Answer:
Slinky is the correct answer.
4) What process produces carbon dioxide?
a) photosynthesis
b) replication
c) mutation
d) respiration
5) What happens during cytokinesis?
a) a spindle forms
b) chloroplasts release energy
c) the cytoplasm divides
d) chromosomes
plz answer asap
Answer:
d and c are the answers :)
calculate the resultant force acting on the object and state its direction
[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]
Direction is east.You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N.
Part A
How much work does the rope do on the wagon if you pull the wagon 200 m at a constant speed?
Answer:
2000 J
Hope you could get an idea from here.
Doubt clarification - use comment section.
S O L U T I O N:
Here we've been provided with the information i.e
Force (F) = 20N Distance (s) = 200m Angle (θ) = 60°Ans we have given to find out what is work done (W) = ?
The standard formula to calculate work done is given by,
[tex]:\implies\sf{w = f \times s \times cos \theta}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times cos60}[/tex]
[tex]:\implies\sf{w = 20 \times 200 \times \frac{1}{2} }[/tex]
[tex]:\implies\sf{w = 20 \times 100 \times 1}[/tex]
[tex]:\implies\sf{w = 2000J}[/tex]
Total work done done by rope is 2000J.a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dealership offer?
The number of variations the dealership have is 40 cars.
Data given;
The number of different product = 4The number of transmission = 2 (standard or automatic)The numbers of colors available = 5Dealership variationThis is the total numbers of cars available in the dealer shop at the moment.
To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.
This is equal to
[tex]4*2*5=40[/tex]
From the above calculation, we can say that the variations the dealership offers is 40
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“Applications of thermal expansion in solids, liquids and gases.”
(Two for each states of matter)
Thermal expansion is the tendency of matter to change its shape dimensions, density in response to a change in temperature.
The following are applications of thermal expansion in various matter.SolidsThe principle of thermal expansion is used in thermostat to regulate the temperature of heating device e.g Electric pressing Iron.Rivets are used to hold steel plates together very tightly.
2. Gases
Hot-air balloons are an application of thermal expansionGases turbine3. Liquids
Engine CoolantsVolume of thermometerLearn more about Expansion of matter here:
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ii. Which of these has a heating element with a low melting point?
a, electric bell
c. electric iron
b. fuse
d. all of these
Which of the following industries is the largest producer of primary air pollutants in the United States?
The largest producer of primary air pollution in the United States is what? electricity producing plants.
Answer:
electricity production
Explanation:
In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?
The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s
We are given the following facts;
Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.Formula for time taken is;
time = distance/speed
Time taken by swimmer 1 for one leg;
t₁ = 50/3.9
t₁ = 12.82 s
Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;
t₂ = 12.82 -0.45
t₂ = 12.37 s
Thus, speed of swimmer 2;
v = 50/12.37
v = 4.04 m/s
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Describe the relative energies of particles in the
different States of matter.
Answer:
MATTER
ARE
OF
THREE
TYPES
SOLID
LIQUID
GAS
the breaks on a 15,680 N car exert a stopping force of 640 N.
Scientific notation of 1,750
A 1000 kg car and a 1500 kg car are driving in opposite directions at 20 m/s and 10 m/s respectively. If the cars collide head-on and stick together, determine their combined speed after the collision.
Hi there!
Recall the conservation of momentum for an inelastic collision:
[tex]\large\boxed{m_1v_1 + m_2v_2 = (m_1 + m_2)v_f}}[/tex]
Remember, velocity is a VECTOR and direction must be accounted for. Let the 1000 kg car have a positive velocity and the 1500 kg car have a negative velocity (opposite direction).
Plug in the given values:
[tex](1000)(20) + (1500)(-10) = (1000 + 1500)v_f}}[/tex]
Solve:
[tex]20000 -15000 = 2500v_f}}\\\\5000 = 2500v_f\\\\v_f =\boxed{ 2 m/s}[/tex]
a narrow slit is illuminated with sodium yellow light of wavelength 589 nm. if the central maximum extends to ±30.0°, how wide is the slit?
Answer:
because of the gravity of the earth
Name a device or gadget that converts
a) Heat energy to mechanical energy b) heat energy to light energy
c)electrical energy to sound energy
Answer:
a heat engine converts heat to mechanical energy.
electric generator
Which of the following statements cannot be supported by Kepler's laws of planetary motion?
A planet's distance from the sun will not be the same in six months.
A planet's speed as it moves around the sun will not be the same in six months.
The rotational speed of the four smallest planets can be determined using the rotational speeds of the four largest planets and their orbital periods.
The average distance of Saturn can be calculated using the average distance of Neptune and the orbital period of both planets.
A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from point D to point E. What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio? Negative one-eleventh One-eleventh Two-fifteenths Fifteen-halves.
The location of the point F that partitions a line segment from D to E ([tex]\overline{DE}[/tex]), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at negative -4 and point E is at positive 5, we have:
[tex] \overline{DE} = E - D = 5 - (-4) = 9 [/tex]
Hence, the segment of the line DE ([tex]\overline{DE}[/tex]) is 9.
