m" = pV₁A₁ = pV₂A₂

we calculate the mass flow rate;

m" = pV₁A₁

= (1.94[tex]\frac{slug}{ft^2}[/tex]) × 30[tex]\frac{ft}{s}[/tex] × 0.0491 ft²

=  2.8576 slug/s

Now, Apply the linear momentum along the horizontal direction for the control volume between 1 - 2

-pV₁A₁V₁ = pV₂A₂V₂ = P₁A₁ - F[tex]_A[/tex] - P₂A₂

m"( V₂ - V₁ ) = P₁A₁ - F[tex]_A[/tex] - P₂A₂

F[tex]_A[/tex] = P₁A₁ - P₂A₂ - m"( V₂ - V₁ )

we substitute

F[tex]_A[/tex] = ((80×[tex]\frac{144 in^2}{1 ft^2}[/tex])×0.0491 ft²) - (0×(πd²/4)) - 2.8576( 100 - 30 )ft/s

F[tex]_A[/tex] =  565.632 - 0 - 200.032

F[tex]_A[/tex] = 565.632 - 200.032

F[tex]_A[/tex] = 365.6 lb

Therefore, the axial component of the anchoring force required to hold the contraction in place is 365.6 lb

A 50kg crate is being push on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk=0.1 . What is the push force?​

Answers

Answer:

  F = 49 N

Explanation:

For this exercise we must use Newton's second law. Let's set a reference frame with the x axis parallel to the floor.

As they indicate that the box is going at constant speed, its acceleration is zero

Y axis y

       N-W = 0

       N = mg

X axis

        F-fr = 0

        F = fr

the friction force has the formula

      fr = μ N

      fr = μ mg

we substitute

            F = μ m g

let's calculate

            F = 0.1 50 9.8

            F = 49 N

if mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion​

Answers

Answer:

See explanations below

Explanation:

According to Newtons second law of motion

F = mass * acceleration

F = ma

If mass of an object is decreased to half, then m₂ = 1/2 m

If acting force is reduced by quarter, then F₂ = 3/4 F

F₂ = m₂a₂

3/4F = 1/2m a₂

Divide both expressions

(3/4F)/F = (1/2m)a₂/ma

3/4 = 1/2a₂/a

3/4 = a₂/2a

4a₂ = 6a

2a₂ = 3a

a₂ = 3/2 a

Hence the acceleration of its motion will be one and a half of its original acceleration.

Write an equation to help Stacy find the gravitational force on an object if she knows the mass. In the equation, let W represent gravitational force, m represent mass, and g represent the ratio you found in part D. Test your equation using a set of values from the table to be sure it works.

Answers

Answer:

The last column of the table gives this relationship:

w/m = g

Rewrite the equation to solve for W: W = m × g.

For one washer, the table shows a mass of 0.6 kilograms, a force of 5.9 newtons, and an acceleration due to gravity of 9.8 N/kg. The equation works correctly for these values and for the other values in the table:

W = m × g = 0.6 kg × 9.8 N/kg    5.9 N.

Explanation:

This is the answer on Edmentum. :)

An object, accelerating from rest at a constant rate, travels over 28 m in 11 s. What is its final velocity?

1.81 m/s

3.20 m/s

5.09 m/s

0.00 m/s

none of the above

Answers

Answer:

answer is 3

Explanation:

by using s= [(v+ u)/2] x t

28= (v+ 0)/2 x 11

v= 5.09 ms^-1

What factors affect the speed of a wave? Check all that apply.
the amplitude of the wave
the energy of the wave
the temperature of the medium
the type of wave
the type of medium

Answers

Answer:

the amplitude of the wave

the energy of the wave

the type of wave

the type of medium

A students walks at a rate of 4 miles per hour to school. If she leaves her
house at 7:40am how long will it take her to travel 2 miles?

Answers

Answer:

30 minutes or 1/2 hour

she'll get there at 8:10am but that's not important

Explanation:

u can divide 4mph by two to find how long it would take her to travel 2 miles

she travels at 2 miles per 1/2 hour

hope this helps chu <3

3
How does the electrical conductivity of metals
and metalloids change with an increase in
temperature?​

Answers

Answer:

In metals there are free electrons at normal temperature so when we increase temperature it resistivity gets increases,so conductivity decreases,while in semiconductor the electrons are not free so when we increase the temperature the covalent bonds begin to break and the electron becomes free so conductivity get.

Explanation:

Why are Big cinema hall are carpeted and their walls are made of some rough matenals.​

Answers

Okay jsmsksmsms s. I amaks. Sis ammoammapaa
Max
Aka

In a test of an energy-absorbing bumper, a 2800-lb car is driven into a barrier at 5 mi/h. The duration of the impact is 0.4 seconds. When the car rebounds from the barrier [in the opposite direction], the magnitude of its velocity is 1.5 mi/h. Use the principle of impulse and momentum to determine the magnitude of the average horizontal force (lb) exerted on the car during the impact.

Answers

Answer:

F = 2074.13 lb

Explanation:

Given that,

Mass of car, m = 2800 lb = 1270.059 kg

Initial speed, u = 5 mi/h = 2.2352 m/s

Final speed, v = - 1.5 mi/h = -0.67056 m/s  (in opposite direction)

Time, t = 0.4 s

We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

[tex]F=m\times \dfrac{v-u}{t}\\\\F=1270.059\times \dfrac{-0.67056 -2.2352 }{0.4}\\\\F=9226.21\ N[/tex]

or

F = -2074.13 lb

So, the required force is 2074.13 lb.

A train with proper length L has clocks at the front and back. A photon is fired from the front to the back. Working in the train frame, we can easily say that if the photon leaves the front of the train when a clock there reads zero, then it arrives at the back when a clock there reads L/c. Now consider this setup in the ground frame, where the train travels by at speed v. Rederive the above frame-independent result (namely, if the photon leaves the front of the train when a clock there reads zero, then it arrives at the back when a clock there reads L/c) by working only in the ground frame.

Answers

Explanation:

In train's rest frame, the speed of photon is [tex]c[/tex] and the proper length of the train is [tex]L[/tex]. The time taken by the photon to cross the train is [tex]t=\frac{L}{c}[/tex]

In ground frame, the speed of the photon is given as follows:

[tex]v_{x}=\frac{v_{x}+v}{1+\frac{v_{x} \cdot v}{c^{2}}}[/tex]

[tex]=\frac{c+v}{1+\frac{c v}{c^{2}}} \\=c[/tex]

The speed of light or photon remains same in every frame of reference.

Now, the speed of train is very less as compared to the speed of photon so that [tex]v<c[/tex] So that, [tex]\frac{v}{c} \ll 1[/tex]

The length contraction in the ground frame is given as follows:

[tex]L^{\prime}=L \sqrt{1-\frac{v^{2}}{c^{2}}}[/tex]

[tex]=L[/tex]

Time taken by the photon to travel the length of the train in ground frame is .

When measuring espresso for a drink, which instrument would give the
greatest precision?

Answers

How many mL is an espresso?

One shot of espresso is generally about 30–50 ml (1–1.75 oz), and contains about 63 mg of caffeine (3). Important point: The “golden ratio” for espresso is this: a single shot is 30 to 44 mL (1 to 1.5 ounces) of water and 7 grams of coffee

Two Carnot heat engines are operating in series such that the heat sink of the first engine serves as the heat source of the second on. If the source temperature of the first engine is 1300 K and the sink temperature of the second engine is 300 K and the thermal efficiencies of both engines are the same, the temperature of the intermediate reservoir is

Answers

Answer:

the temperature of the intermediate reservoir is 624.5 K

Explanation:

Given the data in the question  

The two Carnot heat engines are operating in series;

[ T[tex]_H[/tex] ]

  ↓

((1)) ⇒ W[tex]_{out[/tex]

  ↓

[ T[tex]_M[/tex] ]

   ↓

 ((2)) ⇒ W[tex]_{out[/tex]

[ T[tex]_L[/tex] ]

The maximum possible efficiency for any heat engine is the Carnot efficiency;

η[tex]_{rev[/tex] = 1 - [tex]\frac{T_L}{T_H}[/tex]

the thermal efficiencies if both engines are the same will be;

η[tex]_A[/tex] = η[tex]_B[/tex]

1 -  [tex]\frac{T_M}{T_H}[/tex] = 1 - [tex]\frac{T_L}{T_M}[/tex]

