The speed of blood in an arteriole is approximately 0.0019 cm/s.
The blood speed in the capillaries is approximately 0.000053 cm/s.
To find the speed of blood in an arteriole, we can use the equation:
Speed = Flow rate / Cross-sectional area
Given:
Diameter of arteriole = 0.080 mm = 0.008 cm (converting mm to cm)
Flow rate = 9.6 ×[tex]10^(^-^5[/tex] ) [tex]cm^3/s[/tex]
The cross-sectional area of an arteriole can be calculated using the formula for the area of a circle:
Area = π * [tex](radius)^2[/tex]
Since the diameter is given, we can find the radius:
Radius = diameter / 2 = 0.008 cm / 2 = 0.004 cm
Now, we can calculate the cross-sectional area:
Area = π * (0.004 [tex]cm)^2[/tex] ≈ 0.00005027 [tex]cm^2[/tex]
Finally, we can find the speed:
Speed = 9.6 × [tex]10^(-5)[/tex] [tex]cm^3/s[/tex]/ 0.00005027 [tex]cm^2[/tex] ≈ 0.0019 cm/s (rounded to 2 significant figures)
Given:
Number of capillaries = 8800
Diameter of capillary = 6.0 × [tex]10^(^-^6^)[/tex] m = 0.000006 m (converting mm to m)
To calculate the speed of blood in the capillaries, we need to consider the total cross-sectional area of all the capillaries combined. The total area can be calculated by multiplying the area of one capillary by the number of capillaries:
Total Area = Number of capillaries * π * (radius of capillary[tex])^2[/tex]
The radius of the capillary can be found by dividing the diameter by 2:
Radius = 0.000006 m / 2 = 0.000003 m
Now, we can calculate the total cross-sectional area:
Total Area = 8800 * π * (0.000003 [tex]m)^2[/tex] ≈ 0.018 sq. m
To find the blood speed in the capillaries, we need to convert the flow rate from[tex]cm^{3/s[/tex] to[tex]m^3/s[/tex] :
Flow rate = 9.6 ×[tex]10^(^-^5^)[/tex] [tex]cm^3/s[/tex] = 9.6 × [tex]10^(^-^8^)[/tex] [tex]m^3/s[/tex]
Finally, we can find the speed:
Speed = 9.6 × [tex]10^{(-8)[/tex] [tex]m^{3/s[/tex] / 0.018 sq. m ≈ 5.33 × [tex]10^{(-6)[/tex] m/s ≈ 0.000053 cm/s (rounded to 2 significant figures)
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1) The speed of the blood in the arteriole is approximately 1.2 cm/s.
Determine the speed of the blood?To calculate the speed of the blood in an arteriole, we can use the equation:
Speed = Flow Rate / Cross-sectional Area
Given the flow rate of 9.6 × 10⁻⁵ cm³/s and the diameter of the arteriole as 0.080 mm (or 0.008 cm), we can calculate the cross-sectional area:
Cross-sectional Area = π × (diameter/2)²
Plugging in the values, we have:
Cross-sectional Area = π × (0.008 cm/2)² = 3.14 × (0.004 cm)² ≈ 0.00005024 cm²
Now we can calculate the speed:
Speed = (9.6 × 10⁻⁵ cm³/s) / 0.00005024 cm² ≈ 1.2 cm/s
Therefore, the speed of the blood in the arteriole is approximately 1.2 cm/s.
2) The blood speed in the capillaries is approximately 0.004 cm/s.
Determine the blood speed in the capillaries?To find the blood speed in the capillaries, we need to consider the relationship between the flow rate and cross-sectional area. Since the arteriole branches into 8800 capillaries, the total cross-sectional area of the capillaries will be 8800 times larger than that of the arteriole.
Cross-sectional Area of Capillaries = 8800 × Cross-sectional Area of Arteriole
Using the previously calculated cross-sectional area of the arteriole (0.00005024 cm²), we can find the cross-sectional area of the capillaries:
Cross-sectional Area of Capillaries = 8800 × 0.00005024 cm² = 0.44192 cm²
Now we can calculate the blood speed in the capillaries using the same equation:
Speed = Flow Rate / Cross-sectional Area
Given that the flow rate remains the same (9.6 × 10⁻⁵ cm³/s), we have:
Speed = (9.6 × 10⁻⁵ cm³/s) / 0.44192 cm² ≈ 0.004 cm/s
Therefore, the blood speed in the capillaries is approximately 0.004 cm/s.
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Identify the phase and division I or II for the following:
Metaphase II
Metaphase I
Telophase II
Cytokinesis
Answer:
Metaphase II
Explanation:
Metaphase II is the division of two daughter cells and is when sister chromatids line up in the middle of the cell. This is what appears to be happening in the image. Additionally, you can see that the chromosomes have already crossed over.
Metaphase I only involves 1 cell, not 2 daughter cells.
Telophase II and Cytokinesis are when the cell splits. Also, Telophase II would result in 4 daughter cells, not just 2.
if the charge of the force is doubled would the force double
Answer: The electrostatic force between two point charge particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. So, if you double the individual charges while keeping the same distance, the net electrostatic force will be four times the previous value.
Explanation:
Since, we know
F = (k×q1×q2)/r²
When the charges are doubled, we have :
F' = (k × 2q1 × 2q2)/r²
F' = 4 (k×q1×q2)/r²
Thus,
F' = 4F
Hence, the force becomes 4 times its initial value.
b) Include this table on your slide:
Mass of Object 1 Mass of Object 2 (kg)
(kg)
Gravitational Force
(N)
1 x 1020
1 x 1020
1 x 1040 G
3 x 1020
1 x 1020
3 x 100 G
2 x 1020
2 x 1020
4 x 10"G
20
3 x 1020
4 x 10
12 x 10 G
c) Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force
between them. Be sure to:
Describe the scenario.
Explain the table headings to introduce the data in the table.
Use the data to show a trend.
Summarize the information from the table in a sentence, showing the relationship between
the masses of objects and the gravitational force between the objects.
d) Place text in the notes section below the slide explaining the information presented on it. This text
will act as the script for your presentation.
e) Remember to save your work.
Answer:
hryrbrhrururjrn djbrr he dvhd the ry rhr
urur
Explanation:
jrurhr dye dhrb the yd rhd due sh dgd eye rh
Answer:
I dont know i was looking for the same answer for my project
Explanation:
Explain in detail how clouds form.
Answer:
Clouds are formed when moist air rises upward . As the air rises , it becomes colder. Eventually the air can't hold all of the water vapour in it, and some of water vapour condenses to form tiny water droplets... Clouds form at wide range of altitudes , from near the ground to very high in the atmosphere.
What is linear expansivity?will receive brainliest if answered correctly
Answer:
Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature. If a specimen increases in length from l1 to l2 when its temperature is raised θ°, then the expansivity (α) is given by: l2 = l1(1 + αθ). This relationship assumes that α is independent of temperature. This is not, in general, the case and a more accurate relationship is: l2 = l1(1 + aθ + bθ2 + cθ3…), where a, b, and c are constants.
l2 = l1(1 + αθ).
l2 = l1(1 + aθ + bθ2 + cθ3…),
Answer:
Linear expansivity is the fractional increase in length of a specimen of a solid, per unit rise in temperature. ... Superficial expansivity is the fractional increase in area of a solid surface caused by unit rise in temperature, i.e. A2 = A1(1 + βθ), where β is the superficial expansivity.
I hope it's helpful!
A car drives 40 km due east and then 50 km due west .what is the cars overall displacement?
Answer:10 km westExplanation:he go 40 east then 50 west 50-40 is 10 so he displaces 10 km and as west is more than east in terms of km so we will say that it's 10 km west pls mark as brainliest thanks
The car's overall displacement if, A car drives 40 km due east and then 50 km due west is 10 km in the west.
What is displacement?Displacement is defined as the overall alteration of an object's location and motion direction. Displacement is recognized as a vector quantity since it takes into account both the direction of the motion and the magnitude of the changing position. Displacement may be zero, positive, or negative.
Given:
A car drives 40 km due east and then 50 km due west,
Consider the west direction as positive and the east direction as negative, then,
The displacement = Displacement in the west + displacement in the east,
The displacement = 50 - 40
The displacement = 10
As the sign is positive, then the direction would be west.
Thus, the displacement of the car is +10 km.
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The model shows eight positions of the moon around Earth during the
lunar cycle.
In which positions would a first
quarter moon and last quarter moon
appear to an observer on Earth?
Lunar Cycle
1
Sunlight
First quarter: position 1
Last quarter: position 5
N
8
B
First quarter: position 2
Last quarter: position 6
First quarter: position 3
Last quarter: position 7
اليا
3
CM
Answer: 1-5 so A
Explanation:
if u just look at a diagram of like the moons it says that
The moon changes shape every day the changes in their shape are defined as the moon phase. In positions 1 and 5 first-quarter moon and last quarter moon appear to an observer on Earth.
What is the moon phase?The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.
Only the side of the moon facing the sun can reflect this light and seem bright. On the opposite side appears black is a full moon.
We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.
The moon changes shape every day the changes in their shape are defined as the moon phase.
In general, we may estimate the third by knowing any two of the following three things
(1) the moon's position in the sky
(2) the moon phase
(3) the time
Hence in positions 1 and 5 first-quarter moon and last quarter moon appear to an observer on Earth.
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A student swings a 5.0 Kg pail of water in a vertical circle of radius 1.3m. What is the minimum speed at the top of the circle if the water is not to spill from pail.
Answer:
v = 3.57 m / s
Explanation:
Let's use Newton's second law in the upper part of the circle, with the minimum speed so that the water does not rest on the circle, that is, the normal is zero
W = m a
acceleration is centripetal
a = v² / r
let's substitute
mg = m v² / r
v = [tex]\sqrt{r g }[/tex]
let's calculate
v = [tex]\sqrt{1.3 \ 9.8}[/tex]ra 1.3 9.8
v = 3.57 m / s
Round off to the nearest one (units place):
(a) 57.326 57.000
(b) 8.808
(c) 290.752
(d) 1394.301
(e) 434.28
Answer:
a
Explanation:
Answer:
(a) 57
(b) 9
(c) 291
(d) 1394
(e) 434
What does attributed mean
Answer:
attribute is defined as a quality or characteristic of a person, place, or thing
Explanation:
Answer:
regard something as being caused by (someone or something).
Explanation:
Online dictionary
Why do we have two colors of arrows on the map?
Answer:
To differentiate the two concepts each colour represents (perhaps)
Explanation:
Where is the map?
Answer:
such as green representing forested land and blue representing waterways.
please say something i dk which one
emergency plsss is copper stronger than bricks or that's all the way the opposite pls write ur answer clearly n' I will give 15 points and mark brainliest who answers first so hurry up
Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for each resistor
Answer:
[tex]R=5.2\ \Omega[/tex]
Explanation:
In series combination, the equivalent resistance is given by :
[tex]R_{eq}=R_1+R_2+R_3+...[/tex]
Let the identical resistors be R. We have, [tex]R_{eq}=15.6\ \Omega[/tex]
So,
[tex]R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega[/tex]
So, the resistance of each resistor is [tex]5.2\ \Omega[/tex].
Which element has the same number of valence electrons as rubidium.
A. lithium
B. argon
C. calcium
D.iron
A rubber stopper, which has a mass of m = 14.5 grams, is tied to the end of a string which is threaded through a glass tube. You then spin the rubber stopper about your head in a horizontal circle as shown to the right. The stopper sags = 18.0o below the horizontal as shown and the distance from the top of the tube to the stopper is L = 1.25 m.
b. What will be the magnitude of the centripetal force acting on the stopper?
c. What is the speed of the stopper?
d. What is the tension in the string?
e. How much Mass M is hanging on the end of the string?
Answer:
T cos18=mv^2/1.25cos18
T sin18=mg
solve for T
centripetal force-=Tcos18
A vehicle of mass 3200kg moving with a velocity of 10m/s increases it's velocity to 20m/s in 5 sec. calculate the magnitude of the force exerted on the engine
Answer:
xitxutdtidtiittieitetdtdt
Answer:
Please find the attached file
Explanation:
ordinary kriging method assume that
ears
Explanation:
I want to eat your ears
Un automóvil viajó 186.4 Km a una velocidad constante de 57 Km/h. ¿Cuánto tiempo se necesitó para el viaje?
Answer:
t = 1.177 10⁴ s
Explanation:
For this exercise we use the uniform motion relationships
v = x / t
t = x / v
let's reduce the magnitudes to the SI system
v = 57 km / h (1000m / 1km) (1h / 3600s) = 15.833 m / s
x = 186.4 km (1000m / 1 km) = 186.4 10³ m
let's calculate
t = 186.4 10³ / 15.833
t = 11.77 10³ s
t = 1.177 10⁴ s
An 18kg block moving at 6 m/s has kinetic energy of
½ × 18 × 6² = 324 J
hope that helps^^
4.) The diagram to the right is the orbit of a comet:
A) Label the two focal points
B) Label the Perihelion
C) Label the Aphelion
Answer: This is what I found hope it helps
Explanation:
Which option correctly matches the chemical formula of a compound with its name?