Knowing that point F partitions the line segment from D to E ([tex]\overline{DE}[/tex]) into a 5:6 ratio, its location would be:
[tex] F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2} [/tex]
Therefore, the location of point F is fifteen halves (option 4).
Learn more about segments here:
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I hope it helps you!
Answer:
The above answer is actually incorrect - the real answer is B. 1/11
Explanation:
I'm adding a ss below for proof
Hope this helped!
I'd really appreciate Brainliest :)
A wave has frequency of 50 Hz and a wavelength of 10 m. What is the speed of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
Which impact would be more forceful, decreasing speed from 60mph to 0 mph over 2 seconds or 0.5 seconds? Explain
Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass of 0.8 kg. The spring is released and causes the two carts to push off from each other. Which of the following correctly compares the motion and forces acting on the two carts?
A. Cart A experiences a greater force but has the same speed as Cart
B. Cart A experiences a greater force and has a greater speed after the recoil.
C. Both carts experience the same force but Cart A has a greater speed after the recoil.
D. Both carts experience the same force and have the same speed after the recoil.
Both carts experience the same force but Cart A has a greater speed after the recoil.
The given parameters;
Mass of the cart A = 0.4 kgMass of the cart B = 0.8 kgApply the principle of conservation of linear momentum to determine the velocity of the carts after collision;
[tex]m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s[/tex]
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.
[tex]F_A = -F_B[/tex]
Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."
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PLEASE HELP MEEEEE 80 points on the line and i need this done
Answer:
5) A 200n
F net=0n
6) B 50n
F net=0n
7) C 200n
F net= 900n, up
8) D 80n
F net=60n,left
9) E 300n
F net=60n,left
10)???
11) G 20n
F net=30n,Right
__________________________________
All the answers is hard
correct me if i'm wrong
A textbook is sitting at rest on a desk. Compared to the magnitude of the force of the textbook on the desk, how
would you describe the magnitude of the force of the desk on the book?
o less
O zero
O more
O equal
Which of the balls will exert the greatest force on object A?Why?
F = mass × Acceleration ( give Acceleration is 9.8 )
So force of 5 kg mass on A is
F = 5 × 9.8 = 49N
Force of mass 1 kg on A
F = 1 × 9.8 = 9.8 N
Force of mass 10 kg on A is
F = 10 × 9.8 = 98N
Clearly the 10 kg ball experts the most force cause it has more mass
Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?
This question involves the concepts of the equations of motion in vertical direction.
The height of the bridge is "116.8 m".
We will use the second equation of motion in vertical direction to find out the height of the bridge.
[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]
where,
h = hieght = ?
vi = initial speed = 0 m/s
t = time taken = 4.88 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]
h = 116.8 m
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A race car accelerates uniformly from 18.5 m/s in 2.47 seconds m. Determine the acceleration of the car in m/sec^2 and the distance
The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2. The distance traveled is average velocity times time of travel.
Can someone help with 25 to 28 it’s multiple-choice!
Answer:
25:speed
26:acceleration
27:scalar
28:kinetic
An experiment is conducted such that an applied force is exerted on a 5kg object as it travels across a horizontal surface in which frictional forces are NOT considered to be negligible. A graph of the net force exerted on the object as a function of the object’s distance traveled is shown. How could a student use the graph to determine the net work done on the object?
If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.
The graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.
A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5mFor more information on work done, visit
https://brainly.com/subject/physics
Answer:
D. There is not enough information that is known or can be obtained from the graph to determine the net work done on the object.
Explanation:
it’s the answer For Ap classroom
A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
The weak nuclear force causes:
(A). Lightning
(B). Combustion
(C). Radiation
D). Protons and neutrons to form the nuclear of atoms
Answer:
(C) Radiation
Explanation:
The weak nuclear forces causes radiation to form.
If the western component of the wind is half of the south, what is the angle of the wind with the south?
Answer this question in details!
Answer is 26.57 or tan^-1 (1/2) or cot^-1 (2)
no links !
Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
[tex] \tan(x) = \frac{opp}{adj} [/tex]
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]
[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]
Now we take the arctan or inverse tan of 1/2.
[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]
Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.
What are the values of the western and southern component of the wind?The western and southern component have a negative displacement as shown in the graph.
Let the southern component be -x
The western component is half of -x = -x/2
What is the angle of the wind with the South?Since the angle is with the south, the trigonometric ratio to be used to find the angle is:
Tan θ = opp/adjTan θ = -×/2 /-x
Tan θ = 1/2
θ = tan^-1(0.5)
θ = 26.6°
Therefore, angle of the wind with the south is 26.57°.
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HELP!!!!!!!!!!!!
9. Estimate the change in the thermal energy of water in a pond with a mass of
1000 kg and a specific heat of 4200 J/(kg. C) if the water cools by 1°C.
Answer:
-4,200,000 J
Explanation: