Answer:
sodium and magnesium
Explanation:
A change resulting in one or more new substances being formed is a?
A. nuclear reaction
B.physical property
C. chemical change
D.physical change
Answer:
C. Chemical change
Explanation:
A physical change is where something is changed but it doesnt affect the build up of the chemical. For example, if you broke sticks and threw them on the ground, that would be a physical change because the change is happening to the physical being of the object and not its chemical buildup. However, if you lit those sticks on fire, that would be considered a chemical change because you end up with two substances, ash and the remnants of the stick. A nuclear reaction would result in something blowing up so its not that. And a physical property is like what it looks like or how it smells. Hope I helped you!
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What is the percent composition of hydrogen in glucose
Answer:
67%Explanation:
Thus the % composition of glucose by mass is carbon 40.0 % oxygen 53.3 % hydrogen 6.7 % in this way, the % composition by mass of any compound can be calculated provided that is formed is known.Mg(s) + Cu(NO3)2(aq) → Mg(NO3)2(aq) + Cu(s)
How will the rate of the chemical reaction change if the solid piece of magnesium metal is ground into a powder?
Select one:
a. Increase
b. Cannot be predicted
c. Will not change
d. Decrease
Answer: increase
Explanation: when Mg is powder it has greater surface area and
Reaction occurs faster
How many moles is 2.04x1023 molecules of NH3?
Answer:
We will Multiply the number of moles with Avagadro's number
So it will be (2.04×1023)×6.022×10^23
or 2.04×1023 NANA means Avagadro's number
Best answer gets brainliest
Answer:
C) Mercury based thermometer
Explanation:
Answer:
Mercury based thermometer
Explanation:
When you touch a lightbulb it is warm. Hairdryer produces heat to dry your hair. Stove heats up to warm food and liquids up.
Is water an element or compound
Answer:
Compound
Explanation:
H2O is made up of multiple types of atoms, which makes it a compound. It isn't an element because they only consist of one type of atom.
When optically active (S)-2-methylcyclopentanone is treated with an acid (H3O ), the compound loses its optical activity. Explain this observation and draw a mechanism that shows how racemization occurs. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.
Answer:
See explanation
Explanation:
When (S)-2-methylcyclopentanone is treated with an acid, the carbonyl oxygen atom is protonated.
This leads to the emergence of a positive charge on the cabonyl oxygen. Then the C=O bond is now transformed into H-C-OH where C is a carbocation which leads to a racemic mixture. Loss of a proton from the adjacent carbon atom completes the mechanism.
In this process, the optically active (S)-2-methylcyclopentanone is converted to a pair of diastereomers thereby loosing its optical activity.
Which of these processes removes carbondioxide from the air?
Answer:
It’s Photosynthesis
Explanation:
Don’t click the file it’s a virus ! Also I hope I helped!
Someone drops a book on the floor and it makes a loud noise. At the time you turn and look at the person who dropped the book .
In the scenario above turning and looking at the person who dropped the book is an example of a :
Answer: curiosity?
Explanation:
How many moles of LiOH are in a 4.5 M solution containing 1.5 L of water?
Answer:
d
Explanation:
What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The density of water is 1.00 g/mL)
Answer:
13.5 %
Explanation:
First we calculate the mass of 500 mL of water, using its density:
Volume * Density = Mass500 mL * 1.00 g/mL = 500 gThen we calculate the mass percent of potassium sulfate, using the formula:
Mass of Potassium Sulfate / Total Mass * 100%
78 g / (78 + 500) g * 100 % = 13.5 %The heat of combustion of ethane is -337.0kcal at 25 degrees celsius. what is the heat of the reaction when 3g of ethane is burnt completely
Answer:
Q = -33.6kcal .
Explanation:
Hello there!
In this case, according to the equation for the calculation of the total heat of reaction when a fixed mass of a fuel like ethane is burnt, we can write:
[tex]Q=n*\Delta _cH[/tex]
Whereas n stands for the moles and the other term for the enthalpy of combustion. Thus, for the required total heat of reaction, we first compute the moles of ethane in 3 g as shown below:
[tex]n=3g*\frac{1mol}{30.08g}=0.1mol[/tex]
Next, we understand that -337.0kcal is the heat released by the combustion of 1 mole of ethane, therefore, to compute Q, we proceed as follows:
[tex]Q=0.1mol*-337.0\frac{kcal}{mol}\\\\Q=-33.6kcal[/tex]
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Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. what is the balanced equation?
PLEASE HELP 30 POINTS PLS PLS
A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,
zinc nitrate and the precipitate gold.
Explanation:
Gold (AU)................
8. Zeolite is used to remove moisture from methane. A vertical column is filled with 1000.0 kg of dry zeolite. The zeolite has the capacity to hold 0.100 kg water/kg dry zeolite. Once the zeolite becomes saturated with moisture, it must be regenerated by heating. The inlet moisture content of the methane is 7.00% (by mass) and the outlet moisture content is 0.05% (by mass). How much methane (kg) will be produced before the zeolite must be regenerated
Answer:
Follows are the solution to this question:
Explanation:
Methane inlet humidity content of [tex]=7.00\%[/tex]
Methane moisture outlet content [tex]=0.05\%[/tex]
Zeolite absorption humidity [tex]= 6.95\%[/tex]
Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]
One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]
The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]
Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]
That's why it will be producing 1439 kg of methane.
The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.
What is zeolite?
Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.
In the question, it is given that:
Capacity of 1kg of zeolite to hold water = 0.100kg
Capacity of 1000kg of zeolite to hold water = 100kg
Inlet moisture content of the methane = 7.00 % (by mass)
Outlet moisture content of the methane = 0.05% (by mass)
Capacity of zeolite to absorb methane content = 6.95 %
Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg
Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.
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How many moles is equal 82.4 grams of CO,?
Answer:
1 mole = 28.0101
Hence,
82.4 = around 2.8 mole
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What is measured by the heat of reaction?
Answer:
The heat of reaction is basically the energy that is being released and or absorbed when chemicals are transformed in a type of chemical reaction. However, the heat of reaction or also called reaction enthalpy is mostly or typically expressed as a molar enthalpy in kJ/mol and or as just a specific enthalpy in kJ/kg or kJ/L.
Which of the following statements is correct?
A. 2 moles of O2 is equal to 64 g of O2.
B. 2 moles of O2 is equal to 32 g of O2.
C. 2 moles of O2 is equal to 2 g of O2.
D. 1 moles of O2 is equal to 2 g of O2.
Answer:
pretty sure its B but if not I'm sorry
2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct. It can be solved by mole concept
What is Mole concept ?
The mole, symbol mol, is the SI base unit of amount of substance.
The quantity amount of substance is a measure of how many elementary entities of a given substance are in an object or sample.
formula ;
n = given weight / molecular weight
= 64 / 32
= 2 moles
Therefore, 2 moles of O₂ is equal to 64 g of O₂ is the only correct statement among the given statements. Hence, Option (A) is correct.
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Rank the following compounds in order of decreasing acidity. Be sure to answer all parts. A) Benzyl alcohol B) Methylbenzene C) Benzoic acid
The order of decreasing the acidity of the given compounds:
Benzoic acid > Benzyl alcohol > Methylbenzene.
What is the acidic strength?The acidic strength of an acid can be described as the ability of the acid to lose its H⁺ ion. In general, the dissociation of acid can be represented as:
HA → H⁺ + A⁻
Some examples of strong acids are hydrochloric acid, sulfuric acid (H2SO₄), perchloric acid (HClO₄), etc.
The benzoic acid is a very strong acid with pka value of 4.5 as it contains the (-COOH) group. The Benzyl alcohol with pka value of 15.4 as it contains the (-CH₂OH) group attached to the benzene ring. The methylbenzene with pka value of 41 has the lowest acidity as it contains the methyl group attached to the benzene ring.
Therefore, the order of acidic strength for the given compounds is Benzoic acid > Benzyl alcohol > Methylbenzene.
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How many moles of NaHCO3 are in 2.4 x
1024 molecules of NaHCO:?
4.0 moles NaHCO
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 2.4 × 10²⁴ molecules NaHCO
[Solve] moles NaHCO
Step 2: Identify Conversion
Avogadro's Number
Step 3: Convert
[DA] Set up: [tex]\displaystyle 2.4 \cdot 10^{24} \ molecules \ NaHCO(\frac{1 \ mol \ NaHCO}{6.022 \cdot 10^{23} \ molecules \ NaHCO})[/tex][DA] Divide [Cancel out units]: [tex]\displaystyle 3.98539 \ moles \ NaHCO[/tex]Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
3.98539 moles NaHCO ≈ 4.0 moles NaHCO
The mass ratio of H to O in water (H2O) is 1:8. What is the mass
ratio of H to O in hydrogen peroxide (H2O2)?
Answer: 1:16
Explanation:
An iron sulfide compound is analyzed, and found to contain 11.26 g iron and 9.70 g sulfur. Determine the molar ratio of sulfur to iron in this compound, and hence its chemical formula.
Answer:
Molar ratio = 1.5Chemical formula = Fe₂S₃Explanation:
First we convert the given masses of each element into moles, using their respective molar masses:
Fe ⇒ 11.26 g ÷ 55.845 g/mol = 0.202 mol FeS ⇒ 9.70 g ÷ 32.065 g/mol = 0.302 mol SNow we divide them in order to calculate the molar ratio of S to Fe:
0.302 / 0.202 = 1.5Meaning that for each 1 Fe mol, there's 1.5 S moles. We can write that as Fe₁S₁.₅
Finally we double those subscripts so that they become the lowest possible integers: Fe₂S₃.
Assuming the partial pressure of oxygen in air (0.20 atm) and nitrogen in air (0.80 atm). Calculate the mole fractions of oxygen and nitrogen in water at 298 K. FOR THIS QUESTION report the mole fraction of OXYGEN
Answer:
oxygen = 4.7 * 10^-6
Nitrogen = = 9.7 * 10^6
Explanation:
partial pressure of oxygen = 0.20 atm
partial pressure of Nitrogen = 0.80 atm
calculate the mole fractions of oxygen and Nitrogen in water
Temp = 298k
applying henry's law
molar conc of oxygen in water ( Coxygen )
= Kp = 1.3 * 10^-3 Mol/L.atm * 0.20 atm = 2.6 * 10^-4 Mol
molar conc of Nitrogen in water ( Cnitrogen )
= Kp = 6.8 * 10^-4 Mol/L.atm * 0.80 atm = 5.4 * 10^-4
next Given that the number of moles in 1 liter of water = 55.5 mol
therefore the mole fraction of oxygen
= 2.6 * 10^-4 / 55.5
= 4.7 * 10^-6
mole fraction of Nitrogen
= 5.4 * 10^-4 / 55.5
= 9.7 * 10^6
calculate the percentage mass of calcium chloride, CaCi^2
Answer: m-%(Ca) = 40.08 / 110.98
Explanation: molar mass of CaCl2 is 40.08+ 2·35.45 = 110.98
Think you have one mole substance. It contains 40.08 g Ca
How many grams are in 1.2 x 10^24 atoms of sodium?
PLEASE PLEAS HELP I REALLY NEED IT
Answer:
A i took the quiz
Explanation:
The half-life of 226Ra is 1.60x103 years. How long until only 12.5% of the original sample of 226Ra remains?
Answer:
4.80×10³ years
Explanation:
Let the original amount (N₀) of ²²⁶Rn = 1 g
Therefore,
12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g
Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:
Original amount (N₀) = 1
Amount remaining (N) = 0.125 g
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
0.125 = 1/2ⁿ × 1
0.125 = 1/2ⁿ
Cross multiply
0.125 × 2ⁿ = 1
Divide both side by 0.125
2ⁿ = 1/0.125
2ⁿ = 8
Express 8 in index form with 2 as the base
2ⁿ = 2³
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.
This can be obtained as follow:
Half-life (t½) = 1.60×10³ years
Number of half-lives (n) = 3
Time (t) =?
t = n × t½
t = 3 × 1.60×10³
t = 4.80×10³ years.
Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.
Match the box basically lol