1 - 1 -  [tex]\frac{T_M}{T_H}[/tex] = - [tex]\frac{T_L}{T_M}[/tex]

-  [tex]\frac{T_M}{T_H}[/tex] = - [tex]\frac{T_L}{T_M}[/tex]

[tex]\frac{T_M}{T_H}[/tex] =  [tex]\frac{T_L}{T_M}[/tex]

T[tex]_M[/tex]² = T[tex]_L[/tex] × T[tex]_H[/tex]

T[tex]_M[/tex] = √(T[tex]_L[/tex] × T[tex]_H[/tex])

source temperature of the first engine T[tex]_H[/tex] = 1300 K

sink temperature of the second engine T[tex]_L[/tex] = 300 K

we substitute

T[tex]_M[/tex] = √(300 × 1300)

T[tex]_M[/tex] = √390000

T[tex]_M[/tex] = 624.4998 K ≈ 624.5 K

Therefore, the temperature of the intermediate reservoir is 624.5 K

When we add or remove energy from a substance, what kind of changes can we observe? Can they happen at the same time ?

Answers

Answer:

When you add energy to a substance?

One change of state happens when you add energy to the substance. This change of state is called melting. By adding energy to the molecules in a solid the molecules begin to move quicker and can break away from the other molecules. The temperature at which a substance goes from a solid to a liquid is it melting point.

When you remove energy from a substance?

When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.

Explanation:

The addition of energy increases the kinetic energy of the particles, which reduces the intermolecular forces between the particles. Freezing occurs when a liquid becomes a solid and energy is released.

Atoms lose energy when they change from solid to liquid or gas and quid to gas.

3. Two bullets have masses of 0.003 kg and 0.006 kg, respectively. Both are fired with a speed of 40.0 m/s.
A. Which bullet has more kinetic energy?
B. When you double the mass, what happens to the kinetic energy?

Answers

Answer:

A. The bullet with 0.006kg has more energy

B. When the mass is doubled the kinetic energy increases

Explanation:

Kinetic energy increases when mass increases

kinetic energy increases when velocity increases

What type of fault is shown in the image below?


In this fault, the hanging wall and footwall are side by side and moving in opposite directions.


Public Domain


Lateral fault

Normal fault

Reverse fault

Thrust fault

Answers

Answer:

this is a lateral fault

Explanation:

At the base of a hill, a 90 kg cart drives at 13 m/s toward it then lifts off the accelerator pedal). If the cart just barely makes it to the top of this hill and stops, how high must the hill be?

Answers

Answer:

8.45 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 90 Kg

Initial velocity (u) = 13 m/s

Final velocity (v) = 0 m/s

Height (h) =?

NOTE: Acceleration due to gravity (g) = 10 m/s²

The height of the hill can be obtained as follow:

v² = u² – 2gh (since the cart is going against gravity)

0² = 13² – (2 × 10 × h)

0 = 169 – 20h

Rearrange

20h = 169

Divide both side by 20

h = 169/20

h = 8.45 m

Therefore, the height of the hill is 8.45 m

Select four of the following that would increase the magnetic field of an electromagnet

Answers

Answer:

The correct answers are: A, C, D, E

Explanation:

The magnetic field is a solenoid is given by

         B = μ₀  [tex]\frac{N}{L}[/tex]   I

where N is the number of turns, I the current and L length of the solenoid.

Using this equation let's examine the different responses to permute increasing the magnetic field

A) True. a thicker wire decreases the resistance and the current can increase the system.

B) False. If there is no voltage source there is no current in the system

C) True. the field is proportional to the number of turns

D) True. the magnetic moments of the core align with the field increasing its value

E) True. When the loops are closer together, more of them can fit per unit length

F) False. If the wire is shorter the number of turns decreases.

The correct answers are: A, C, D, E

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.145 kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 14.5 m/s , shatters the glass as it passes through, and leaves the window at 10.9 m/s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball

Answers

Answer:

J = -0.522 m/s

Explanation:

Given that,

The mass of the baseball, m = 0.145 kg

Initial velocity, u = 14.5 m/s

Final velocity, v = 10.9 m/s

aWe need to find the direction of the impulse that the glass imparts to the baseball. Impulse is equal to the change in momentum such that,

[tex]J=m(v-u)[/tex]

Substitute all the values,

[tex]J=0.145\times (10.9-14.5)\\\\=-0.522\ kg-m/s[/tex]

The direction of impulse is opposite to the direction of velocity.

16–2. Just after the fan is turned on, the motor gives the
blade an angular acceleration a = (202-0.6) rad/s'. where :
is in seconds. Determine the speed of the tip P of one of the
blades when i 3 s. How many revolutions has the blade
turned in 3 s? When / O the blade is at rest.​

Answers

Answer:

P.S My answer may not render so let me know if it doesn't

Explanation:

A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at the elbow. During this punch, the horizontal flexor muscles of the shoulder contract and shorten at an average speed of 75 cm/s. They move through an arc length of 5 cm during the hook, while the fist moves through an arc length of 100 cm. What is the average speed of the fist during the hook

Answers

Answer:

average speed of the fist during the hook = 15 m/s or 1500 cm/s

Explanation:

We are given;

Speed of shoulder contraction, v_s = 75 cm/s = 0.75 m/s

Distance moved through the arc length by shoulder, d_s = 5 cm = 0.05 m

Distance moved by the fist, d_f = 100 cm = 1 m

Now, we are to find the average speed of the fist during the hook; v_f

Thus can be gotten from proportion;.

d_f/d_s = v_f/ v_s

Making V_f the subject, we have;

v_f = (d_f × v_s)/d_s

Thus;

v_f = (1 × 0.75)/0.05

v_f = 0.75/0.05

v_f = 15 m/s

How can Newton’s laws of motion and the law of gravitation predict the motion of an object, and how can frames of reference be used to describe that motion?

Answers

An inertial frame is defined as one in which Newton's law of ... The “laws of physics” we shall consider first are those of ... to predict future planetary motions with great accuracy.


1. Define force and give its Sl unit​

Answers

Answer:

Force is an external agency that changes or tends to change the state of body from rest to motion or motion to rest.

The SI unit of force is newton(N)

A camper hears her echo off a
hillside 1.52 s after yelling. How
far is she from the hill?

Answers

Answer:

261

Explanation:

Acellus

if the water measures -5 feet at low tide and 3ft at high tide what is the tidal range ​

Answers

Answer:

8 feet

................

Calculate the momentum of a 10 kg bowling ball rolling at 2m/s towards north.

Answers

Answer:

momentum=mass x velocity= 10 x 2 = 20kgm/s

A strong electromagnet produces a uniform magnetic field of 1.60 T and a cross-sectional area of 0.200 m2. If we place a coil having 240 turns and a total resistance of 21.0 around the electromagnet and then we then smoothly reduced the current in the electromagnet until it reaches zero in 20.0 ms, what is the current induced in the coil

Answers

Answer:

the magnitude of the induced current is 182.86 A.

Explanation:

Given;

number of turns, N = 240 turns

cross sectional area of the loop, A = 0.2 m²

uniform magnetic field strength, B = 1.6 T

resistance of the loop, R = 21 ohms

time, Δt = 20.0 ms

The magnitude of the induced emf is calculated as;

[tex]emf = \frac{NA B}{t} \\\\emf = \frac{240 \times 0.2 \times 1.6}{20 \times 10^{-3}} \\\\emf = 3,840\ V[/tex]

The induced current in the loop is calculated as;

[tex]I = \frac{emf}{R} \\\\I = \frac{3840}{21} \\\\I= 182.86 \ A[/tex]

Therefore, the magnitude of the induced current is 182.86 A.

Which of the following is true for the entropy of the universe?
A It is always decreasing.
B It is always increasing.
C It is always negative.
D It is always a constant.

Answers

Answer:

B It is always increasing.

Explanation:

In Physics, entropy can be defined as the tendency or ability of a substance to reach maximum disorder i.e to be randomly distributed.

This ultimately implies that, entropy is a thermodynamic quantity that measures the degree of maximum disorder or randomness of a system.

The S.I unit used for the measurement of the degree of maximum order or randomness of a system is Joules per Kelvin (JK¯¹). An example of entropy is the mixing of ideal gases.

Generally, the entropy in an irreversible process always increases and as such the change in entropy has a positive value.

Hence, the entropy of the universe is always increasing because its energy flow is considered to be in a downward direction rather than upward i.e from a hot region to a cold region; making the energy to be evenly distributed.

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