Answer:
d
Explanation:
the correct chemical formula of a compound with its name is NO₂, Nitrogen Dioxide, the correct option is D.
What is a Chemical compound?The chemical compound is a combination of two or more either similar or dissimilar chemical elements
for example, H₂O is a chemical compound made up of two oxygen atoms and a single hydrogen atom
The correct chemical formula for nitrogen Dioxide is NO₂
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20.Two balls are in motion. A 2-kg ball moving at 4m/s and a 4-kg ball moving at 2m/s, which one has greater kinetic energy? a. 2 kg ball moving at 4 m/s c. Both balls have the same KE b. 4 kg ball moving at 2 m/s d. Cannot be determined
Answer:
A
Explanation:
Given that two balls are in motion. A 2-kg ball moving at 4m/s and a 4-kg ball moving at 2m/s, which one has greater kinetic energy? a. 2 kg ball moving at 4 m/s c. Both balls have the same KE b. 4 kg ball moving at 2 m/s d. Cannot be determined
The formula for kinetic energy is :
K.E = 1/2mv^2
A 2-kg ball moving at 4m/s will have kinetic energy of 1/2 × 2 × 4^2
K.E = 16J
and a 4-kg ball moving at 2m/s will have kinetic energy of 1/2 × 4 × 2^2
K.E = 2 × 4
K.E = 8J
which one has greater kinetic energy? Definitely it is a 2 kg ball moving at 4 m/s. Since 16J is greater than 8J. The correct answer is A.
The energy which we obtained from the moving particle is called kinetic energy. According to the conservation of energy, the energy can neither be created nor be destroyed.
Hence, the formula used in the question is:- [tex]K.E =\frac{1}{2} mv^{2}[/tex] .
A 2-kg ball moving at 4m/s will have kinetic energy that is [tex]K.E =\frac{1}{2} 2*4^{2} = 16J[/tex]Therefore, the kinetic energy of the ball moving the 2kg is 16J.
A 4-kg ball moving at 2m/s will have kinetic energy that is [tex]K.E =\frac{1}{2} 4*2^{2} = 8J[/tex]
Hence the Kinetic energy of the ball moving the 4 kg is 8J.
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An object completes 2500 cycles in
26s. The radius of motion is 3.5m.
Answer:
That statement is correct.
Explanation:
An object that completes 2500 cycles in 26 seconds has a radius of motion of 3.5.
Will the gravitational force between 2 objects increase or decrease if the distance between them decreases.
Answer:
increase
Explanation:
The formula for the gravitation for of attraction is:
[tex]F = \dfrac{Gm_1m_2}{r^2}[/tex]
It implies that the force of attraction is inversely proportional to the square of the distance. i.e.
[tex]F \infty \dfrac{1}{r^2}[/tex]
where;
G = gravitational constant
m = mass; &
r = distance between the two objects.
Now let's assume that the distance between is reduced from 1 to half;
Then:
[tex]F \infty \dfrac{1}{\Big (\dfrac{r}{2} \Big)^2}[/tex]
[tex]F \infty \dfrac{4}{r^2}[/tex]
Thus, the new gravitational force of attraction increased by a factor of 4.
A 615 watt refrigerator runs 24 hours/day. How much energy is used per month (30 days)?
Answer:
14.76
Explanation:
If you put it in the calculator it would show
A crate is sliding on the floor. If there is a total force acting on the crate in the same direction as it is sliding, the crate would
A) slow down
B) speed up
C) remains the same speed
D) slow down, change direction and then speed up going the other way,
E) remains the same speed but changes direction
But we do not know whether the force is pushing or pulling (the same direction (both forces are parallel) but: .........[ ]<-F-- or .......[ ]--F-->). I suppose the correct answer is B
A 98N weight is lifted to a height of 4m. What is its potential energy at this position?
Answer:
i need points
Explanation:
Which model would best demonstrate the role of gravity in the Solar System? O A. a large ball with 8 smaller balls arranged around it because gravity is between the sun and 8 planets O B. a magnet drawn close to another magnet because planets are dbvn towards the magnetism of the Sun O c. a football field with a pea at one end and a grain of sand at the other because the scale of gravity is large O D. a ball attached to a string moving in a circular motion because the string keeps the ball in place like gravity
Anyone knows this ???
Answer:
JUST A MINUTE KAPENG MAINIT